**Aldehydes** contain the **carbonyl group (-CHO)** bonded to one carbon and one hydrogen, while **ketones** contain the carbonyl group bonded to two carbon atoms. Both are crucial in organic chemistry with widespread applications in medicines, perfumes, solvents, and food products.
**Common Names of Aldehydes:**
**Common Names of Ketones:**
**IUPAC Names of Aldehydes:**
**IUPAC Names of Ketones:**
**Hybridization and Bonding:**
**Polarity and Resonance:**
**Key Exam Point:** The planar sp² geometry of carbonyl carbon and its polarity are fundamental to understanding all subsequent nucleophilic addition reactions.
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**1. Oxidation of Alcohols:**
**2. Dehydrogenation of Alcohols:**
**3. From Hydrocarbons - Ozonolysis of Alkenes:**
**4. From Hydrocarbons - Hydration of Alkynes:**
**1. Rosenmund Reduction (From Acyl Chlorides):**
**2. Stephen Reaction (From Nitriles):**
**3. DIBAL-H Reduction (From Nitriles and Esters):**
**4. Etard Reaction (From Methylbenzene/Toluene):**
**5. Chromic Oxide Method (From Methylbenzene):**
**6. Side-Chain Chlorination Followed by Hydrolysis (From Toluene):**
**7. Gatterman-Koch Reaction (From Benzene/Substituted Benzenes):**
**1. Friedel-Crafts Acylation (From Benzene/Substituted Benzenes):**
**2. From Acyl Chlorides with Dialkylcadmium (Cadmium Method):**
**3. From Nitriles with Grignard Reagents:**
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**State of Matter at Room Temperature:**
**Boiling Points:**
**Comparative Boiling Point Table:**
| Compound | Molecular Mass | B.P. (K) |
|----------|---|---|
| n-Butane | 58 | 273 |
| Methoxyethane (diethyl ether) | 60 | 281 |
| Propanal | 58 | 322 |
| Acetone (propanone) | 58 | 329 |
| Propan-1-ol | 60 | 370 |
**Interpretation:** n-Butane < Methoxyethane < Propanal < Acetone < Propan-1-ol
**Solubility in Water:**
**Odor:**
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Both aldehydes and ketones possess the same functional group (carbonyl) and therefore undergo **very similar chemical reactions**. Key differences arise from steric and electronic effects.
**Contrast with Alkenes:**
**Mechanism of Nucleophilic Addition:**
**Step 1: Nucleophilic Attack**
**Step 2: Hybridization Change and Intermediate Formation**
**Step 3: Protonation**
**Overall Reaction:** C=O + Nu⁻ + H⁺ → CH(OH)-Nu
**Reactivity Differences: Aldehydes vs. Ketones**
**Aldehydes are more reactive than ketones** in nucleophilic addition reactions due to:
1. **Steric Reasons:**
2. **Electronic Reasons:**
**Reactivity Order:** HCHO > RCHO > (R)₂CO (Formaldehyde most reactive, then aldehydes, then ketones)
**Aromatic vs. Aliphatic Aldehydes:**
**Benzaldehyde is less reactive than aliphatic aldehydes (e.g., propanal)** because:
**(a) Addition of Hydrogen Cyanide (HCN) - Cyanohydrin Formation:**
**Reaction:** RCOR' + HCN → RCH(OH)CN (aldehyde) or R₂C(OH)CN (ketone)
**Specific Example:** CH₃CHO + HCN → CH₃CH(OH)CN (acetaldehyde cyanohydrin)
**Mechanism:**
**Importance:**
**Real-life Example:** Acetaldehyde cyanohydrin (acetone cyanohydrin) is intermediate in industrial synthesis of methacrylic acid.
**(b) Addition of Sodium Hydrogensulfite (NaHSO₃) - Bisulfite Addition:**
**Reaction:** RR'C=O + NaHSO₃ → RR'C(OSO₃⁻Na⁺)(H) or RR'C(OH)(SO₃⁻)
**Structural representation:** Formation of **addition product** (sulfonated adduct)
**Mechanism:**
**Equilibrium Position:**
**Properties of Addition Products:**
**Application:** **Separation and purification of aldehydes** from ketones
**(c) Addition of Grignard Reagents:**
**Reaction:** RR'C=O + R''MgX → RR'C(OMgX)R'' → RR'C(OH)R'' (after aqueous workup)
**Mechanism:**
**Product Formation:**
**Example:** CH₃CHO + C₂H₅MgBr → CH₃CH(OH)C₂H₅ (sec-butyl alcohol, secondary alcohol)
**Refer to Unit 7 for detailed mechanism and applications.**
**(d) Addition of Alcohols - Acetal and Ketal Formation:**
**Reaction with Aldehydes (Acetal Formation):**
**Overall Reaction:** RCH=O + 2R'OH ⇌ RCH(OR')(OR'') + H₂O
**Specific Example:** CH₃CHO + 2CH₃OH ⇌ CH₃CH(OCH₃)₂ + H₂O (acetaldehyde dimethyl acetal)
**Mechanism:**
**Reaction with Ketones (Ketal Formation):**
**Overall Reaction:** R₂C=O + HOCH₂CH₂OH → [cyclic structure with R, R, and two oxygens] + H₂O
**Specific Example:** Acetone + ethylene glycol → **Acetone ethylene glycol ketal** (2,2-dimethyl-1,3-dioxolane)
**Mechanism:**
**Importance of Acetals and Ketals:**
**Real-life Application:** In steroid synthesis and complex organic molecules, aldehydes are converted to acetals to protect them during subsequent transformations (e.g., Grignard reactions on other parts of molecule), then regenerated when needed.
**(e) Addition of Ammonia and Its Derivatives:**
**General Reaction:** RR'C=O + H₂N-Z → RR'C=N-Z + H₂O (loss of water)
**Where Z = Alkyl group (R), aryl group (Ar), OH (hydroxyl), NH₂ (amino), C₆H₅NH (phenyl), NHCONH₂ (semicarbazide), etc.**
**Mechanism:**
**Products and Nomenclature:**
| Nucleophile (H₂N-Z) | Reagent Name | Product | Product Name |
|---|---|---|---|
| NH₃ | Ammonia | RR'C=NH | Imine or Schiff's base |
| R-NH₂ | Amine | RR'C=N-R | Substituted imine (Schiff's base) |
| HO-NH₂ | Hydroxylamine | RR'C=N-OH | Oxime |
| H₂N-NH₂ | Hydrazine | RR'C=N-NH₂ | Hydrazone |
| C₆H₅-NH-NH₂ | Phenylhydrazine | RR'C=N-NH-C₆H₅ | Phenylhydrazone |
| O₂N-C₆H₄-NH-NH₂ | 2,4-Dinitrophenylhydrazine | RR'C=N-NH-C₆H₃(NO₂)₂ | 2,4-DNP derivative* |
| H₂N-CO-NH-NH₂ | Semicarbazide | RR'C=N-NH-CO-NH₂ | Semicarbazone |
*2,4-DNP derivatives are **yellow, orange, or red solids**, useful for **characterization of aldehydes and ketones** (melting point values are unique and help identify specific compounds). These derivatives are insoluble in aqueous solution, facilitating isolation and purification.
**Exam-Important Reactions:**
**Real-life Example:** Brady's reagent (2,4-dinitrophenylhydrazine in ethanol + HCl) is used in lab to detect aldehydes and ketones within seconds — a purple/red/orange precipitate confirms presence of C=O functional group.
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**Reagents:** Sodium borohydride (NaBH₄), Lithium aluminium hydride (LiAlH₄), Catalytic hydrogenation (H₂/Pd, Ni, Pt)
**Reactions:**
Q1. The IUPAC name of CH₃CH₂CH(Cl)CHO is:
Answer: B — The aldehyde carbon is C1; the chain has 4 carbons (butanal); Cl is on C3, so the name is 3-chlorobutanal.
Q2. Which statement about the carbonyl group is INCORRECT?
Answer: B — The oxygen is the nucleophilic centre (has lone pairs and electron density), not an electrophilic centre; the statement reverses their roles.
Q3. Formaldehyde undergoes the Cannizzaro reaction while acetaldehyde does not. The key difference is:
Answer: B — Cannizzaro is a disproportionation occurring only with aldehydes lacking α-H (like HCHO); acetaldehyde with α-H undergoes aldol condensation instead.
Q4. In the aldol condensation, the new C–C bond forms between:
Answer: A — The nucleophilic enolate ion (from α-carbon of one aldehyde) attacks the electrophilic carbonyl carbon of the second aldehyde, forming a C–C bond.
Q5. Which aldehyde is more reactive toward nucleophilic addition and why?
Answer: B — Formaldehyde's lack of bulky alkyl groups allows easier access to the carbonyl carbon; acetaldehyde is hindered by the methyl group, reducing nucleophilic approach.
Q6. The pKa of benzoic acid (C₆H₅COOH) is ~4.2. If a nitro group (–NO₂) is attached to the benzene ring, the pKa of the resulting compound is likely to be:
Answer: B — –NO₂ is an electron-withdrawing group that stabilises the conjugate base (COO⁻) via resonance, increasing acidity and lowering pKa.
Q7. The structure of 4-oxopentanal (CH₃COCH₂CH₂CHO) contains:
Answer: A — The compound has an aldehyde (–CHO) at one end and a ketone (CH₃CO–) at position 4, making it both an aldehyde and a ketone.
Q8. When 50 g of ethanol (C₂H₅OH) is oxidised to ethanal (CH₃CHO), approximately how many grams of ethanal can be produced (assuming 100% yield)? (Molar mass: C = 12, H = 1, O = 16; M(ethanol) = 46 g/mol, M(ethanal) = 44 g/mol)
Answer: A — Moles of ethanol = 50/46 ≈ 1.087 mol; 1:1 molar ratio in oxidation; mass of ethanal = 1.087 × 44 ≈ 47.8 g.
Q9. Both assertion and reason are given. Assertion: Aldehydes are more reactive than ketones toward nucleophilic addition. Reason: Aldehydes have a less bulky hydrogen atom attached to the carbonyl carbon, making the carbon more accessible.
Answer: A — Aldehydes are indeed more reactive; the reason (reduced steric hindrance from H vs. alkyl) correctly explains why this reactivity difference exists.
Q10. In nucleophilic addition to a carbonyl (R₂C=O + :Nu⁻), the first step forms a tetrahedral intermediate. This intermediate is stabilised by:
Answer: B — The negative charge on oxygen in the tetrahedral intermediate is stabilised by resonance, allowing the negative charge to delocalise via the C–O bond.
What is the hybridisation of carbonyl carbon and its bond geometry?
Carbonyl carbon is sp² hybridised with trigonal planar geometry (~120° bond angles).
Why is the carbonyl group polarised?
Oxygen is more electronegative than carbon, pulling electron density toward itself and making the carbonyl carbon electrophilic.
What is the IUPAC naming rule for open-chain aldehydes?
Replace the terminal '-e' of the alkane with '-al' and number the chain starting from the aldehyde carbon (C1).
How do IUPAC names of ketones differ from aldehydes in numbering?
In ketones, number the chain from the end nearest to the carbonyl group to give it the lowest number.
What does nucleophilic addition to a carbonyl mean?
A nucleophile attacks the electrophilic carbonyl carbon, forming a tetrahedral intermediate with a new C–Nu bond.
What is the aldol condensation reaction?
Two carbonyl compounds with α-hydrogens condense to form a β-hydroxy carbonyl (aldol), followed by dehydration to an α,β-unsaturated carbonyl.
Why can formaldehyde undergo Cannizzaro reaction but acetaldehyde cannot?
Formaldehyde has no α-hydrogen and undergoes disproportionation (one molecule oxidised to formic acid, one reduced to methanol); acetaldehyde has α-H and undergoes aldol instead.
What makes aldehydes more reactive than ketones toward nucleophilic addition?
Aldehydes have one less bulky group (H instead of alkyl) around the carbonyl, making the carbon more accessible and transition states less sterically hindered.
What is the carboxyl group structure and why are carboxylic acids acidic?
Carboxyl group is –COOH; carboxylic acids are acidic because the conjugate base (COO⁻) is stabilised by resonance between two C–O bonds.
How do electron-withdrawing groups affect carboxylic acid acidity?
Electron-withdrawing groups (e.g., Cl, NO₂) attached to the α-carbon stabilise the negative charge on COO⁻, increasing acidity (lower pKa).
Define the carbonyl group and write the structure of an aldehyde and a ketone. Which one is more reactive toward nucleophilic addition and why? [2 marks]
Carbonyl is C=O; aldehydes have RCHO structure (less bulky H around C), ketones have R₂CO (more bulky alkyl). Aldehydes are more reactive due to reduced steric hindrance.
Explain the aldol condensation mechanism for two molecules of ethanal (CH₃CHO). Include the formation of the enolate ion, the nucleophilic attack, and the final product after dehydration. Show all steps. [5 marks]
Step 1: α-H deprotonation forms enolate (CH₂=CHO⁻). Step 2: Enolate attacks second ethanal's C=O (nucleophilic addition). Step 3: Tetrahedral intermediate formed. Step 4: Dehydration removes water, giving CH₃CH=C(OH)CH₃ (but-3-en-2-ol) → dehydration to α,β-unsaturated ketone. Show resonance stabilisation of conjugate base.
Carboxylic acids are weakly acidic (pKa ≈ 4.75) and their acidity is affected by substituents. (a) Using resonance structures, explain why the carboxyl group (–COOH) is acidic. (b) Compare the acidity of benzoic acid (C₆H₅COOH), 4-nitrobenzoic acid (O₂N–C₆H₄–COOH), and 4-methoxybenzoic acid (CH₃O–C₆H₄–COOH). Justify the order using electronic effects. Show all resonance forms of the conjugate base. [6 marks]
Part (a): COOH ⇌ COO⁻ + H⁺; resonance in COO⁻ shows two equivalent C–O bonds, delocalising negative charge (stabilising conjugate base, favouring ionisation). Part (b): –NO₂ withdraws electrons (EWG) → stabilises COO⁻ → increases acidity (pKa < benzoic); –OCH₃ donates electrons (EDG) → destabilises COO⁻ → decreases acidity (pKa > benzoic). Order: 4-nitrobenzoic acid > benzoic acid > 4-methoxybenzoic acid. Draw two resonance forms of COO⁻ showing C=O and C–O⁻ structures.
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