A **set** is a well-defined collection of objects. Well-defined means we can definitively decide whether any given object belongs to the collection or not. For example, "the set of all prime numbers less than 20" is well-defined: {2, 3, 5, 7, 11, 13, 17, 19}. However, "the collection of intelligent students in your class" is not well-defined because the criterion for intelligence is subjective and varies from person to person.
**Key Terminology:**
**Standard Sets Used in Mathematics:**
**Method 1: Roster Form (Tabular Form)**
In roster form, all elements are listed within braces {}, separated by commas. The order of elements is immaterial, and elements should not be repeated.
**Key Points:**
**Method 2: Set-Builder Form**
In set-builder form, elements are described using a property that distinguishes them from all other objects. The format is **{x : property of x}** or **{x | property of x}**, read as "the set of all x such that x has the given property."
**Advantages of Set-Builder Form:**
**Worked Example:**
Express the set {1/2, 2/3, 3/4, 4/5, 5/6, 6/7} in set-builder form.
*Solution:* Each element has numerator one less than the denominator, and the numerator ranges from 1 to 6. Therefore:
**{x : x = n/(n+1), where n ∈ N and 1 ≤ n ≤ 6}**
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**Definition:** A set that contains no elements is called the **empty set**, **null set**, or **void set**, denoted by **φ** or **{ }**.
**Important Property:** The empty set is a subset of every set.
**Examples of Empty Sets:**
**Distinction:**
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**Definition:** A set is **finite** if it is empty or contains a definite (countable) number of elements. A set is **infinite** if it is not finite.
The **cardinality** or **cardinal number** of a set S, denoted **n(S)**, is the number of distinct elements in S.
**Examples of Finite Sets:**
**Examples of Infinite Sets:**
**Note:** Not all infinite sets can be written in roster form. For example, the set of all real numbers between 0 and 1 cannot be listed sequentially because no pattern exists. This set must be expressed in set-builder form: **{x : x ∈ R and 0 < x < 1}**.
**Worked Example:**
State whether each set is finite or infinite:
(i) {x : x ∈ N and (x-1)(x-2) = 0}
(ii) {x : x ∈ N and x is prime}
(iii) {x : x ∈ N and 2x - 1 = 0}
*Solution:*
(i) (x-1)(x-2) = 0 gives x = 1 or x = 2. Both are in N, so the set is {1, 2} — **finite**, n = 2
(ii) The set is {2, 3, 5, 7, 11, 13, ...} with infinitely many primes — **infinite**
(iii) 2x - 1 = 0 gives x = 1/2, which is not in N. The set is φ — **finite**, n = 0
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**Definition:** Two sets A and B are **equal**, written **A = B**, if and only if they contain exactly the same elements. The order and repetition of elements do not matter.
Formally: **A = B if and only if (a ∈ A ⇔ a ∈ B)** for all elements a.
Equivalently: **A = B ⟺ A ⊂ B and B ⊂ A** (both subsets of each other)
**Key Principle:** Repetition of elements does not change a set.
**Examples of Equal Sets:**
**Examples of Unequal Sets:**
**Worked Example:**
Find pairs of equal sets from the given options:
A = {0}, B = {x : 15 < x < 5}, C = {x : x - 5 = 0}, D = {x : x² = 25}, E = {x : x is a positive integer root of x² - 2x - 15 = 0}
*Solution:*
**Comparison:**
**Answer: C and E are equal sets.**
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**Definition of Subset:** A set A is a **subset** of a set B, written **A ⊂ B** or **A ⊆ B**, if every element of A is also an element of B.
Formally: **A ⊂ B ⟺ (a ∈ A ⇒ a ∈ B)**
This means if you pick any element from A, it must be in B. The converse is not required — B may have elements not in A.
**Key Properties:**
1. **Every set is a subset of itself:** A ⊂ A
2. **The empty set is a subset of every set:** φ ⊂ A for any set A
3. **Transitivity:** If A ⊂ B and B ⊂ C, then A ⊂ C
4. **Equality characterization:** A = B if and only if A ⊂ B and B ⊂ A
**Definition of Proper Subset:** If A ⊂ B and A ≠ B, then A is a **proper subset** of B, written **A ⊂ B** (some texts use ⊂ for proper and ⊆ for subset including equality).
In a proper subset relationship, A is entirely contained in B, but B has at least one element not in A.
**Definition of Superset:** If A ⊂ B, then B is called a **superset** of A.
**Examples of Subsets:**
**Examples of Non-Subsets:**
**Singleton Set:** A set with exactly one element is called a **singleton set**. Examples: {5}, {a}, {φ}.
**Worked Example:**
Consider the sets φ, A = {1, 3}, B = {1, 5, 9}, C = {1, 3, 5, 7, 9}. Determine subset relationships:
*Solution:*
(i) **φ ⊂ B** — The empty set is a subset of every set ✓
(ii) **A ⊄ B** — 3 ∈ A but 3 ∉ B, so A is not a subset of B ✗
(iii) **A ⊂ C** — Both 1 and 3 belong to C, so A ⊂ C ✓
(iv) **B ⊂ C** — 1 ∈ B and 1 ∈ C; 5 ∈ B and 5 ∈ C; 9 ∈ B and 9 ∈ C, so B ⊂ C ✓
**Additional Observation:**
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1. **Confusing φ with {φ}:** φ is the empty set with 0 elements; {φ} is a singleton set containing the empty set as its element. n(φ) = 0 but n({φ}) = 1.
2. **Forgetting that order and repetition don't matter:** {1, 2, 3} = {3, 1, 2} = {1, 1, 2, 3}. Many students incorrectly treat these as different sets.
3. **Misidentifying well-defined collections:** Collections like "tallest students" or "best movies" are NOT sets because the criteria are subjective. Focus on objectively verifiable membership.
4. **Subset vs. Element:** {1} ⊂ {1, 2, 3} is correct (subset), but 1 ∈ {1, 2, 3} is also correct (element). However, 1 ⊂ {1, 2, 3} is incorrect, and {1} ∈ {1, 2, 3} is also incorrect.
5. **Forgetting φ ⊂ every set:** This is a fundamental principle often overlooked. The empty set is always a subset.
6. **Converting between roster and set-builder form:** Always verify by listing elements. For {x : x² < 9 and x ∈ Z}, the elements are {-2, -1, 0, 1, 2}, not {0, 1, 2}.
Q1. Which of the following is a well-defined set?
Answer: B — Only option B has a clear, objective criterion (natural numbers < 100) that allows definite membership decision; all others depend on subjective judgment.
Q2. Write the set {1, 4, 9, 16, 25, 36} in set-builder form.
Answer: B — Option B correctly identifies that all elements are perfect squares of natural numbers from 1 to 6; option A is incomplete as 49 < 40 is false.
Q3. The set of solution of the equation x² – 5x + 6 = 0 in roster form is:
Answer: A — Factoring gives (x – 2)(x – 3) = 0, so x = 2 or x = 3; the solution set is {2, 3}.
Q4. Which representation correctly describes the set of positive integers greater than 5 and less than 10?
Answer: B — Integers strictly greater than 5 and strictly less than 10 are 6, 7, 8, 9; endpoints are excluded because of strict inequalities.
Q5. The set A = {x : x is a vowel in the English alphabet} in roster form is:
Answer: B — The five pure vowels in English are a, e, i, o, u; y is sometimes a vowel but not a pure vowel by definition.
Q6. If P = {x : x is a prime factor of 30}, which statement is NOT correct?
Answer: D — Prime factors of 30 are 2, 3, 5 only; 6 = 2 × 3 is composite, not prime, so 6 ∉ P.
Q7. Consider the statements: (I) In roster form, elements can be repeated. (II) Set {1, 2, 3} and {3, 2, 1} are the same. Which is true?
Answer: C — Statement I is false: repetition is avoided in roster form. Statement II is true: order is immaterial, so {1, 2, 3} = {3, 2, 1}.
Q8. Write {n/(n+1) : n ∈ N and n ≤ 4} in roster form.
Answer: A — For n = 1, 2, 3, 4: n/(n+1) gives 1/2, 2/3, 3/4, 4/5 respectively.
Q9. The set of letters in the word 'SCHOOL' in roster form is:
Answer: B — Repetition is omitted in roster form, so O appears only once; the correct set is {S, C, H, O, L}, order irrelevant.
Q10. A student claims that the set {x : x is the largest natural number} is a valid set. Analyze this claim.
Answer: B — Natural numbers are infinite with no upper bound, so no largest natural number exists; this makes the condition not well-defined and membership undecidable.
What is a well-defined collection?
A collection where you can definitely decide whether any given object belongs to it or not.
What is the difference between roster and set-builder form?
Roster form lists all elements separated by commas in braces {1, 2, 3}; set-builder form describes elements by a common property {x : x is odd}.
What does the symbol ∈ mean?
The symbol ∈ means 'belongs to' and is used to show that an element is a member of a set.
Can elements repeat in a set written in roster form?
No, in roster form each element is listed only once; all elements are taken as distinct.
What does the colon ':' represent in set-builder notation?
The colon ':' stands for 'such that' and introduces the common property that all elements possess.
Give examples of three standard sets in mathematics.
N = natural numbers, Z = integers, Q = rational numbers, R = real numbers.
Convert {2, 4, 6, 8} to set-builder form.
{x : x is an even positive integer and x ≤ 8} or {x : x = 2n, where n ∈ N and n ≤ 4}.
Is the collection 'five most talented actors in India' a set? Why or why not?
No, because the criterion for 'most talented' varies from person to person, making it not well-defined.
What property must a collection have to be called a set?
It must be well-defined, meaning there is a clear rule to determine whether any object belongs to it or not.
If A = {1, 4, 9, 16, 25}, what property do all elements share?
All elements are perfect squares of natural numbers; A = {x : x = n², where n ∈ N and 1 ≤ n ≤ 5}.
What is a well-defined set? Give two examples of well-defined collections and two examples of collections that are NOT sets. [2 marks]
A well-defined set has an unambiguous criterion for membership. Example sets: odd numbers less than 10, prime factors of 12. Non-sets: famous actors, beautiful paintings (subjective criteria).
Convert the following sets between roster and set-builder forms: (i) {2, 4, 6, 8, 10} (ii) {x : x is a natural number and x² < 50}. Explain your reasoning in each case. [5 marks]
For (i), identify the common property (even numbers up to 10). For (ii), find which natural numbers satisfy n² < 50 by testing: 1, 4, 9, 16, 25, 36, 49. Show both conversions with clear property descriptions.
Write the set A = {1/2, 2/3, 3/4, 4/5, 5/6} in set-builder form and verify your answer by converting back to roster form. Also express the general term for the nth element of this set. [6 marks]
Observe that each numerator is one less than the denominator and numerators range from 1 to 5. The set-builder form is A = {x : x = n/(n+1), where n ∈ N and 1 ≤ n ≤ 5}. The general term is aₙ = n/(n+1). Convert back by substituting n = 1, 2, 3, 4, 5 to verify all elements match.
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