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Aldehydes, Ketones and Carboxylic Acids

NCERT Class 12 · Chemistry Based on NCERT Class 12 Chemistry textbook · Free CBSE study kit

Chapter Notes

ALDEHYDES, KETONES AND CARBOXYLIC ACIDS

8.1 NOMENCLATURE AND STRUCTURE OF CARBONYL GROUP

8.1.1 Nomenclature of Aldehydes and Ketones

**Aldehydes** contain the **carbonyl group (-CHO)** bonded to one carbon and one hydrogen, while **ketones** contain the carbonyl group bonded to two carbon atoms. Both are crucial in organic chemistry with widespread applications in medicines, perfumes, solvents, and food products.

**Common Names of Aldehydes:**

  • Derived from the common names of corresponding carboxylic acids by replacing the ending "-ic acid" with "-aldehyde"
  • Location of substituents indicated by Greek letters (α, β, γ, δ) where α-carbon is directly attached to the aldehyde group
  • Examples: Formaldehyde (HCHO), Acetaldehyde (CH₃CHO), Valeraldehyde (CH₃CH₂CH₂CH₂CHO)
  • **Common Names of Ketones:**

  • Named by identifying the two alkyl or aryl groups bonded to the carbonyl group
  • Substituent positions indicated as αα', ββ', etc.
  • Simplest ketone (CH₃COCH₃) is called **acetone**
  • Alkyl phenyl ketones named by adding the acyl group name as prefix to "phenone"
  • Examples: Methyl n-propyl ketone, Diisopropyl ketone
  • **IUPAC Names of Aldehydes:**

  • Replace the terminal "-e" of the corresponding alkane with "-**al**"
  • For open-chain aldehydes, numbering starts from the carbonyl carbon
  • When aldehyde group is attached to a ring, use suffix "**-carbaldehyde**" (e.g., benzene**carbaldehyde**)
  • Aromatic aldehydes: **Benzaldehyde** (IUPAC accepts common name); derivatives named as substituted benzaldehydes
  • Examples: Methanal (HCHO), Ethanal (CH₃CHO), 2-Methylpropanal [(CH₃)₂CHCHO]
  • **IUPAC Names of Ketones:**

  • Replace terminal "-e" of corresponding alkane with "-**one**"
  • Numbering begins from the end nearer to the carbonyl carbon
  • For cyclic ketones, carbonyl carbon is numbered as position 1
  • Substituents prefixed in alphabetical order with position numerals
  • Examples: Pentan-2-one (CH₃COCH₂CH₂CH₃), 2,4-Dimethylpentan-3-one
  • 8.1.2 Structure of Carbonyl Group

    **Hybridization and Bonding:**

  • Carbonyl carbon is **sp² hybridized**, forming three sigma (σ) bonds in the same plane
  • Fourth valence electron remains in p-orbital and forms a **π-bond** with oxygen's p-orbital
  • Oxygen atom possesses two non-bonding electron pairs
  • Three atoms attached to carbonyl carbon, carbonyl carbon, and oxygen lie in the same plane
  • Bond angles approximately **120°** (trigonal planar geometry)
  • **Polarity and Resonance:**

  • **Carbon-oxygen double bond is polar** due to higher electronegativity of oxygen (3.44) vs. carbon (2.55)
  • Carbonyl carbon acts as **electrophilic (Lewis acid) center**
  • Carbonyl oxygen acts as **nucleophilic (Lewis base) center**
  • Carbonyl compounds have **substantial dipole moments**, making them more polar than ethers
  • Polarity explained by resonance between neutral structure (A) and dipolar structure (B):
  • Structure A: Neutral with C=O double bond
  • Structure B: Polar with C⁺-O⁻ charge separation
  • This resonance explains both the electrophilicity of carbon and nucleophilicity of oxygen
  • **Key Exam Point:** The planar sp² geometry of carbonyl carbon and its polarity are fundamental to understanding all subsequent nucleophilic addition reactions.

    ---

    8.2 PREPARATION OF ALDEHYDES AND KETONES

    8.2.1 General Methods for Both Aldehydes and Ketones

    **1. Oxidation of Alcohols:**

  • Primary alcohols → Aldehydes (oxidized with mild oxidizing agents like PCC, DMP, or Jones reagent)
  • Secondary alcohols → Ketones (oxidized with same agents)
  • Refers back to Unit 7 mechanisms; key reagent is **pyridinium chlorochromate (PCC)**
  • Example: CH₃CH₂OH → CH₃CHO (ethanol to ethanal)
  • **2. Dehydrogenation of Alcohols:**

  • Suitable for **volatile alcohols**; industrially important
  • Alcohol vapors passed over heavy metal catalysts: **Silver (Ag) or Copper (Cu)**
  • Primary alcohols → Aldehydes; Secondary alcohols → Ketones
  • Reaction: R-CH₂OH → R-CHO + H₂
  • Example: CH₃CH₂OH → CH₃CHO at high temperature over Cu or Ag catalyst
  • **3. From Hydrocarbons - Ozonolysis of Alkenes:**

  • Alkene treated with ozone (O₃), followed by zinc dust and water
  • **Zn breaks the ozonide** (1,2,4-trioxolane intermediate) to yield carbonyl compounds
  • Product depends on alkene substitution:
  • Terminal alkenes give aldehydes
  • Internal alkenes give ketones
  • Mixed substitution gives mixture of both
  • Example: CH₃CH=CHCH₃ → CH₃CHO + CH₃CHO
  • **4. From Hydrocarbons - Hydration of Alkynes:**

  • Addition of water to alkynes in presence of **H₂SO₄ and HgSO₄** catalyst
  • Ethyne (HC≡CH) → Acetaldehyde (CH₃CHO)
  • All other alkynes → Ketones (follows Markovnikov's rule; OH adds to more substituted carbon)
  • Reaction: RC≡CR' + H₂O → RCOCH₂R' or RCOCR' depending on substitution
  • 8.2.2 Specific Methods for Aldehydes

    **1. Rosenmund Reduction (From Acyl Chlorides):**

  • Acid chloride (acyl chloride) reduced with **H₂ over Pd/BaSO₄** catalyst
  • **Pd/BaSO₄** is a special catalyst (Lindlar-type) that reduces C=O without further reduction to CH₂
  • **Reaction:** R-COCl + H₂ → R-CHO + HCl
  • Example: CH₃COCl + H₂ → CH₃CHO
  • BaSO₄ acts as "**poison**" to prevent over-reduction of aldehyde to alcohol
  • **2. Stephen Reaction (From Nitriles):**

  • Nitrile reduced with **SnCl₂ in HCl** to form **imine intermediate** [R-CH=NH⁺]
  • Imine hydrolyzed with water to give **aldehyde**
  • **Reaction:** R-CN + SnCl₂/HCl → R-CH=NH (imine) → R-CHO + NH₃
  • Example: CH₃CH₂CN → CH₃CH₂CHO
  • Advantage: Stops at aldehyde stage, doesn't over-reduce to alcohol
  • **3. DIBAL-H Reduction (From Nitriles and Esters):**

  • **Diisobutylaluminium hydride (DIBAL-H)** at **low temperature (-78°C)**
  • Selective reduction:
  • Nitrile → Imine intermediate → Aldehyde (upon hydrolysis)
  • Ester → Aldehyde (upon hydrolysis)
  • **Reaction:** R-CN + DIBAL-H → R-CH=N-Al(iBu)₂ → R-CHO (after aqueous workup)
  • Example: HOCH₂CH₂CHO can be prepared from EOCRCH₂CH₂OEt
  • **4. Etard Reaction (From Methylbenzene/Toluene):**

  • Toluene or substituted toluene treated with **CrO₂Cl₂** (chromyl chloride)
  • Methyl group oxidized to chromium complex intermediate
  • Complex hydrolyzed with **water** to give **benzaldehyde or substituted benzaldehyde**
  • **Reaction:** C₆H₅CH₃ + CrO₂Cl₂ → C₆H₅CHO + Cr³⁺ salts
  • Example: p-CH₃-C₆H₄-CH₃ → p-CH₃-C₆H₄-CHO
  • Advantage: Stops at aldehyde stage; strong oxidants like KMnO₄ would give carboxylic acid
  • **5. Chromic Oxide Method (From Methylbenzene):**

  • Toluene treated with **CrO₃ in acetic anhydride**
  • Forms **benzylidene diacetate intermediate** [C₆H₅CH(OAc)₂]
  • Diacetate hydrolyzed with **dilute aqueous acid** to give **benzaldehyde**
  • **Reaction:** C₆H₅CH₃ + CrO₃/(CH₃CO)₂O → C₆H₅CH(OAc)₂ + H⁺/H₂O → C₆H₅CHO + CH₃COOH
  • Example: Used for m-bromobenzaldehyde preparation from m-bromotoluene
  • **6. Side-Chain Chlorination Followed by Hydrolysis (From Toluene):**

  • **Commercial method** for benzaldehyde manufacture
  • Toluene treated with **Cl₂ in presence of light (photochemical reaction)**
  • Forms **benzal chloride** [C₆H₅CHCl₂] after substitution of two H atoms
  • Benzal chloride hydrolyzed with **aqueous base or acid** to yield **benzaldehyde**
  • **Reaction:** C₆H₅CH₃ + 2Cl₂ (light) → C₆H₅CHCl₂ + 2HCl; then C₆H₅CHCl₂ + H₂O → C₆H₅CHO + 2HCl
  • Advantage: Simple, economical, scalable
  • **7. Gatterman-Koch Reaction (From Benzene/Substituted Benzenes):**

  • Benzene or substituted benzene treated with **CO and HCl** in presence of **AlCl₃ (anhydrous) or CuCl (cuprous chloride)**
  • Directly inserts -CHO group on benzene ring without side chain first
  • **Reaction:** C₆H₆ + CO + HCl → C₆H₅CHO
  • Example: p-CH₃-C₆H₄ + CO/HCl/AlCl₃ → p-CH₃-C₆H₄-CHO
  • Advantage: Direct formylation without need for toluene intermediate
  • 8.2.3 Specific Methods for Ketones

    **1. Friedel-Crafts Acylation (From Benzene/Substituted Benzenes):**

  • Benzene or substituted benzene treated with **acid chloride (R-COCl) in presence of AlCl₃ (anhydrous)**
  • Forms **ketone (Ar-CO-R)**
  • **Reaction:** C₆H₆ + CH₃COCl → C₆H₅COCH₃ + HCl (requires AlCl₃)
  • Example: C₆H₆ + n-C₄H₉COCl → C₆H₅CO-C₄H₉ (butyrophenone)
  • Mechanism: Acylium ion [R-CO]⁺ attacks benzene ring as electrophile
  • Limitations: Cannot use on benzene rings with electron-withdrawing groups (-CN, -NO₂) as they deactivate ring
  • **2. From Acyl Chlorides with Dialkylcadmium (Cadmium Method):**

  • Acid chloride treated with **dialkylcadmium** reagent
  • Dialkylcadmium prepared by reacting **CdCl₂ with Grignard reagent (R-MgBr)**
  • **Reaction:** CdCl₂ + 2R-MgBr → (R)₂Cd + 2MgBrCl; then (R)₂Cd + R'-COCl → R-CO-R' + CdClR
  • Example: (CH₃)₂Cd + CH₃CH₂COCl → CH₃COCH₂CH₃ (pentan-2-one)
  • Advantage: **Doesn't over-reduce** to alcohols (unlike Grignard directly with acid chloride)
  • Cadmium reagents more selective than Grignard
  • **3. From Nitriles with Grignard Reagents:**

  • Nitrile treated with **excess Grignard reagent (R-MgBr)**, followed by **aqueous acid hydrolysis**
  • Forms **imine intermediate [R-C≡N + R'-MgBr]**, which is hydrolyzed to **ketone**
  • **Reaction:** R-CN + R'-MgBr (excess) → R-C(=NMgBr)-R' → R-CO-R' (after H₂O workup)
  • Example: CH₃CN + C₂H₅MgBr → CH₃COCH₂CH₃ (pentan-2-one)
  • Note: Excess Grignard ensures complete reaction; aqueous acid workup neutralizes MgBr
  • ---

    8.3 PHYSICAL PROPERTIES OF ALDEHYDES AND KETONES

    **State of Matter at Room Temperature:**

  • **Methanal (HCHO):** Gas at room temperature (bp -19°C)
  • **Ethanal (CH₃CHO):** Volatile liquid
  • **Higher aldehydes and ketones:** Liquids or solids at room temperature
  • **Boiling Points:**

  • **Higher than hydrocarbons and ethers** of comparable molecular mass due to **polar C=O dipole and dipole-dipole interactions**
  • **Lower than alcohols** of similar molecular mass due to **absence of intermolecular hydrogen bonding** (oxygen has non-bonding pairs but cannot form H-bonds as donor; carbon-hydrogen not sufficiently polar)
  • **Comparative Boiling Point Table:**

    | Compound | Molecular Mass | B.P. (K) |

    |----------|---|---|

    | n-Butane | 58 | 273 |

    | Methoxyethane (diethyl ether) | 60 | 281 |

    | Propanal | 58 | 322 |

    | Acetone (propanone) | 58 | 329 |

    | Propan-1-ol | 60 | 370 |

    **Interpretation:** n-Butane < Methoxyethane < Propanal < Acetone < Propan-1-ol

  • n-Butane (weakest: only van der Waals forces)
  • Ether (slightly stronger: weak dipole interactions)
  • Aldehyde (stronger: dipole-dipole from C=O)
  • Ketone (similar to aldehyde: strong dipole-dipole)
  • Alcohol (strongest: hydrogen bonding)
  • **Solubility in Water:**

  • **Lower members (methanal, ethanal, propanone):** Miscible with water in all proportions
  • Reason: **Form hydrogen bonds with water molecules** (C=O oxygen acts as H-bond acceptor)
  • **Higher homologs:** Solubility decreases rapidly with increasing chain length
  • Reason: Hydrophobic alkyl chains dominate; lipophilic character increases
  • All aldehydes and ketones: **Fairly soluble in organic solvents** (benzene, ether, methanol, chloroform, acetone)
  • **Odor:**

  • **Lower aldehydes:** Sharp, pungent odors (unpleasant)
  • Methanal: Pungent, irritating
  • Ethanal: Pungent
  • **Higher aldehydes:** Odor becomes less pungent, more fragrant
  • **Many natural aldehydes and ketones:** Used in perfumes and flavoring agents
  • Vanillin (from vanilla): Pleasant vanilla fragrance
  • Cinnamaldehyde (from cinnamon): Spicy-sweet fragrance
  • Salicylaldehyde (from meadowsweet): Floral fragrance
  • ---

    8.4 CHEMICAL REACTIONS OF ALDEHYDES AND KETONES

    Both aldehydes and ketones possess the same functional group (carbonyl) and therefore undergo **very similar chemical reactions**. Key differences arise from steric and electronic effects.

    8.4.1 Nucleophilic Addition Reactions

    **Contrast with Alkenes:**

  • **Alkenes undergo electrophilic addition** (electrophile attacks π-electron-rich C=C)
  • **Aldehydes and ketones undergo nucleophilic addition** (nucleophile attacks electrophilic C)
  • **Mechanism of Nucleophilic Addition:**

    **Step 1: Nucleophilic Attack**

  • Nucleophile (Nu⁻) approaches the electrophilic carbonyl carbon from a direction **approximately perpendicular to the plane of sp² hybridized orbitals**
  • Attack occurs from above or below the plane of the C=O bond
  • Electrons from Nu⁻ form new C-Nu σ-bond
  • **Step 2: Hybridization Change and Intermediate Formation**

  • Carbonyl carbon hybridization changes from **sp² to sp³** during attack
  • π-electrons of C=O move onto oxygen, forming **alkoxide intermediate** (R₂C-O⁻)
  • Intermediate is tetrahedral with negative charge localized on oxygen
  • **Step 3: Protonation**

  • Alkoxide intermediate **captures proton (H⁺)** from reaction medium (water, alcohol, acid)
  • Forms electrically neutral final product: R₂C(OH)-Nu
  • **Overall Reaction:** C=O + Nu⁻ + H⁺ → CH(OH)-Nu

    **Reactivity Differences: Aldehydes vs. Ketones**

    **Aldehydes are more reactive than ketones** in nucleophilic addition reactions due to:

    1. **Steric Reasons:**

  • Aldehydes: Only ONE bulky R group attached to carbonyl carbon (R-CHO)
  • Ketones: TWO bulky R groups attached to carbonyl carbon (R-CO-R')
  • Two large substituents in ketones create **steric hindrance** preventing nucleophile approach
  • Nucleophile can access aldehyde carbon more easily
  • 2. **Electronic Reasons:**

  • Two alkyl groups in ketones **reduce electrophilicity of carbonyl carbon** more effectively than one group in aldehydes
  • Alkyl groups are electron-donating (through σ-bonding), increasing electron density on carbon
  • Increased electron density reduces carbon's ability to accept electrons from nucleophile
  • One alkyl group (in aldehyde) has weaker electron-donating effect
  • **Reactivity Order:** HCHO > RCHO > (R)₂CO (Formaldehyde most reactive, then aldehydes, then ketones)

    **Aromatic vs. Aliphatic Aldehydes:**

    **Benzaldehyde is less reactive than aliphatic aldehydes (e.g., propanal)** because:

  • Benzene ring carbon (to which CHO is attached) is **sp² hybridized**
  • Lone pairs on benzene ring oxygen can **resonate** through the ring, **delocalize negative charge**, and **reduce electrophilicity** of carbonyl carbon
  • Resonance structure: C₆H₅-CHO ↔ C₆H₅⁺-CHO⁻ (dipolar form reduces electrophilicity)
  • In aliphatic aldehydes, no such resonance stabilization occurs
  • 8.4.2 Important Nucleophilic Addition Reactions

    **(a) Addition of Hydrogen Cyanide (HCN) - Cyanohydrin Formation:**

    **Reaction:** RCOR' + HCN → RCH(OH)CN (aldehyde) or R₂C(OH)CN (ketone)

    **Specific Example:** CH₃CHO + HCN → CH₃CH(OH)CN (acetaldehyde cyanohydrin)

    **Mechanism:**

  • Pure HCN reacts very slowly (not a good nucleophile)
  • **Reaction is catalyzed by weak base (NaOH, NH₃, or KCN)** which generates **cyanide ion (CN⁻)**, a **strong nucleophile**
  • CN⁻ attacks carbonyl carbon forming C-CN bond
  • Intermediate accepts H⁺ from solution or regenerated HCN
  • **Overall: RR'C=O + CN⁻ → RR'C(-CN)O⁻ → RR'C(OH)CN**
  • **Importance:**

  • **Cyanohydrins are useful synthetic intermediates**
  • Can be reduced (with LiAlH₄) to corresponding **primary amines** [RCH(OH)CN → RCH(OH)CH₂NH₂]
  • Can be hydrolyzed to **hydroxy acids** [RCH(OH)CN + H₂O → RCH(OH)COOH]
  • Adds two carbon chain (one from CN, one becomes carboxylic acid or amine group)
  • Allows **chain elongation** in synthesis
  • **Real-life Example:** Acetaldehyde cyanohydrin (acetone cyanohydrin) is intermediate in industrial synthesis of methacrylic acid.

    **(b) Addition of Sodium Hydrogensulfite (NaHSO₃) - Bisulfite Addition:**

    **Reaction:** RR'C=O + NaHSO₃ → RR'C(OSO₃⁻Na⁺)(H) or RR'C(OH)(SO₃⁻)

    **Structural representation:** Formation of **addition product** (sulfonated adduct)

    **Mechanism:**

  • Hydrogen sulfite ion (HSO₃⁻) acts as nucleophile
  • Attacks carbonyl carbon, forms C-OSO₃⁻ linkage
  • Oxygen of carbonyl receives proton
  • **Equilibrium Position:**

  • **For most aldehydes:** Equilibrium lies **largely to the right** (products favored)
  • Reason: Less steric hindrance in aldehydes
  • Addition products are stable
  • **For most ketones:** Equilibrium lies **largely to the left** (reactants favored)
  • Reason: Steric hindrance from two alkyl groups
  • Addition products are less stable or don't form readily
  • **Properties of Addition Products:**

  • **Water-soluble** (unlike original carbonyl compounds)
  • **Can be reconverted** to original aldehyde/ketone by:
  • Treatment with **dilute mineral acid (HCl, H₂SO₄)** which regenerates free aldehyde/ketone
  • Treatment with **alkali (NaOH)** which also regenerates carbonyl compound
  • **Application:** **Separation and purification of aldehydes** from ketones

  • Aldehyde-rich mixture treated with NaHSO₃
  • Aldehydes selectively removed as water-soluble bisulfite adducts
  • Ketones remain in organic layer (not affected)
  • Aldehydes recovered by adding acid back to bisulfite adducts
  • Used industrially for aldehyde purification
  • **(c) Addition of Grignard Reagents:**

    **Reaction:** RR'C=O + R''MgX → RR'C(OMgX)R'' → RR'C(OH)R'' (after aqueous workup)

    **Mechanism:**

  • Grignard reagent [R''⁻...⁺MgX] acts as source of carbanion (R''⁻)
  • Carbanion attacks electrophilic carbonyl carbon
  • Forms C-R'' bond and C-O⁻ bond (alkoxide intermediate with Mg²⁺ coordinated to O⁻)
  • Aqueous acid workup protonates alkoxide: RR'C(OMgX)R'' + H⁺ → RR'C(OH)R'' + Mg²⁺ salts
  • **Product Formation:**

  • **Aldehyde + Grignard → Secondary alcohol:** RCHO + R''MgX → RCH(OH)R''
  • **Ketone + Grignard → Tertiary alcohol:** R-CO-R' + R''MgX → R-C(OH)(R'')-R'
  • **Ester + Grignard (2 equiv.) → Tertiary alcohol:** RC(=O)OR' + 2R''MgX → RC(OH)(R'')₂ + R'OMgX
  • **Example:** CH₃CHO + C₂H₅MgBr → CH₃CH(OH)C₂H₅ (sec-butyl alcohol, secondary alcohol)

    **Refer to Unit 7 for detailed mechanism and applications.**

    **(d) Addition of Alcohols - Acetal and Ketal Formation:**

    **Reaction with Aldehydes (Acetal Formation):**

  • **First equivalent:** Aldehyde + Monohydric alcohol (in presence of dry HCl) → **Hemiacetal** (intermediate)
  • RCH=O + R'OH → RCH(OR')(OH) [hemiacetal]
  • **Second equivalent:** Hemiacetal + Another alcohol molecule → **Acetal**
  • RCH(OR')(OH) + R'OH → RCH(OR')(OR'') + H₂O [acetal or gem-dialkoxy compound]
  • **Overall Reaction:** RCH=O + 2R'OH ⇌ RCH(OR')(OR'') + H₂O

    **Specific Example:** CH₃CHO + 2CH₃OH ⇌ CH₃CH(OCH₃)₂ + H₂O (acetaldehyde dimethyl acetal)

    **Mechanism:**

  • Dry HCl **protonates oxygen** of carbonyl: RCH=O + H⁺ → RCH=O⁺H (acylium ion)
  • Protonation **increases electrophilicity** of carbonyl carbon
  • Alcohol nucleophile attacks: RCH(O⁺H) + R'OH → RCH(OH)(OR') + H⁺ (hemiacetal forms)
  • Second equivalent of alcohol attacks hemiacetal: RCH(OH)(OR') + H⁺ → RCH(O⁺H)(OR') → RCH(OR')(OR'') (loss of H₂O)
  • Product is acetal (fully protected form of aldehyde)
  • **Reaction with Ketones (Ketal Formation):**

  • Ketones react with **ethylene glycol** under similar conditions (dry HCl catalyst)
  • Forms **cyclic ketal** (five-membered ring containing two oxygen atoms)
  • **Overall Reaction:** R₂C=O + HOCH₂CH₂OH → [cyclic structure with R, R, and two oxygens] + H₂O

    **Specific Example:** Acetone + ethylene glycol → **Acetone ethylene glycol ketal** (2,2-dimethyl-1,3-dioxolane)

    **Mechanism:**

  • Similar to acetal formation
  • First alcohol OH attacks protonated ketone
  • Second OH (from same molecule, i.e., ethylene glycol) attacks intermediate
  • Forms five-membered ring (1,3-dioxolane) with two C-O bonds and two oxygens
  • **Importance of Acetals and Ketals:**

  • **Protecting groups in synthesis:** Aldehyde/ketone can be masked as acetal/ketal during reactions that might affect the carbonyl
  • **Hydrolysis regenerates carbonyl:** Treat with aqueous mineral acid (HCl, H₂SO₄, dilute) to regenerate free aldehyde/ketone
  • RCH(OR')(OR'') + H₂O (acidic) → RCHO + 2R'OH
  • **Real-life Application:** In steroid synthesis and complex organic molecules, aldehydes are converted to acetals to protect them during subsequent transformations (e.g., Grignard reactions on other parts of molecule), then regenerated when needed.

    **(e) Addition of Ammonia and Its Derivatives:**

    **General Reaction:** RR'C=O + H₂N-Z → RR'C=N-Z + H₂O (loss of water)

    **Where Z = Alkyl group (R), aryl group (Ar), OH (hydroxyl), NH₂ (amino), C₆H₅NH (phenyl), NHCONH₂ (semicarbazide), etc.**

    **Mechanism:**

  • Ammonia or substituted ammonia (R'NH, R'OH, etc.) acts as nucleophile
  • Attacks carbonyl carbon forming tetrahedral intermediate: RR'C(OH)(NH-Z)
  • Intermediate loses water (dehydration occurs readily, especially under acidic conditions)
  • Forms **C=N double bond (imine or substituted imine): RR'C=N-Z**
  • Reaction is **reversible and acid-catalyzed**
  • **Equilibrium favors product** due to rapid dehydration of intermediate
  • **Products and Nomenclature:**

    | Nucleophile (H₂N-Z) | Reagent Name | Product | Product Name |

    |---|---|---|---|

    | NH₃ | Ammonia | RR'C=NH | Imine or Schiff's base |

    | R-NH₂ | Amine | RR'C=N-R | Substituted imine (Schiff's base) |

    | HO-NH₂ | Hydroxylamine | RR'C=N-OH | Oxime |

    | H₂N-NH₂ | Hydrazine | RR'C=N-NH₂ | Hydrazone |

    | C₆H₅-NH-NH₂ | Phenylhydrazine | RR'C=N-NH-C₆H₅ | Phenylhydrazone |

    | O₂N-C₆H₄-NH-NH₂ | 2,4-Dinitrophenylhydrazine | RR'C=N-NH-C₆H₃(NO₂)₂ | 2,4-DNP derivative* |

    | H₂N-CO-NH-NH₂ | Semicarbazide | RR'C=N-NH-CO-NH₂ | Semicarbazone |

    *2,4-DNP derivatives are **yellow, orange, or red solids**, useful for **characterization of aldehydes and ketones** (melting point values are unique and help identify specific compounds). These derivatives are insoluble in aqueous solution, facilitating isolation and purification.

    **Exam-Important Reactions:**

  • **Oxime formation:** Used to identify aldehydes and ketones; oximes have characteristic melting points
  • **Phenylhydrazone formation:** Phenylhydrazones form as orange-red or yellow solids; useful for compound identification
  • **2,4-DNP formation:** Yellow/red solids; rapid test for aldehyde/ketone functional group
  • **Semicarbazone formation:** White crystalline solids; also used for identification and purification
  • **Real-life Example:** Brady's reagent (2,4-dinitrophenylhydrazine in ethanol + HCl) is used in lab to detect aldehydes and ketones within seconds — a purple/red/orange precipitate confirms presence of C=O functional group.

    ---

    8.5 REDUCTION OF ALDEHYDES AND KETONES

    8.5.1 Reduction to Primary and Secondary Alcohols

    **Reagents:** Sodium borohydride (NaBH₄), Lithium aluminium hydride (LiAlH₄), Catalytic hydrogenation (H₂/Pd, Ni, Pt)

    **Reactions:**

  • **Aldehyde → Primary alcohol:** RCHO + NaBH₄ (or LiAlH₄) → RCH₂OH
  • Example: CH₃CHO + NaBH₄ → CH₃CH₂OH
  • Example: HCHO + LiAlH₄ → CH₃OH (methanol)
  • **Ketone → Secondary
  • MCQs — 10 Questions with Answers

    Q1. The IUPAC name of CH₃CH₂CH(Cl)CHO is:

    • A. 3-Chloropropanal
    • B. 3-Chlorobutanal ✓
    • C. 2-Chlorobutanal
    • D. 4-Chlorobutanal

    Answer: B — The aldehyde carbon is C1; the chain has 4 carbons (butanal); Cl is on C3, so the name is 3-chlorobutanal.

    Q2. Which statement about the carbonyl group is INCORRECT?

    • A. The carbonyl carbon is sp² hybridised with trigonal planar geometry.
    • B. The oxygen atom in a carbonyl is more electronegative and acts as a nucleophilic centre. ✓
    • C. The carbonyl carbon is an electrophilic centre due to polarisation.
    • D. The π-bond in C=O is formed by overlap of p-orbitals.

    Answer: B — The oxygen is the nucleophilic centre (has lone pairs and electron density), not an electrophilic centre; the statement reverses their roles.

    Q3. Formaldehyde undergoes the Cannizzaro reaction while acetaldehyde does not. The key difference is:

    • A. Formaldehyde is more volatile.
    • B. Formaldehyde has no α-hydrogen; acetaldehyde has α-hydrogens. ✓
    • C. Acetaldehyde is a stronger acid.
    • D. Formaldehyde is a gas at room temperature.

    Answer: B — Cannizzaro is a disproportionation occurring only with aldehydes lacking α-H (like HCHO); acetaldehyde with α-H undergoes aldol condensation instead.

    Q4. In the aldol condensation, the new C–C bond forms between:

    • A. The α-carbon of one aldehyde and the carbonyl carbon of another. ✓
    • B. Two carbonyl carbons directly.
    • C. The α-hydrogen of one aldehyde and the carbonyl carbon of another.
    • D. The hydroxyl group and the carbonyl carbon.

    Answer: A — The nucleophilic enolate ion (from α-carbon of one aldehyde) attacks the electrophilic carbonyl carbon of the second aldehyde, forming a C–C bond.

    Q5. Which aldehyde is more reactive toward nucleophilic addition and why?

    • A. Acetaldehyde is more reactive because it has methyl groups to stabilise the intermediate.
    • B. Formaldehyde is more reactive because H is less bulky than alkyl, making C more accessible. ✓
    • C. Acetaldehyde is more reactive because it has more α-hydrogens.
    • D. Both are equally reactive; reactivity depends only on solvent polarity.

    Answer: B — Formaldehyde's lack of bulky alkyl groups allows easier access to the carbonyl carbon; acetaldehyde is hindered by the methyl group, reducing nucleophilic approach.

    Q6. The pKa of benzoic acid (C₆H₅COOH) is ~4.2. If a nitro group (–NO₂) is attached to the benzene ring, the pKa of the resulting compound is likely to be:

    • A. Greater than 4.2 (more weakly acidic).
    • B. Less than 4.2 (more strongly acidic). ✓
    • C. Equal to 4.2 (no change).
    • D. Cannot be determined without additional data.

    Answer: B — –NO₂ is an electron-withdrawing group that stabilises the conjugate base (COO⁻) via resonance, increasing acidity and lowering pKa.

    Q7. The structure of 4-oxopentanal (CH₃COCH₂CH₂CHO) contains:

    • A. One aldehyde and one ketone functional group. ✓
    • B. Two aldehyde functional groups.
    • C. Two ketone functional groups.
    • D. One aldehyde and one carboxylic acid.

    Answer: A — The compound has an aldehyde (–CHO) at one end and a ketone (CH₃CO–) at position 4, making it both an aldehyde and a ketone.

    Q8. When 50 g of ethanol (C₂H₅OH) is oxidised to ethanal (CH₃CHO), approximately how many grams of ethanal can be produced (assuming 100% yield)? (Molar mass: C = 12, H = 1, O = 16; M(ethanol) = 46 g/mol, M(ethanal) = 44 g/mol)

    • A. 47.8 g ✓
    • B. 44.0 g
    • C. 50.0 g
    • D. 52.2 g

    Answer: A — Moles of ethanol = 50/46 ≈ 1.087 mol; 1:1 molar ratio in oxidation; mass of ethanal = 1.087 × 44 ≈ 47.8 g.

    Q9. Both assertion and reason are given. Assertion: Aldehydes are more reactive than ketones toward nucleophilic addition. Reason: Aldehydes have a less bulky hydrogen atom attached to the carbonyl carbon, making the carbon more accessible.

    • A. Both assertion and reason are correct, and reason is the correct explanation. ✓
    • B. Both assertion and reason are correct, but reason is not the correct explanation.
    • C. Assertion is correct, but reason is incorrect.
    • D. Assertion is incorrect, but reason is correct.

    Answer: A — Aldehydes are indeed more reactive; the reason (reduced steric hindrance from H vs. alkyl) correctly explains why this reactivity difference exists.

    Q10. In nucleophilic addition to a carbonyl (R₂C=O + :Nu⁻), the first step forms a tetrahedral intermediate. This intermediate is stabilised by:

    • A. The π-bond in C=O.
    • B. Resonance delocalisation of the negative charge from the newly formed C–O⁻ bond. ✓
    • C. Breaking of the C=O σ-bond.
    • D. Electrostatic attraction between the negatively charged oxygen and the positively charged carbon.

    Answer: B — The negative charge on oxygen in the tetrahedral intermediate is stabilised by resonance, allowing the negative charge to delocalise via the C–O bond.

    Flashcards

    What is the hybridisation of carbonyl carbon and its bond geometry?

    Carbonyl carbon is sp² hybridised with trigonal planar geometry (~120° bond angles).

    Why is the carbonyl group polarised?

    Oxygen is more electronegative than carbon, pulling electron density toward itself and making the carbonyl carbon electrophilic.

    What is the IUPAC naming rule for open-chain aldehydes?

    Replace the terminal '-e' of the alkane with '-al' and number the chain starting from the aldehyde carbon (C1).

    How do IUPAC names of ketones differ from aldehydes in numbering?

    In ketones, number the chain from the end nearest to the carbonyl group to give it the lowest number.

    What does nucleophilic addition to a carbonyl mean?

    A nucleophile attacks the electrophilic carbonyl carbon, forming a tetrahedral intermediate with a new C–Nu bond.

    What is the aldol condensation reaction?

    Two carbonyl compounds with α-hydrogens condense to form a β-hydroxy carbonyl (aldol), followed by dehydration to an α,β-unsaturated carbonyl.

    Why can formaldehyde undergo Cannizzaro reaction but acetaldehyde cannot?

    Formaldehyde has no α-hydrogen and undergoes disproportionation (one molecule oxidised to formic acid, one reduced to methanol); acetaldehyde has α-H and undergoes aldol instead.

    What makes aldehydes more reactive than ketones toward nucleophilic addition?

    Aldehydes have one less bulky group (H instead of alkyl) around the carbonyl, making the carbon more accessible and transition states less sterically hindered.

    What is the carboxyl group structure and why are carboxylic acids acidic?

    Carboxyl group is –COOH; carboxylic acids are acidic because the conjugate base (COO⁻) is stabilised by resonance between two C–O bonds.

    How do electron-withdrawing groups affect carboxylic acid acidity?

    Electron-withdrawing groups (e.g., Cl, NO₂) attached to the α-carbon stabilise the negative charge on COO⁻, increasing acidity (lower pKa).

    Important Board Questions

    Define the carbonyl group and write the structure of an aldehyde and a ketone. Which one is more reactive toward nucleophilic addition and why? [2 marks]

    Carbonyl is C=O; aldehydes have RCHO structure (less bulky H around C), ketones have R₂CO (more bulky alkyl). Aldehydes are more reactive due to reduced steric hindrance.

    Explain the aldol condensation mechanism for two molecules of ethanal (CH₃CHO). Include the formation of the enolate ion, the nucleophilic attack, and the final product after dehydration. Show all steps. [5 marks]

    Step 1: α-H deprotonation forms enolate (CH₂=CHO⁻). Step 2: Enolate attacks second ethanal's C=O (nucleophilic addition). Step 3: Tetrahedral intermediate formed. Step 4: Dehydration removes water, giving CH₃CH=C(OH)CH₃ (but-3-en-2-ol) → dehydration to α,β-unsaturated ketone. Show resonance stabilisation of conjugate base.

    Carboxylic acids are weakly acidic (pKa ≈ 4.75) and their acidity is affected by substituents. (a) Using resonance structures, explain why the carboxyl group (–COOH) is acidic. (b) Compare the acidity of benzoic acid (C₆H₅COOH), 4-nitrobenzoic acid (O₂N–C₆H₄–COOH), and 4-methoxybenzoic acid (CH₃O–C₆H₄–COOH). Justify the order using electronic effects. Show all resonance forms of the conjugate base. [6 marks]

    Part (a): COOH ⇌ COO⁻ + H⁺; resonance in COO⁻ shows two equivalent C–O bonds, delocalising negative charge (stabilising conjugate base, favouring ionisation). Part (b): –NO₂ withdraws electrons (EWG) → stabilises COO⁻ → increases acidity (pKa < benzoic); –OCH₃ donates electrons (EDG) → destabilises COO⁻ → decreases acidity (pKa > benzoic). Order: 4-nitrobenzoic acid > benzoic acid > 4-methoxybenzoic acid. Draw two resonance forms of COO⁻ showing C=O and C–O⁻ structures.

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