Every CBSE Class 12 Chemistry board exam question from 2022-2026 that we have on file, sorted by NCERT chapter and then by type: MCQs and assertion-reason, very short, short and long answers, and case studies. Each question is tagged with its year and marks. A question repeated across paper sets appears once. Questions that depend on a figure from the original paper are left out. Questions only, no answers.
Practise each chapter with free notes, mind maps and graded MCQs.
Practise Class 12 Chemistry →Which of the following colligative properties can preferably determine the molar mass of proteins ?
For an electrolyte consisting of a monovalent cation and a monovalent anion undergoing dissociation in water, the van't Hoff factor (i) is :
Which of the following solutions will have the lowest freezing point in water?
Assertion (A): It is not possible to separate the components of an azeotrope by fractional distillation. Reason (R): Components of an azeotrope have the same composition in liquid and vapour phase and boil at a constant temperature.
Which of the following solutions will have the highest osmotic pressure?
Assertion (A): Components of azeotropes are easily separated by fractional distillation. Reason (R): Components of an azeotrope have same composition in liquid and vapour phase.
Assertion (A) : It is not possible to separate the components of an azeotrope by fractional distillation. Reason (R) : Minimum boiling azeotrope is formed by the solutions showing large positive deviation from Raoult's law.
The boiling point of an azeotropic mixture of water and ethanol is less than that of pure water and ethanol. The mixture shows:
The mole fraction of a solute in 2·0 molal aqueous solution is:
The boiling point of an azeotropic mixture of water and nitric acid is more than that of pure water and nitric acid. The mixture shows :
1 mole of liquid A and 2 moles of liquid B make a solution having a total vapour pressure 40 torr. The vapour pressure of pure A and pure B are 30 torr and 45 torr respectively. The above solution :
The boiling point of one molal NaCl solution, assuming NaCl to be completely dissociated in water is: (Kb for water = 0·52 K kg mol–1)
When a liquid and its vapour are at equilibrium and the pressure is suddenly decreased:
An azeotropic mixture of two liquids has a boiling point higher than that of either of the two liquids when it
Solubility of gases in liquid decreases with increase in
The value of Henry's constant KH is:
Which of the following aqueous solutions will have the highest freezing point?
While doing qualitative analysis in chemistry lab, Abhishek added yellow coloured potassium chromate solution into a test tube. He was surprised to see the colour of the solution changing immediately to orange. He realised that the test tube was not clean and contained a few drops of some liquid. Which of the following substances will be the most likely liquid to be present in the test tube before adding potassium chromate solution?
Assertion (A): Henry's law constant (KH) decreases with increase in temperature. Reason (R): As the temperature increases, solubility of gases in liquids decreases.
The freezing point of one molal KCl solution, assuming KCl to be completely dissociated in water, is : (Kf for water = 1·86 K kg mol–1)
A solution of acetone in ethanol :
A solution of acetone in chloroform:
On mixing 30 mL of acetone with 20 mL of chloroform, the total volume of solution is:
Which of the following solutions will have the highest boiling point in water ?
Assertion (A): Cooking time is reduced in pressure cooker. Reason (R): Boiling point of water inside the pressure cooker is elevated.
Which of the following solution in water will have the lowest freezing point ?
Assertion (A): Cooking time is reduced in pressure cooker. Reason (R): Boiling point of water inside the pressure cooker is lowered down.
Which of the following aqueous solutions will have the highest osmotic pressure?
Assertion (A): Aquatic species are more comfortable in cold water than in warm water. Reason (R): Solubility of oxygen gas in water decreases with increase in temperature.
For an electrolyte undergoing association in a solvent, the v factor:
Assertion (A): When NaCl is added to water a depression in freezing point is observed. Reason (R): NaCl undergoes dissociation in water.
Phenol forms a dimer in benzene with a degree of association of 0.54. Its degree of association is:
Assertion (A): When NaCl is added in water, elevation in boiling point is observed. Reason (R): Elevation in boiling point is a colligative property.
The system that forms maximum boiling azeotrope is:
Assertion (A): ΔHmix for an ideal solution is not equal to zero. Reason (R): A-B interactions in an ideal solution are same as between A-A and B-B interactions.
The relative lowering of vapour pressure of an aqueous solution containing non-volatile solute is 0·0225. The mole fraction of the non-volatile solute is:
On mixing 10 mL of acetone with 50 mL of chloroform, the total volume of the solution will be:
A 1% solution is prepared by dissolving 1 g of sucrose (Molar mass = 342 g mol⁻¹) in 6 solution of the solute is :
Assertion (A): Addition of ethylene glycol to water lowers its freezing point. Reason (R): Ethylene glycol is insoluble in water due to lack of its ability to form hydrogen bonds with water molecules.
A 1% solution of solute in 6 solution of sucrose (molar mass = 342 g mol-1). The molar mass of solute is:
Assertion (A): ΔmixH and ΔmixV are zero for non-ideal solutions. Reason (R): Solute-solvent interactions are not same as pure solute-solute and pure solvent-solvent interactions in non-ideal solutions.
A solution is prepared by dissolving a 1% solution of sucrose (molar mass = 342 g mol⁻¹). The molar mass of the solute is:
Assertion (A): ΔHmix and ΔVmix are zero for an ideal solution. Reason (R): A solution which obeys Raoult's law over the entire range of concentration is called an ideal solution.
The colligative property used for the determination of molar mass of polymers and proteins is:
Low concentration of oxygen in the blood and tissues of people living at high altitude is due to:
On dissolving ammonium chloride in water at room temperature, the solution feels cool to touch. Under which of the following conditions does salt dissolve faster?
Value of Henry's constant KH:
Assertion (A): Osmotic pressure is a colligative property. Reason (R): Osmotic pressure is proportional to the molality.
An azeotropic mixture of two liquids will have a boiling point lower than either of the two liquids when it
Assertion (A): Elevation in boiling point is a colligative property. Reason (R): The lowering of vapour pressure of solution causes elevation in boiling point.
Solubility of gas in liquid decreases with increase in
Assertion (A): The enthalpy of mixing ΔHmix is equal to zero for an ideal solution. Reason (R): For an ideal solution the interaction between solute and solvent molecules is stronger than the interactions between solute-solute or solvent-solvent molecules.
Which of the following colligative property is used to find the molar mass of proteins?
Isotonic solutions have:
Kohlrausch gave the following relation for strong electrolyte: Λ = Λ° - A√C. Which of the following equality holds true?
Which one of the following pairs will not form an ideal solution?
A compound undergoes complete tetramerization in a given organic solvent. Van't Hoff factor i is:
Assertion (A): When NaCl is added to water, a depression in freezing point is observed. Reason (R): The lowering of vapour pressure of a solution causes depression in the freezing point.
A compound undergoes complete dimerization in a given organic solvent. The Van't Hoff factor is:
Assertion (A): When glucose is added to water, an elevation in boiling point is observed. Reason (R): The lowering of vapour pressure causes elevation in the boiling point.
A compound CaCl2 . 6H2O undergoes complete dissociation in water. The van't Hoff factor is:
Assertion (A): When NaCl is added to water, a depression in freezing point is observed. Reason (R): The vapour pressure of solution is increased which causes depression in freezing point.
1 mole of liquid A and 2 moles of liquid B make a solution having a total vapour pressure 40 torr. The vapour pressure of pure A and pure B are 45 torr and 30 torr respectively. The above solution
If molality of a dilute solution is doubled, the value of the molal elevation constant (Kb) will be
Which of the following aqueous solution will have highest boiling point?
The unit of molar conductivity is
Out of the following 1.0 M aqueous solutions, which one will show largest freezing point depression?
State Raoult's law for a solution containing volatile components. Write any two characteristics of a solution which obeys Raoult's law at all concentrations.
What type of deviation from Raoult's law is shown by a mixture of phenol and aniline? Give reason. What will happen to the boiling point of the solution on mixing phenol and aniline?
What type of deviation from Raoult's law is shown by mixture of ethanol and acetone? Give reason. What will happen to the boiling point of the solution on mixing ethanol and acetone?
What type of deviation is shown by a mixture of chloroform and acetone from Raoult's law ? Give reason. What will happen to the boiling point of the solution on mixing chloroform and acetone ?
Explain why, on addition of 1 mol of KCl to 1 litre of water, the boiling point of water increases, while the addition of 1 mol of methyl alcohol to 1 litre of water decreases the boiling point.
(a) Explain the following with the help of Henry's law: (i) Bends (ii) Anoxia
(a) Explain the following with the help of Henry's law: (i) Bends (ii) Anoxia OR (b) How does sprinkling of salt help in clearing the snow covered roads in hilly areas? Write the name of the colligative property involved in this process.
(a) 1·00 molal aqueous solution of trichloroacetic acid is heated to its boiling point. Boiling point of this solution was found to be 100·18°C. Calculate the van't Hoff factor for trichloroacetic acid. (Given : Kb for water = 0·512 K kg mol⁻¹)
(a) 1·00 molal aqueous solution of trichloroacetic acid is heated to its boiling point. Boiling point of this solution was found to be 100·18°C. Calculate the van't Hoff factor for trichloroacetic acid. (Given: Kb for water = 0·512 K kg mol⁻¹) OR (b) State Henry's law. Calculate the mole fraction of CO2 in water at 298 K under 760 mm Hg. (Given: KH for CO2 in H2O at 298 K = 1·25 × 10⁶ mm Hg)
(a) Calculate the elevation of boiling point of a solution when 3 g of CaCl2 (Molar mass = 111 g mol–1) was dissolved in 260 g of water, assuming that CaCl2 undergoes complete dissociation. (Kb for water = 0·52 K kg mol–1)
State Henry's law. Why are aquatic species more comfortable in cold water as compared to warm water ?
State Raoult's law for a solution containing volatile components. Why is the vapour pressure of an aqueous solution of glucose lower than that of water?
Define osmotic pressure. Why is measurement of osmotic pressure method preferred for the determination of molar masses of macromolecules such as proteins and polymers?
What is meant by positive deviation from Raoult's law ? Give an example. What type of azeotrope is formed by positive deviation ?
What is meant by negative deviation from Raoult's law ? Give an example. What type of azeotrope is formed by negative deviation ?
(a) A and B liquids on mixing show rise in temperature. Which type of deviation from Raoult's law is there and why? (b) Why can azeotropic mixture not be separated by fractional distillation?
A 6% solution of glucose (molar mass = 180 g mol−1) is isotonic with 25% solution of an unknown organic substance. Calculate the molecular weight of the unknown organic substance.
A 4% solution of urea (molar mass = 60 g mol^-1) is isotonic with 52% solution of an unknown organic substance. Calculate the molecular weight of the unknown organic substance.
A 3% solution of glucose (molar mass = 180 g mol⁻¹) is isotonic with 25% solution of an unknown organic substance. Calculate the molecular weight of the unknown organic substance.
(a) Define molal depression constant. How is it related to enthalpy of fusion ?
Define molal depression constant. How is it related to enthalpy of fusion? OR What type of deviation is shown by ethanol and acetone mixture? Give reason. What type of azeotropic mixture is formed by that deviation?
A solution is prepared by dissolving 10 g of non-volatile solute in 200 g of water. It has a vapour pressure of 31.84 mm Hg at 308 K. Calculate the molar mass of the solute. (Vapour pressure of pure water at 308 K = 32 mm Hg)
The vapour pressure of pure liquid X and pure liquid Y at 25°C are 120 mm Hg and 160 mm Hg respectively. If equal moles of X and Y are mixed to form an ideal solution, calculate the vapour pressure of the solution.
Give reasons for the following: (a) Aquatic animals are more comfortable in cold water in comparison to warm water. (b) Sprinkling of salt helps in clearing the snow-covered roads in hilly areas.
On mixing liquid X and liquid Y, volume of the resulting solution decreases. The resulting solution shows what kind of deviation from Raoult's law? What change in temperature would you observe after mixing liquids X and Y?
How does the mixture of ethanol and acetone show deviation from Raoult's law? Give reason.
What is shown by a mixture of ethanol and acetone? Give reason.
Do ethanol and acetone form an azeotrope? Give reason.
Why is a mixture of ethanol and acetone unable to show the ideal behavior of Raoult's law? Give reason.
Calculate the molarity and molality of a KI solution if the density of 20% (mass/mass) aqueous solution of KI is 1·2 g mL−1. [Given : Molar mass of KI = 166 g mol−1]
Calculate the boiling point of a solution containing 0.61 g of benzoic acid (Molar mass = 122 g mol–1) in 5 g of CS2 in which it dimerises to the extent of 88%. The boiling point and Kb of CS2 are 46.2°C and 2.3 K kg mol–1 respectively.
When 1.5 g of a non-volatile solute was dissolved in 90 g of benzene, the boiling point of benzene got raised from 353.23 K to 353.93 K. Calculate the molar mass of the solute. (Given Kb for benzene = 2.52 K kg mol–1)
A solution containing 8.0 g of a non-volatile solute in 100 g of diethyl ether boils at 36.86 °C whereas pure diethyl ether boils at 35.60 °C. Determine the molar mass of the solute. (K b for diethyl ether = 2.02 K kg mol–1)
60 g of glucose is dissolved in 250 g of water. Calculate the freezing point of this solution. (molar mass of glucose = 180 g mol–1, Kf for water = 1.86 K kg mol–1)
An antifreeze solution is prepared by dissolving 31 g of ethylene glycol (Molar mass = 62 g mol^−1) in 600 g of water. Calculate the freezing point of the solution. (Kf for water = 1·86 K kg mol^−1)
Calculate the vapour pressure of a solution containing 61 g of benzoic acid (molar mass = 122 g mol–1) dissolved in 500 g of benzene when the vapour pressure of pure benzene at this temperature of experiment is 66 torr. Assume complete dimerization of benzoic acid in benzene.
An aqueous solution of NaOH was made and its molar mass from the measurement of osmotic pressure at 27°C was found to be 25 g mol–1. Calculate the percentage dissociation of NaOH in this solution. [Atomic mass: Na = 23 u, O = 16 u, H = 1 u]
An aqueous solution of NaOH was made and its molar mass from the measurement of osmotic pressure at 25°C was found to be 28 g mol⁻¹. Calculate the percentage dissociation of NaOH in this solution. [Atomic mass: Na = 23·0 u, O = 16·0 u, H = 1·0 u]
(a) Shweta mixed two liquids A and B of 10 mL each. After mixing, the volume of the solution was found to be 20·2 mL. (i) Why was there a volume change after mixing the liquids? (ii) Will there be an increase or decrease of temperature after mixing? (iii) Give one example for this type of solution.
Shweta mixed two liquids A and B of 10 mL each. After mixing, the volume of the solution was found to be 20·2 mL. Why was there a volume change after mixing the liquids ?
Vapour pressure of pure water at 298 K is 24·8 mm Hg. Calculate the lowering in vapour pressure of an aqueous solution which freezes at – 0·3°C. (Kf of water = 1·86 K kg mol–1)
03 g of acetic acid (Molar mass = 60 g mol–1) dissolved in 30 g of benzene shows a depression in freezing point equal to 0.45°C. Calculate the percentage association of acid if it forms a dimer in the solution. (Given : Kf for benzene = 5.12 K kg mol–1)
The vapour pressure of a solvent at 283 K is 100 mm Hg. Calculate the vapour pressure of a dilute solution containing 1 mole of a strong electrolyte AB in 50 moles of the solvent at 283 K (assuming complete dissociation of solute AB).
A solution is prepared by dissolving 5 g of a non-volatile solute in 200 g of water. It has a vapour pressure of 31·84 mm Hg at 300 K. Calculate the molar mass of the solute. (Vapour pressure of pure water at 300 K = 32 mm Hg)
(a) Differentiate between Ideal solution and Non-ideal solution. (b) 30 g of urea is dissolved in 846 g of water. Calculate the vapour pressure of water for this solution if vapour pressure of pure water at 298 K is 23.8 mm Hg.
Give reason: (a) Measurement of osmotic pressure method is preferred for the determination of molar masses of macromolecules such as proteins and polymers. (b) Aquatic animals are more comfortable in cold water than in warm water. (c) Elevation of boiling point of 1 M KCl solution is nearly double than that of 1 M sugar solution.
When 19.5 g of F–CH2–COOH (Molar mass = 78 g mol–1), is dissolved in 500 g of water, the depression in freezing point is observed to be 1°C. Calculate the degree of dissociation of F–CH2–COOH. [Given: Kf for water = 1.86 K kg mol–1]
0.3 g of acetic acid (M = 60 g mol⁻¹) dissolved in 30 g of benzene shows a depression in freezing point equal to 0.45°C. Calculate the percentage association of acid if it forms a dimer in the solution. (Given: Kf for benzene = 5.12 K kg mol⁻¹)
If benzoic acid (M = 122 g mol^-1) is associated into a dimer when dissolved in benzene and the osmotic pressure of a solution of 6.1 g of benzoic acid in 100 mL benzene is 6.5 atm at 27°C, then what is the percentage association of benzoic acid? (Given: R = 0.0821 L atm K^-1 mol^-1)
Write three differences between Lyophobic sol and Lyophilic sol.
(a) (i) Calculate the freezing point of a solution when 10·5 g of MgBr2 was dissolved in 250 g of water, assuming MgBr2 undergoes complete dissociation. (Given : Molar mass of MgBr2 = 184 g mol⁻¹, Kf for water = 1·86 K kg mol⁻¹) (ii) Write two differences between ideal and non-ideal solutions.
(a) (i) Calculate the freezing point of a solution when 10·5 g of MgBr2 was dissolved in 250 g of water, assuming MgBr2 undergoes complete dissociation. (Given: Molar mass of MgBr2 = 184 g mol⁻¹, Kf for water = 1·86 K kg mol⁻¹) (ii) Write two differences between ideal and non-ideal solutions. OR (b) (i) A solution is prepared by dissolving 0·025 g of potassium sulphate in 2 L of water at 27°C. Assuming potassium sulphate is completely dissociated, determine its osmotic pressure. (Given: R = 0·082 L atm K⁻¹ mol⁻¹, Molar mass of K2SO4 = 174 g mol⁻¹) (ii) What type of azeotrope will be formed by a solution of acetone and chloroform? Give reason.
(A) (a) Calculate the boiling point of solution when 6 g of MgSO4 (Molar mass = 120 g mol–1) was dissolved in 200 g of water, assuming the complete dissociation of MgSO4. (Kb for water = 0.52 K kg mol–1). (b) State Raoult's law for a solution containing volatile components. How Raoult's law is a special case of Henry's law ?
(a) (i) At the same temperature, CO2 gas is more soluble in water than O2 gas. Which one of them will have higher value of KH and why? (ii) How does the size of blood cells change when placed in an aqueous solution containing more than 0·9% (mass/volume) sodium chloride? (iii) 1 molal aqueous solution of an electrolyte A2B3 is 60% ionized. Calculate the boiling point of the solution. (Given : Kb for H2O = 0·52 K kg mol1)
(a) (i) At the same temperature, CO2 gas is more soluble in water than O2 gas. Which one of them will have higher value of KH and why?
(a) (i) Why is boiling point of 1M NaCl solution more than that of 1M glucose solution? (ii) A non-volatile solute 'X' (molar mass = 50 g mol–1) when dissolved in 78g of benzene reduced its vapour pressure to 90%. Calculate the mass of X dissolved in the solution. (iii) Calculate the boiling point elevation for a solution prepared by adding 10g of MgCl2 to 200g of water assuming MgCl2 is completely dissociated.
(a) (i) Why is boiling point of 1M NaCl solution more than that of 1M glucose solution? (ii) A non-volatile solute 'X' (molar mass = 50 g mol–1) when dissolved in 78g of benzene reduced its vapour pressure to 90%. Calculate the mass of X dissolved in the solution. (iii) Calculate the boiling point elevation for a solution prepared by adding 10g of MgCl2 to 200g of water assuming MgCl2 is completely dissociated. (Kb for Water = 0.512 K kg mol–1, Molar mass MgCl2 = 95g mol–1)
Case study · CBSE 2026
Osmosis is a process by which the molecules of a solvent pass from a solution of low solute concentration to a solution of high solute concentration through a semi-permeable membrane. Osmotic pressure is a colligative property. When the applied pressure on a solution exceeds its osmotic pressure, reverse osmosis occurs. When two solutions are separated by a semipermeable membrane and they have same osmotic pressure they are said to be isotonic. Of the two solutions separated by a semipermeable membrane, if one is a lower osmotic pressure, it is said to be hypotonic relative to the second solution. If it has a higher osmotic pressure, than the second solution, it is said to be hypertonic relative to the second solution. The osmotic pressure associated with the fluid inside the blood cell is equivalent to that of 0.9% (mass/volume) sodium chloride solution called normal saline solution and it is safe to inject intravenously. Osmotic pressure is vital in daily life and nature. It helps in explain, why IV fluids match blood's osmotic pressure, its also the principle behind food preservation using salt or sugar.
Calculate the amount of CaCl2 (i = 2.59) dissolved in 2.46 litre of water such that its osmotic pressure is 0.70 atm at 27°C. [Given: R = 0.082 L atm K–1 mol–1, molar mass of CaCl2 = 111 g mol–1]
Case study · CBSE 2025
According to the generally accepted definition of the ideal solution there are equal interaction forces acting between molecules belonging to the same or different species. (This is equivalent to the statement that the activity of the components equals the concentration.) Strictly speaking, this condition is fulfilled only in exceptional cases for mixtures (optical isomers, isotopic mixtures of an element, hydrocarbon mixtures). It is still usual to talk about ideal solutions as limiting cases in reality since very dilute solutions behave ideally with respect to the solvent. This view is further supported by the fact that Raoult's law empirically found for describing the behaviour of the solvent in dilute solutions can be deduced thermodynamically via the assumption of ideal behaviour of the solvent.
(a) Give one example of miscible liquid pair which shows negative deviation from Raoult's law. What is the reason for such deviation?
Case study · CBSE 2023
Rahul set-up an experiment to find resistance of aqueous KCl solution for different concentrations at 298 K using a conductivity cell connected to a Wheatstone bridge. He fed the Wheatstone bridge with a.c. power in the audio frequency range 550 to 5000 cycles per second. Once the resistance was calculated from null point he also calculated the conductivity K and molar conductivity Λm and recorded his readings in tabular form. S.No. Conc.(M) k S cm–1 Λm S cm2 mol–1. 1. 1.00 111.3 × 10–3 111.3. 2. 0.10 12.9 × 10–3 129.0. 3. 0.01 1.41 × 10–3 141.0
Why does conductivity increase though the conductivity decrease with dilution?
The standard electrode potentials of three metals A, B and C are, respectively, + 0·34 V, − 1·18 V and − 0·25 V. The correct order of reducing power of these metals is :
What will happen during the electrolysis of aqueous solution of CuCl2 by using platinum electrodes?
How many Faradays are required to reduce 1 mol of Cr2O7²⁻ to Cr³⁺ in acidic medium?
How the conductivity varies on decreasing concentration for both weak and strong electrolytes ?
Consider the following reaction: Zn (s) + Ag2O(s) + H2O(l) → Zn2+(aq) + 2Ag(s) + 2OH–(aq). Given: EoAg+/Ag = 0.80 V, EoZn2+/Zn = – 0.76 V, 1 F = 96500 C mol–1. ΔrGo for the above reaction is:
Consider the following reaction: Zn (s) + Ag2O(s) + H2O(l) → Zn2+(aq) + 2Ag(s) + 2OH–(aq). Given: E°Ag+/Ag = 0.80 V, E°Zn2+/Zn = – 0.76 V, 1 F = 96500 C mol–1. ΔrG° for the above reaction is:
On electrolysis of very dilute aqueous solution of NaCl using platinum electrodes:
Consider the following cell at 298 K: Mg (s) | Mg2+ (1·0 M) || Cu2+ (1·0 M) | Cu (s). How can we increase the emf of the cell using the same substances?
Assertion (A): E°Cu2+/Cu has positive value (+ 0.34 V). Reason (R): It is due to low ∆hydH° and high ∆aH°.
Assertion (A): E°Mn+2/Mn value is highly negative. Reason (R): Because Mn2+ is highly stable due to half-filled 3d5 configuration.
Kohlrausch gave the following relation for strong electrolytes at low concentration: Λm = Λ0m – AC. Which of the following equality holds true ?
ΔrG° and Ecell for a spontaneous reaction will respectively be
In an electrochemical cell, the following reaction takes place: 2Cu+ (aq) + Zn (s) → 2Cu (s) + Zn2+ (aq), E°cell = 1·28 V. As the reaction progresses, what will happen to the overall voltage of the cell?
What amount of electric charge is required for the reduction of 1 mole of MnO4– into Mn2+?
Assertion (A): Electrolysis of aqueous NaCl gives H2 at cathode and Cl2 at anode. Reason (R): Chlorine has higher oxidation potential than H2O.
The product of the oxidation of I– with MnO4– in alkaline medium is:
In an electrochemical cell, the following reaction takes place: 2Ag+ (aq) + Mg (s) → 2Ag (s) + Mg2+ (aq), Ecell = 2·96 V. As the reaction progresses, what will happen to the overall voltage of the cell?
What amount of electric charge is required for the oxidation of 1 mole of H2O to O2?
In an electrochemical cell, the following reaction takes place: 2Cu+ (aq) + Zn (s) → 2Cu (s) + Zn2+ (aq) with E°cell = 1·28 V. As the reaction progresses, what will happen to the overall voltage of the cell?
What amount of electric charge is required for the oxidation of 1 mole of FeO to Fe2O3?
Match the type of cell given in Column I with their use given in Column II. Column I: i. Lead storage cell ii. Mercury cell iii. Dry cell iv. Fuel cell Column II: a. Wall clock b. Apollo Space Programme c. Wrist watch d. Inverter
Assertion (A): For measuring resistance of an ionic solution an AC source is used. Reason (R): Concentration of ionic solution will change if DC source is used.
While doing qualitative analysis in chemistry lab, Abhishek added yellow coloured potassium chromate solution into a test tube. He was surprised to see the colour of the solution changing immediately to orange. He realised that the test tube was not clean and contained a few drops of some liquid. Which of the following substances will be the most likely liquid to be present in the test tube before adding potassium chromate solution?
Which of the following cell converts the energy of combustion of fuel into electrical energy ?
A galvanic cell can behave like an electrolytic cell when
We cannot measure the resistance of an ionic solution using DC because:
During electrolysis of dilute H2SO4, using platinum electrodes, the gas evolved at the anode is :
Kohlrausch gave the following relation for strong electrolytes: Λm = Λ°m – A√C. Which of the following equality holds true ?
A conductivity cell usually consists of two:
The equilibrium Cr2O7²⁻ + 14H⁺ + 6e⁻ → 2Cr³⁺ + 7H2O exists in:
During electrolysis of aqueous solution of NaCl:
The product of oxidation of SO3^2- with MnO4^- in acidic medium is:
During electrolysis of aqueous CuCl2:
The unit of cell constant is:
During the electrolysis of aqueous NaCl, the cathodic reaction is :
Which of the following is a secondary cell?
Which of the following cells is used in hearing aids?
The correct cell to represent the following reaction is: Zn + 2Ag+ → Zn2+ + 2Ag
ΔG and Ecell for a spontaneous reaction will be:
Ag+ (aq) + e⁻ → Ag (s) E° = + 0.80 V Fe²⁺ (aq) + 2e⁻ → Fe (s) E° = −0.44 V Find the cell E° for: Fe (s) + 2Ag+ (aq) → Fe²+ (aq) + 2Ag (s)
Which of the following solutions of KCl will have the highest value of molar conductivity?
Assertion (A): Conductivity decreases with decrease in concentration of electrolyte. Reason (R): Number of ions per unit volume that carry the current in a solution decreases on dilution.
Which of the following relations is incorrect?
Assertion (A): Molar conductivity decreases with increase in concentration. Reason (R): When concentration approaches zero, the molar conductivity is known as limiting molar conductivity.
Assertion (A): Electrolysis of aqueous solution of NaCl gives chlorine gas at anode instead of oxygen gas. Reason (R): Formation of oxygen gas at anode requires overpotential.
Kohlrausch gave the following relation for strong electrolyte: Λ = Λ₀ - A√C. Which of the following equality holds true?
KMnO4 acts as an oxidising agent in alkaline medium. When alkaline KMnO4 is treated with KI, iodide ion is oxidised to:
The cathode reaction during the charging of a lead storage battery leads to the:
How many Faradays are required to reduce 1 mol of MnO4^- to Mn2+?
Assertion (A): λm for weak electrolytes shows a sharp decrease when the electrolytic solution is diluted. Reason (R): For weak electrolytes, degree of dissociation increases with dilution of solution.
The number of faradays passed through a solution of CuSO₄ to produce 1 mol of Cu and O₂ will be:
Assertion (A): Λm for weak electrolytes shows a sharp increase when the electrolytic solution is diluted. Reason (R): For weak electrolytes, degree of dissociation decreases with dilution of solution.
Corrosion of iron is:
Assertion (A): Limiting molar conductivity (Λₘ) is obtained by the extrapolation of the Λₘ versus C^(1/2) curve of strong electrolyte. Reason (R): Λₘ for weak electrolytes is obtained by using Kohlrausch law.
Assertion (A): Cu/2Cu⁺ E° is positive (+0.34 V). Reason (R): Copper has high Δhyd H and low Δhydr H.
A voltaic cell is made by connecting two half cells represented by half equations below: Sn2+(aq) + 2e– → Sn(s) E = –0.14 V; Fe3+(aq) + e– → Fe2+(aq) E = +0.77 V. Which statement is correct about this voltaic cell?
Which of the following cell was used in Apollo space programme?
Consider the following standard electrode potential values: Fe3+(aq) + e– → Fe2+(aq) E = + 0.77 V and MnO4–(aq) + 8H+ + 5e– → Mn2+(aq) + 4 H2O(l) E = + 1.51 V. What is the cell potential for the redox reaction?
A voltaic cell is made by connecting two half cells represented by half equations below: Sn2+(aq) + 2e– → Sn(s) E = – 0.14 V and Fe3+(aq) + e– → Fe2+(aq) E = + 0.77 V. Which statement is correct about this voltaic cell?
Consider the following standard electrode potential values: Sn2+(aq) + 2e– → Sn(s) E = – 0.14 V and Fe3+(aq) + e– → Fe2+(aq) E = + 0.77 V. What is the cell reaction and potential for the spontaneous reaction that occurs?
(a) Name the cell which was used in the Apollo space programme for providing electrical power. (b) Define limiting molar conductivity.
(a) Name any two materials other than hydrogen that can be used as fuel in fuel cells. (b) Define molar conductivity.
(a) Name the cell used in hearing aids and watches. (b) Define conductivity. Why is direct current (DC) not used for the measurement of resistance of an ionic solution?
(a) Why does the cell potential of mercury cell remains constant throughout its life ? (b) Calculate the degree of dissociation (α) of CH3COOH if Λm and Λ0m of CH3COOH are 50 S cm2 mol–1 and 400 S cm2 mol–1 respectively.
Using the E° values of P and Q, predict which one is better for coating the surface of iron [E°(Fe2+ → Fe) = –0.44 V] to prevent corrosion and why ? E°(P2+ → P) = –2.37 V, E°(Q2+ → Q) = –0.14 V
Define fuel cell. Give two advantages of fuel cell over ordinary cell.
Name and define the cell which was used for providing electric power in the Apollo space programme. Also write its one advantage.
Based on the data given: Concentration of KCl solution in mol/L (1.000, 0.100, 0.010), Conductivity at 298.15 K in S cm–1 (0.1113, 0.0129, 0.00141), Molar Conductivity at 298.15 K in S cm2 mol–1 (111.3, 129.0, 141.0). Give plausible reason for the variation of conductivity and molar conductivity with concentration.
Calculate the potential of Iron electrode in which the concentration of Fe2+ ion is 0.01 M. (EoFe2+/Fe = -0.45 V at 298 K) [Given: log 10 = 1]
Calculate the potential of Iron electrode in which the concentration of Fe2+ ion is 0.01 M. (E°Fe2+/Fe = -0.45 V at 298 K) [Given: log 10 = 1]
What is meant by conductivity? Give an application.
On diluting two electrolytes A and B 5 times, the molar conductivity of A becomes 25 while that of B is 1.5. Which of the two electrolytes is strong? Justify your answer graphically.
Complete the following equations: (a) 4MnO2 + 2NO5 + 6H+ → (b) Cr2O7 + 14H+ + 6e- →
(a) The E° value for the Mn³⁺/Mn²⁺ couple is much more positive than that for Cr³⁺/Cr²⁺ couple or Fe³⁺/Fe²⁺ couple. How would you account for this? (b) Complete the following equation: 4MnO₂ + 16H⁺ + 24e⁻ → 2O₂C₅...
(a) On diluting two electrolytes A and B their λₘ values are 5 S cm² mol⁻¹ and 1.5 S cm² mol⁻¹ respectively. Which of the two electrolytes is strong? Justify your answer graphically. OR (b) The electrical resistance of a column of 0.05 mol L⁻¹ NaOH solution of diameter 1 cm and length 50 cm is 5.55 × 10⁻³ ohm. Calculate the conductivity.
(a) Calculate ΔrG for the cell reaction at 25°C: Zn | Zn2+ || Cd2+ | Cd. Given that: E°Zn/2Zn = −0.76 V, E°Cd/2Cd = −0.40 V, 1 F = 96500 C mol−1. OR (b) The electrical resistance of a column of 0.05 mol L−1 NaOH solution of diameter 1 cm and length 50 cm is 5.55 × 10−3 ohm. Calculate the conductivity.
Complete the following equations: (a) 4MnO2 + 2NO3− + 6H+ → (b) Cr2O7²⁻ + 14H+ + 6e− →
Give reasons: (i) Mercury cell delivers a constant potential during its life time. (ii) In the experimental determination of electrolytic conductance, Direct Current (DC) is not used.
(a) Give reasons: (i) Mercury cell delivers a constant potential during its life time. (ii) In the experimental determination of electrolytic conductance, Direct Current (DC) is not used. OR (b) Define fuel cell with an example. What advantages do the fuel cells have over primary and secondary batteries?
Define fuel cell and write its two advantages.
Name the cell which: (a) was used in Apollo Space programme. (b) is used in automobiles and inverters. (c) is suitable for hearing aids and watches. (d) does not give a steady potential and is used in transistors.
(a) (i) What should be the signs (positive/negative) for ECell and ΔG for a spontaneous redox reaction occurring under standard conditions? (ii) State Faraday's first law of electrolysis.
(a)(i) What should be the signs (positive/negative) for ECell and G for a spontaneous redox reaction occurring under standard conditions?
Define molar conductivity for the solution of an electrolyte. How does it vary with concentration ?
The resistance and conductivity of a conductivity cell containing 0·001 M KCl solution at 298 K are 1200 Ω and 1·5 × 10⁻⁴ S cm⁻¹. Calculate its cell constant and molar conductivity.
In a plot of m against the square root of concentration (C1/2) for strong and weak electrolyte, the value of limiting molar conductivity of a weak electrolyte cannot be obtained graphically. Suggest a way to obtain this value. Also state the related law, if any.
Define conductivity and molar conductivity for a solution of an electrolyte. Why does the conductivity of a solution decrease with decrease in concentration ?
Answer the following: (i) Why is the Equilibrium Constant (Kc) related to E°cell and not to Ecell? (ii) Two metals 'A' and 'B' have standard electrode potential values of –0.24 V and +0.80 V respectively. Which of these will liberate hydrogen gas from dil. H2SO4? (iii) Write the cell reaction which occurs in lead storage battery when it is in charging.
Calculate emf of the following cell at 298 K: Sn | Sn2+(0.001 M) || H+(0.01 M) | H2(g) (1 bar) | Pt(s). Given: EoSn2+/Sn = – 0.14 V, EoH+/H2 = 0.00 V [log 10 = 1]
Calculate emf of the following cell at 298 K: Sn | Sn 2+ (0.001 M) | | H+ (0.01 M) | H2(g) (1 bar) | Pt(s). Given: E°Sn2+/Sn = – 0.14 V, E°H+/H2 = 0.00 V [log 10 = 1]
State Kohlrausch's law of independent migration of ions. With the help of a curve, explain why it is not easy to determine λm for weak electrolytes by extrapolating the concentration − molar conductivity curve, as it is for strong electrolytes.
Answer the following questions: (a) Why is direct current (DC) not used to measure the resistance of an ionic solution? (b) Why are the products of electrolysis different for the electrolysis of aqueous solution of AgNO3 with silver electrodes and electrolysis of aqueous solution of AgNO3 with platinum electrodes? (c) Why are magnesium blocks fixed to the iron pipelines carrying water?
(a) Why is direct current (DC) not used to measure the resistance of an ionic solution? (b) Why are the products of electrolysis different for the electrolysis of aqueous solution of AgNO3 with silver electrodes and electrolysis of aqueous solution of AgNO3 with platinum electrodes? (c) Why are magnesium blocks fixed to the iron pipelines carrying water?
Calculate emf of the following cell at 298 K : Cr (s)| Cr³⁺(aq) (0.1 M)|| Fe²⁺(aq) (0.01 M)|Fe (s) (Given : E°Cr³⁺/Cr = – 0.74 V, E°Fe²⁺/Fe = – 0.44 V, [log 10 = 1])
Calculate emf of the following cell at 298 K: Al (s)| Al³⁺(aq) (0.1 M)|| Ni²⁺(aq) (0.01 M)|Ni (s). (Given: E°(Ni²⁺/Ni) = –0.25 V, E°(Al³⁺/Al) = –1.66 V, [log 10 = 1])
Calculate emf of the following cell at 298 K: Zn (s)|Zn²⁺ (aq) (0.1 M)|| Ag⁺ (aq) (0.01 M)|Ag (s) (Given: E°(Zn²⁺/Zn) = –0.76 V, E°(Ag⁺/Ag) = +0.80 V, [log 10 = 1])
Calculate ΔrG° and log KC for the following cell at 25°C : Zn | Zn2+ || Cd2+ | Cd Given that : E°(Zn2+ → Zn) = –0.76 V, E°(Cd2+ → Cd) = –0.40 V 1 F = 96500 C mol–1.
Calculate the cell voltage of the voltaic cell which is set up by joining following half-cells at 25°C: Al/ Al3+ (0.001 M) and Ni/ Ni2+ (0.1 M). Given: E°(Ni2+/Ni) = –0.25 V, E°(Al3+/Al) = –1.66 V
Calculate the cell voltage of the voltaic cell which is set up by joining the following half-cells at 25°C: Al/ Al3+ (0·001 M) and Ni/ Ni2+ (0·001 M). Given: Eo(Ni2+/Ni) = – 0·25 V, Eo(Al3+/Al) = – 1·66 V
Calculate the cell voltage of the voltaic cell which is set up by joining the following half-cells at 25°C: Al/Al³⁺ (0·002 M) and Ni/Ni²⁺ (0·002 M). Given: E°Ni²⁺/Ni = –0·25 V, E°Al³⁺/Al = –1·66 V, log 5 = 0·6990
Give reasons for the following: (a) The pH of aqueous NaCl increases when it is electrolysed. (b) Unlike dry cell, mercury cell has a constant cell potential through its lifetime. (c) Conductivity of solution decreases with dilution.
Write the name of the cell which is generally used in inverters. Write the reactions taking place at anode and cathode of this cell, when it is in use.
(a) Write the name of the cell which is generally used in inverters. Write the reactions taking place at anode and cathode of this cell, when it is in use. OR (b) Explain why electrolysis of an aqueous solution of NaCl gives H2 gas at cathode and Cl2 gas at anode? Write overall reaction. (Given: E°Na+/Na = – 2.71 V, E°H2O/H2 = – 0.83 V, E°Cl2/2Cl– = + 1.36 V, E°O2/H2O = + 1.23 V)
When a certain conductivity cell was filled with 0.05 M KCl solution, it has a resistance of 100 ohm at 25°C. When the same cell was filled with 0.02 M AgNO3 solution, the resistance was 90 ohm. Calculate the conductivity and molar conductivity of AgNO3 solution. (Given: Conductivity of 0.05 M KCl solution = 1.35×10-2 ohm-1cm-1)
When a certain conductivity cell was filled with 0.05 M KCl solution, it has a resistance of 100 ohm at 25ºC. When the same cell was filled with 0.02 M AgNO3 solution, the resistance was 90 ohm. Calculate the conductivity and molar conductivity of AgNO3 solution. (Given: Conductivity of 0.05 M KCl solution = 1.35×10⁻² ohm⁻¹cm⁻¹)
Calculate emf of the following cell: Zn (s) | Zn2+ (0.1 M) || Sn2+ (0.001 M) | Sn (s) [log 10 = 1]
The conductivity of 0·2 M solution of KCl is 2·48 × 10⁻² S cm⁻¹. Calculate its molar conductivity and degree of dissociation (α). Given: λ°ₖ = 73·5 S cm² mol⁻¹, λ°ₓₗ = 76·5 S cm² mol⁻¹
The conductivity of 0·2 M solution of KCl is 2·48 × 10-2 S cm-1. Calculate its molar conductivity and degree of dissociation (α). Given: λoK = 73·5 S cm2 mol-1, λoCl = 76·5 S cm2 mol-1
The conductivity of 0.2 M solution of KCl is 2.48 × 10⁻² S cm⁻¹. Calculate its molar conductivity and degree of dissociation (α). Given: λ°ₖ = 73.5 S cm² mol⁻¹ and λ°ᶜˡ = 76.5 S cm² mol⁻¹
Calculate the degree of dissociation (α) of CH3COOH if Λm and Λ₀m of CH3COOH are 48 S cm² mol⁻¹ and 400 S cm² mol⁻¹ respectively.
Calculate the emf of the following cell: Zn (s)|Zn²⁺ (0·01 M) || (0·001 M) Ag⁺|Ag (s) Given: E°Zn/Zn² = −0·76 V and E°Ag/Ag = +0·80 V [log 2 = 0·3010, log 3 = 0·4771, log 10 = 1]
Calculate the emf of the following cell : Zn (s)|Zn²⁺ (0·01 M) || Ag⁺ (0·001 M) Ag (s) Given : E°(Zn/Zn²⁺) = -0·76 V and E°(Ag/Ag⁺) = +0·80 V [log 2 = 0·3010, log 3 = 0·4771, log 10 = 1]
Write the Nernst equation and calculate emf of the following cell at 298 K: Cr|Cr3+ (0·1 M)||Fe2+ (0·01 M)|Fe Given: Cr3+/Cr E° = -0.75 V; Fe2+/Fe E° = -0.45 V (log 10 = 1)
Write the Nernst equation and calculate the emf of the following cell at 298 K: Zn|Zn2+ (0·001 M)| |H+ (0·01 M)|H2 (g) (1 bar)|Pt (s) Given: Zn2+/Zn E° = -0·76 V, 2H+/H2 E° = 0·00 V [log 10 = 1]
Write the Nernst equation and calculate the emf of the following cell at 298 K: Zn|Zn2+ (0.1 M)| |Cd2+ (0.01)|Cd Given: E°Zn2+/Zn = -0.76 V, E°Cd2+/Cd = -0.40 V (log 10 = 1)
Write the Nernst equation and calculate the emf of the following cell at 298 K : Mg (s)Mg2+ (0·001 M) || Cu2+ (0·0001 M)Cu (s) Given : E°Mg2+/Mg = − 2·36 V, E°Cu2+/Cu = + 0·34 V [log 10 = 1]
From the given data of E values, answer the following questions: E°(M2+/M) V: Cr –1.18, Mn –0.91, Fe –1.18, Co –0.44, Ni –0.28, Cu –0.25, Cu +0.34. (I) Why E°(M2+/M) show irregular trend in the above values? (II) Why is E°(Cu2+/Cu) value exceptionally positive? (III) Why E°(Mn2+/Mn) value is highly negative?
Calculate emf and ΔG for the following cell at 298 K: Mg(s) / Mg2+(0.01 M) // Ag+(0.001 M) / Ag(s). Given: E°(Mg2+/Mg) = –2.37 V, E°(Ag+/Ag) = +0.80 V. [1 F = 96500 C mol–1, log 10 = 1]
Calculate emf and ΔG for the following cell at 298 K: Mg(s) / Mg²⁺(0.01 M) // Ag⁺(0.001 M) / Ag(s). Given: E°(Mg²⁺/Mg) = –2.37 V, E°(Ag⁺/Ag) = +0.80 V [Note: 1 F = 96500 C mol⁻¹, log 10 = 1]
The conductivity of 0.1 mol L–1 solution of NaCl is 1.06 × 10–2 S cm–1. Calculate its molar conductivity and degree of dissociation. (Given: λo(Na+) = 50.1 S cm2 mol–1, λo(Cl–) = 76.5 S cm2 mol–1). Following cell reaction occurs in a galvanic cell: 2Ag+(aq) + Zn(s) → 2Ag(s) + Zn2+(aq) E°(cell) = +1.56 V. Predict the direction of flow of current. Differentiate between a primary battery and a secondary battery.
(a) The conductivity of 0.1 mol L–1 solution of NaCl is 1.06 × 10–2 S cm–1. Calculate its molar conductivity and degree of dissociation. °Na+ = 50.1 S cm2 mol–1, °Cl– = 76.5 S cm2 mol–1 (b) (i) Following cell reaction occurs in a galvanic cell : 2Ag +(aq) + Zn(s) — 2Ag(s) + Zn2+(aq) E°(cell) = +1.56 V. Predict the direction of flow of current. (ii) Differentiate between a primary battery and a secondary battery.
(a) The conductivity of 0.1 mol L–1 solution of NaCl is 1.06 × 10–2 S cm–1. Calculate its molar conductivity and degree of dissociation. (Given: Λ°Na+ = 50.1 S cm2 mol–1, Λ°Cl– = 76.5 S cm2 mol–1) (b) (i) Following cell reaction occurs in a galvanic cell: 2Ag +(aq) + Zn(s) — 2Ag(s) + Zn2+(aq) E°(cell) = +1.56 V. Predict the direction of flow of current. (ii) Differentiate between a primary battery and a secondary battery.
Calculate the electrode potential of a half-cell for zinc electrode dipping in 0·01 M ZnSO4 solution at 25°C. Given: E°(Zn2+/Zn) = − 0·76 V [log 10 = 1]. Write anode, cathode and overall reaction involved in dry cell. Equilibrium constant (Kc) is related to E°cell, but not to Ecell. Why?
(a) (i) Calculate the electrode potential of a half-cell for zinc electrode dipping in 0·01 M ZnSO4 solution at 25°C. Given: E°(Zn2+/Zn) = − 0·76 V [log 10 = 1]
(a) Calculate the electrode potential of a half-cell for zinc electrode dipping in 0·01 M ZnSO4 solution at 25°C. Given: E°(Zn2+/Zn) = − 0·76 V [log 10 = 1] (ii) Write anode, cathode and overall reaction involved in dry cell. (iii) Equilibrium constant (Kc) is related to E°cell, but not to Ecell. Why ?
(a)(i) Calculate Eocell for the following reaction which is at equilibrium: Cu (s) + 2Ag+(aq) ⇌ Cu2+(aq) + 2Ag (s). Equilibrium constant (Kc) for the cell is 1015. [Given: log 10 = 1] (ii) Write anode, cathode and overall reaction of lead storage battery when it is in use. (iii) How much electricity is required in coulombs for the oxidation of 1 mol of FeO to Fe2O3?
(a)(i) Calculate E°cell for the following reaction which is at equilibrium: Cu (s) + 2Ag+ (aq) → Cu2+ (aq) + 2Ag (s). Equilibrium constant (Kc) for the cell is 1015. [Given: log 10 = 1] (ii) Write anode, cathode and overall reaction of lead storage battery when it is in use. (iii) How much electricity is required in coulombs for the oxidation of 1 mol of FeO to Fe2O3?
(a)(i) For a galvanic cell, the following half reactions are given. Decide, which will remain as reduction reaction and which will be reversed to become an oxidation reaction. Give reason for your answer. (I) Cr3+ + 3e– → Cr(s); E = – 0·74 V (II) Fe2+ + 2e– → Fe(s); E = – 0·44 V
For a galvanic cell, the following half reactions are given. Decide, which will remain as reduction reaction and which will be reversed to become an oxidation reaction. Give reason for your answer. (I) Cr3+ + 3e– → Cr(s); E = –0·74 V (II) Fe2+ + 2e– → Fe(s); E = –0·44 V. Represent the cell in which the following reaction takes place: Mg(s) + 2Ag+ (0·001 M) → Mg2+ (0·100 M) + 2Ag(s). Calculate Ecell if E°cell = 3·17 V. (log 10 = 1)
(a) (i) Calculate Ecell of a galvanic cell in which the following reaction takes place at 25°C: Zn(s) + Pb2+(0·02 M) → Zn2+(0·1 M) + Pb(s) [Given: E°Zn2+/Zn = – 0·76 V, E°Pb2+/Pb = – 0·13 V; log 2 = 0·3010, log 4 = 0·6021, log 5 = 0·6990]. (ii) State Faraday's first law of electrolysis. How much electricity, in terms of Faraday, is required to reduce one mol of MnO4– to Mn2+ ion ?
(a) (i) Calculate Ecell of a galvanic cell in which the following reaction takes place at 25C: Zn(s) + Pb2+(0·02 M) → Zn2+(0·1 M) + Pb(s) [Given: EZn/Zn2+ = – 0·76 V, EPb/Pb2+ = – 0·13 V; log 2 = 0·3010, log 4 = 0·6021, log 5 = 0·6990] OR (b) (i) The resistance of a conductivity cell containing 0·001 M KCl solution at 298 K is 1000 ohm. What is the cell constant if conductivity of 0·001 M KCl solution at 298 K is 0·125 × 10–3 S cm–1?
Calculate E°cell of a galvanic cell in which the following reaction takes place at 25C: Zn(s) + Pb²⁺(0·02 M) → Zn²⁺(0·1 M) + Pb(s) [Given: E°Zn²⁺/Zn = – 0·76 V, E°Pb²⁺/Pb = – 0·13 V; log 2 = 0·3010, log 4 = 0·6021, log 5 = 0·6990]
Calculate the emf of the following cell at 25°C: Zn(s)|Zn2+ (0.1 M) || H+ (0.01 M)|H2(g) (1 bar), Pt(s). (Given : E°(Zn2+/Zn) = – 0.76 V, E°(H+/H2) = 0.00 V, log 10 = 1). State Faraday's second law of electrolysis. How much electricity is required in terms of Faraday for the reduction of 1 mol of Cr2O72– to Cr3+ ?
Calculate the emf of the following cell at 25°C: Zn(s)|Zn2+ (0.1 M) || H+ (0.01 M)|H2(g) (1 bar), Pt(s) [Given: E°Zn2+/Zn = –0.76 V, E°H2+/H2 = 0.00 V, log 10 = 1]
(a) (i) Calculate the emf of the following cell at 25°C: Zn(s)|Zn2+ (0.1 M) || H+ (0.01 M)|H2(g) (1 bar), Pt(s) [Given: E°Zn2+/Zn = – 0.76 V, E°H+/2H2 = 0.00 V, log 10 = 1] (ii) State Faraday's second law of electrolysis. How much electricity is required in terms of Faraday for the reduction of 1 mol of Cr2O72– to Cr3+?
(a) (i) The resistance of 0.05 M CH3COOH solution is found to be 100 ohm. If the cell constant is 0.0354 cm^-1, calculate the molar conductivity of the acetic acid solution. (ii) How much charge in Faraday is required for the reduction of 1 mol of MnO4^- to Mn^2+?
(a) The resistance of 0.05 M CH₃COOH solution is found to be 100 ohm. If the cell constant is 0.0354 cm⁻¹, calculate the molar conductivity of the acetic acid solution. (b) State Faraday's law. How many Faradays are required for the reduction of 1 mol of MnO₄⁻ to Mn²⁺?
(a) (i) Calculate emf of the following cell at 25ºC : Zn (s) Zn²⁺ (0·001M) ∥ Cd²⁺ (0·1 M) Cd (s) Given : E°Zn²⁺/Zn = -0·76 V, E°Cd²⁺/Cd = -0·40 V [log 10 = 1]
Calculate emf of the following cell at 25ºC: Zn (s) | Zn2+ (0·001M) || Cd2+ (0·1 M) | Cd (s). Given: EoZn2+/Zn = -0·76 V, EoCd2+/Cd = -0·40 V [log 10 = 1] OR State Faraday's second law of electrolysis. How will the pH of aqueous NaCl solution be affected when it is electrolysed?
Calculate emf of the following cell at 25°C: Zn (s) | Zn²⁺ (0.001M) || Cd²⁺ (0.1 M) | Cd (s). Given: E°(Zn²⁺/Zn) = −0.76 V, E°(Cd²⁺/Cd) = −0.40 V [log 10 = 1]
(a) (i) Write an expression for the limiting molar conductivity of an acetic acid on the basis of Kohlrausch law. (ii) Calculate the maximum work and log Kc for the given reaction at 298 K: Ni (s) + 2Ag+ (aq) → Ni2+ (aq) + 2Ag (s). Given: Ni/Ni2+ E° = -0.25 V, Ag+/Ag E° = +0.80 V, 1 F = 96500 C mol-1
(a) (i) Write an expression for the molar conductivity of acetic acid at infinite dilution according to Kohlrausch law. (ii) Calculate the maximum work and log Kc for the given reaction at 298 K: Ni (s) + 2Ag⁺ (aq) → Ni²⁺ (aq) + 2Ag (s). Given: E°(Ni/Ni²⁺) = −0.25 V, E°(Ag/Ag⁺) = +0.80 V, 1 F = 96500 C mol⁻¹ OR (b) (i) Write Faraday's first law of electrolysis. How many Faradays of electric charge are required for the reduction of 1 mol Cu²⁺ to Cu? (ii) Calculate emf of the following cell at 298 K: Mg (s) | Mg²⁺ (0.1 M) || Cu²⁺ (0.1 M) | Cu (s). [E°cell = +2.71 V, 1 F = 96500 C mol⁻¹, log 10 = 1]
(a) (i) Write an expression for the limiting molar conductivity of acetic acid. (ii) Calculate the maximum work and log Kc for the given reaction at 298 K: Ni (s) + 2Ag+ (aq) → Ni2+ (aq) + 2Ag (s). Given: E°Ni/2Ni = −0.25 V, E°Ag/Ag = +0.80 V, 1 F = 96500 C mol−1. OR (b) (i) How many Faraday of electricity, in terms of Faraday, is required for the reduction of 1 mol Cu2+ to Cu? (ii) Calculate emf of the following cell at 298 K for Mg (s) | Mg2+ (0.1 M) || Cu2+ (0.1 M) | Cu (s). [E°cell = +2.71 V, 1 F = 96500 C mol−1, log 10 = 1]
Conductivity of 2×10–3 M methanoic acid is 8×10–5 S cm–1. Calculate its molar conductivity and degree of dissociation if λ°m for methanoic acid is 404 S cm2 mol–1.
Conductivity of 2 × 10–3 M methanoic acid is 8 × 10–5 S cm–1. Calculate its molar conductivity and degree of dissociation if λ°m for methanoic acid is 404 S cm2mol–1. Calculate the ΔrG and log Kc for the given reaction at 298 K: Ni (s) + 2Ag+(aq) → Ni2+(aq) + 2Ag(s). Given: E Ni2+/Ni = – 0.25 V, E°Ag+/Ag = +0.80 V, 1F = 96500 C mol –1.
(a) Conductivity of 2 × 10–3 M methanoic acid is 8 × 10–5 S cm–1. Calculate its molar conductivity and degree of dissociation if Λ⁰m for methanoic acid is 404 S cm2mol–1. (b) Calculate the ΔrG and log Kc for the given reaction at 298 K: Ni (s) + 2Ag+(aq) → Ni2+(aq) + 2Ag(s) Given: E°Ni2+/Ni = – 0.25 V, E°Ag+/Ag = +0.80 V; 1F = 96500 C mol–1.
(a) Calculate the emf of the following cell at 25°C: Zn(s) | Zn²⁺(0.1 M) || H⁺(0.01 M) | H2(g)(1 bar), Pt(s) [Given: E°(Zn²⁺/Zn) = -0.76 V, E°(2H⁺/H2) = 0.00 V, log 10 = 1]
(a) Calculate the emf of the following cell at 25°C: Zn (s) | Zn²⁺ (0.1 M) || H⁺ (0.01 M) | H2 (g) (1 bar), Pt (s). (Given: E°Zn/2Zn = −0.76 V, E°2H/H = 0.00 V, log 10 = 1) (b) State Kohlrausch law of independent migration of ions. Why does the conductivity of a solution decrease with dilution?
Calculate the emf of the following cell at 25°C: Zn (s) | Zn²⁺ (0.1 M) || H⁺ (0.01 M) | H₂ (g) (1 bar), Pt (s)
(a) (i) Calculate the emf of the following cell at 298 K: Al (s) | Al3+ (0.001 M) || Ni2+ (0.1 M) | Ni (s). [Given: E°(Al/3Al) = -1.66 V, E°(Ni/2Ni) = -0.25 V, log 10 = 1]
(a) (i) Calculate the emf of the following cell at 298 K: Al (s) | Al³⁺ (0.001 M) || Ni²⁺ (0.1 M) | Ni (s). [Given: E°(Al/³⁺Al) = -1.66 V, E°(Ni/²⁺Ni) = -0.25 V, log 10 = 1] (ii) With the help of a graph explain why it is not possible to determine Λ°m for a weak electrolyte by extrapolating the molar conductivity (Λm) versus C^(1/2) curve as for strong electrolyte.
Case study · CBSE 2026
Electrochemistry is the study of the relationship between chemical energy and electrical energy. Many spontaneously occurring chemical reactions liberate electrical energy. In electrolysis, electrical energy is converted directly into chemical energy. The product of an electrolytic reaction depends on the nature of the material being electrolysed and the type of electrode used. Oxidising and reducing species present in the electrolytic cell and their standard electrode potential too, affect the products of electrolysis. Electrolysis plays an important role in most people's daily lives, whether it is for the manufacturing of aluminium, electroplating of metals, or the synthesis of chemical compounds. Michael Faraday was the first scientist who proposed two laws to explain the quantitative aspects of electrolysis, popularly known as Faraday's laws of electrolysis. Faraday's laws of electrolysis provide a basis for mathematical analysis of the mass deposited at electrodes and the amount of charge passed through them. Faraday's laws are fundamental in various applications, including electroplating, metal extraction, battery technology and chemical synthesis. These laws also help in environmental monitoring and in various chemistry experiments.
(a) Predict the products of electrolysis in each of the following : (i) An aqueous solution of CuCl2 with platinum electrodes. (ii) A concentrated solution of H2SO4 with platinum electrodes.
Case study · CBSE 2024
Batteries and fuel cells are very useful forms of galvanic cell. Any battery or cell that we use as a source of electrical energy is basically a galvanic cell. However, for a battery to be of practical use it should be reasonably light, compact and its voltage should not vary appreciably during its use. There are mainly two types of batteries—primary batteries and secondary batteries. In the primary batteries, the reaction occurs only once and after use over a period of time the battery becomes dead and cannot be reused again, whereas the secondary batteries are rechargeable. Production of electricity by thermal plants is not a very efficient method and is a major source of pollution. To solve this problem, galvanic cells are designed in such a way that energy of combustion of fuels is directly converted into electrical energy, and these are known as fuel cells. One such fuel cell was used in the Apollo space programme.
(a) How do primary batteries differ from secondary batteries?
Case study · CBSE 2023
Rahul set-up an experiment to find resistance of aqueous KCl solution for different concentrations at 298 K using a conductivity cell connected to a Wheatstone bridge. He fed the Wheatstone bridge with a.c. power in the audio frequency range 550 to 5000 cycles per second. Once the resistance was calculated from null point he also calculated the conductivity K and molar conductivity λm and recorded his readings in tabular form.
(a) Why does conductivity decrease with dilution?
The rate of a reaction is doubled when the concentration of the reactant is doubled. The order of the reaction is :
Assertion (A) : Rate of reaction increases with an increase in temperature. Reason (R) : Number of effective collisions decreases with an increase in temperature.
Which of the following curve represents the first order reaction?
For a reaction: N2 + 3H2 → 2NH3, the rate of reaction with respect to NH3 is
Identify the correct statement:
The order for the given reaction is: A + 2B → Products, Rate = k[A]½[B]1
Assertion (A): The molecularity of the given reaction is 2. 2HI → H2 + I2. Reason (R): Two molecules of the reactants are involved in simultaneous collision between them.
For a reaction 3A → 2B, the rate of reaction +d[B]/dt is equal to:
Assertion (A): Order of reaction is applicable to elementary as well as complex reactions. Reason (R): Order of a reaction is an experimental quantity.
For the reaction 2A → 3B, the rate of reaction +d[B]/dt is equal to :
Assertion (A): Order of reaction is not applicable for elementary reaction but applicable for complex reaction. Reason (R): Order of reaction is an experimental quantity.
The half-life periods of decomposition of NH3 for different initial pressures are given below: p (torr) 704, 75, 34·5; t1/2 (min) 80, 80, 80. The order of the reaction is :
The rate of a first order reaction is 5·6 × 10–4 mol L–1 s–1, when the concentration of reactant is 0·2 mol L–1. The rate constant 'k' is:
Assertion (A): For complex reaction, order of reaction is given by the slowest step. Reason (R): Order of a reaction is an experimental quantity.
Assertion (A): For complex reaction, order of reaction is given by the fast step. Reason (R): Order of reaction is determined experimentally.
Assertion (A): For complex reaction, order of reaction is given by the slowest step. Reason (R): Order of reaction is not applicable for the complex reaction.
Half-life (t1/2) of a first order reaction is 1386 s. The value of rate constant is :
The rate of reaction X + Y → products, is given by the equation Rate = k[X] [Y]. If Y is taken in large excess, the order of the reaction would be
Assertion (A): In a first order reaction, if the concentration of the reactant is doubled, its half-life is also doubled. Reason (R): The half-life of a reaction does not depend upon the initial concentration of the reactant in a first order reaction.
The role of a catalyst is to change:
The unit of rate and rate constant are same for a :
Assertion (A) : Hydrolysis of an ester follows first order kinetics. Reason (R) : The concentration of water does not get altered much during the reaction.
The value of rate constant for a pseudo first order reaction:
Assertion (A): Order of the reaction can be zero or fractional. Reason (R): We cannot determine order from balanced chemical equation.
In the Arrhenius equation k = Ae^(–Ea/RT), 'A' represents:
Assertion (A): Molecularity of reaction is determined experimentally. Reason (R): Molecularity is applicable only for an elementary reaction and not for a complex reaction.
The activation energy (Ea) of a reaction can be determined from the slope of which of the following plots ?
Unit of rate constant 'k' for a second order reaction is :
Which of the following represents the fraction of molecules with energies equal to or greater than Ea ?
Which of the following is the slope of the first order reaction in the plot of ln[R] vs. time?
In the Arrhenius equation, when log k is plotted against 1/T, a straight line is obtained whose:
A reaction A2 + B2 → 2AB occurs by the following mechanism: A2 → A + A (slow); A + B2 → AB + B (fast); A + B → AB (fast). Its order would be:
A zero-order reaction is one whose rate is independent of:
The addition of catalyst during a chemical reaction alters which of the following quantities of the reaction?
For the elementary reaction P→Q, when the concentration of P is doubled, the rate of reaction becomes 8 times. The order of the reaction is:
Half-life period of a first order reaction is 1386 seconds. The rate constant (k) of the reaction is:
The rate of the reaction 2A + B2 → 2AB is given by Rate = k [A]^2 [B2]. The value of rate constant (k) can be increased by:
For a certain reaction R → products, a plot of log [R] vs. time gives a straight line with a slope of −1.25 s⁻¹. The order of the reaction is:
For a zero order reaction A → products, t₁/₂ is:
When a catalyst increases the rate of a chemical reaction, then the rate constant (k) :
Assertion (A): Order of reaction and molecularity are always same for complex reactions. Reason (R): Order is determined experimentally and molecularity is applicable only for elementary reactions.
When the initial concentration of a reactant is doubled in the reaction, the half life period remains same. The order of reaction is:
Assertion (A): Rate of reaction increases with increase in temperature. Reason (R): Number of effective collisions increase with increase in temperature.
The half-life of a first-order reaction with rate constant (k) of 3 min⁻¹ is:
Assertion (A): Rate of reaction decreases with increase in temperature. Reason (R): Number of effective collisions increases with increase in temperature.
Which of the following is affected by catalyst?
The order of the reaction H2 (g) + Cl2 (g) → 2HCl (g) is:
Assertion (A): The molecularity of the reaction H2 + Br2 → 2HBr appears to be 2. Reason (R): Two molecules of the reactants are involved in the given elementary reaction. Select the correct answer.
A first order reaction takes 30 minutes for 50% completion. The value of rate constant k would be:
Assertion (A): The molecularity of the reaction H₂ + Br₂ → 2HBr appears to be 2. Reason (R): Two molecules of the reactants are involved in the given elementary reaction.
The slope in the plot of ln[R] vs. time for a first order reaction is
For the reaction 3A → 2B, rate of reaction +d[B]/dt is equal to
The slope in the plot of [R] vs. time for a zero order reaction is
For a reaction 2A → 3B, rate of reaction – d[A]/dt is equal to
The slope in the plot of log R/R₀ vs. time for a first order reaction is
For the reaction 3A → 2B, rate of reaction – d[A]/dt is equal to
The unit of the rate of reaction is the same as that of the rate constant for a:
Assertion (A): Order and molecularity of a reaction are always same. Reason (R): Complex reactions involve a sequence of elementary reactions and the slowest step is rate determining.
The rate of reaction A + B → Products, is given by the equation r = k[A] [B]. If B is taken in large excess, the order of reaction would be:
The half-life of a reaction is doubled when the initial concentration is doubled. The order of the reaction is:
The half-life for a zero order reaction equals:
In a reaction, the initial concentration of the reactants increases four fold and the rate becomes sixteen times its initial value. The order of the reaction is:
For the reaction A + 2B → C + D, the rate law is given by r = k[A][B]², the concentration of A is kept constant while that of B is doubled. The rate of the reaction will:
If the initial concentration is reduced to 1/4th in a zero order reaction, then the time taken for half the reaction to complete:
For a zero order reaction of the type A → products, the rate equation may be expressed as:
The number of molecules that react with each other in an elementary reaction is a measure of the:
The following experimental rate data were obtained for a reaction carried out at 25 C: A (g) + B(g) → C(g) + D(g). What are the orders with respect to A(g) and B(g)?
Assertion (A): For a zero order reaction the unit of rate constant and rate of reaction are same. Reason (R): Rate of reaction for zero order reaction is independent of concentration of reactant.
Assertion (A): The half life of a reaction is the time in which the concentration of the reactant is reduced to one half of its initial concentration. Reason (R): In first order kinetics when concentration of reactant is doubled, its half life is doubled.
Assertion (A): Order of reaction is applicable to elementary as well as complex reactions. Reason (R): For a complex reaction molecularity has no meaning.
Write any two differences between the order of a reaction and molecularity of a reaction.
Following reaction takes place in one step: 2A + B → 2C. How will the rate of above reaction change if the volume of the reaction vessel is decreased to one third of its original volume? Will there be any change in the order of reaction with the reduced volume?
The concentration of the reactant is reduced from 0.6 mol L–1 to 0.2 mol L–1 in 5 minutes in a first order reaction. Calculate rate constant of the reaction. (log 3 = 0.48)
Define activation energy. Write the unit of rate constant for (i) zero order reaction, (ii) second order reaction.
(a) Define Collision frequency. (b) Write the units of (i) first order reaction and (ii) zero order reaction
(a) Define Effective collision. (b) Write the unit of (i) second order reaction and (ii) zero order reaction
For a reaction A + B → Products, the rate law is: Rate = k[A][B]^(3/2). Write the overall order of the reaction. Can this reaction be an elementary reaction? Give reason in support of your answer.
For a reaction A + B → Products, the rate law is: Rate = (3/2)k[A][B]^2. Write the overall order of the reaction. Can this reaction be an elementary reaction ? Give reason in support of your answer.
For a reaction A + B → Products, the rate law is: Rate = (3/2)k[A][B]. Write the overall order of the reaction. Can this reaction be an elementary reaction ? Give reason in support of your answer.
(a) Reactions of which order will show the rate to be independent of the concentration of the reactant? Give one example of this order. (b) State the condition under which a bimolecular reaction may be kinetically a first order reaction.
(a) A reaction is second order in 'A' and first order in 'B'. How is the rate affected when the concentrations of both 'A' and 'B' are doubled ? (b) Write the unit of 'k' for zero order reaction.
(a) The reaction between A2 (g) and B2 (g) was carried out in a sealed isothermal container. The rate law for the reaction was found to be: Rate = k[A2][B2]. If 1 mole of A2 (g) was added to the reaction chamber and the temperature was kept constant, then predict the change in rate of the reaction and the rate constant.
(a) Write the rate law expression for the reaction 2HI → H2 + I2, if the order of the reaction is zero.
Define rate constant and identify the reaction order which has a rate constant of 4·5 × 10–5 L mol–1 s–1.
Give any two differences between order and molecularity of a reaction.
State a condition under which a bimolecular reaction is kinetically first order reaction. Give an example. For which type of reactions, do order and molecularity have the same value ?
Why is molecularity applicable only for elementary reactions and order is applicable for elementary as well as complex reactions?
Define molecularity of the reaction. State any one condition in which a bimolecular reaction may be kinetically of first order.
Write two differences between order of reaction and molecularity of reaction.
A first order reaction has a rate constant 1.25×10−3 s−1. How long will 5 g of this reactant take to reduce to 2.5 g? [log 2 = 0·301, log 3 = 0·4771, log 4 = 0·6021]
(a) In a reaction, when the concentration of a reactant is tripled, the rate of the reaction becomes twenty-seven times. What is the order of the reaction ?
When the initial concentration of a reactant is tripled, the reaction rate becomes twenty-seven times. What is the order of the reaction? OR State a condition under which a bimolecular reaction is kinetically a first-order reaction. Give an example of such a reaction.
If the concentration of a reactant in a reaction becomes twenty-seven times, the rate of reaction becomes twenty-seven times. What is the order of the reaction?
The conversion of molecule A to B followed second order kinetics. If concentration of A increased to three times, how will it affect the rate of formation of B?
(a) The conversion of molecule A to B followed second order kinetics. If concentration of A increased to three times, how will it affect the rate of formation of B? (b) Define Pseudo first order reaction with an example.
A chemical reaction 2N2O5(g) → 4NO2(g) + O2(g) in gas phase was carried out in a closed vessel. The concentration of NO2 was found to increase by 5×10⁻³ mol L⁻¹ in 10 seconds. Calculate: (a) the rate of formation of NO2, and (b) the rate of consumption of N2O5.
The following data were obtained for the reaction: 2NO2 (g) + F2 (g) → 2NO2F (g). Experiment No. 1: [NO2]/M = 0.2, [F2]/M = 0.05, Initial rate M min⁻¹ = 6×10⁻³. Experiment No. 2: [NO2]/M = 0.4, [F2]/M = 0.05, Initial rate M min⁻¹ = 12×10⁻². Experiment No. 3: [NO2]/M = 0.8, [F2]/M = 0.10, Initial rate M min⁻¹ = 48×10⁻². Determine the overall order of reaction.
The half-life of a first order reaction is 60 minutes. How long will it take to consume 90% of the reactant?
The rate constant for the first order decomposition of N2O5 is given by the following equation: log k = 236 - (TK/1024). Calculate Ea for this reaction. [R = 8.314 J K^-1 mol^-1]
The rate constant for the first order decomposition of N₂O₅ is given by the following equation: log k = 23.6 - 1024/T(K). Calculate Ea for this reaction. [R = 8.314 J K⁻¹ mol⁻¹]
What happens to the rate constant k and activation energy Ea as the temperature of a chemical reaction is increased? Justify.
In a reaction 2N2O5 (g) → 4NO2 (g) + O2 (g), the concentration of N2O5 decreases from 0·5 mol L⁻¹ to 0·4 mol L⁻¹ in 10 minutes. Calculate the average rate of this reaction and rate of production of NO2 during this period.
A reaction is first order in X and second order in Y. (i) How is the rate affected on increasing the concentration of Y three times? (ii) How is the rate affected when the concentrations of both X and Y are doubled?
A first order reaction is 50% complete in 20 minutes. Calculate the time for 75% completion of the reaction. [log 4 = 0·6]
For the first order thermal decomposition reaction, following data was obtained: C2H5Cl(g) → C2H4(g) + HCl(g). S. No. Time(s) Total Pressure (atm) 1 0 0.30 2 30 0.50. Calculate rate constant. [Given: log 3 = 0.48]
The half-life period of a radioactive element is 1·5 × 10^10 years. Calculate the time in which the activity of the element is reduced to 75% of its original value. [Given: log 2 = 0·30, log 3 = 0·48, log 4 = 0·60]
Consider the decomposition of hydrogen peroxide (H2O2) as per the equation given below: 2H2O2 → 2H2O + O2 (I– catalyst). The mechanism for this reaction was found to be: Step I: H2O2 + I– → H2O + IO– (slow). Step II: H2O2 + IO– → H2O + I– + O2 (fast). (a) Write the rate law expression. (b) Determine the order of reaction with respect to H2O2, I– and overall order of reaction. (c) What is the molecularity of the reaction in Step II?
Consider the decomposition of hydrogen peroxide (H2O2) as per the equation given below: 2H2O2 —[I,Alkaline medium]→ 2H2O + O2. The mechanism for this reaction was found to be: Step I: H2O2 + I– → H2O + IO– (slow), Step II: H2O2 + IO– → H2O + I– + O2 (fast). (a) Write the rate law expression. (b) Determine the order of reaction with respect to H2O2, I– and overall order of reaction. (c) What is the molecularity of the reaction in Step II?
(a) Define order of a reaction. (b) The rate for the following reaction is given by : A + B → C, Rate = k[A][B]². (i) How is the rate of reaction affected if we double the concentration of B ? (ii) Write the overall order of a reaction if 'A' is present in large excess.
The rate of the chemical reaction doubles when the temperature is raised from 298 K to 308 K. Calculate activation energy (Ea) for this reaction assuming that it does not change with temperature. (Given : R = 8·314 J mol⁻¹ K⁻¹, log 2 = 0·30)
The rate of a particular reaction quadruples when the temperature increases from 293 K to 313 K. Calculate the energy of activation (Ea) of the reaction assuming that it does not change with temperature. (Given: log 4 = 0·60, R = 8·314 JK⁻¹ mol⁻¹)
The rate of a particular reaction quadruples when the temperature increases from 300 K to 320 K. Calculate the energy of activation (Ea) of the reaction assuming that it does not change with temperature. (Given: log 4 = 0·60, R = 8·314 JK⁻¹ mol⁻¹)
The rate constant of a first order reaction increases from 0.04 s–1 to 0.08 s–1 when the temperature increases from 27°C to 37°C. Calculate the energy of activation (Ea). [Given : 2.303R = 19.15 JK–1mol–1] [log 2 = 0.3010, log 3 = 0.4771, log 4 = 0.6021]
For the reaction A + B → Products, the following initial rates were obtained at various initial concentrations of reactants: Sl. No. 1: [A]=0.1 mol L–1, [B]=0.1 mol L–1, Initial rate=0.05 mol L–1 s–1; Sl. No. 2: [A]=0.2 mol L–1, [B]=0.1 mol L–1, Initial rate=0.10 mol L–1 s–1; Sl. No. 3: [A]=0.1 mol L–1, [B]=0.2 mol L–1, Initial rate=0.05 mol L–1 s–1. Determine the order of the reaction with respect to A and B and overall order of the reaction.
For the reaction A + B → Products, the following initial rates were obtained at various initial concentrations of reactants: Sl. No. 1: [A]/mol L–1 = 0·1, [B]/mol L–1 = 0·1, Initial rate/mol L–1 s–1 = 0·05; Sl. No. 2: [A]/mol L–1 = 0·2, [B]/mol L–1 = 0·1, Initial rate/mol L–1 s–1 = 0·10; Sl. No. 3: [A]/mol L–1 = 0·1, [B]/mol L–1 = 0·2, Initial rate/mol L–1 s–1 = 0·05. Determine the order of the reaction with respect to A and B and overall order of the reaction.
The rate of a reaction : A + B → product is given below as a function of different initial concentrations of A and B. Calculate the order of the reaction with respect to A and B. Determine the rate constant of the reaction.
The following data were obtained during the first order thermal decomposition of N2O5 (g) at constant volume: 2N2O5 (g) → 2N2O4 (g) + O2 (g). S.No. Time/s Total Pressure/atm: 1) 0 0.5, 2) 100 0.625. Calculate rate constant. (Given : log 2 = 0.3010, log 10 = 1)
The following data were obtained during the first order thermal decomposition of N2O5 (g) at constant volume: 2N2O5 (g) → 2N2O4 (g) + O2 (g). S.No. 1: Time 0 s, Total Pressure 0.5 atm; S.No. 2: Time 100 s, Total Pressure 0.625 atm. Calculate rate constant. [Given: log 2 = 0.3010, log 10 = 1]
The following initial rate data were obtained for the reaction: 2NO(g) + Br2(g) → 2NOBr(g). Expt. No. 1: [NO]=0.05, [Br2]=0.05, Rate=1.0×10-3. Expt. No. 2: [NO]=0.05, [Br2]=0.15, Rate=3.0×10-3. Expt. No. 3: [NO]=0.15, [Br2]=0.05, Rate=9.0×10-3. (a) What is the order with respect to NO and Br2 in the reaction? (b) Calculate the rate constant (k). (c) Determine the rate of reaction when concentration of NO and Br2 are 0.4 M and 0.2 M, respectively.
The following initial rate data were obtained for the reaction: 2NO(g) + Br2(g) → 2NOBr(g). Expt. No. | [NO]/mol L⁻¹ | [Br2]/mol L⁻¹ | Initial Rate (mol L⁻¹ s⁻¹) | 1 | 0.05 | 0.05 | 1.0×10⁻³ | 2 | 0.05 | 0.15 | 3.0×10⁻³ | 3 | 0.15 | 0.05 | 9.0×10⁻³ | (a) What is the order with respect to NO and Br2 in the reaction? (b) Calculate the rate constant (k). (c) Determine the rate of reaction when concentration of NO and Br2 are 0.4 M and 0.2 M, respectively.
The rate of a gaseous reaction triples when temperature is increased from 17ºC to 27ºC. Calculate the energy of activation for this reaction. [Given: 2.303 R = 19.15 JK−1 mol−1, log 3 = 0.48]
The rate of a gaseous reaction triples when temperature is increased from 17°C to 27°C. Calculate the energy of activation for this reaction. [Given: 2.303 R = 19.15 J K⁻¹ mol⁻¹, log 3 = 0.48]
A first-order reaction is 25% complete in 40 minutes. Calculate the value of rate constant. In what time will the reaction be 80% complete ? Given : log 2 = 0·30, log 3 = 0·48, log 4 = 0·60, log 5 = 0·69
A first order reaction is 50% complete in 30 minutes at 300 K and in 10 minutes at 320 K. Calculate activation energy (Ea) for the reaction. [R = 8.314 J K–1 mol–1] [Given: log 2 = 0.3010, log 3 = 0.4771, log 4 = 0.6021]
The rate of a reaction doubles when temperature changes from 27°C to 37°C. Calculate energy of activation for the reaction. (R = 8.314 J K⁻¹ mol⁻¹) (Given: log 2 = 0.3010, log 3 = 0.4771, log 4 = 0.6021)
The rate of a reaction doubles when temperature changes from 27°C to 37°C. Calculate energy of activation for the reaction. (R = 8.314 J K⁻¹ mol⁻¹)
The following data were obtained during the first order thermal decomposition of C2H5Cl at a constant volume: C2H5Cl (g) → C2H4 (g) + HCl (g). Experiment 1: Time = 0 s, Total pressure = 0.4 atm. Experiment 2: Time = 100 s, Total pressure = 0.6 atm. Calculate the rate constant. [Given: log 2 = 0.3010, log 3 = 0.4771, log 4 = 0.6021]
(a) For the reaction 2N2O5(g) → 4NO2(g) + O2(g) at 318 K calculate the rate of reaction if rate of disappearance of N2O5(g) is 1.4 × 10–3 m s–1.
(a) For the reaction 2N2O5(g) → 4NO2(g) + O2(g) at 318 K calculate the rate of reaction if rate of disappearance of N2O5(g) is 1.4 × 10–3 m s–1. (b) For a first order reaction derive the relationship t99% = 2t90%
In the given reaction N2 (g) + 3H2 (g) → 2NH3 (g), the rate of formation of NH3 is 3·6 × 10⁻⁴ mol L⁻¹ s⁻¹. Calculate: (i) rate of reaction, and (ii) rate of disappearance of H2 (g).
A first order reduction takes 30 minutes for 75% decomposition. Calculate t₁/₂. Given: [log 2 = 0·3, log 3 = 0·48, log 4 = 0·6, log 5 = 0·7]
A first order reaction takes 30 minutes for 75% decomposition. Calculate t₁/₂. Given: [log 2 = 0·3, log 3 = 0·48, log 4 = 0·6, log 5 = 0·7]
(a) (i) The initial concentration of N2O5 in the first order reaction: N2O5 (g) → 2NO2 (g) + 1/2 O2 (g) was 1.2 × 10–2 mol L–1. The concentration of N2O5 after 60 minutes was 0.2 × 10–2 mol L–1. Calculate the rate constant of the reaction at 318 K. [log 6 = 0.778]
(a) (i) The initial concentration of N2O5 in the first order reaction: N2O5 (g) → 2NO2 (g) + 1/2 O2 (g) was 1·2 × 10⁻² mol L⁻¹. The concentration of N2O5 after 60 minutes was 0·2 × 10⁻² mol L⁻¹. Calculate the rate constant of the reaction at 318 K. [log 6 = 0·778]. (ii) Account for the following: (I) We cannot determine the order of a reaction by taking into consideration the balanced chemical equation. (II) A bimolecular reaction may become kinetically of first order under a specified condition.
Case study · CBSE 2023
The rate of reaction is concerned with decrease in concentration of reactants or increase in the concentration of products per unit time. It can be expressed as instantaneous rate at a particular instant of time and average rate over a large interval of time. Mathematical representation of rate of reaction is given by rate law. Rate constant and order of a reaction can be determined from rate law or its integrated rate equation.
(i) What is average rate of reaction?
Case study · CBSE 2022
The rate law for a chemical reaction relates the reaction rate with the concentrations or partial pressures of the reactants. For a general reaction aA + bB → C with no intermediate steps in its reaction mechanism, meaning that it is an elementary reaction, the rate law is given by r = k[A]x[B]y, where [A] and [B] express the concentrations of A and B in moles per litre. Exponents x and y vary for each reaction and are determined experimentally. The value of k varies with conditions that affect reaction rate, such as temperature, pressure, surface area, etc. The sum of these exponents is known as overall reaction order. A zero order reaction has a constant rate that is independent of the concentration of the reactants. A first order reaction depends on the concentration of only one reactant. A reaction is said to be second order when the overall order is two. Once we have determined the order of the reaction, we can go back and plug in one set of our initial values and solve for k.
Calculate the overall order of a reaction which has the following rate expression: Rate = k[A]1/2[B]3/2
Which of the following is not a transition metal ?
Assertion (A) : Transition metals have high melting points. Reason (R) : Transition metals have incompletely filled d-orbitals.
Which of the following is most basic?
Assertion (A): Actinoids show irregularities in their electronic configurations. Reason (R): In actinoids 5f, 6d and 7s orbitals are of comparable energies.
Which of the following transition metals has lowest enthalpy of atomisation ?
Assertion (A) : Actinoids show irregularities in their electronic configurations. Reason (R) : Due to varying stabilities of f0, f7 and f14 occupancies of the 5f orbitals.
Electronic configuration of chromium is:
Assertion (A): Zinc, cadmium and mercury are not considered as transition elements. Reason (R): These elements have completely filled orbitals in their ground state as well as in their common oxidation states.
In aqueous solution, Cr2O7(2-) ion converts to which of the following in alkaline medium?
Assertion (A): Separation of Zr and Hf is difficult. Reason (R): Because Zr and Hf lie in the same group of the periodic table.
In aqueous acidified solution, CrO4^2- ion converts to which of the following ?
Assertion (A): Separation of Zr and Hf is difficult. Reason (R): Zr and Hf have almost identical atomic and ionic radii due to lanthanoid contraction.
Manganate ion is paramagnetic due to the presence of:
Assertion (A): Eo(Sc3+/Sc2+) has low value. Reason (R): Because of the stability of Sc3+ ion which has a noble gas configuration.
Which property of transition metals enables them to form alloys ?
Which of the following d-orbitals experience more repulsion in the crystal field splitting of octahedral complex?
Actinoids show larger number of oxidation states :
Assertion (A) : Highest oxidation state of Mn is +7 in first series of transition elements. Reason (R) : Transition metals exhibit variable oxidation states.
Which of the following transition metals does not show variable oxidation states ?
Assertion (A): Zinc is not regarded as a transition element. Reason (R): Zinc has completely filled 3d orbitals in its ground state as well as in its oxidised state.
Out of Fe3+, Sc3+, Cr3+ and Co3+ ions, the one which is colourless in aqueous solution is: [Atomic number: Fe = 26, Sc = 21, Cr = 24, Co = 27]
Out of the following statements, the incorrect statement is:
The product of the oxidation of I– with MnO4– in alkaline medium is:
Assertion (A): Cuprous salts are diamagnetic. Reason (R): Cuprous ion has completely filled 3d-orbitals.
Out of Ti3+, Cr3+, Mn2+ and Ni2+ ions, the one which has the highest magnetic moment is: [Atomic number: Ti = 22, Cr = 24, Mn = 25, Ni = 28]
Assertion (A): Cuprous salts are diamagnetic. Reason (R): In cuprous ion, 3d-orbitals are partially filled.
Out of Ti3+, Cr3+, Fe2+ and Ni2+ ions, the one which is the most stable ion in aqueous solution is: [Atomic number: Ti = 22, Cr = 24, Fe = 26, Ni = 28]
Out of the following statements, the correct statement is:
Which of the following properties of transition metals enables them to behave as catalysts?
In which of the following groups are both ions coloured in aqueous solution? I. Cu+ II. Ti4+ III. Co2+ IV. Fe2+ [Atomic number: Cu = 29, Ti = 22, Co = 27, Fe = 26]
Which of the following is the softest metal ?
Assertion (A) : Actinoids show wide range of oxidation states. Reason (R) : Actinoids are radioactive in nature.
Assertion (A): Actinoids show wide range of oxidation states. Reason (R): This is due to comparable energies of 5f, 6d and 7s orbitals.
Which of the following transition metals has the highest melting point?
Assertion (A): Actinoid contraction is greater from element to element than lanthanoid contraction. Reason (R): Actinoids show wide range of oxidation states.
Which of the following transition metal ion is not coloured ?
Assertion (A): Actinoids show irregularities in their electronic configurations. Reason (R): Actinoids are radioactive in nature.
Among the following outermost electronic configurations of transition metals, which one shows the highest oxidation state ?
Assertion (A): Actinoids show irregularities in their electronic configurations. Reason (R): This is due to varying stability of f0, f7 and f14 configurations.
With increase in atomic number, the melting point of transition metals:
Assertion (A): First ionisation enthalpy of Cr is lower than that of Zn. Reason (R): Zinc is a non-transition element.
Which one of the following first row transition elements is expected to have the highest third ionization enthalpy?
Assertion (A): Separation of Zr and Hf is difficult. Reason (R): Zr and Hf have similar radii due to lanthanoid contraction.
The most stable oxidation state of Iron is:
Assertion (A): Transition metals have high enthalpy of atomization. Reason (R): This is because transition metals have low melting points.
Assertion (A): Separation of Zr and Hf is difficult. Reason (R): Zr and Hf are radioactive.
When MnO2 is fused with KOH in air, it gives:
The correct order for the increasing oxidizing power in 3d series of transition elements is:
Transition elements form alloys easily because they have:
Which of the following elements of 3d series of transition elements has the lowest aHₒ?
The most common and stable oxidation state of a Lanthanoid is:
Lanthanoid contraction is due to increase in:
Which of the following characteristics of transition metals is associated with their catalytic activity?
Assertion (A): Copper is a non-transition element. Reason (R): Copper has completely filled d-orbitals in its ground state.
Which one among the following metals of 3d series has the lowest melting point ?
Assertion (A): Transition metals have high enthalpy of atomisation. Reason (R): Greater number of unpaired electrons in transition metals results in weak metallic bonding.
Which of the following transition metals shows + 1 and + 2 oxidation states?
Assertion (A): Transition metals show their highest oxidation state with oxygen. Reason (R): The ability of oxygen to form multiple bonds to metals.
Among the following outermost configurations of transition metals which one shows the highest oxidation state?
Assertion (A): Zinc is not regarded as a transition element. Reason (R): In zinc, 3d orbitals are completely filled in its ground state as well as in its oxidised state.
Which of the following transition metals does not show variable oxidation state?
Which of the following ions has the maximum number of unpaired d-electrons?
Assertion (A): Fe²⁺ acts as a reducing agent. Reason (R): Fe³⁺ state is stable due to 3d⁵ configuration.
The ions of metals of Group 12 (Zn, Cd and Hg) have completely filled d orbitals and so they:
Assertion (A): Zr and Hf have almost identical radii. Reason (R): Both Zr and Hf exhibit similar properties.
The interstitial compounds of transition metals are:
Assertion (A): Manganese shows the highest oxidation state of +7 in 3d series. Reason (R): Transition metals show variable oxidation states.
Which of the following Cu²⁺ halide is not known?
Which property of transition metals enables them to behave as catalysts?
In the two tetrahedral structures of dichromate ion
Which of the following ions has the electronic configuration 3d6?
First ionization enthalpy of Cr is lower than that of Zn. Why? Mention any one property of the transition elements which makes them good catalysts.
(a) Why is third ionization enthalpy of manganese very high ? (b) Why Zn, Cd and Hg are not regarded as transition elements ?
(a) Why second ionization enthalpies of chromium and copper are exceptionally higher than those of their neighbouring elements? (b) Why transition elements form interstitial compounds?
(a) What is lanthanoid contraction? Actinoid contraction is greater from element to element than lanthanoid contraction. Why?
(a) What is lanthanoid contraction? Actinoid contraction is greater from element to element than lanthanoid contraction. Why? OR (b) Why do transition metals have high enthalpy of atomization? Which element of 3d-series has lowest enthalpy of atomization?
Complete the following ionic equations: (a) 42MnO₄⁻ + 35SO₃²⁻ + 6H⁺ →
Complete and balance the following chemical equations: (a) ⁴₃MnO⁴⁻ + 4H⁺ → (b) ₂₇Cr₂O₇²⁻ + 14H⁺ + 6Fe²⁺ →
Complete and balance the following equations: (i) 2KMnO4 → K2MnO4... (ii) Na2Cr2O7 + 2KCl → ... Why is it difficult to separate lanthanoid elements in pure state?
(a) Complete and balance the following equations : (i) 4FeCr 2O4 + 8Na2CO3 + 7O2 –– (ii) 5Fe 2+ + MnO4– + 8H+ –– (b) Explain why actinoid contraction is greater from element to element than lanthanoid contraction.
(a) Complete and balance the following equations: (i) 2Na 2CrO4 + 2H+ –– (ii) 5S 2– + 2MnO4– + 16H+ –– (b) Why is chemistry of actinoids complicated as compared to lanthanoids?
Give explanation for each of the following observations: (a) With the same d-orbital configuration (d4), Mn3+ ion is an oxidising agent whereas Cr2+ ion is a reducing agent. (b) Actinoid contraction is greater from element to element than that among lanthanoids. (c) Transition metals form large number of interstitial compounds with H, B, C and N.
(a) On the basis of crystal field theory write the electronic configuration for d5 ion with a weak ligand for which 0 < P.
From the given E° values of the first row transition elements (Cr = −0·91, Mn = −1·18, Fe = −0·44, Co = −0·28, Ni = −0·25, Cu = +0·34, Zn = −0·76 V), answer the following questions: (i) Why is E°M/²M⁺ value highly negative as compared to other elements for Mn? (ii) What is the reason for the irregularity in the above E° values? (iii) Why is E°Cu/²Cu⁺ value exceptionally positive?
Account for the following: (i) Transition metals and their compounds show catalytic activities. (ii) Zn, Cd and Hg are non-transition elements. (iii) Zr and Hf are of almost identical atomic radii.
From the given E°(M/2M⁺) values of the first row transition elements (Cr: -0·91, Mn: -1·18, Fe: -0·44, Co: -0·28, Ni: -0·25, Cu: +0·34, Zn: -0·76 V), answer the following questions : (i) Why is Mn/2Mn⁺ E° value highly negative as compared to other elements ? (ii) What is the reason for the irregularity in the above E° values ? (iii) Why is Cu/2Cu⁺ E° value exceptionally positive ?
(i) Which ion amongst the following is colourless and why? Ti4+, Cr3+, V3+ (Atomic number of Ti = 22, Cr = 24, V = 23) (ii) Why is Mn2+ much more resistant than Fe2+ towards oxidation? (iii) Highest oxidation state of a metal is shown in its oxide or fluoride only. Justify the statement.
(a) (i) Silver atom has completely filled d-orbitals in its ground state, it is still considered to be a transition element. Justify the statement. (ii) Why are ΔMH°/M2+ values of Mn and Zn more negative than expected? (iii) Why do transition metals form alloys?
(a) (i) Silver atom has completely filled d-orbitals in its ground state, it is still considered to be a transition element. Justify the statement. (ii) Why are M^(M/E2) values of Mn and Zn more negative than expected? (iii) Why do transition metals form alloys?
(b) (i) Calculate the spin only magnetic moment of the complex [Fe(H2O)6]2+. (Atomic number of Fe = 26) (ii) Which out of the following two complexes is more stable and why? [CoF6]3-, [Co(C2O4)3]3- (iii) Write the IUPAC name of the given complex: [Pt(NH3)2Cl2]
(a) (i) Silver atom has completely filled d-orbitals in its ground state, it is still considered to be a transition element. Justify the statement. (ii) Why are M2+/M E° values of Mn and Zn more negative than expected? (iii) Why do transition metals form alloys?
Define transition elements. Mention any two characteristics of transition elements.
(a) (i) From the given data of E values, answer the following questions: (I) Why E(M²⁺/M) show irregular trend in the above values? (II) Why is E(Cu²⁺/Cu) value exceptionally positive? (III) Why E(Mn²⁺/Mn) value is highly negative? (ii) Write the ionic equations for the oxidising action of potassium permanganate for its reaction with I⁻ in both acidic and alkaline solutions.
(a) (i) From the given data of E values, answer the following questions : (I) Why E M2+/M show irregular trend in the above values ? (II) Why is E Cu2+/Cu value exceptionally positive ? (III) Why E Mn2+ / Mn value is highly negative ?
Describe giving reason which one of the following pairs has the property indicated: (I) Fe or Cu − higher melting point (II) Ti3+ or Sc3+ − coloured in aqueous solution (III) Cr or Zn − higher third ionisation enthalpy. Write the ionic equations for the oxidizing action of MnO4^− in acidic medium with: (I) Fe2+ ion (II) I^− ion
(a) (i) Describe giving reason which one of the following pairs has the property indicated: (I) Fe or Cu − higher melting point (II) Ti3+ or Sc3+ − coloured in aqueous solution (III) Cr or Zn − higher third ionisation enthalpy
(a) Describe giving reason which one of the following pairs has the property indicated: (I) Fe or Cu − higher melting point (II) Ti3+ or Sc3+ − coloured in aqueous solution (III) Cr or Zn − higher third ionisation enthalpy (ii) Write the ionic equations for the oxidizing action of MnO4− in acidic medium with: (I) Fe2+ ion (II) I− ion
(a)(i) Account for the following: (I) MnO is basic while Mn2O7 is acidic. (II) Iron has higher enthalpy of atomization than that of copper. (III) Mn3+ is a stronger oxidising agent than Cr3+. (ii) How do you prepare potassium dichromate from sodium chromate? Write balanced chemical equation for each step.
(a) (i) (I) Why do transition metals show variable oxidation states ? (II) Out of Mn²⁺ and Ti²⁺ which will be more paramagnetic and why ? [Atomic No. : Ti = 22, Mn = 25] (III) Which ion is the strongest oxidising agent in the options given below : Cr³⁺, V³⁺, Mn³⁺. Give reason. [Atomic No. : Cr = 24, V = 23, Mn = 25] (ii) Complete and balance the following equations: (I) 2MnO2 + 4KOH + O2 → (II) 5C2O4²⁻ + 2MnO4⁻ + 16H⁺ →
(a) (i) (I) Why do transition metals show variable oxidation states? (I) Out of Mn²⁺ and Ti²⁺ which will be more paramagnetic and why? [Atomic No.: Ti = 22, Mn = 25] (III) Which ion is the strongest oxidising agent in the options given below: Cr³⁺, V³⁺, Mn³⁺. Give reason. [Atomic No.: Cr = 24, V = 23, Mn = 25] (ii) Complete and balance the following equations: (I) 2MnO₂ + 4KOH + O₂ → ? (II) 5C₂O₄²⁻ + 2MnO₄⁻ + 16H⁺ → ?
(A) (a) Account for the following : (i) Transition metals and their compounds show catalytic activities. (ii) Mn3+ is a strong oxidising agent. (iii) Cu+ is not stable in aqueous solution. (b) Write the preparation of KMnO4 from Pyrolusite ore (MnO2).
(a)(i) When pyrolusite ore is fused with KOH, in presence of air, a dark green coloured product 'A' is obtained which changes to purple coloured compound 'B' in acidic medium. (I) Write the formulae of 'A' and 'B'. (II) Write the ionic equation for the reaction when compound 'B' reacts with Fe2+ in acidic medium.
When pyrolusite ore is fused with KOH, in presence of air, a dark green coloured product 'A' is obtained which changes to purple coloured compound 'B' in acidic medium. (I) Write the formulae of 'A' and 'B'. (II) Write the ionic equation for the reaction when compound 'B' reacts with Fe2+ in acidic medium. Give reasons: (I) Ce4+ in aqueous solution is a good oxidising agent. (II) The actinoid contraction is greater from element to element than lanthanoid contraction. (III) E°(Zn2+/Zn) value is more negative than expected, whereas E°(Cu2+/Cu) is positive.
When pyrolusite ore is fused with KOH, in presence of air, a dark green coloured product 'A' is obtained which changes to purple coloured compound 'B' in acidic medium. Write the formulae of 'A' and 'B'.
(a) (i) Account for the following: (I) Orange colour of Cr2O72– ion changes to yellow when treated with an alkali. (II) Zn, Cd and Hg are non-transition elements. (III) E° value for Mn3+/Mn2+ couple is highly positive (+1·57 V) as compared to Cr3+/Cr2+. (ii) What happens when: (I) Manganate ion undergoes disproportionation reaction in acidic medium ? (II) KMnO4 is heated ?
(a) (i) Account for the following: (I) Orange colour of Cr2O72– ion changes to yellow when treated with an alkali. (II) Zn, Cd and Hg are non-transition elements. (III) Eº value for Mn3+/Mn2+ couple is highly positive (+1·57 V) as compared to Cr3+/Cr2+.
Account for the following: (I) Orange colour of Cr2O7²⁻ ion changes to yellow when treated with an alkali. (II) Zn, Cd and Hg are non-transition elements. (III) E° value for Mn³⁺/Mn²⁺ couple is highly positive (+1·57 V) as compared to Cr³⁺/Cr²⁺.
Account for the following: (I) The E°(Mn2+/Mn) value for manganese is highly negative, whereas E°(Mn3+/Mn2+) is highly positive. (II) Actinoids show wide range of oxidation states. (III) Transition metals have high melting points. Complete the following ionic equations: (I) 5SO32– + 2MnO4– + 6H+ → (II) 2MnO4– + H2O + I– →
Account for the following: (I) The E°Mn2+/Mn value for manganese is highly negative, whereas E°Mn3+/Mn2+ is highly positive.
(a) (i) Account for the following: (I) The E°Mn2+/Mn value for manganese is highly negative, whereas E°Mn3+/Mn2+ is highly positive. (II) Actinoids show wide range of oxidation states. (III) Transition metals have high melting points. (ii) Complete the following ionic equations: (I) 5SO32– + 2MnO4– + 6H+ → (II) 2MnO4– + H2O + I– →
(a)(i) Account for the following: (1) The melting and boiling points of Zn, Cd and Hg are low. (2) Of the d4 species, Cr2+ is strongly reducing while Mn3+ is strongly oxidizing. (3) E° value of Cu2+/Cu is +0.34 V. (ii) Complete and balance the following chemical equations: (1) KMnO4 (heat) → (2) Cr2O7(2-) + 6I(-) + 14H+ →
(a) (i) Account for the following: (1) The melting and boiling points of Zn, Cd and Hg are low. (2) Of the d⁴ species, Cr2+ is strongly reducing while Mn3+ is strongly oxidizing. (3) E° value of Cu2+/Cu is +0.34 V.
Assign reason for each of the following: (i) Manganese exhibits the highest oxidation state of +7 among the 3d series of transition elements. (ii) Transition metals and their compounds are generally found to be good catalysts in chemical reactions. (iii) Cr2+ is reducing in nature while with the same d-orbital configuration (d4) Mn3+ is an oxidising agent. (iv) Zn has lowest enthalpy of atomization. (v) Cu+ is unstable in an aqueous solution.
(a) (i) In 3d series, which transition element has positive M2+/ME value and why? (ii) Name a member of lanthanide series which is well-known to show +4 oxidation state. (b) Give reason: (i) The highest oxidation state is exhibited in oxoanions of transition metals. (ii) HCl is not used to acidify KMnO4 solution.
Account for the following: (i) Eo value for Mn3+/Mn2+ couple is much more positive than that for Cr3+/Cr2+. (ii) Sc3+ is colourless whereas Ti3+ is coloured in an aqueous solution. (iii) Actinoids show wide range of oxidation states. (iv) Write the chemical equations for the preparation of KMnO4 from MnO2.
Account for the following: (i) E°o value for Mn3+/ Mn2+ couple is much more positive than that for Cr3+/ Cr2+. (ii) Sc3+ is colourless whereas Ti3+ is coloured in an aqueous solution. (iii) Actinoids show wide range of oxidation states. Write the chemical equations for the preparation of KMnO4 from MnO2.
(I) Account for the following: (i) E° value for Mn3+/Mn2+ couple is much more positive than that for Cr3+/Cr2+. (ii) Sc3+ is colourless whereas Ti3+ is coloured in an aqueous solution. (iii) Actinoids show wide range of oxidation states. (II) Write the chemical equations for the preparation of KMnO4 from MnO2. OR (I) Account for the following: (i) Transition metals form alloys. (ii) Ce4+ is a strong oxidising agent. (II) Write one similarity and one difference between chemistry of Lanthanoids and Actinoids. (III) Complete the following ionic equation: Cr2O72– + 2OH– → ___________
(a) (i) Account for the following: (1) Transition metals form complex compounds. (2) The Mn²⁺/Mn value for manganese is highly negative whereas Mn³⁺/Mn²⁺ is highly positive. (3) Cu⁺ ion is unstable in aqueous solution. (ii) Write the equations involved in the preparation of KMnO4 from Pyrolusite ore (MnO2).
(a) (i) Account for the following: (1) Transition metals form complex compounds. (2) The M²⁺/2M E value for manganese is highly negative whereas 2Mn³⁺/3Mn E is highly positive. (3) Cu⁺ ion is unstable in aqueous solution. (ii) Write the equations involved in the preparation of KMnO4 from Pyrolusite ore (MnO2).
Give reasons: (1) Transition metals form complex compounds. (2) The Mn²⁺/Mn³⁺E° value for manganese is highly negative whereas Mn³⁺/MnE° is highly positive. (3) Cu⁺ ion is unstable in aqueous solution.
(a) (i) Account for the following: (1) Zn2+ salts are colourless while Ni2+ salts are coloured. (2) Cr2+ is a strong reducing agent. (3) Transition metals and their compounds show catalytic activities.
(a) (i) Account for the following: (1) Zn²⁺ salts are colourless while Ni²⁺ salts are coloured. (2) Cr²⁺ is a strong reducing agent. (3) Transition metals and their compounds show catalytic activities. (ii) Write the ionic equations for the oxidizing action of MnO₄⁻ in acidic medium with (1) I⁻ ion, and (2) Fe²⁺ ion.
(a) (i) Account for the following: (1) Zn²⁺ salts are colourless while Ni²⁺ salts are coloured. (2) Cr²⁺ is a strong reducing agent. (3) Transition metals and their compounds show catalytic activities. (ii) Write the ionic equations for the oxidizing action of 4MnO₄⁻ in acidic medium with (1) I⁻ ion, and (2) Fe²⁺ ion.
(a) A transition element X has electronic configuration [Ar] 4s2 3d3. Predict its likely oxidation states. (b) Complete the reaction mentioning all the products formed: 2 KMnO4 + heat → (c) Account for the following: (i) In the 3d transition series, zinc has the lowest enthalpy of atomisation, (ii) Cu+ ion is unstable in aqueous solution, (iii) Actinoids show more number of oxidation states than lanthanoids.
(a) Write the number of unpaired electrons in Cr3+. (Atomic number of Cr = 24) (b) Complete the reaction mentioning all the products formed: Cr2O72– + 3H2S + 8H+ → (c) Account for the following: (i) Mn2+ is more stable than Fe2+ towards oxidation to +3 state. (ii) Copper has exceptionally positive EM2+/M value. (iii) Eu2+ with electronic configuration [Xe] 4f76s2 is a strong reducing agent.
Case study · CBSE 2024
Transition metals have incomplete d-subshell either in neutral atom or in their ions. The presence of partly filled d-orbitals in their atoms makes transition elements different from that of the non-transition elements. With partly filled d-orbitals, these elements exhibit certain characteristic properties such as display of a variety of oxidation states, formation of coloured ions and entering into complex formation with a variety of ligands. The transition metals and their compounds also exhibit catalytic properties and paramagnetic behaviour. The transition metals are very hard and have low volatility. An examination of the 2ºM /ME values shows the varying trends.
(a) On what basis can we say that Cu is a transition element but Zn is not? (Atomic number: Cu = 29, Zn = 30)
Case study · CBSE 2024
The involvement of (n−1)d electrons in the behaviour of transition elements impart certain distinct characteristics to these elements. Thus, in addition to variable oxidation states, they exhibit paramagnetic behaviour, catalytic properties and tendency for the formation of coloured ions. The transition metals react with a number of non-metals like oxygen, nitrogen and halogens. KMnO₄ and K₂Cr₂O₇ are common examples. The two series of inner transition elements, lanthanoids and actinoids, constitute the f-block of the periodic table. In the lanthanoids, there is regular decrease in atomic size with increase in atomic number due to the imperfect shielding effect of 4f-orbital electrons which causes contraction.
(a) Why do transition metals and their compounds act as good catalysts ?
The secondary valency of Co in [Co(en)3]2 (SO4)3 is :
The secondary valency of Co in the complex [Co(NH3)5(NO2)]2+ is
The secondary valency of Pt in [Pt(en)2Cl2]²⁺ is
The correct IUPAC name of the complex [Pt(NH3)2Cl2] is:
Which of the following is heteroleptic complex?
The oxidation number of Co in [Co(en)3]2(SO4)3 is:
According to Werner's theory, the primary valencies of the central metal atom:
The oxidation number of Co in [Co(NH3)5 (ONO)] SO4 is :
The oxidation number of Pt in [Pt(en)2Cl2]2+ is :
Which of the following d-orbitals experience more repulsion in the crystal field splitting of octahedral complex?
The chelating ligand used for the treatment of lead poisoning is:
Which of the following d-orbitals experience more repulsion in the crystal field splitting of tetrahedral complex ?
Number of possible stereoisomers for the complex [Co(en)2Cl2]Cl will be :
The coordination number of Co in [Co(en)2Cl2]+ is:
Which of the following ligands forms a chelate complex ?
According to Werner's theory of coordination compounds :
Which of the following complex ion is not optically active ?
Coordination number of Fe in [Fe(C2O4)3]3– is:
Which of the following complexes shows geometrical isomerism?
Which of the following complexes show linkage isomerism?
The primary and secondary valences of Co in [Co(en)3]Cl3 respectively are:
The number of moles of AgCl precipitated when excess AgNO3 solution is mixed with one mole of [Co(NH3)3Cl3] is :
The number of moles of AgCl precipitated when excess AgNO3 solution is mixed with one mole of [Co(NH3)4Cl2]Cl is :
The number of moles of AgCl precipitated when excess AgNO3 solution is mixed with one mole of [Co(NH3)6]Cl3 is:
Ligand EDTA4− is an example of a:
Which of the following ligand forms chelate complex?
The coordination number of Co in [Co(en)3]^3+ is:
Which one of the following complexes is non-ionisable?
The type of isomerism shown by the complex [CoCl₂(en)₂]⁺ is:
Which one of the following hybrid states is associated with low spin complex?
Which of the following is diamagnetic in nature ? [ Atomic number : Co = 27 ]
Which of the following ligands can show linkage isomerism in a coordination compound?
On adding AgNO3 solution to 1 mole of complex NiCl2 . 4NH3, two moles of AgCl are formed. The secondary valency of Ni in the complex will be:
On adding AgNO₃ solution to 1 mole of CoCl₃.4NH₃, one mole of AgCl is precipitated. The secondary valency of Co is:
The compounds [Co(SO4)(NH3)5]Br and [Co(Br)(NH3)5]SO4 represent:
Assertion (A): Low spin tetrahedral complexes are rarely observed. Reason (R): Crystal field splitting energy is less than pairing energy for tetrahedral complexes. Select the correct answer.
Assertion (A): EDTA is used to determine hardness of water. Reason (R): EDTA is a bidentate ligand.
Assertion (A): Low spin tetrahedral complexes are rarely observed. Reason (R): Crystal field splitting energy is less than pairing energy for tetrahedral complexes.
The oxidation state of Fe in [Fe(CO)5] is
The formula of the complex dichloridobis (ethane–1, 2-diamine) platinum (IV) nitrate is
What is the secondary valency of Cobalt in [Co(en2)Cl2]+?
Which of the following ligands is an ambidentate ligand?
The formula of the complex Iron (III) hexacyanidoferrate (II) is:
How many ions are produced in the solution from the complex [Ni(NH3)6]Cl2?
Which of the following species is not expected to be a ligand?
Which of the following is the most stable complex species?
Optical isomerism is not shown by the complex:
Which of the following is a polydentate ligand?
Which of the following coordination compounds exhibits linkage isomerism?
[Co(NH3)5NO3]SO4 and [Co(NH3)5SO4]NO3 exhibit:
In which of the following does the central atom exhibit an oxidation state of +3?
What type of isomerism is shown by the following pair of complex compounds? [Co(NH3)6][Cr(CN)6] and [Cr(NH3)6][Co(CN)6]
In which of the following does the central atom exhibit an oxidation state of +4?
The compounds [Cr(H₂O)₆]Cl₃, [Cr(H₂O)₅Cl]Cl₂ . H₂O and [Cr(H₂O)₄Cl₂]Cl . 2H₂O exhibit:
The magnetic moment of [NiCl4]2–
Assertion (A): Trans [CrCl2(ox)2]3– shows optical isomerism. Reason (R): Optical isomerism is common in octahedral complexes involving didentate ligands.
Assertion (A): EDTA is a hexadentate ligand. Reason (R): EDTA has 2 nitrogen and 4 oxygen donor atoms.
Assertion (A): [Co(NH3)5 SO4] Cl gives a white precipitate with silver nitrate solution. Reason (R): The complex dissociates to give Cl– and SO42– ions.
Define the following terms : (a) Ambidentate ligand (b) Crystal field splitting energy
Write IUPAC names of the following coordination compounds: (i) [Ag(NH3)2][Ag(CN)2] (ii) K3[Fe(C2O4)3]
Define coordination number. Indicate the type of isomerism exhibited by the following complex: [Co(en)3]Cl3
(a) Define didendate ligand. Give an example. (b) Indicate the type of isomerism exhibited by the given complex : [Pt(NH 3)(H2O)Cl2]
(a) Define coordination number. (b) Indicate the type of isomerism exhibited by the following complex: [Co(en)3]Cl3
Write IUPAC names of the following compounds: (i) [PtCl2(en)2]SO4 (ii) (NH4)2[CoF4]
Write IUPAC names of the following compounds: (a) [Cr(NH3)4(ONO)Cl]NO3 (b) Na[Ag(CN)2]
Write the formulas for the following coordination compounds: (a) Mercury(I) tetrathiocyanato-S-cobaltate(III) (b) Dichloridobis (ethane-1,2-diamine) platinum(IV) nitrate
Write IUPAC names of the following compounds: (a) [Ag(NH3)2] [Ag(CN)2] (b) [Co(en)3]2 (SO4)3
PtCl4 . 2KCl doesn't give precipitate of AgCl with AgNO3 solution. Write the structural formula and IUPAC name of the complex.
PdCl2 . 2KCl does not give precipitate of AgCl with AgNO3 solution. Write the structural formula and IUPAC name of the complex.
(a) Write IUPAC names of the following coordination compounds: (i) [CoCl2(en)2]SO4 (ii) K3[Fe(C2O4)3]
(a) Write IUPAC names of the following coordination compounds: (i) [CoCl2(en)2]SO4 (ii) K3[Fe(C2O4)3] OR (b) Differentiate between: (i) Double salt and Complex compound (ii) Didentate ligand and Ambidentate ligand
Write the IUPAC name of the complex [Pt(en)2Cl2]2+. Draw the structure of geometrical isomer of this complex which is optically inactive.
(a) Write the IUPAC name of the complex [Pt(en)2Cl2]2+. Draw the structure of geometrical isomer of this complex which is optically inactive. OR (b) (i) Write the formula of the following coordination compound: Pentaamminecarbonatocobalt(III)chloride (ii) Write the IUPAC name of the linkage isomer of the complex [Co(NH3)5(NO2)]Cl2.
Write the IUPAC names of the following: (i) [Co(NH3)5(ONO)]2+ (ii) K2[NiCl4]
(a) Write the IUPAC names of the following: (i) [Co(NH3)5(ONO)]2+ (ii) K2[NiCl4] OR (b) (i) What is a chelate complex? Give one example. (ii) What are heteroleptic complexes? Give one example.
Write IUPAC names of the following coordination entities: (a) [Co(NH3)4Cl(NO2)]Cl (b) [PtCl2(en)2]2+
Write IUPAC names of the following coordination entities: (a) [Cr(NH3)3(H2O)3]Cl3 (b) K3[Al(C2O4)3]
Write IUPAC names of the following: (a) [Co(en)₂(H₂O)(CN)]²⁺ (b) [Ni(NH₃)₆]Cl₂
(a) Which of the following species cannot act as a ligand? Give reason. OH–, NH4, CH3NH2, H2O
(a) Which of the following species cannot act as a ligand? Give reason. OH–, 4NH, CH3NH2, H2O (b) The complex [Co(NH3)5(NO2)]Cl2 is red in colour. Give IUPAC name of its linkage isomer.
Give reasons : (i) Why are low spin tetrahedral complexes not formed ? (ii) Why is [Co(en)3]3+ complex more stable than [Co(NH3)6]3+ ? (iii) Why are geometrical isomers not possible for tetrahedral complexes having two different types of unidentate ligands coordinated to the central metal ion ?
[Co(NH3)6]3+ is diamagnetic whereas [CoF6]3– is paramagnetic. Justify the statement. [Atomic number of Co = 27]. Write the electronic configuration for d4 ion if Δo > P on the basis of crystal field theory.
(a) [Fe(H2O)6]2+ is paramagnetic whereas [Fe(CO)5] is diamagnetic. Justify the statement. [Atomic number of Fe = 26] (b) On the basis of crystal field theory write the electronic configuration for d4 ion if 0 < P.
(a) Explain why [Fe(H2O)6]3+ is strongly paramagnetic whereas [Fe(CN)6]3– is weakly paramagnetic. [Atomic number of Fe = 26] (b) On the basis of crystal field theory, write the electronic configuration for d5 ion for which 0 < P.
Answer the following questions about the complexes [NiCl4]^2− and [Ni(CN)4]^2−: (i) Write the hybridization involved in each case. (ii) Which of them is the inner orbital complex and which one is the outer orbital complex? (iii) Compare their magnetic behaviour. [Atomic number: Ni = 28]
(a) When a coordination compound CoCl3·6NH3 is mixed with excess of AgNO3 solution, 3 moles of AgCl are precipitated per mole of the compound. Write the structural formula of the complex, IUPAC name, its hybridisation and magnetic behaviour on the basis of valence bond theory.
(a) When a coordination compound CoCl3 . 6NH3 is mixed with excess of AgNO3 solution, 3 moles of AgCl are precipitated per mole of the compound. Write the structural formula of the complex, IUPAC name, its hybridisation and magnetic behaviour on the basis of valence bond theory. OR (b) (i) How many geometrical isomers are possible in each of the following complexes? (I) [Cr(C2O4)3]3– (II) [Co(NH3)3Cl3] (ii) [Co(NH3)6]3+ is an inner orbital complex whereas [Ni(NH3)6]2+ is an outer orbital complex. Why? [Atomic number: Co = 27, Ni = 28] (iii) Write the formula of Wilkinson catalyst and its use.
(a) Write the IUPAC name of the following complex : K3[Cr(C2O4)3]. (b) Differentiate between homoleptic complex and heterolyptic complex. (c) Which type of isomerism is exhibited by the following complex : [Pt(NH3)2Cl2]
(a) A coordination compound CrCl3 . 6H2O is mixed with excess of AgNO3 solution, two moles of AgCl are precipitated per mole of the compound. Write the structural formula of the coordination compound. (b) Write the oxidation state and hybridisation of the central metal in the following complex : [Fe(H2O)6]³⁺ [Atomic number of Fe = 26]. (c) Why is [Ni(H2O)6]²⁺ coloured ? [Atomic number of Ni = 28]
(a) Write the IUPAC name of the given complex: [Co(NH3)4(H2O)Cl] Cl2 (b) Define polydentate ligand. Give an example. (c) Mention the type of isomerism exhibited by the given complex: [Co(en)3]Cl3
(a) A coordination compound CrCl3 . 6H2O is mixed with excess of AgNO3 solution, one mole of AgCl is precipitated per mole of the compound. Write the structural formula of the coordination compound. (b) Write the oxidation state and hybridisation of the central metal in the given complex: [Fe(CN)6]³⁻. [Atomic number: Fe = 26] (c) Why is [Ti(H2O)6]³⁺ coloured? [Atomic number: Ti = 22]
(a) Write the IUPAC name of the given complex: K₂[Zn(OH)₄] (b) Differentiate between a double salt and a complex. (c) Mention the type of isomerism exhibited by the following complex: [Pt(NH₃) (H₂O) Cl₂]
(a) A coordination compound CrCl₃ · 6H₂O is mixed with excess of AgNO₃ solution, three moles of AgCl are precipitated per mole of the compound. Write the structural formula of the coordination compound. (b) Write the oxidation state and hybridisation of the central metal in the given complex: [Cr(NH₃)₆]³⁺. [Atomic number: Cr = 24] (c) Why is [Sc(H₂O)₆]³⁺ colourless?
(a) When a co-ordination compound CoCl3·6NH3 is mixed with excess of AgNO3 solution, 3 moles of AgCl are precipitated per mole of the compound. Write (i) Structural formula of the complex (ii) IUPAC name of the complex (iii) Hybridization of the complex using valence bond theory [Atomic number: Co = 27] OR (b) (i) Write IUPAC name of [Pt(NH3)2Cl(ONO)]. (ii) Why [Co(en)3]3+ is more stable complex than [Co(NH3)6]3+ ? (iii) Predict the hybridization of [Ni(CO)4] on the basis of valence bond theory. [Atomic number : Ni = 28]
(a) What is meant by crystal field splitting energy? For a d4 ion, write the configuration if (i) Δo < P, and (ii) Δo > P. (b) Explain why in tetrahedral coordination entities, low spin configurations are rarely observed.
Based on Valence Bond Theory, explain the geometry and magnetic character of [NiCl4]2–. [Atomic number: Ni = 28] Draw the possible isomers of [Co(en)2Cl2]+.
Write the name and structure of a hexadentate ligand.
(a) Answer the following about the complexes [FeF6]3– and [Fe(CN)6]4– : (i) Write the hybridization involved in each case. (ii) Which of them is the outer orbital complex and which one is the inner orbital complex ? (iii) Compare their magnetic behaviour. [Atomic number : Fe = 26]
(a) Answer the following about the complexes [FeF6]3– and [Fe(CN)6]4–: (i) Write the hybridization involved in each case. (ii) Which of them is the outer orbital complex and which one is the inner orbital complex? (iii) Compare their magnetic behaviour. [Atomic number: Fe = 26] OR (b) (i) What happens to the colour of complex [Ti(H2O)6]3+ when heated gradually? (ii) Write the electronic configuration for d5 ion if o ≪ P. (iii) Write the hybridization and magnetic behaviour of the complex [Ni(CO)4]. [Atomic number: Ni = 28]
(a) Write the formula for the following coordination compound: Potassium tetrahydroxidozincate (II) (b) Arrange the following complexes in the increasing order of conductivity of their solution: [Cr(NH3)5Cl]Cl2, [Cr(NH3)3Cl3], [Cr(NH3)6]Cl3 (c) Identify the type of isomerism exhibited by the following complexes: (i) [Co(NH3)5NO2]2+ (ii) [Co(en)3]Cl3
Draw the geometrical isomers of [Co(en)2Cl2]2+. Which geometrical isomer of [Co(en)2Cl2]2+ is not optically active and why?
Draw the geometrical isomers of [Co(en)2Cl2]2+. Which geometrical isomer of [Co(en)2Cl2]2+ is not optically active and why ? Write the hybridisation and magnetic behaviour of [CoF6]3–. [Given : Atomic number of Co = 27]
(a) Draw the geometrical isomers of [Co(en)2Cl2]2+. Which geometrical isomer of [Co(en)2Cl2]2+ is not optically active and why? (b) Write the hybridisation and magnetic behaviour of [CoF6]3–. [Given: Atomic number of Co = 27]
Answer any three of the following questions: (a) Explain the type of hybridization in [Fe(CN)6]3- on the basis of valence bond theory. (Given: Atomic number of Fe = 26) (b) Draw the geometrical isomers of [PtCl2(en)2]2+ ion. (c) [NiCl4]2- is paramagnetic while [Ni(CO)4] is diamagnetic though both are tetrahedral. Why? (d) Name the type of isomerism when ambidentate ligands are attached to central metal ion. Give one example of ambidentate ligand.
(a) On the basis of crystal field theory write the electronic configuration for d5 ion with a strong field ligand for which ΔO > P.
(b) Explain [Fe(CN)6]3– is an inner orbital complex whereas [FeF6]3– is an outer orbital complex.
(a) On the basis of crystal field theory, write the electronic configuration for d4 with a strong field ligand for which Δ0 > P. (b) A solution of [Ni(H2O)6]2+ is green but a solution of [Ni(CO)4] is colourless. Explain.
Write the hybridisation and magnetic character of the following complexes: (i) [NiCl4]²⁻ (ii) [Co(NH3)6]³⁺ (iii) [FeF6]³⁻ [Atomic number: Ni = 28, Co = 27, Fe = 26]
(i) Write the electronic configuration of d5 on the basis of crystal field splitting theory if Δo < P. (ii) [Fe(CN)6]3 is weakly paramagnetic whereas [Fe(CN)6]4 is diamagnetic. Give reason to support this statement. [Atomic no.: Fe = 26] (iii) Write the number of ions produced from the complex [Co(NH3)6]Cl2 in solution.
(a) (i) Write the electronic configuration of d4 on the basis of crystal field splitting theory, if Δo < P. (ii) [Ni(CN)4]2 with square-planar structure is diamagnetic and [NiCl4]2 with tetrahedral geometry is paramagnetic. Give reason to support the statement. [Atomic number: Ni = 28] (iii) Write the number of ions produced in the solution from the following complex: [PtCl2(NH3)4]Cl2
(a) (i) Write the electronic configuration of d4 on the basis of crystal field splitting theory if Δo > P. (ii) [Co(NH3)6]3+ is an inner orbital complex whereas [Ni(NH3)6]2+ is an outer orbital complex. (Atomic number: Co = 27, Ni = 28) (iii) Write the number of ions produced from the complex [Pt(NH3)6]Cl4 in solution.
(a) (i) Give reasons: (I) [Ni(CO)4] is diamagnetic whereas [NiCl4]2– is paramagnetic. [Atomic number: Ni = 28]
(a)(i)(I) Give reasons: [Ni(CO)4] is diamagnetic whereas [NiCl4]2– is paramagnetic. [Atomic number: Ni = 28]
(a) (i) Give reasons: (I) [Ni(CO)4] is diamagnetic whereas [NiCl4]²⁻ is paramagnetic. [Atomic number: Ni = 28] (II) CO is a stronger complexing agent than NH3. (III) The trans isomer of complex [Co(en)2Cl2]⁺ is optically inactive. (ii) Using Crystal Field theory, write the number of unpaired electrons in octahedral complexes of Fe³⁺ in the presence of: (I) Strong field ligand. (II) Weak field ligand. [Atomic number: Fe = 26]
(a) How is the crystal field splitting energy for octahedral complex (Δo) related to that of tetrahedral complex (Δt)?
Answer any five of the following: (a) How is the crystal field splitting energy for octahedral complex (Δo) related to that of tetrahedral complex (Δt)? (b) Write the IUPAC name of the following complex: [PtCl2(en)2] (NO3)2 (c) Write the geometry and magnetic behaviour of the complex [Ni(CO)4] on the basis of Valency Bond Theory (VBT). (d) What type of isomerism is shown by the complex [Co(NH3)6] [Cr(CN)6]? (e) For the coordination compound on the basis of crystal field theory, write the electronic configuration for d^4 ion if Δo < P. Is the coordination compound a high spin or low spin complex? (f) Out of [Co(NH3)6]^3+ and [Co(NH3)4Cl2]^+, which complex is heteroleptic and why? (g) Draw the structures of optical isomers of [PtCl2(en)2]^2+.
(a) Write the IUPAC name of the complex : [Co(H₂O)(CN)(en)₂]²⁺
Case study · CBSE 2026
The Valence Bond Theory (VBT) explains the formation, magnetic behaviour and geometry of coordination compounds. The Crystal Field Theory (CFT) of coordination compounds is based on the effect of different crystal fields (provided by the ligands taken as point charges), on the degeneracy of d-orbital energies of the central metal atom/ion. The splitting of the d-orbitals provides different electronic arrangements in strong and weak crystal fields.
In octahedral crystal field, energies of which d-orbitals will be raised when ligands approach the central metal atom/ion? Give reason in support of your answer.
(a) In octahedral crystal field, energies of which d-orbitals will be raised when ligands approach the central metal atom/ion? Give reason in support of your answer. (2 marks)
Case study · CBSE 2025
Werner proposed the concept of a primary valence and a secondary valence for a metal ion. The primary valences are normally ionisable and are satisfied by negative ions. The secondary valences are non-ionisable. These are satisfied by neutral molecules or negative ions. The secondary valency is equal to the co-ordination number and is normally fixed for a metal. The Valence Bond Theory (VBT) explains the formation, magnetic behaviour and geometrical shapes of co-ordination compounds whereas the Crystal Field Theory (CFT) is based on the effect of different crystal fields on the degeneracy of d-orbitals energies of the central metal atom / ion.
(a) [Cr(NH3)6]3+ is paramagnetic while [Ni(CN)4]2– is diamagnetic. Explain why ? [Atomic number : Cr = 24, Ni = 28]
Case study · CBSE 2025
Werner's coordination theory in 1893 was the first attempt to explain the bonding in coordination complexes. It must be remembered that this theory was put forward before the electron had been discovered by J.J. Thomson in 1897, and before the electronic theory of valency. Werner did not have any of the modern instrumental techniques and all his studies were made using simple experimental techniques. Werner was able to explain the nature of bonding in complexes and he concluded that in complexes, the metal shows two different sorts of valency: primary and secondary. Primary valences are normally ionisable whereas secondary valences are non ionisable.
(a) One mole of CrCl3·4H2O precipitates one mole of AgCl when treated with excess of AgNO3 solution. Write (i) the structural formula of the complex, and (ii) the secondary valency of Cr.
Case study · CBSE 2025
The Crystal Field Theory (CFT) of coordination compounds is based on the effect of different crystal fields (provided by the ligands taken as point charges) on the degeneracy of d-orbital energies of the central metal atom/ion. The splitting of the d-orbitals provides different electronic arrangements in strong and weak crystal fields. In tetrahedral coordination entity formation, the d-orbital splitting is smaller as compared to the octahedral entity.
On the basis of CFT, explain why [Ti(H2O)6]Cl3 complex is coloured ? What happens on heating the complex [Ti(H2O)6]Cl3 ? Give reason. [Atomic no. : Ti = 22]
Case study · CBSE 2024
The Valence Bond Theory (VBT) explains the formation, magnetic behaviour and geometrical shapes of coordination compounds whereas for coordination compounds is based on the effect of different crystal fields (provided by ligands taken as point charges), on the degeneracy of d-orbital energies of the central metal atom/ion. The splitting of the d-orbitals provides different electronic arrangements in strong and weak crystal fields. The crystal field theory attributes the colour of the coordination compounds to d-d transition of the electron. Coordination compounds find extensive applications in metallurgical processes, analytical and medicinal chemistry.
(a) What is crystal field splitting energy?
Case study · CBSE 2024
The Valence Bond Theory (VBT) explains the formation, magnetic behaviour and geometrical shapes of coordination compounds whereas Crystal Field Theory for coordination compounds is based on the effect of different crystal fields (provided by ligands taken as point charges), on the degeneracy of d-orbital energies of the central metal atom/ion. The splitting of the d-orbitals provides different electronic arrangements in strong and weak crystal fields. The crystal field theory attributes the colour of the coordination compounds to d-d transition of the electron. Coordination compounds find extensive applications in metallurgical processes, analytical and medicinal chemistry.
(a) What is crystal field splitting energy?
Case study · CBSE 2024
The Valence Bond Theory (VBT) explains the formation, magnetic behaviour and geometrical shapes of coordination compounds whereas the crystal field theory for coordination compounds is based on the effect of different crystal fields (provided by ligands taken as point charges), on the degeneracy of d-orbital energies of the central metal atom/ion. The splitting of the d-orbitals provides different electronic arrangements in strong and weak crystal fields. The crystal field theory attributes the colour of the coordination compounds to d-d transition of the electron. Coordination compounds find extensive applications in metallurgical processes, analytical and medicinal chemistry.
What is crystal field splitting energy?
Case study · CBSE 2023
In coordination compounds, metals show two types of linkages, primary and secondary. Primary valencies are ionisable and are satisfied by negatively charged ions. Secondary valencies are non-ionisable and are satisfied by neutral or negative ions having lone pair of electrons. Primary valencies are non-directional while secondary valencies decide the shape of the complexes.
(i) If PtCl2 . 2NH3 does not react with AgNO3, what will be its formula?
Case study · CBSE 2023
Coordination compounds are widely present in the minerals, plant and animal worlds and are known to play many important functions in the area of analytical chemistry, metallurgy, biological systems and medicine. Alfred Werner postulated the use of two types of linkages (primary and secondary), by a metal atom/ion in a coordination compound. He predicted the geometrical shapes of a large number of coordination entities using the property of isomerism. The Valence Bond Theory (VBT) explains the formation, magnetic behaviour and geometrical shapes of coordination compounds. It, however, fails to describe the optical properties of these compounds. The Crystal Field Theory (CFT) explains the effect of different crystal fields (provided by the ligands taken as point charges) on the degeneracy of d-orbital energies of the central metal atom/ion.
When a coordination compound NiCl2·6H2O is mixed with AgNO3 solution, 2 moles of AgCl are precipitated per mole of the compound. Write the structural formula of the complex and secondary valency for Nickel ion.
Case study · CBSE 2023
Coordination compounds are widely present in the minerals, plant and animal worlds and are known to play many important functions in the area of analytical chemistry, metallurgy, biological systems and medicine. According to Alfred Werner's theory, coordination compounds consist of a central metal atom/ion surrounded by a fixed number of ligands (primary and secondary valencies). By using the property of isomerism, he predicted the geometrical shapes of a large number of coordination entities. The Valence Bond Theory (VBT) explains the formation, magnetic behaviour and geometrical shapes of coordination compounds. However, it fails to describe the optical properties of these compounds. The Crystal Field Theory (CFT) explains the effect of different crystal fields (provided by the ligands taken as point charges) on the degeneracy of d-orbital energies of the central metal atom/ion.
When a coordination compound NiCl2·6H2O is mixed with AgNO3 solution, 2 moles of AgCl are precipitated per mole of the compound. Write the structural formula of the complex and secondary valency for Nickel ion.
Chloroform, in the presence of air and sunlight, produces a poisonous gas known as :
(CH3)3C–OC2H5 on reaction with HI gives
Consider the following compounds: Chlorobenzene (I), 2,4,6-trinitrochlorobenzene (II), 2,4-dinitrochlorobenzene (III), 4-nitrochlorobenzene (IV). The correct order of increasing ease of nucleophilic substitution reactions of these compounds is :
Oxidation of chloroform by air in the presence of sunlight produces a poisonous gas known as:
The position of − Br in the compound can be classified as :
Which of the following is not correct for SN1 reaction?
Consider the following reaction and identify A and B : CH3Cl + NaI (in dry acetone) → A + B
Consider the following reaction and identify A and B: CH3Cl + NaI (dry acetone) → A + B
The conversion of an alkyl halide into an alcohol by aqueous NaOH is classified as
The synthesis of alkyl fluoride is best accomplished by
Assertion (A): (CH3)3C–O–CH3 gives (CH3)3C–I and CH3OH on treatment with HI. Reason (R): The reaction occurs by SN1 mechanism.
Assertion (A): Nucleophilic substitution reaction of chlorobenzene is easier than that of chloroethane. Reason (R): C–Cl bond in chlorobenzene has partial double bond character due to resonance.
Out of 2-Bromobutane, 1-Bromobutane, 2-Bromopropane and 1-Bromopropane, the molecule which is chiral in nature is:
Polyhalogen compounds have wide application in industries and agriculture. DDT is also a very important polyhalogen compound. It is a:
Assertion (A): n-Butyl chloride has higher boiling point than n-Butyl bromide. Reason (R): C – Cl bond is more polar than C – Br bond.
Which of the following molecules is chiral in nature?
The treatment of ethyl bromide with alcoholic silver nitrite gives:
Assertion (A): The boiling points of alkyl halides decrease in the order RI > RBr > RCl > RF. Reason (R): The van der Waals forces of attraction decrease in the order RI > RBr > RCl > RF.
Which of the following compounds would be hydrolysed by aqueous KOH most easily ?
Which reagents are required for one step conversion of chlorobenzene to toluene?
Which reagents are required for one step conversion of Chlorobenzene to Diphenyl?
Which of the following haloalkanes react with aqueous KOH most rapidly by SN1 reaction ?
The synthesis of alkyl fluoride is best carried out by :
Which of the following haloalkanes is most reactive towards SN2 reaction?
Which of the following alkyl halides will undergo SN1 reaction most readily?
Assertion (A): p-nitroaniline is a weaker base than p-toluidine. Reason (R): The electron withdrawing effect of NO2 group in p-nitroaniline makes it a weaker base.
(CH3)2CH O CH3 when treated with HI gives :
The synthesis of alkyl fluoride is best obtained from:
In the reaction R-OH + HCl → R-Cl + H2O (with 2ZnCl2), what is the correct order of reactivity of alcohol?
In the reaction R—OH + HCl —→ (ZnCl2) R—Cl + H2O, what is the correct order of reactivity of alcohol?
The species that attacks benzene in following is:
The conversion of an alkyl halide into an alkene by alcoholic KOH is classified as
Racemisation occurs in
Which of the following reactions are feasible?
Assertion (A): Nucleophilic substitution of iodoethane is easier than chloroethane. Reason (R): Bond enthalpy of C-I bond is less than that of C-Cl bond.
Which of the following belongs to the class of Vinyl halides ?
Retention of configuration is observed in
Assertion (A): Chlorobenzene is resistant to electrophilic substitution reaction. Reason (R): C-Cl bond in chlorobenzene acquires partial double bond characters due to resonance.
Auto oxidation of chloroform in air and sunlight produces a poisonous gas known as
Inversion of configuration occurs in
Assertion (A): Chlorobenzene is resistant to nucleophilic substitution reaction at room temperature. Reason (R): C–Cl bond gets weaker due to resonance.
Assertion (A): Nucleophilic substitution of iodoethane is easier than chloroethane. Reason (R): Bond energy of C-Cl bond is less than C-I bond.
Which of the following has the highest melting point?
Benzene diazonium chloride on hydrolysis gives:
Which of the following belongs to the class of alkyl halides?
Reaction of 1-phenyl-2-chloropropane with alcoholic KOH gives mainly:
Assertion (A): Monobromination of aniline can be conveniently done by protecting the amino group by acetylation. Reason (R): Acetylation decreases the activating effect of the amino group.
Which of the following molecules has a chiral centre correctly labelled with an asterisk (*)?
Which of the following would not be a good choice for reducing nitrobenzene to aniline?
What happens when : (a) n-butyl chloride is treated with alcoholic KOH ? (b) Chlorobenzene is treated with CH3Cl in the presence of anhydrous AlCl3 ?
Why are haloarenes less reactive towards nucleophilic substitution reaction? Give two reasons.
Draw the structure of the given compound: 4–Bromo–3–methylpent–2–ene. What happens when chloroethane is treated with aqueous potassium hydroxide?
(a) Draw the structure of the given compound : 4–Bromo–3–methylpent–2–ene (b) What happens when chloroethane is treated with aqueous potassium hydroxide ?
For the compound having molecular formula C4H9Br, write: (a) the isomer which is most reactive towards SN1 displacement. (b) the isomer which, on reacting with Na metal in the presence of dry ether, gives 2,5-Dimethylhexane.
Draw the structures of major product(s) in each of the following reactions: (b) CH3CH = C(CH3)2 + HBr
(a) Complete the equation: 2NH₂⁻ + (N⁺Cl₂) + H⁺ → ? (b) How will you convert chlorobenzene to p-chloroaniline?
Draw the structures of product(s) in each of the following reactions: (a) CH3–CH=CH2 with NO2, heat, (b) Cl with Br2, anhydrous AlCl3, then with CH3COCl
Why are haloarenes less reactive towards nucleophilic substitution reaction ? How does the presence of nitro (–NO2) group at ortho- and para-positions in haloarenes increase the reactivity towards nucleophilic substitution reaction ?
(a) Which one of the following pairs of substances undergoes SN1 reaction faster and why? CH₃-CH₂-CH₂-Cl OR CH₂=CH-CH₂-Cl
(a) Which halogen compound in the following pair will react faster in SN2 reactions and why ? CH3CH2I OR CH3CH2Br
Which halogen compound in the following pair will react faster in SN1 reaction and why? Why is the dipole moment of chlorobenzene lower than that of cyclohexyl chloride?
Which halogen compound in the following pair will react faster in SN2 reaction and why?
Identify A, B and C in the following reactions: (a) CH3-CH(OH)-CH3 + PCl5 → A + AgCN → B (b) CH3CH2CH2Cl + KOH (ethanol) → C + HBr
Write the main product formed when: (a) n-Butyl chloride is treated with alc. KOH. (b) 2,4,6-Trinitrochlorobenzene is subjected to hydrolysis.
An alkyl halide (A) of molecular formula C6H13Cl on treatment with alcoholic KOH gives two isomeric alkenes (B) and (C) of molecular formula C6H12. Both alkenes on hydrogenation give 2,3-dimethylbutane. Write the structures of (A), (B) and (C).
Which of the following is an appropriate set of reactants for the preparation of 1-methoxy-4-nitrobenzene and why?
(b) Write equations for: Reaction of chlorobenzene with CH3Cl / anhyd. AlCl3
Why haloarenes are not reactive towards nucleophilic substitution reaction? Give two reasons.
Write two differences between SN1 and SN2 reactions. Out of chlorobenzene and 2,4,6-trinitrochlorobenzene, which one is more reactive towards nucleophilic substitution reactions ?
Compound 'X' with molecular formula C4H9Br reacts with aqueous KOH to give an alcohol. The rate of this reaction depends only on the concentration of the compound 'X'. When an optically active isomer 'Y' of the compound 'X' was treated with aqueous KOH solution, the rate of reaction was found to be dependent on concentration of compound 'Y' and aqueous KOH both. (a) Write down the structural formula of both 'X' and 'Y'. (b) Out of 'X' and 'Y', which one will undergo racemisation and why? (c) Out of 'X' and 'Y', which one will form product with inversion of configuration and why?
(a) Write the IUPAC name of the given compound: CH 3CH(CH3)CH(Br)CH3 (b) Define Racemisation. (c) The boiling points of the alkyl halides with the same alkyl group decrease in the given order: RI > RBr > RC l > RF. Explain the above statement.
Give reasons for the following: (a) Alkyl halides, though polar, yet their solubility in water is very low. (b) p-Dichlorobenzene has higher melting point than those of o- and m-isomers. (c) CH3 – I is more reactive than CH3 – Br towards SN2 reactions.
Answer the following: (a) Which isomer of C4H9Br is most reactive towards SN1 reaction? (b) Predict the alkene that would be formed by dehydrohalogenation of 1-Bromo-1-methylcyclohexane. (c) Although chlorine shows strong –I effect, yet it is ortho- and para-directing in electrophilic aromatic substitution reactions. Why?
(a) Which isomer of C4H9Br is most reactive towards SN1 reaction? (b) Predict the alkene that would be formed by dehydrohalogenation of 1-Bromo-1-methylcyclohexane. (c) Although chlorine shows strong –I effect, yet it is ortho- and para-directing in electrophilic aromatic substitution reactions. Why?
Define Racemization. Out of SN1 and SN2 reactions, which is accompanied by racemization ? Give reason in support of your answer.
(a) Account for the following: (i) Allyl chloride is hydrolysed more readily than n-propyl chloride. (ii) Isocyanides are formed when alkyl halides are treated with silver cyanide. (iii) Methyl chloride reacts faster with OH– ion in SN2 reaction than t-butyl chloride.
Account for the following: (a) The C – Cl bond length in chlorobenzene is shorter than that in methyl chloride. (b) Grignard reagents should be prepared under anhydrous conditions. (c) In case of optically active alkyl halides, SN1 reactions are accompanied by racemisation.
Among the following, which will have inversion of configuration on reaction with aqueous alkali and why? (i) 1-chloropropane OR (ii) 2-chloro-2-methylpropane. Which of the following (A) or (B) will be the major product in the reaction given: CH3 – CH2 – CH(Br) – CH3 + alc. KOH → CH3 – CH2 – CH = CH2 (A) + CH3 – CH = CH – CH3 (B)? Give a suitable reason for your answer.
Haloarenes are less reactive towards nucleophilic substitution reactions.
Write any two differences between SN1 and SN2 reactions. Which of the following compounds would undergo SN1 reaction faster and why ? (choice between two structural compounds)
Write any two differences between SN1 and SN2 reactions. Which of the following compounds would undergo SN1 reaction faster and why? CH2–Cl or CH2–Cl (with benzene ring)
A compound (A) with molecular formula C4H9I which is a primary alkyl halide, reacts with alcoholic KOH to give compound (B). Compound (B) reacts with HI to give (C) which is an isomer of (A). When (A) reacts with Na metal in the presence of dry ether, it gives a compound (D), C8H18, which is different from the compound formed when n-butyl iodide reacts with sodium. Write the structures of (A), (B), (C) and (D). Write the chemical equation when compound (A) is reacted with alcoholic KOH.
(a) Which of the following is an allylic halide? (i) CH3-CH=CH-Br (ii) CH2=CH-CH(Br)-CH3. (b) Out of chlorobenzene and 2,4,6-trinitrochlorobenzene, which is more reactive towards nucleophilic substitution and why? (c) Which isomer of C4H9Cl has the lowest boiling point?
Give reasons for the following: (a) Chlorine is ortho/para directing in electrophilic aromatic substitution reactions, though chlorine is an electron withdrawing group. (b) Racemic mixture is optically inactive. (c) Allyl chloride is hydrolysed more readily than n-propyl chloride.
(a) What type of nucleophilic substitution (SN1 or SN2) occurs in the hydrolysis of 2-Bromobutane to form ()-Butan-2-ol ? Give reason. (b) What happens when chlorobenzene and methyl chloride are treated with sodium metal in dry ether ?
What type of nucleophilic substitution (SN1 or SN2) occurs in the hydrolysis of 2-Bromobutane to form ()-Butan-2-ol? Give reason. OR What happens when chlorobenzene and methyl chloride are treated with sodium metal in dry ether?
What type of nucleophilic substitution (SN1 or SN2) occurs in the hydrolysis of 2-Bromobutane to form ()-Butan-2-ol? Give reason.
Write main product formed when: (a) Methyl chloride is treated with NaI/Acetone. (b) 2,4,6-trinitrochlorobenzene is subjected to hydrolysis. (c) n-Butyl chloride is treated with alcoholic KOH.
Answer any 3 of the following: (a) Which isomer of C5H10 gives a single monochloro compound C5H9Cl in bright sunlight ? (b) Arrange the following compounds in increasing order of reactivity towards SN2 reaction: 2-Bromopentane, 1-Bromopentane, 2-Bromo-2-methylbutane
Account for the following: (a) Benzyl chloride is highly reactive towards SN1 reaction. (b) ()-Butan-2-ol is optically inactive, though it contains a chiral carbon atom. (c) Chloroform is stored in closed dark coloured bottles.
(i) How will you bring about the following conversions: (I) Bromobenzene to 1-phenylethanol (II) Benzene to m-nitroacetophenone (ii) An organic compound with the molecular formula C8H8O forms 2,4-DNP derivative, reduces Tollens' reagent and undergoes Cannizzaro reaction. On vigorous oxidation with acidic or alkaline KMnO4 it gives Benzene-1,2-dicarboxylic acid. Identify the compound and write the products when it undergoes Cannizzaro reaction. (iii) Arrange the following compounds in increasing order of their acid strength: C6H5COOH, O2N–CH2–COOH, CF3–COOH, HCOOH
(a) (i) (I) Which of the following is more reactive towards SN1 reaction : 2-Bromo-2-methylbutane or 1-Bromopentane. (II) What type of halide is present in the following compound : CH3-CH(CH3)-C(=CH2)-Cl. (III) Why is chloroform stored in dark coloured bottles ? (ii) Define the following terms: (I) Ambident Nucleophiles (II) Racemic mixture
(a) (i) (I) Which of the following is more reactive towards SN1 reaction: 2-Bromo-2-methylbutane or 1-Bromopentane (II) What type of halide is present in the following compound: CH₃-CH(CH₃)-C(Cl)=CH₂ (III) Why is chloroform stored in dark coloured bottles? (ii) Define the following terms: (I) Ambident Nucleophiles (II) Racemic mixture
Case study · CBSE 2023
The polarity of C-X bond of alkyl halides is responsible for their nucleophilic substitution, elimination and their reaction with metal atoms to form organometallic compounds. Alkyl halides are prepared by the free radical halogenation of alkanes, addition of halogen acids to alkenes, replacement of OH group of alcohols with halogens using phosphorus halides, thionyl chloride or halogen acids. Aryl halides are prepared by electrophilic substitution of arenes. Nucleophilic substitution reactions are categorised into SN1 and SN2 on the basis of their kinetic properties. Chirality has a profound role in understanding the SN1 and SN2 mechanism.
What happens when bromobenzene is treated with Mg in the presence of dry ether?
Case study · CBSE 2023
Nucleophilic Substitution reaction of haloalkane can be conducted according to both SN1 and SN2 mechanisms. SN1 is a two step reaction while SN2 is a single step reaction. For any haloalkane which mechanism is followed depends on factors such as structure of haloalkane, properties of leaving group, nucleophilic reagent and solvent. Influences of solvent polarity: In SN1 reaction, the polarity of the system increases from the reactant to the transition state, because a polar solvent has a greater effect on the transition state than the reactant, thereby reducing activation energy and accelerating the reaction. In SN2 reaction, the polarity of the system generally does not change from the reactant to the transition state and only charge dispersion occurs. At this time, polar solvent has a great stabilizing effect on Nu than the transition state, thereby increasing activation energy and slow down the reaction rate. For example, the decomposition rate (SN1) of tertiary chlorobutane at 25 C in water (dielectric constant 79) is 300000 times faster than in ethanol (dielectric constant 24). The reaction rate (SN2) of 2-Bromopropane and NaOH in ethanol containing 40% water is twice slower than in absolute ethanol. Hence the level of solvent polarity has influence on both SN1 and SN2 reaction, but with different results. Generally speaking weak polar solvent is favourable for SN2 reaction, while strong polar solvent is favourable for SN1. Generally speaking the substitution reaction of tertiary haloalkane is based on SN1 mechanism in solvents with a strong polarity (for example ethanol containing water).
(a) Why racemisation occurs in SN1?
(a) Why does racemisation occur in SN1?
Propan-2-ol on oxidation with CrO3 gives :
Assertion (A) : p-nitrophenol is less acidic than phenol. Reason (R) : Nitro group is an electron-withdrawing group, which stabilises the phenoxide ion.
Aspirin is obtained by acetylation of
At low temperature, phenol reacts with dil. HNO3 to yield
Assertion (A): The presence of –OH group in phenols directs the incoming group to meta position in the ring. Reason (R): –OH group in phenols activates the aromatic ring towards electrophilic substitution reaction.
Assertion (A): The presence of –OH group in phenols directs the incoming group to ortho and para positions. Reason (R): –OH group in phenols activates the aromatic ring towards electrophilic substitution reaction.
Which of the following is 'not' true about enantiomers ?
At low temperature, phenol on reaction with Br2 in CS2 gives
Assertion (A) : The presence of –OH group in phenols directs the incoming group at ortho- and para- positions. Reason (R) : –OH group in phenols deactivates the aromatic ring.
Which of the following molecules is chiral in nature?
Identify the correct increasing order of boiling points of the given compounds:
The intermediate formed during the slowest step involved in the dehydration of alcohol is:
Assertion (A): Phenol is less acidic than 4-methylphenol. Reason (R): The presence of an electron releasing group in phenol makes it less acidic.
The dehydration of 1º, 2º and 3º alcohols follows the order :
Assertion (A): Phenol is more acidic than 4-methylphenol. Reason (R): The presence of an electron releasing group in phenol makes it more acidic.
Assertion (A): Ethers have lower boiling points than the boiling points of alcohols. Reason (R): This is due to the presence of hydrogen bonding in alcohols.
Lucas reagent produces cloudiness immediately with:
Assertion (A): Alcohols act as Bronsted bases as well as Bronsted acids. Reason (R): It is due to the presence of unshared electron pairs on oxygen atom and presence of polar O–H bond.
Williamson synthesis is an example of :
Assertion (A): Alcohols act as Bronsted bases as well as Bronsted acids. Reason (R): Alcohols react as both nucleophiles and electrophiles.
Assertion (A): (CH3)3 C – O – CH3 gives (CH3)3 C – I and CH3OH on reaction with HI. Reason (R): The reaction occurs by SN1 mechanism.
Primary, secondary and tertiary alcohols can be distinguished by :
Assertion (A) : p-nitrophenol is more acidic than phenol. Reason (R) : Nitro group is an electron-withdrawing group, it stabilises phenoxide ion by dispersal of negative charge.
The compound which undergoes dehydration most easily is
Alkenes are formed by heating alcohols with conc. H2SO4. The first step in the reaction is:
CH3CH2OH can be converted to CH3CHO by :
Williamson synthesis of preparing unsymmetrical ether is :
Assertion (A) : Phenol is strongly acidic as compared to ethanol. Reason (R) : Phenoxide ion is more stable than ethoxide ion.
Which by-product is obtained in the manufacture of phenol from cumene?
Assertion (A): Phenol is less acidic than alcohol. Reason (R): Phenoxide ion is more stable than alkoxide ion.
During dehydration of alcohol to alkene by heating with conc. H2SO4, the initiation step is:
Assertion (A): The bond angle C – O – C in ethers is slightly greater than tetrahedral angle. Reason (R): This is because of the repulsive interaction between the two bulky alkyl groups.
The reaction R – OH + Na → RO– Na+ + 1/2 H2 (g) suggests that alcohols are :
At low temperature, phenol reacts with Br2 in CS2 to form :
Assertion (A): A mixture of o-nitrophenol and p-nitrophenol can be separated by steam distillation. Reason (R): o-nitrophenol is steam volatile due to intermolecular hydrogen bonding.
In the reaction R – OH + HCl → (2ZnCl) RCl + H2O, what is the correct order of reactivity of alcohols ?
Phenol reacts with Bromine (Br2) water to form :
Assertion (A): A mixture of o-nitrophenol and p-nitrophenol can be separated by steam distillation. Reason (R): o-nitrophenol is steam volatile due to intramolecular hydrogen bonding.
The reaction OH + NaOH (aq) → O–Na+ + 1/2 H2 (g) suggests that phenol is:
Phenol reacts with conc. HNO3 to form:
Assertion (A): A mixture of o-nitrophenol and p-nitrophenol can be separated by fractional distillation. Reason (R): o-nitrophenol is steam volatile due to intramolecular hydrogen bonding.
The reaction of an alkyl halide with sodium alkoxide forming ether is known as:
Decarboxylation of sodium benzoate on heating with soda lime gives:
Dehydration of tertiary alcohols with Cu at 573 K gives:
Phenol on reaction with aqueous bromine at room temperature gives:
Phenol does not undergo nucleophilic substitution reaction easily due to:
Ethanol on heating with conc. H2SO4 at 413 K gives:
Phenol is less acidic than:
(CH3)3 C-O-CH3 reacts with HI to give:
(CH₃)₂CH-O-CH₃ reacts with HI to give:
A compound (X) with the molecular formula C₃H₈O can be oxidized by strong oxidizing agents to another compound (Y) whose molecular formula is C₃H₆O₂. The compound (X) is:
Which one of the following compounds has the lowest pKa value ?
Assertion (A): The boiling point of ethanol is higher than that of dimethyl ether. Reason (R): Ethanol molecules are associated through hydrogen bonding whereas in dimethyl ether, it is not possible.
Which one of the following compounds has the highest pKa value?
C6H5 O CH3 when treated with HI gives:
Assertion (A): The boiling point of ethanol is higher than that of dimethyl ether. Reason (R): Dimethyl ether molecules are associated through hydrogen bonding.
CH₃ – O – CH₃ when treated with excess HI gives:
Assertion (A): Phenol on reaction with aqueous NaOH gives sodium phenoxide. Reason (R): This reaction supports the acidic nature of phenol.
Assertion (A): Boiling point of butan-1-ol is higher than that of butan-1-amine. Reason (R): Being more polar, butan-1-ol forms stronger intermolecular hydrogen bonds as compared to butan-1-amine.
Assertion (A): NH2 group is o- and p-directing in electrophilic substitution reactions. Reason (R): Aniline cannot undergo Friedel-Crafts reaction. Select the correct answer.
Assertion (A): Acetylation of aniline gives a monosubstituted product. Reason (R): Activating effect of NHCOCH3 group is more than that of amino group. Select the correct answer.
In the reaction R−OH + HCl → R−Cl + H₂O (with ZnCl₂), what is the correct order of reactivity of alcohol?
Which of the following reactions are feasible ?
Aspirin is obtained by the acetylation of which of the following compounds?
Sodium phenoxide when heated with CO2 under pressure, followed by acidification, yields:
For the conversion of propene into 1-propanol, which of the following reagents and conditions should be used?
When diethyl ether is heated with excess of HI, it produces:
Which of the following alkenes on acid catalysed hydration gives a tertiary alcohol?
Which of the following alcohols will not undergo oxidation?
(a) Write the major product in the following reaction: (benzene) + CH3 – Cl Na dry ether ? (b) What happens when 2-Bromobutane is made to react with alcoholic potassium hydroxide?
Explain the mechanism of acid catalysed hydration of ethene.
Write the mechanism of dehydration of ethyl alcohol with conc. H2SO4 at 413 K.
Write the mechanism of dehydration of ethyl alcohol with conc. H2SO4 at 443 K.
(b) What type of deviation is shown by ethanol and acetone mixture ? Give reason. What type of azeotropic mixture is formed by that deviation ?
Account for the following: (i) Phenol is a stronger acid than an alcohol. (ii) The boiling point of alcohols decreases with increase in branching of alkyl chain.
(a) Predict the products of the following reactions: (i) CH₃CH₂OH →(K, 573Cu) (ii) C₆H₅OH →(aq.Br₂) OR (b) Give reasons for the following: (i) p-nitrophenol is more acidic than p-methylphenol. (ii) (CH₃)₃C−Br on reaction with NaOCH₃ gives alkene as the main product and not an ether.
(a) Account for the following: (i) Phenol is a stronger acid than an alcohol. (ii) The boiling point of alcohols decreases with increase in branching of alkyl chain. OR (b) (i) Write the mechanism of the following reaction: CH3CH2OH →(K, 443K) CH2=CH2 + H2O (ii) Write the equation involved in Reimer-Tiemann reaction.
Write the chemical equation involved in the following reactions: (a) Reimer-Tiemann reaction (b) Acetylation of Salicylic acid
Write the chemical equation involved in the following: (a) Kolbe's reaction (b) Williamson synthesis
Give the structures and IUPAC name of the products expected from the following reactions: (b) Reaction of phenol with Br₂(aq).
Write the mechanism of the following reaction: CH2 = CH2 + H2O →(H+) CH3CH2OH
Write the mechanism of acid dehydration of ethanol to yield ethene.
Why is boiling point of o-dichlorobenzene higher than p-dichlorobenzene but melting point of para isomer is higher than ortho isomer?
(b) (i) Complete the reaction with the main product formed: CH3CH2OH (ii) Convert Bromoethane to Propanamine.
(a) For the pair phenol and cyclohexanol: Why is phenol more acidic than cyclohexanol?
(a) Write equations for: Oxidation of chloroform by air and light
For the pair phenol and cyclohexanol, answer the following: (a) Why is phenol more acidic than cyclohexanol? (b) Give one chemical test to distinguish between the two.
Write the reaction involved in the following: (a) Reimer-Tiemann reaction (b) Kolbe's reaction (c) Friedal-Crafts acylation of anisole
Give reasons for the following: (a) Although chlorine is an electron-withdrawing group, yet it is ortho-, para-directing in electrophilic aromatic substitution reactions. (b) Aryl halides cannot be prepared by reacting phenol with concentrated halogen acids or phosphorus halides. (c) Chloroform is stored in closed dark coloured bottles.
How will you obtain the following from benzene diazonium chloride ? Write chemical equations involved: (a) Phenol (b) Iodobenzene (c) p-Aminoazobenzene
(a) Can sodium ethoxide and t-butyl chloride be used for the preparation of t-butyl ethyl ether? Give suitable explanation. Justify your answer by suggesting the appropriate starting material required for preparation of t-butyl ethyl ether. (b) Give the IUPAC name of above mentioned ether.
(a) Can sodium methoxide and t-butyl bromide be used for the preparation of t-butyl methyl ether. Give suitable reason. Justify your answer by suggesting the appropriate starting material if required for the preparation of t-butyl methyl ether. (b) Give the IUPAC name of above mentioned ether.
(a) Can sodium propoxide and t-butyl chloride be used for the preparation of t-butyl propyl ether? Give suitable explanation. Justify your answer by suggesting the appropriate starting material required for the preparation of t-butyl propyl ether. (b) Give the IUPAC name of the above mentioned ether.
(a) Arrange the following compounds in the increasing order of their acidic strength: 3,5-dinitrophenol, 4-methylphenol, phenol, 2,4,6-trinitrophenol. (b) What happens when: (i) Phenol is distilled with Zn dust? (ii) Anisole is treated with HBr? (write equations)
Write the chemical equation for Williamson's synthesis. Give a method to separate o-nitrophenol and p-nitrophenol. Explain the principle involved.
Write the chemical equation for the following: (i) Preparation of phenol from cumene (ii) Nitration of anisole
Compound (A) (C6H12O2) on reduction with LiAlH4 gives two compounds (B) and (C). The compound (B) on oxidation with PCC gives compound (D) which upon treatment with dilute NaOH and subsequent heating gives compound (E). Compound (E) on catalytic hydrogenation gives compound (C). The compound (D) is oxidized further to give compound (F) which is found to be a monobasic acid (Molecular weight = 60). Identify the compounds (A), (B), (C), (D), (E) and (F).
Give the equations of reactions for the preparation of (any three): (a) Phenol from chlorobenzene (b) Salicylaldehyde from phenol (c) 2-Methoxyacetophenone from anisole (d) Picric acid from phenol
Give reasons for the following: (a) Chlorine is ortho/para directing in electrophilic aromatic substitution reactions, though chlorine is an electron withdrawing group. (b) Racemic mixture is optically inactive. (c) Allyl chloride is hydrolysed more readily than n-propyl chloride.
(a) Write the equations of the reactions involved in the following: (i) Reimer-Tiemann reaction (ii) Kolbe reaction (b) Name the reagent used in the bromination of phenol to form 2,4,6-Tribromophenol.
Write the reactions involved in the following: (i) Reimer-Tiemann reaction (ii) Colbe reaction OR Name the reagent used in the bromination of phenol to form 2,4,6-Tribromophenol.
How do you convert the following: (Any three) (a) Phenol to picric acid (b) Propanone to 2-Methylpropan-2-ol (c) Phenol to anisole (d) Propene to Propan-1-ol
How do you convert the following (Any three): (a) Phenol to 2-Hydroxybenzaldehyde (b) Anisole to 2-Methoxyacetophenone (c) Propene to Propan-2-ol (d) Ethanol to Ethanal
Write the mechanism of the following reaction: 2CH3CH2OH + H+/413K → CH3–CH2–O–CH2–CH3 + H2O
Write the mechanism of the following reaction: 2CH3CH2OH →(H+, 413 K) CH3 – CH2 – O – CH2 – CH3 + H2O. Why ortho-nitrophenol is steam volatile while para-nitrophenol is not ?
(a) (i) Write the mechanism of the following reaction: 2CH3CH2OH H+ 413 K → CH3–CH2–O–CH2–CH3 + H2O (ii) Why ortho-nitrophenol is steam volatile while para-nitrophenol is not? OR (b) What happens when (i) Anisole is treated with CH3Cl/anhydrous AlCl3? (ii) Phenol is oxidised with Na2Cr2O7/H+? (iii) (CH3)3C–OH is heated with Cu/573 K? Write chemical equation in support of your answer.
(a) Write the mechanism of the following reaction: CH3-CH2-OH →(K,443H) CH2=CH2 + H2O (b) Write the equation of the reaction for the preparation of phenol from cumene.
Write the mechanism of the following reaction: CH₃-CH₂-OH (K, 443°C) → CH₂ = CH₂ + H₂O
(a) (i) Why is the C – O bond length in phenols less than that in methanol? (ii) Arrange the following in order of increasing boiling point: Ethoxyethane, Butanal, Butanol, n-butane (iii) How can phenol be prepared from anisole? Give reaction.
(a)(i) Why is the C – O bond length in phenols less than that in methanol?
(b) (v) Draw the structure of 'X' in the following reaction : C6H5CH2CH(OH)CH3 + CrO3 → 'X'
An organic compound 'A', with molecular formula C2H6O reacts with active metals such as sodium to give compound 'B' and hydrogen gas. 'A' on treatment with iodine and sodium hydroxide gives 'C' and in presence of H2SO4 at 413 K gives 'D' (C4H10O). 'D' on reaction with excess of HI gives 'E'. Identify 'A', 'B', 'C', 'D' and 'E' and write all the reactions involved.
Case study · CBSE 2026
The boiling points of alcohols and phenols increase with increase in the number of carbon atoms due to increase in van der Waals forces. The − OH group in alcohols and phenols is involved in intermolecular hydrogen bonding, due to which their boiling points are higher than those of ethers, haloalkanes and haloarenes of comparable molecular masses. Alcohols and phenols are acidic in nature. Electron-withdrawing groups in phenol increase its acidic strength, while electron-releasing groups decrease it. The presence of − OH group in phenols activates the aromatic ring towards electrophilic substitution and directs the incoming group to the ortho and para positions due to resonance effect. The Reimer-Tiemann reaction of phenol yields salicylaldehyde, whereas Kolbe's reaction of phenol yields salicylic acid. Aspirin is formed by the acetylation of salicylic acid.
(i) Write the name of the major product(s) formed in : (I) Reimer-Tiemann reaction (II) Kolbe's reaction (ii) Name the method by which aspirin is formed from salicylic acid.
Case study · CBSE 2026
Like NH3, nitrogen atom of amine is trivalent and carries an unshared pair of electrons. Nitrogen orbitals in amines are therefore sp3 hybridised and the geometry of amines is pyramidal. Lower aliphatic amines are soluble in water due to the formation of hydrogen bond with water molecules. The solubility decreases as the molar mass of amines increases due to increase in size of hydrophobic part. Higher amines are insoluble in water. However amines are less soluble in water than alcohols because of low electronegativity of nitrogen as compared to oxygen. Boiling points of isomeric amines follow the order 1º > 2º > 3º. It is due to the fact the amines are held together due to hydrogen bonding. Extent of hydrogen bonding is more in primary amines than in secondary amines as two hydrogen atoms are available for hydrogen bond formation. Tertiary amines do not show hydrogen bonding because of the absence of hydrogen atom attached to nitrogen. Amines can be prepared from, nitro compounds, nitriles, amides etc.
Out of Butan–1–amine and Butan–1–ol, which is more soluble in water?
Case study · CBSE 2026
Alcohols have higher boiling points than other compounds, namely hydrocarbons, ethers and haloalkanes of comparable molecular masses. On oxidation, primary alcohols yield aldehydes with mild oxidizing agents and carboxylic acids with strong oxidizing agents. Secondary alcohols yield ketones on oxidation while tertiary alcohols are resistant to oxidation. Ethers may be prepared by dehydration of alcohols and Williamson synthesis. The C − O bond in ethers can be cleaved by hydrogen halides. The presence of − OH group in phenols activates the aromatic ring towards electrophilic substitution and directs the incoming group to ortho and para positions due to resonance effect. In presence of NaOH, phenol generates phenoxide ion which is even more reactive than phenol. Thus, in alkaline medium, phenol undergoes Kolbe's reaction.
Name the reagents used in the following reactions: (i) Oxidation of a primary alcohol to aldehyde (ii) Oxidation of a primary alcohol to carboxylic acid
Case study · CBSE 2026
Alcohols and Phenols are acidic in nature. Electron withdrawing groups in phenol increase its acidic strength and electron releasing groups decrease it. Alcohols undergo nucleophilic substitution with hydrogen halides to yield alkyl halides. Dehydration of alcohols gives alkenes. On oxidation, primary alcohols yield aldehydes with mild oxidising agents and carboxylic acids with strong oxidising agents, while secondary alcohols yield ketones. Tertiary alcohols are resistant to oxidation. The presence of –OH group in phenols activates the aromatic ring towards electrophilic substitution and directs the incoming group to ortho and para positions due to resonance effect.
(a) Write the mechanism of acid dehydration of ethanol to yield ethene.
Case study · CBSE 2026
Ethers are prepared by the dehydration of alcohols in presence of protic acids at 413 K. Symmetrical and unsymmetrical ethers can also be prepared by Williamson synthesis. This reaction involves SN2 attack of an alkoxide ion on primary alkyl halide. If a tertiary alkyl halide is used, elimination reaction occurs and an alkene is formed, no ether is formed. C – O bond in ethers are cleaved under drastic conditions with excess of HI. When unsymmetrical ethers react with HI, the alkyl halide is formed from smaller alkyl group. If one of the alkyl group is tertiary, the alkyl halide is formed from the tertiary alkyl group because tertiary alkyl carbocation is more stable than the primary carbocation. Cleavage of alkyl aryl ethers takes place at the alkyl-oxygen bond due to more stable aryl-oxygen bond. The order of reactivity of hydrogen halides is HI > HBr > HCl. Aromatic ethers undergo electrophilic substitution reactions. The alkoxy group attached to the aromatic ring activates the ring towards electrophilic substitution and directs the incoming group to ortho- and para-positions.
(a) Complete the following equations: (i) CH₃Cl + S + AlCl₃ (anhyd.) → ? (ii) Anisole + Conc. (HNO₃ + H₂SO₄) → ?
Case study · CBSE 2025
Alcohols undergo a number of reactions involving the cleavage of C – OH bond. However, phenols do not undergo reactions involving the cleavage of C – OH bond. Alcohols are weaker acids than water. Alcohols react with halogen acids to form the corresponding haloalkanes. Phenols are stronger acids than alcohols. A characteristic feature of phenols is that they undergo electrophilic substitution reactions such as halogenation, nitration, etc. Since – OH group is a strong activating group, phenol gives trisubstituted products during halogenation, nitration, etc.
(a) What happens when phenol is treated with the following ? (i) Br2 water (ii) Conc. HNO3
Which of the following is 'not' true about enantiomers?
Identify 'X' in the following reaction : CH 3 – CO – CH2 – COO – CH3 + NaBH4 → 'X'
Which of the reactions is used in the conversion of a ketone into hydrocarbon ?
Assertion (A) : All aliphatic aldehydes give a positive Fehling's test. Reason (R) : Aliphatic aldehydes are reduced by Fehling's reagent.
CH3CH2OH can be converted to CH3CHO by:
Which of the following aldehydes will undergo Cannizzaro reaction?
CH3CH2CHO and CH3CH2COOH can be distinguished by:
Assertion (A): The solubility of aldehydes and ketones in water decreases with increase in size of the alkyl group. Reason (R): Aldehydes and ketones have dipole-dipole interaction.
The formation of cyanohydrin from an aldehyde is an example of:
The product formed as a result of reaction of CH3MgBr and CO2 followed by hydrolysis is:
The IUPAC name of the compound with structure showing 3-oxobutanal is:
Assertion (A): The pKa of O2N-CH2-COOH is lower than that of CH3-COOH. Reason (R): NO2 group shows electron withdrawing effect which increases the acidic character of O2N-CH2-COOH.
Which of the following is the strongest acid?
Which of the following has the highest boiling point?
The suitable Grignard reagent used for the synthesis of CH3-CH(CH3)-CH2-OH with methanal is:
Assertion (A): Fluoroacetic acid is stronger acid than chloroacetic acid. Reason (R): This is due to greater electron withdrawing nature of F than Cl.
Aspirin is formed by the acetylation of:
Which of the following is most reactive in nucleophilic addition reactions?
Which of the following does not give aldol condensation reaction?
Aldehydes and ketones react with hydroxylamine to form
The reagent that can be used to distinguish acetophenone and benzophenone is
Which of the following compounds will undergo self-condensation in the presence of dilute NaOH solution?
The reactivities of the carbonyl compounds HCHO (I), CH3CHO (II) and CH3COCH3 (III) towards nucleophilic addition reaction decreases in the order:
A compound (A) with molecular formula C5H10O, forms a compound on reduction gives n-pentane. The compound (A) is:
Which of the following reagents would one choose to transform CH₃COCl into acetone?
C6H5CHO + CH3COCH3 →(OH) C6H5CH = CH-COCH3. This reaction is known as:
This reaction is known as:
Which one of the following has lowest pKa value?
Assertion (A): Acetic acid but not formic acid can be halogenated in presence of red P and Cl2. Reason (R): Acetic acid is a weaker acid than formic acid.
Assertion (A): Bromination of benzoic acid gives m-bromobenzoic acid. Reason (R): Carboxyl group increases the electron density at the meta position.
Which of the following would not be a good choice for reducing nitrobenzene to aniline?
Assertion (A): The final product in Aldol condensation is always α-β-unsaturated carbonyl compound. Reason (R): α-β-unsaturated carbonyl compounds are stabilised due to conjugation.
(a) How can acetaldehyde be prepared from acetyl chloride?
Give a simple chemical test to distinguish between 3-pentanone and 2-pentanone, and write an equation for Clemmensen reduction.
Carboxylic acid is more acidic than phenol. Give reason.
Write the chemical equation when: (a) Butan-2-one is treated with Zn(Hg) and conc. HCl. (b) Two molecules of benzaldehyde are treated with conc. NaOH.
Write the chemical equations when: (a) Pentan-3-one is treated with H2N-NH2 followed by heating with KOH in high boiling solvent such as ethylene glycol. (b) Two molecules of (CH3)3C-CHO are treated with conc. NaOH.
Write the chemical equations when: (a) Ethanal is treated with 2,4-dinitrophenylhydrazine? (b) Propanone is treated with Zn(Hg) and conc. HCl?
Complete and balance the following chemical equations: (a) KMnO4 heat (b) MnO2 + 2C2O4 + 16H+
Write the structures and IUPAC names of the products expected from the following reactions: (a) Reaction of methanal with (CH3)2CHMgBr followed by hydrolysis. (b) Reaction of phenol with conc. HNO3.
Give reasons for the following: (a) Carboxylic carbon is less electrophilic than Carbonyl carbon of aldehydes and ketones. (b) Propanal is more reactive than Propanone towards addition of HCN.
Give the structures and IUPAC name of the products expected from the following reactions: (a) Reaction of methanal with C₆H₅-CH₂-MgBr followed by hydrolysis.
Give reasons: (a) Formic acid is a stronger acid than acetic acid.
Write the products of the following reactions: (i) Reaction with concentrated NaOH. (ii) Reaction with H2N-NH-CO-NH2
Write the products of the following reactions: (i) Benzaldehyde + Concentrated NaOH (ii) Acetophenone + H₂N-NH-CO-NH₂
Predict the products formed when CH3CH2CHO reacts with the following reagents : (Any two) (i) PhMgBr and then H3O+ (ii) LiAlH4 (iii) HCN
Predict the products formed when CH3CHO reacts with the following reagents: (Any two) (i) CH3MgBr and then H3O+ (ii) Zn(Hg)/Conc. HCl (iii) Tollens reagent
Arrange the following compounds in the increasing order of their property indicated: (Any two) (i) Acetaldehyde, Benzaldehyde, Acetophenone, Acetone (Reactivity towards HCN) (ii) (CH3)2CHCOOH, CH3CH2CH(Br)COOH, CH3CH(Br)CH2COOH (Acidic strength) (iii) CH3CH2OH, CH3CHO, CH3COOH (Boiling point)
Write reasons for the following statements: (i) Benzoic acid does not undergo Friedel-Crafts reaction. (ii) Oxidation of aldehydes is easier than that of ketones.
Give reasons for the following statements (Any two): (i) Benzaldehyde is less reactive than propanal in nucleophilic addition reactions. (ii) Carboxylic acids do not give reactions of carbonyl group. (iii) 4-nitrobenzoic acid is a stronger acid than benzoic acid.
(i) (CH3)3C-CHO does not undergo aldol condensation. Why? (ii) Distinguish between Acetophenone and Benzophenone with the help of a chemical test.
How do you convert the following ? (a) Propanone to Propan-2-ol (b) Ethanal to Ethane (c) Sodium benzoate to Benzene
Give reasons for the following: (a) Carboxylic acids have higher boiling point than alcohols of comparable molecular masses. (b) Alpha (α) hydrogens of aldehydes and ketones are acidic in nature. (c) Nucleophilic addition of ammonia and its derivatives does not occur with carbonyl group in strongly acidic medium.
Write the reaction involved in (a) Rosenmund's reduction (b) Cannizzaro's reaction (c) Hell – Volhard – Zelinsky reaction
An organic compound (A) with molecular formula C3H5N on reaction with C6H5MgBr followed by hydrolysis, gives a compound (B). Compound (B) forms an orange-red precipitate with 2,4-DNP reagent and does not give iodoform test. It neither reduces Tollens' or Fehling's reagent nor does it decolourise bromine water. On drastic oxidation with chromic acid it gives a carboxylic acid (C) having molecular formula C7H6O2. Identify the compounds (A), (B) and (C). Write the reactions of compound (A) with C6H5MgBr followed by hydrolysis to give compound (B).
Write the structures of A, B and C in the following reactions:
What happens when: (a) Propanenitrile is treated with phenyl magnesium bromide followed by hydrolysis? (b) p-fluorotoluene is treated with CrO3 in the presence of acetic anhydride followed by hydrolysis with aqueous acid. (c) Phthalic acid is treated with NH3 followed by heating? Write chemical reactions in support of your answer.
How do you convert the following ? (a) Acetophenone to Benzoic acid (b) Acetonitrile to Acetone (c) Benzoic acid to Benzene
How do you convert the following? (a) Toluene to Benzaldehyde (b) Benzoyl chloride to Acetophenone (c) Bromobenzene to Benzoic acid
How do you convert the following? (a) Benzene to m-Nitroacetophenone (b) Bromobenzene to 1-Phenylethanol (c) But-3-en-2-one to Prop-2-en-1-oic acid
(a) (i) Arrange the following compounds in increasing order of their acidic strengths: CH₃CH(Br)CH₂COOH, CH₃CH(CH₃)COOH, CH₃CH₂CH(Br)COOH (ii) Why is CH₃CHO more reactive than acetone towards reaction with HCN? (iii) Complete the equation: CH₃CH=O + NH₂NH₂ → ?
What happens when (a) Ethanal is treated with CH3MgBr followed by hydrolysis ? (b) Phenol is treated with Zinc dust ? (c) Anisole is treated with HI ?
Explain the following reactions : (a) Rosenmund's Reduction (b) Cannizzaro's reaction (c) Hell-Volhard Zelinsky reaction
An aromatic compound 'A' with molecular formula C8H8O gives positive 2,4-DNP test. It gives yellow precipitate of compound 'B' on treatment with sodium hypoiodite. Compound 'A' does not react with Tollen's or Fehling's reagent; on drastic oxidation with KMnO4 it forms a carboxylic acid 'C'. Elucidate the structures of A, B and C. Also give their IUPAC names.
A compound 'A' with molecular formula C4H8O gives positive 2,4-DNP test. It gives yellow precipitate of compound 'B' on treatment with sodium hypoiodite. Compound 'A' does not react with Tollen's or Fehling's reagent; on drastic oxidation with KMnO4, it forms a carboxylic acid 'C'. Elucidate the structures of 'A', 'B' and 'C'. Also give their IUPAC names.
An organic compound 'A' (molecular formula C8H8O) gives 2,4-DNP test. It does not give Tollen's test, but gives a yellow precipitate 'B' with NaOH and I2. On drastic oxidation, it gives a carboxylic acid 'C' with formula C7H6O2. Identify 'A', 'B', 'C' and write the reactions involved.
Write the products formed in the following reaction: CH3CHO + NH2CONHNH2 →
A compound (A) with molecular formula C4H5N on reduction with DIBAL-H followed by hydrolysis, gives a compound (B). Compound (B) gives positive Tollens' test but does not give iodoform test. Compound (B) can also be obtained when ethanal is treated with dilute NaOH followed by heating. Identify (A) and (B). Write the reactions of (A) with DIBAL-H followed by hydrolysis.
Write structure of the products of the following reactions: (a) MgBr + HCHO followed by H+/H2O. (b) An aromatic compound + conc. HNO3. (c) An organic compound + HI followed by OCH3.
Give reasons for the following: (a) Benzoic acid does not undergo Friedel-Crafts reaction. (b) HCHO is more reactive than CH3CHO towards addition of HCN. (c) Vinyl group directly attached with carboxylic acid should decrease the acidity of corresponding carboxylic acid due to resonance, but on the contrary it increases the acidity.
Write structure of the products of the following reactions : (a) 3-OCH3-C6H4-CHO + HI → (b) C6H5-OH + conc. HNO3 → (c) C6H5-MgBr + HCHO → (followed by H+/H2O)
Compound (A) (C6H12O2) on reduction with LiAlH4 gives two compounds (B) and (C). The compound (B) on oxidation with PCC gives compound (D) which upon treatment with dilute NaOH and subsequent heating gives compound (E). Compound (E) on catalytic hydrogenation gives compound (C). The compound (D) is oxidized further to give compound (F) which is found to be a monobasic acid (Molecular weight = 60). Identify the compounds (A), (B), (C), (D), (E) and (F).
Write the reaction involved in the following: (a) Wolff-Kishner reduction (b) Decarboxylation reaction (c) Cannizzaro reaction
How will you bring about the following conversions ? (any three) (a) Benzoic acid to Benzaldehyde (b) Ethanal to Propanone (c) Acetophenone to Benzoic acid (d) Bromobenzene to 1-Phenylethanol
Give the structures of A, B and C in the following reactions:
Explain why: (i) Carboxyl group in benzoic acid is meta directing. (ii) Sodium bisulphite is used for the purification of aldehydes and ketones. (iii) Carboxylic acids do not give characteristic reactions of carbonyl group.
Complete the following reactions:
(a) Explain why: (i) Carboxyl group in benzoic acid is meta directing. (ii) Sodium bisulphite is used for the purification of aldehydes and ketones. (iii) Carboxylic acids do not give characteristic reactions of carbonyl group. OR (b) A compound with molecular formula C₃H₈O on reaction with Cu at 573 K gives a compound B. B gives positive Fehling test and also reacts with iodine and NaOH solution. B does not give iodoform test but C precipitates. Identify A to D.
(a) Explain why: (i) Carboxyl group in benzoic acid is meta directing. (ii) Sodium bisulphite is used for the purification of aldehydes and ketones. (iii) Carboxylic acids do not give characteristic reactions of carbonyl group. OR (b) Give chemical equation for the following reactions: (i) Propanone is treated with dil. Ba(OH)2. (ii) Acetophenone is treated with Zn(Hg)/Conc. HCl. (iii) Benzoyl chloride is hydrogenated in presence of Pd-BaSO4.
Write the equation of the reaction for the preparation of phenol from cumene.
How will you carry out the following conversions (Any two): (i) Propanal to Propane (ii) Ethanal to But-2-enal (iii) Ethanoic acid to ethanamide
Write the equation involved in the following reactions: (i) Rosenmund reduction (ii) Etard reaction (iii) Stephen reaction
Write the equations involved in the following reactions : (i) Cannizzaro reaction (ii) Aldol condensation (iii) Hell-Volhard-Zelinsky reaction
Arrange the following compounds in increasing order of their reactivity towards HCN: CH3CHO, CH3CH2CHO, CH3-C(=O)-CH2-CH3, CH3-C(=O)-CH3
A compound gives yellow precipitate with Iodoform reaction and reacts with HCN to form a compound. On hydrolysis, products A and B are identified. Write equations for the reactions involved.
Give reasons for the following : (i) Oxidation of propanal is easier than propanone. (ii) There are two − NH2 groups in semicarbazide. However, only one − NH2 groups is involved in the formation of semicarbazones. (iii) HCHO does not undergo aldol condensation reaction. (iv) Boiling points of carboxylic acids are higher than those of alcohols of comparable molecular masses. (v) Aldehydes are more reactive towards nucleophilic addition reactions than ketones.
An organic compound (X) has the molecular formula C5H10O. Draw structures for (X) if it: (I) does not give Tollen's test but gives a positive iodoform test. (II) does not give Tollen's test and iodoform test but undergoes Aldol condensation. (III) undergoes Cannizzaro's reaction.
(a) (i) An organic compound (X) has the molecular formula C5H10O. Draw structures for (X) if it: (I) does not give Tollen's test but gives a positive iodoform test. (II) does not give Tollen's test and iodoform test but undergoes Aldol condensation. (III) undergoes Cannizzaro's reaction. (ii) Show how each of the following compounds can be converted to benzoic acid: (I) Acetophenone (II) Ethyl benzene
How will you convert the following: (i) Propanone to Propene (ii) Benzoic acid to Benzaldehyde (iii) Benzene to m-Nitroacetophenone. Arrange the following compounds in increasing order of their reactivity towards HCN. Identify the compounds, which would undergo Aldol condensation.
(a) How will you convert the following : (i) Propanone to Propene (ii) Benzoic acid to Benzaldehyde (iii) Benzene to m-Nitroacetophenone (b) (i) Arrange the following compounds in increasing order of their reactivity towards HCN : CH3 CH3 C = O, (CH3)3 C (CH3)3 C C = O, CH3 H C = O (ii) Identify the compounds, which would undergo Aldol condensation : HCHO, C 6H5CHO, CH3CHO
(a) How will you convert the following: (i) Propanone to Propene (ii) Benzoic acid to Benzaldehyde (iii) Benzene to m-Nitroacetophenone (b) (i) Arrange the following compounds in increasing order of their reactivity towards HCN: (CH3)2C=O, [(CH3)3C]2C=O, CH3CH2CHO (ii) Identify the compounds, which would undergo Aldol condensation: HCHO, C6H5CHO, CH3CHO, (CH3)3CCHO
Write the product(s) when: (I) One mol of ethanal is treated with 1 mol of CH3OH in the presence of dry HCl gas. (II) Benzaldehyde is treated with conc. NaOH. (III) Ethanoic acid is heated in the presence of P2O5. Write a simple chemical test to distinguish between Ethanal and Propanal. Write the name of the reagent to transform Allyl alcohol to Propenal.
(a) (i) Write the product(s) when: (I) One mol of ethanal is treated with 1 mol of CH3OH in the presence of dry HCl gas. (II) Benzaldehyde is treated with conc. NaOH. (III) Ethanoic acid is heated in the presence of P2O5.
(a) Write the product(s) when: (I) One mol of ethanal is treated with 1 mol of CH3OH in the presence of dry HCl gas. (II) Benzaldehyde is treated with conc. NaOH. (III) Ethanoic acid is heated in the presence of P2O5. (ii) Write a simple chemical test to distinguish between Ethanal and Propanal. (iii) Write the name of the reagent to transform Allyl alcohol to Propenal.
(a)(i) How will you bring about the following conversions: (I) Bromobenzene to 1-phenylethanol (II) Benzene to m-nitroacetophenone (ii) An organic compound with the molecular formula C8H8O forms 2,4-DNP derivative, reduces Tollens' reagent and undergoes Cannizzaro reaction. On vigorous oxidation with acidic or alkaline KMnO4 it gives Benzene-1,2-dicarboxylic acid. Identify the compound and write the products when it undergoes Cannizzaro reaction. (iii) Arrange the following compounds in increasing order of their acid strength: C6H5COOH, O2N–CH2–COOH, CF3–COOH, HCOOH
(A) (a) 'A' and 'B' are two functional isomers of compound C4H8O. On heating with NaOH and I2, isomer 'B' forms yellow precipitate of iodoform whereas isomer 'A' does not form any precipitate. (i) Identify 'A' and 'B'. (ii) What happens when isomer 'A' is treated with Zn(Hg) in the presence of Conc. HCl ? (iii) Write the reaction of isomer 'B' with NaOH and I2. (b) Arrange the following in the increasing order of their property as indicated : (i) Ethanol, Ethanoic acid, Ethanal (boiling point). (ii) Ethanal, Methanal, acetone (reactivity towards addition of HCN).
(a) (i) Identify A, B and C in the following reactions: (with structural formulas shown) (ii) Give reasons for the following: (I) Carboxylic acids do not give the characteristic reactions of carbonyl group. (II) Ethanoic acid is a stronger acid than ethanol.
Identify A, B and C in the following reactions: CH3COO⁻ + CrO3 (with K2Cr2O7, H⁺, heat, 273 K, 28 bar) → A + 3H2O → B → C
An organic compound (X) having molecular formula C5H10O can show various properties depending on its structures. Draw each of the structures if it: (I) shows Cannizzaro reaction. (II) reduces Tollens' reagent and has a chiral carbon. (III) gives positive iodoform test. Write the reaction involved in the following: (I) Clemmensen reduction (II) Etard reaction
An organic compound (X) having molecular formula C5H10O can show various properties depending on its structures. Draw each of the structures if it shows Cannizzaro reaction.
(a) (i) An organic compound (X) having molecular formula C5H10O can show various properties depending on its structures. Draw each of the structures if it: (I) shows Cannizzaro reaction. (II) reduces Tollens' reagent and has a chiral carbon. (III) gives positive iodoform test. (ii) Write the reaction involved in the following: (I) Clemmensen reduction (II) Etard reaction
Write the major product(s) in the following reactions:
(a) (i) Carry out the following conversions: (1) Ethanal to But-2-en-1-al (2) Propanoic acid to 2-chloropropanoic acid (ii) An alkene with molecular formula C5H10 on ozonolysis gives compounds A and B. Compound A gives positive Fehling test and also reacts with iodine and NaOH solution. Compound B gives Fehling test but forms iodoform on reaction with I2 and NaOH solution. Identify A, B and the original alkene.
(a) (i) Carry out the following conversions: (1) Ethanal to But-2-en-1-al (2) Propanoic acid to 2-chloropropanoic acid (ii) An alkene with molecular formula C₅H₁₀ on ozonolysis gives a mixture of two compounds. A gives positive Fehling test and also reacts with iodine and NaOH. B does not give Fehling test but forms an iodoform precipitate. Identify A, B and the alkene. OR (b) (i) Distinguish with a suitable chemical test: (1) CH₃COCH₂CH₃ and CH₃CH₂CH₂CHO (2) Ethanal and Ethanoic acid (ii) Write the structure of oxime of acetone. (iii) Identify A to D: CH₃COOH →(PCl₅) A →(4BaSO₄, Pd/H₂) B →(MgBr/ether) C →(LiAlH₄) D
(a) (i) Carry out the following conversions: (1) Ethanal to But-2-en-1-al (2) Propanoic acid to 2-chloropropanoic acid (ii) An alkene with molecular formula C5H10 on ozonolysis gives positive Fehling test and also reacts with iodine and NaOH forms iodoform. Identify the compounds. OR (b) (i) Distinguish with a suitable chemical test: (1) CH3COCH2CH3 and CH3CH2CH2CHO (2) Ethanal and Ethanoic acid (ii) Write the structure of oxime of acetone. (iii) Identify A to D: CH3COOH →(PCl5) A →(BaSO4/Pd/H2) B →(MgBr/CH3I) C →(LiAlH4) D (then H3O+)
(a) (i) An organic compound (X) having molecular formula C5H10O can show various properties depending on its structures. Draw each of the structures if it (1) gives positive iodoform test. (2) shows Cannizzaro reaction. (3) reduces Tollens reagent and has a chiral carbon. (ii) Write the reaction involved in the following: (1) Wolff-Kishner reduction (2) Hell-Volhard-Zelinsky reaction
An organic compound (X) having molecular formula C₅H₁₀O can show various properties depending on its structures. Draw each of the structures if it (1) gives positive iodoform test (2) shows Cannizzaro reaction (3) has a chiral carbon.
(a) Draw structure of the 2,4-dinitrophenylhydrazone of benzaldehyde.
(a) (i) Write the reaction involved in Cannizaro's reaction. (ii) Why are the boiling point of aldehydes and ketones lower than that of corresponding carboxylic acids? (iii) An organic compound 'A' with molecular formula C5H8O2 is reduced to n-pentane with hydrazine followed by heating with NaOH and Glycol. 'A' forms a dioxime with hydroxylamine and gives a positive Iodoform and Tollen's test. Identify 'A' and give its reaction for Iodoform and Tollen's test.
Case study · CBSE 2023
The carbon–oxygen double bond is polarised in aldehydes and ketones due to higher electronegativity of oxygen relative to carbon. Therefore they undergo nucleophilic addition reactions with a number of nucleophiles such as HCN, NaHSO3, alcohols, ammonia derivatives and Grignard reagents. Aldehydes are easily oxidised by mild oxidising agents as compared to ketones. The carbonyl group of carboxylic acid does not give reactions of aldehydes and ketones. Carboxylic acids are considerably more acidic than alcohols and most of simple phenols.
Write the name of the product when an aldehyde reacts with excess alcohol in presence of dry HCl.
The reaction of ammonia with a large excess of ethyl chloride will give mainly :
Acetamide reacts with Br2 and aqueous KOH to form :
Assertion (A) : Boiling point of propylamine is higher than that of trimethylamine. Reason (R) : In propylamine, intermolecular hydrogen bonding occurs, whereas trimethylamine does not undergo intermolecular hydrogen bonding.
Aniline on direct nitration yields
Benzene diazonium chloride on reaction with phenol in weakly basic medium gives
CH3 – NH2 on reaction with (CH3CO)2O gives
Identify the compound produced by the reduction of Ethanenitrile with Lithium aluminium hydride:
Assertion (A): Aromatic primary amines can be prepared by Gabriel Phthalimide synthesis. Reason (R): Aryl halides do not undergo nucleophilic substitution with the anion formed by phthalimide.
Which of the following reagent is used to distinguish between (C2H5)2NH and (C2H5)3N?
Assertion (A): Aromatic primary amines cannot be prepared by Gabriel phthalimide synthesis. Reason (R): Gabriel phthalimide synthesis is used for the preparation of primary aliphatic amines.
Which reagent is used to distinguish between C2H5NH2 and (C2H5)2NH ?
Assertion (A): Aromatic primary amines can easily be prepared by Gabriel phthalimide synthesis. Reason (R): Gabriel phthalimide synthesis is used to prepare only aliphatic primary amines.
Which reagent is used to distinguish between primary, secondary and tertiary amines ?
The correct order of decreasing basic strength in aqueous solution of the following is :
Assertion (A): Monobromination of aniline can be conveniently done by protecting the amino group by acetylation. Reason (R): Acetylation increases the activation effect of the amino group.
The correct order of decreasing basicities of C2H5NH2, (C2H5)2NH and (C2H5)3N in aqueous solution is:
In the reaction of NaOBr with amide, the carbonyl carbon is lost as:
Assertion (A): Diazonium salts of aromatic amines are more stable than those of aliphatic amines. Reason (R): Diazonium salts of aliphatic amines undergo resonance.
The correct order of decreasing basic strength of CH3 − NH2, (CH3)2NH and (CH3)3N in aqueous solution is :
Which of the following reagent is used to convert benzene diazonium chloride to benzene ?
Assertion (A): Diazonium salts of aromatic amines are more stable than those of aliphatic amines. Reason (R): Diazonium salts of aromatic amines undergo resonance.
The correct order of decreasing order of pKb values is:
Assertion (A): Diazonium salts of aromatic amines are less stable than those of aliphatic amines. Reason (R): Diazonium salts of aromatic amines undergo resonance.
Which of the following reagents are used to prepare primary amines by Hoffmann bromamide degradation reaction ? (i) R-CO-NH2 (ii) NaOH (iii) Br2 (iv) CHCl3
The major product of carbylamine reaction is :
The correct formula of Hinsberg's reagent is :
Consider the following compounds : C2H5NH2, (C2H5)2NH, C6H5CH2NH2, NH3, C6H5NH2. The correct increasing order of the above compounds on the basis of their basic strength is :
The Gabriel Phthalimide Synthesis is used for the preparation of
Hoffmann Bromamide degradation reaction is given by:
Assertion (A): Acetanilide is less basic than aniline. Reason (R): Acetylation of aniline results in decrease of electron density on nitrogen.
Assertion (A): Acetanilide is more basic than aniline. Reason (R): Acetylation of aniline results in decrease of electron density on nitrogen.
The IUPAC name for CH3 – CH2 – N(CH3) – CH2 – CH2 – CH3 is:
In the Hinsberg's method for separation of primary, secondary and tertiary amines, the reagent used is :
Which one of the following amines gives an alcohol on reaction with HNO2 ?
Assertion(A): Boiling point of (CH3)3N is higher than that of CH3CH2CH2NH2. Reason (R) : Hydrogen bonding is more extensive in CH3CH2CH2NH2.
The reagent that can be used to convert benzenediazonium chloride to benzene is:
The gas evolved when methylamine reacts with HNO2 is:
Assertion (A): Boiling point of (C2H5)2NH is lower than that of n-C4H9NH2. Reason (R): Hydrogen bonding is much more extensive in n-C4H9NH2 as compared to (C2H5)2NH.
The reagent that can be used to convert benzenediazonium chloride to benzonitrile is:
The strongest base in aqueous solution among the following amines is:
Assertion (A): Boiling point of (C2H5)2NH is lower than that of n-C4H9NH2. Reason (R): Hydrogen bonding is much more extensive in (C2H5)2NH as compared to n-C4H9NH2.
When alkyl iodide is treated with large excess of ammonia, the major product obtained is :
An amine 'X' reacts with Hinsberg reagent and the product obtained is soluble in alkali. The amine 'X' is :
When excess of alkyl iodide is treated with ammonia, the product obtained is :
An amine 'X' reacts with Hinsberg reagent and the product obtained is insoluble in alkali. The amine 'X' is :
Anilinium hydrogen sulphate on heating at 453 – 473 K produces which of the following as a major product?
Which of the following amines does not give foul smell of isocyanide on heating with chloroform and ethanolic KOH?
Assertion (A): Aniline is a stronger base than ammonia. Reason (R): The unshared electron pair on nitrogen atom in aniline becomes less available for protonation due to resonance.
Assertion (A): p-nitroaniline is a weaker base than p-toluidine. Reason (R): The electron donating NO2 group in p-nitroaniline makes it a weaker base.
Assertion (A): Aliphatic primary amines can be prepared by Gabriel phthalimide synthesis. Reason (R): Alkyl halides undergo nucleophilic substitution with anion formed by phthalimide.
Assertion (A): Diazonium salts of aromatic amines are more stable than those of aliphatic amines. Reason (R): Diazonium salts of aliphatic amines show resonance.
Assertion (A): Aromatic primary amines can be prepared by Gabriel phthalimide synthesis. Reason (R): Alkyl halide undergoes nucleophilic substitution with anion formed by phthalimide.
Assertion (A): Diazonium salts of aliphatic amines are more stable than those of aromatic amines. Reason (R): Diazonium salts of aromatic amines show resonance.
Assertion (A): Acetanilide is less basic than aniline. Reason (R): Acetylation of aniline results in decrease of electron density on nitrogen in acetanilide.
Butanenitrile may be prepared by heating:
Assertion (A): Aniline is a weaker base than cyclohexylamine. Reason (R): Aniline is resonance stabilized. Select the correct answer.
Assertion (A): Ammonolysis of alkyl halides involves reaction between alkyl halide and ethanolic solution of ammonia. Reason (R): Ammonolysis of alkyl halides mainly produces secondary amines. Select the correct answer.
Assertion (A): Aniline does not undergo Friedel-Crafts reaction. Reason (R): Friedel-Crafts reaction is a nucleophilic substitution reaction. Select the correct answer.
Which of the following compounds on treatment with benzene sulphonyl choride forms an alkali-soluble precipitate ?
The order of increasing basicities of CH3NH2 (I), (CH3)2NH (II), (CH3)3N (III) and C6H5NH2 (IV) in aqueous media is :
Assertion (A): Aniline does not undergo Friedel-Crafts reaction. Reason (R): Friedel-Crafts reaction is an electrophilic substitution reaction.
Which of the following compounds on treatment with benzene sulphonyl chloride forms product insoluble in alkali?
Which of the following amines gives carbylamine reaction?
Assertion (A): Aniline undergoes Friedel-Crafts reaction. Reason (R): Aniline forms salt with AlCl3, the Lewis acid in Friedel-Crafts reaction.
Aniline on reaction with Bromine water gives:
CH3CONH2 on reaction with NaOH and Br2 in alcoholic medium gives:
Which of the following is least basic?
Assertion (A): (C₂H₅)₂NH is more basic than (C₂H₅)₃N in aqueous solution. Reason (R): In (C₂H₅)₂NH, there is more steric hindrance and +I effect than (C₂H₅)₃N.
Assertion (A): Acetylation of aniline gives a monosubstituted product. Reason (R): Activating effect of −NHCOCH₃ group is more than that of amino group.
Assertion (A): Ammonolysis of alkyl halides is not a suitable method for the preparation of pure primary amines. Reason (R): Ammonolysis of alkyl halides yields mainly secondary amines.
Among the following, which is the strongest base?
When Benzene diazonium chloride reacts with phenol, it forms a dye. This reaction is called
The reaction of ammonia with a large excess of methyl chloride will yield mainly:
The reduction of ethanenitrile with sodium and alcohol gives:
The action of nitrous acid on ethylamine gives mainly:
Assertion (A): Monobromination of aniline can be conveniently done by protecting the amino group by acetylation. Reason (R): Acetylation decreases the activating effect of the amino group.
Amides can be converted into amines by the reaction named
Which of the following would not be a good choice for reducing nitrobenzene to aniline?
In the reaction C6H5NH2 + CHCl3 + 3 KOH → A + 3B + 3C the product A is
(a) How do you convert the following ? (i) Ethanenitrile to Ethanamine (ii) Benzenediazonium chloride to benzonitrile OR (b) (i) Write a simple chemical test to distinguish between ethanamine and dimethylamine. (ii) What happens when CH3CONH2 is heated with Br2 and an aqueous solution of NaOH ?
Explain briefly: (a) Carbylamine reaction (b) Gabriel phthalimide synthesis
(a) CH₃−CH−CH₃ →(PCl₅) A →(AgCN) compound with useful applications | OH (b) CH₃CH₂CH₂Cl + KOH →(ethanol) B →(HBr) C Identify A, B and C in the above reactions.
Write the chemical equation involved in the following reactions: (a) Carbylamine reaction (b) Gabriel phthalimide synthesis
Write the chemical equation involved in the following reactions: (a) Carbylamine reaction
(a) (i) Draw the zwitter ion structure for sulphanilic acid. (ii) How can the activating effect of –NH2 group in aniline be controlled?
(a)(i) Draw the zwitter ion structure for sulphanilic acid.
Explain the following : (a) Carbylamine reaction (b) Hoffmann's bromamide degradation reaction (c) Diazotisation reaction
How will you obtain the following from benzenediazonium chloride? Give chemical equations involved: (a) Chlorobenzene (b) Benzene (c) Benzonitrile
How will you obtain the following from aniline ? Write the chemical equations involved: (a) Sulphanilic acid (b) 2,4,6-Tribromoaniline (c) Acetanilide
Give reactions for the following : (i) Aniline does not undergo Friedel–Crafts reaction. (ii) (CH3)2NH is more basic than (CH3)3N in an aqueous solution. (iii) Ethyl amine is soluble in water whereas aniline is insoluble.
Arrange the following compounds as asked: (a) in decreasing order of pKb values: C2H5NH2, (C2H5)2NH, C6H5NHCH3, C6H5NH2 (b) in increasing order of boiling point: C2H5OH, C2H5NH2, (CH3)2NH (c) in increasing order of solubility in water: C6H5NH2, (C2H5)2NH, C2H5NH2
Arrange the following compounds as asked: (a) in increasing order of pKb values: C2H5NH2, (C2H5)2NH, C6H5NHCH3, C6H5NH2. (b) in decreasing order of boiling point: C2H5OH, C2H5NH2, (CH3)2NH. (c) in decreasing order of solubility in water: C6H5NH2, (C2H5)2NH, C2H5NH2.
Identify P, Q and R in the following reaction sequence: P + NH3 → CH3COO– NH4+ + Q → R + PCl5
How will you obtain the following from aniline ? Give chemical equations only. (a) Sulphanilic acid (b) Phenylisocyanide (c) Acetanilide
How can you obtain the following from aniline? Give only chemical equation. (a) p-nitroaniline (b) Chlorobenzene (c) Phenol
How can you obtain the following? (a) Aniline from ammonium benzoate (b) Benzene diazonium chloride from nitrobenzene (c) 2,4,6-tribromoaniline from aniline
Write the structures of A, B and C in the following reactions: (a) CH3–CH2–Br → (KCN hydrolysis) A → (NaOH) B + Br → C (b) C6H5–NH2 + Fe/HCl → A (2NaNO2 + HCl) B (C2H5OH) C
Write the structures of A, B and C in the following reactions: (a) CH₃-CH₂-Br → (KCN, partial hydrolysis) → A → (2 NaOH) → B + Br⁻ → C
Write the structures of A, B and C in the following reactions: (i) C₆H₅NH₂ + CO + COCl₂ → A + NaOH → B + Br₂ → C + HCl + NaNO₂ → product
(a) Illustrate Sandmeyer's reaction with an equation.
(a) Illustrate Sandmeyer's reaction with an equation. (b) Explain, why (CH3)2NH is more basic than (CH3)3N in aqueous solution.
(i) Why is oxidation of propanal easier than propanone? (ii) How can you distinguish between Acetophenone and Benzophenone? (iii) Draw the structure of 2,4-Dinitrophenylhydrazone of Propanone
Write reasons for the following: (i) Ethylamine is soluble in water whereas aniline is insoluble. (ii) Amino group is o- and p-directing in aromatic electrophilic substitution reactions, but aniline on nitration gives a substantial amount of m-nitroaniline. (iii) Amines behave as nucleophiles.
(a) Write equations involved in the following reactions: (i) Ethanamine reacts with acetyl chloride. (ii) Aniline reacts with bromine water at room temperature. (iii) Aniline reacts with chloroform and ethanolic potassium hydroxide.
(a)(i) In a chemistry practical class, the teacher gave his students an amine 'X' having molecular formula C2H7N, and asked the students to identify the type of amine. One of the students, Neeta, observed that it reacts with C6H5SO2Cl, to give a compound which dissolves in NaOH solution. Can you help Neeta to identify the compound 'X'?
In a chemistry practical class, the teacher gave his students an amine 'X' having molecular formula C2H7N, and asked the students to identify the type of amine. One of the students, Neeta, observed that it reacts with C6H5SO2Cl, to give a compound which dissolves in NaOH solution. Can you help Neeta to identify the compound 'X'? Arrange the following in the increasing order of their pKb value in aqueous phase: C6H5NH2, (CH3)2NH, NH3, CH3NH2, (CH3)3N. Aniline on nitration gives considerable amount of meta product along with ortho and para products. Why? Convert aniline to: (I) p-bromoaniline, (II) phenol
(a) N,N-diethyl-benzenesulphonamide is insoluble in alkali. Give reason.
Give reasons: (i) Aniline on nitration gives good amount of m-nitroaniline, though –NH2 group is o/p directing in electrophilic substitution reactions. (ii) (CH3)2NH is more basic than (CH3)3N in an aqueous solution. (iii) Ammonolysis of alkyl halides is not a good method to prepare pure primary amines. (iv) Write the reaction involved in the following: (a) Carbyl amine test (b) Gabriel phthalimide synthesis
Give reasons: (i) Aniline on nitration gives good amount of m-nitroaniline, though – NH2 group is o/p directing in electrophilic substitution reactions. (ii) (CH3)2 NH is more basic than (CH3)3N in an aqueous solution. (iii) Ammonolysis of alkyl halides is not a good method to prepare pure primary amines. Write the reaction involved in the following: (i) Carbyl amine test (ii) Gabriel phthalimide synthesis
(I) Give reasons: (i) Aniline on nitration gives good amount of m-nitroaniline, though –NH2 group is o/p directing in electrophilic substitution reactions. (ii) (CH3)2NH is more basic than (CH3)3N in an aqueous solution. (iii) Ammonolysis of alkyl halides is not a good method to prepare pure primary amines. (II) Write the reaction involved in the following: (i) Carbyl amine test (ii) Gabriel phthalimide synthesis
Case study · CBSE 2026
The reaction of amines with mineral acids to form ammonium salts shows that these are basic in nature. Aliphatic amines are stronger bases than ammonia whereas aromatic amines are weaker bases than ammonia. Aliphatic and aromatic primary and secondary amines react with acid chlorides, anhydrides and esters by nucleophilic substitution reaction. The main problem encountered during electrophilic substitution reactions of aromatic amines is that of their high reactivity. Substitution tends to occur at ortho-and para-positions. Hinsberg reagent is used for the identification and distinction between primary, secondary and tertiary amines. Aryldiazonium salts, usually obtained from arylamines, undergo replacement of the diazonium group with a variety of nucleophiles to provide advantageous methods for producing aryl halides, cyanides, phenols and arenes.
Why CH3 – NH2 is a stronger base than (CH3)3N in aqueous solution?
(a) (i) Why is CH3–NH2 a stronger base than (CH3)3N in aqueous solution? (2 marks) (ii) Write structural formulae of the compound A and B: CH3CONH2 →(NaOBr) A →(C6H5COCl Base) B
Case study · CBSE 2026
Like NH3, nitrogen atom of amine is trivalent and carries an unshared pair of electrons. Nitrogen orbitals in amines are therefore sp3 hybridised and the geometry of amines is pyramidal. Lower aliphatic amines are soluble in water due to the formation of hydrogen bond with water molecules. The solubility decreases as the molar mass of amines increases due to increase in size of hydrophobic part. Higher amines are insoluble in water. However amines are less soluble in water than alcohols because of low electronegativity of nitrogen as compared to oxygen. Boiling points of isomeric amines follow the order 1º > 2º > 3º. It is due to the fact the amines are held together due to hydrogen bonding. Extent of hydrogen bonding is more in primary amines than in secondary amines as two hydrogen atoms are available for hydrogen bond formation. Tertiary amines do not show hydrogen bonding because of the absence of hydrogen atom attached to nitrogen. Amines can be prepared from, nitro compounds, nitriles, amides etc.
(a) Complete the following equations: (i) CH 3CONH2 (i) LiAlH4(ii) H2O (ii) (NO2-benzene) Fe + HCl
Case study · CBSE 2025
Amines are usually formed from amides, imides, halides, nitro compounds, etc. They exhibit hydrogen bonding which influences their physical properties. In alkyl amines, a combination of electron releasing, steric and H-bonding factors influence the stability of the substituted ammonium cations in protic polar solvents and thus affect the basic nature of amines. Alkyl amines are found to be stronger bases than ammonia. Amines being basic in nature, react with acids to form salts. Aryldiazonium salts, undergo replacement of the diazonium group with a variety of nucleophiles to produce aryl halides, cyanides, phenols and arenes.
How can you convert the following? (i) Ethanoic acid to methanamine (ii) Propanenitrile to 1-aminopropane
Case study · CBSE 2023
Amines are usually formed from nitro compounds, halides, amides, imides, etc. They exhibit hydrogen bonding which influences their physical properties. In alkyl amines, a combination of electron releasing, steric and hydrogen bonding factors influence the stability of the substituted ammonium cations in protic polar solvents and thus affect the basic nature of amines. In aromatic amines, electron releasing and withdrawing groups, respectively increase and decrease their basic character. Influence of the number of hydrogen atoms at nitrogen atom on the type of reactions and nature of products is responsible for identification and distinction between primary, secondary and tertiary amines. Presence of amino group in aromatic ring enhances reactivity of the aromatic amines. Aryl diazonium salts provide advantageous methods for producing aryl halides, cyanides, phenols and arenes by reductive removal of the diazo group.
(i) Arrange the following in the increasing order of their pKb values in aqueous solution: C2H5NH2, (C2H5)2NH, (C2H5)3N
Case study · CBSE 2022
Amines constitute an important class of organic compounds derived by replacing one or more hydrogen atoms of ammonia molecule by alkyl/aryl groups. Amines are usually formed from nitro compounds, halides, amides, etc. They exhibit hydrogen bonding which influences their physical properties. Alkyl amines are found to be stronger bases than ammonia. In aromatic amines, electron releasing and withdrawing groups, respectively increase and decrease their basic character. Reactions of amines are governed by availability of the unshared pair of electrons on nitrogen. Influence of the number of hydrogen atoms at nitrogen atom on the type of reactions and nature of products is responsible for identification and distinction between primary, secondary and tertiary amines. Reactivity of aromatic amines can be controlled by acylation process.
Why does aniline not give Friedel-Crafts reaction?
Vitamin B12 is a complex compound of :
In the ring structure of fructose, the anomeric carbon is :
The deficiency of which of the following vitamins causes increased fragility of red blood cells and muscular weakness:
Assertion (A): The pentaacetate of glucose does not react with H2N – OH. Reason (R): It indicates the presence of free – CHO group in glucose.
An example of non-reducing sugar is
Assertion (A): The two strands of DNA are complementary to each other. Reason (R): The hydrogen bonds are formed between specific pairs of bases.
Assertion (A) : The pentaacetate of glucose does not react with H2N – OH. Reason (R) : It indicates the absence of free –CHO group in glucose.
The base which is present in DNA but not in RNA is:
Proteins are polymers of α-amino acids which are joined to each other by:
Which of the following reactions is not explained by the open chain structure of glucose?
Assertion (A): Glucose gets oxidized to six carbon gluconic acid on reaction with bromine water. Reason (R): The carbonyl group is absent in the open chain structure of glucose.
Nucleic acids are polymers of:
Which of the following is a water-soluble vitamin ?
Each polypeptide in a protein has amino acids linked with each other in a specific sequence and it is this sequence of amino acids that is said to be:
Identify the polysaccharide among the following :
The polypeptide chain in a protein has amino acids linked with each other in a specific sequence. This specific sequence of amino acids is called :
Assertion (A) : D (+) – Glucose is dextrorotatory in nature. Reason (R) : (+) represents dextrorotatory nature and D represents the configuration.
Which of the following is a polysaccharide ?
Pyranose ring of glucose is formed due to the reaction between :
Furanose ring of fructose is formed due to reaction between:
α-D-glucose and β-D-glucose differ from each other with respect to the:
α-helix structure refers to :
Assertion (A): Vitamin K can be stored in our body. Reason (R): Vitamin K is a water soluble vitamin.
'Scurvy' is caused due to the deficiency of :
Assertion (A): Maltose is a reducing sugar. Reason (R): One of the two glucose units can open to expose free aldehydic group in solution.
Deficiency of vitamin B1 causes the disease:
Assertion (A): Vitamin C cannot be stored in our body. Reason (R): Vitamin C is water soluble and excreted in urine.
Two among the three components of DNA are-D-2-deoxyribose and a heterocyclic base. The third component is:
Nucleotides are composed of a:
The specific sequence in which amino acids are arranged in a protein is called:
Maltose is made up of:
All proteins on hydrolysis give:
Assertion (A): Uracil base is present in DNA. Reason (R): DNA undergoes self-replication.
Assertion (A): Uracil base is present in RNA. Reason (R): RNA undergoes self-replication.
Assertion (A): Vitamin C cannot be stored in our body. Reason (R): Vitamin C is water soluble and readily excreted in urine. Select the correct answer.
The vitamin which plays an important role in coagulating blood is :
The glycosidic linkage involved in linking the glucose units in amylase part of starch is:
An α-helix is a structural feature of:
Which of the following is a non-reducing sugar?
Proteins are polymers of
When D-glucose reacts with HI, it forms
Which of the following is not true about enantiomers?
On hydrolysis, which of the following carbohydrates gives only glucose?
Which of the following vitamins is water soluble?
Helical structure of proteins is stabilized by:
A vitamin which plays a vital role in the clotting of blood is:
In the ring structure of glucose, the anomeric carbon is:
Deficiency of Vitamin B causes:
Deficiency of which of the following vitamins causes Pernicious anaemia?
On hydrolysis, which of the following carbohydrates gives glucose and fructose?
The deficiency of which of the following vitamins causes Scurvy?
On hydrolysis, which of the following carbohydrates gives glucose and galactose?
The deficiency of which of the following vitamin causes rickets?
Hydrolysis of sucrose is called
Assertion (A): Proteins are polymers of α-amino acids connected by a peptide bond. Reason (R): A tetrapeptide contains 4 amino acids linked by 4 peptide bonds.
Which of the following statements is not true about glucose?
Assertion (A): Vitamin C cannot be stored in our body. Reason (R): Vitamin C is fat soluble and is excreted from the body in urine.
β-pleated sheet structure in proteins refers to
Assertion (A): The backbone of DNA and RNA molecules is a chain consisting of heterocyclic base, pentose sugar and phosphate group. Reason (R): Nucleotides and nucleosides mainly differ from each other in presence of phosphate group.
What are essential amino acids ? How do you explain the amphoteric behaviour of amino acids ?
Differentiate between the following: (i) Peptide linkage and Glycosidic linkage (ii) Essential amino acids and Non-essential amino acids
Differentiate between the following: (i) Acidic amino acids and basic amino acids (ii) Nucleotide and Nucleoside
Differentiate between the following : (i) Fibrous protein and Globular protein (ii) Peptide linkage and Phosphodiester linkage
How do you explain the following? (a) Presence of a straight chain in glucose (b) Presence of five − OH groups in glucose which are attached to different carbon atoms
How do you explain the following ? (a) Presence of a carbonyl group in glucose (b) Presence of five – OH groups in glucose
How do you explain the following? (a) Presence of an aldehyde group in glucose (b) Presence of a primary alcoholic group in glucose
What are the hydrolysis products of the following? (a) Lactose (b) DNA containing Thymine
Name the sugar present in sugarcane. What are the hydrolysis products of this sugar? Is this sugar a reducing sugar?
What is the effect of denaturation on the structure of proteins? What are the common types of secondary structures of proteins?
(a) What are the products obtained on hydrolysis of sucrose ? (b) What are essential amino acids ?
(a) Write any two fat soluble vitamins. (b) How will you confirm the presence of five – OH groups in a glucose molecule, which are attached to different carbon atoms ?
(a) Write the hydrolysis products of lactose. (b) What are non-essential amino acids ?
(a) Name two water-soluble vitamins. (b) How will you prove the absence of free –CHO group in the cyclic structure of glucose molecule ?
(a) Name the disease caused by the deficiency of Vitamin A. (b) How will you confirm the presence of carbonyl group as an aldehydic group in glucose?
What is the effect of denaturation on the structures of protein ? Give one example each of fibrous protein and globular protein.
What is meant by essential amino acids? Why are amino acids amphoteric in nature?
How do you explain the following ? (a) Presence of an aldehydic group in glucose. (b) Presence of five – OH groups in glucose.
The two strands in DNA are not identical but complementary. Explain. What products would be formed when DNA is hydrolysed ?
Write two differences between Amylose and Amylopectin components of starch.
What happens when D-glucose is treated with the following reagents? (a) HI (b) Conc. HNO3
What happens when D-glucose is treated with the following reagents? (a) Br2 water (b) HCN
What happens when D-glucose is treated with the following reagents? (a) H2N-OH (b) (CH3CO)2O
Define the following terms: (a) Denaturation of protein (b) Invert sugar
Define the following terms: (a) Essential amino acids (b) Nucleotide
Define the following terms: (a) Peptide linkage (b) Essential amino acids
Give reaction of glucose with the following: (a) HCN
Write the reactions of glucose with: (a) H2N-OH (b) Br2 water
Write the reactions of glucose with: (a) HI (b) (CH₃CO)₂O
Answer the following: (a) Write chemical reaction to show that open structure of D-glucose contains the straight chain. (b) What type of linkage is responsible for the formation of protein?
Define denaturation of protein. What is the effect of denaturation on the structure of protein?
(a) Write chemical reaction to show that open structure of D-glucose contains the straight chain. (b) What type of linkage is responsible for the formation of protein?
Write two differences between DNA and RNA.
What is the difference between a nucleoside and nucleotide ?
What are nucleic acids? Why two strands in DNA are not identical but are complementary?
(a) (i) How are carbohydrates stored in animal body? Mention any one organ where they are present. (ii) What is the basic structural difference between starch and cellulose?
How are carbohydrates stored in animal body? Mention any one organ where they are present.
Give the reaction of glucose with hydrogen cyanide. Presence of which group is confirmed by this reaction?
Give the reaction of glucose with acetic anhydride. Presence of which group is confirmed by this reaction?
Give the reaction of heating glucose with hydroxylamine. Presence of which group is confirmed by this reaction?
Write the reactions of D-Glucose with the following: (a) HI (b) Br2 water (c) Conc. HNO3
Define the following terms: (a) Anomers (b) Invert sugar (c) Glycosidic linkage
How do you explain the presence of following in open structure of glucose ? (a) all the six carbon atoms are in a straight chain. (b) five –OH groups which are attached to different carbon atoms. (c) an aldehyde group.
Define the following term: (a) Reducing sugar (b) Differentiate between the following: (i) Fibrous proteins and globular proteins (ii) Nucleotide and nucleoside
(a) Define the following terms : (i) Denaturation as related to proteins (ii) Oligosaccharides (b) On the basis of structure differentiate between Amylose and Amylopectin.
(a) Define the following terms: (i) Invert Sugar (ii) Polysaccharides (b) On the basis of structure differentiate between fibrous and globular proteins.
(a) Name the type of linkage responsible for the formation of proteins from α-amino acids. (b) Write any two differences between DNA and RNA.
Name the vitamin whose deficiency causes pernicious anaemia. Write any two differences between globular and fibrous proteins.
Name the vitamin which is responsible for coagulation of blood.
Write the reaction of D-Glucose with the following: (a) HCN (b) Br2 water (c) (CH3CO)2O
Differentiate between : (a) Essential amino acids and Non-essential amino acids (b) Peptide linkage and Glycosidic linkage (c) Fibrous protein and Globular protein
Answer the following (any three): (a) What is peptide linkage? (b) What type of bonds hold a DNA double helix together? (c) Which one of the following is a polysaccharide? Sucrose, Glucose, Starch, Fructose (d) Give one example each for water-soluble vitamins and fat-soluble vitamins.
(a) What are the hydrolysis products of (i) Lactose, (ii) Maltose? (b) Give the basic structural difference between starch and cellulose.
(a) Write the product when D-glucose reacts with conc. HNO3. (b) Amino acids show amphoteric behaviour. Why? (c) Write one difference between α-helix and β-pleated structure of protein.
Write the structure of product when D-Glucose reacts with the following: (any three) (a) HI (b) Conc. HNO3 (c) Br2 water (d) HCN
Write the structure of product when D-Glucose reacts with the following: (any three) (a) HI
Give reasons for any 3 of the following observations: (a) Penta-acetate of glucose does not react with hydroxylamine. (b) Amino acids behave like salts. (c) Water soluble vitamins must be taken regularly in diet. (d) The two strands in DNA are complimentary to each other.
A compound on reduction gives 2-propanol. Iodoform reaction to give yellow precipitate and reacts with HCN to form 2-hydroxy-3-methylpropanoic acid. Identify the compound and write the equations for the reactions involved.
Case study · CBSE 2026
Carbohydrates are optically active polyhydroxy aldehydes or ketones or molecules that provide such units on hydrolysis. They are broadly classified into three groups : monosaccharides, oligosaccharides and polysaccharides. Monosaccharide units are held together by glycosidic linkages to form disaccharides or polysaccharides. Starch and cellulose are polysaccharides. Starch is a polymer of α-glucose and consists of two components : Amylose and Amylopectin. Amylose is water soluble, having 15 – 20% of starch, whereas Amylopectin is insoluble in water, having 80 – 85% starch. Chemically, amylose is a long unbranched chain of α-glucose units held together by C1 − C4 glycosidic linkage. Amylopectin is a branched chain of α-glucose units held together by C1 − C4 and C1 − C6 glycosidic linkages.
Write two differences between Amylose and Amylopectin.
Case study · CBSE 2026
Living systems are made up of various complex biomolecules like carbohydrates, proteins, nucleic acids, lipids, etc. Proteins and carbohydrates are essential constituents of our food. In addition, some simple molecules like vitamins and mineral salts also play an important role in the functions of organisms. All proteins are polymers of α-amino acids. Proteins can be classified into two types on the basis of their molecular shape — Fibrous and Globular proteins. Vitamins are accessory food factors required in the diet. They are classified as fat-soluble and water-soluble. Deficiency of vitamins leads to many diseases. Nucleic acids are the polymers of nucleotides which in turn consist of a base, a pentose sugar and phosphate moiety. There are two types of nucleic acids — DNA and RNA. Nucleic acids are responsible for the transfer of characters from parents to offsprings.
Write the name of basic building units of proteins and nucleic acids. How can you differentiate between Fibrous and Globular proteins on the basis of their structures?
Case study · CBSE 2026
Carbohydrates are optically active polyhydroxy aldehydes or ketones or the compounds which produce such units on hydrolysis. They have been broadly classified into three groups — monosaccharides, oligosaccharides and polysaccharides. The carbohydrates may also be classified as either reducing or non-reducing sugars. An important monosaccharide glucose is an aldohexose and is correctly named as D(+)–glucose. It was assigned the open structure on the basis of its reactions with HI, NH2OH, Br2 water, (CH3CO)2O and nitric acid. Despite having the –CHO group, glucose does not give Schiff's test and hydrogen sulphite addition product with NaHSO3. It was found that glucose forms a six-membered ring in which one of the –OH groups add to the –CHO group and form a cyclic hemiacetal structure.
(a) How do you explain the following? (i) Presence of a carbonyl group in glucose (ii) Presence of five –OH groups in glucose which are attached to different carbon atoms.
Case study · CBSE 2025
Carbohydrates are optically active polyhydroxy aldehydes or ketones or molecules which provide such units on hydrolysis. They are broadly classified into three groups – monosaccharides, oligosaccharides and polysaccharides. Monosaccharides are held together by glycosidic linkage to form disaccharides like sucrose, maltose. Another biomolecule : proteins are polymers of α-amino acids which are linked by peptide bonds. On the basis of number of amino group and carboxyl group, amino acids are classified as acidic, basic or neutral amino acids. Amino acids are amphoteric in nature.
(a) What is difference between glycosidic linkage and peptide linkage ? The pentacetate of glucose does not react with Hydroxyl amine. What does it indicate ?
Case study · CBSE 2025
Ribose and 2-deoxyribose have an important role in biology. Among the most important derivatives are those with phosphate groups attached at the 5 position. Mono-, di- and tri-phosphate forms are important, as well as 3-5 cyclic monophosphates. Purines and pyrimidines form an important class of compounds with ribose and deoxyribose. When these purine and pyrimidine derivatives are coupled to a ribose sugar, they are called nucleosides.
(a) What products would be formed when DNA is hydrolysed? How is DNA different from RNA with reference to a structure?
What products would be formed when DNA is hydrolysed? How is DNA different from RNA with reference to structure?
Case study · CBSE 2025
Carbohydrates are polyhydroxy aldehydes or ketones that represent enormous structural diversity in terms of the arrangement of atoms in space, resulting in hundreds of stereoisomers. Although the chemical properties of most stereoisomers may not be very different, their metabolic rate and utilization in biological systems is significantly different and known to influence the overall carbohydrate metabolism. Structural variants, which arise due to a different arrangement of atoms in three-dimensional space are known as stereoisomers. The number of stereoisomers can be theoretically estimated by using the formula 2n, where 'n' is the number of stereocenters or asymmetric (chiral) carbon atoms in a molecule. Out of these stereoisomers, there are some structures, which are mirror images of each other, and they are referred to as enantiomers.
(a) Give chemical reactions to show the presence of an aldehydic group and straight chain in glucose.
Case study · CBSE 2025
The α-amino acids are the building blocks of proteins. All α-amino acids exist as zwitter ion due to which they show amphoteric behaviour. All amino acids are joined through peptide bond. Proteins are broadly classified as globular proteins and fibrous proteins. Globular proteins are water soluble, whereas fibrous proteins are not. The complete structure of protein is discussed at four different levels i.e. primary, secondary, tertiary and quaternary structures. Protein loses its biological activity in denatured form.
(a) Define the following: (i) Peptide linkage (ii) Denatured protein
Case study · CBSE 2024
Carbohydrates are essential for life in both plants and animals. Carbohydrates are used as storage molecules as starch in plants and glycogen in animals. Chemically they are polyhydroxy aldehydes or ketones. On the basis of their behaviour on hydrolysis, carbohydrates are classified as monosaccharides, oligosaccharides and polysaccharides. All monosaccharides like glucose is aldohexose and its molecular formula was found to be C6H12O6. After reacting with different reagents like HI, H2N–OH, Bromine water, (CH3CO)2O, etc. its structure was found to contain one aldehyde group, one primary alcoholic group, (CH2OH) and four secondary alcoholic groups (CHOH). Despite having the aldehyde group, glucose does not give some of the reactions of aldehyde group like Schiff addition. This explains the existence of glucose in two cyclic hemiacetal forms which differ only in the configuration of the hydroxyl group at C1.
(a) What are reducing sugars?
Case study · CBSE 2024
Proteins are the most abundant biomolecules of the living system. Proteins are the polymers of about twenty different α-amino acids which are linked by peptide bonds. Ten amino acids are called essential amino acids. In zwitter ionic form, amino acids show amphoteric behaviour as they react both with acids and bases. On the basis of their molecular shape, proteins are classified into two types: Fibrous and Globular proteins. Structure and shape of proteins can be studied at four different levels i.e., primary, secondary, tertiary and quaternary, each level being more complex than the previous one. The secondary or tertiary structure of proteins get disturbed on change of pH or temperature and they are not able to perform their functions. This is called denaturation of proteins.
(a) What are essential amino acids ?
Case study · CBSE 2023
Carbohydrates are optically active polyhydroxy aldehydes and ketones. They are also called saccharides. All those carbohydrates which reduce Fehling's solution and Tollen's reagent are referred to as reducing sugars. Glucose, the most important source of energy for mammals, is obtained by the hydrolysis of starch. Vitamins are accessory food factors required in the diet. Proteins are the polymers of α-amino acids and perform various structural and dynamic functions in the organisms. Deficiency of vitamins leads to many diseases.
The penta-acetate of glucose does not react with Hydroxylamine. What does it indicate?
Case study · CBSE 2023
Living systems are made up of various complex biomolecules like carbohydrates, proteins, nucleic acids, lipids, etc. Carbohydrates are optically active polyhydroxy aldehydes or ketones or molecules which provide such units on hydrolysis. They are broadly classified into three groups — monosaccharides, oligosaccharides and polysaccharides. Monosaccharides are held together by glycosidic linkages to form disaccharides like sucrose, maltose or polysaccharides like starch and cellulose. Another biomolecule: proteins are polymers of α-amino acids which are linked by peptide bonds. Ten amino acids are called essential amino acids. Structure and shape of proteins can be studied at four different levels i.e. primary, secondary, tertiary and quaternary, each level being more complex than the previous one.
(i) What is the difference between a glycosidic linkage and peptide linkage?
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