**Definition**: Given two non-empty sets P and Q, the Cartesian product P × Q is the set of all ordered pairs (p, q) where p ∈ P and q ∈ Q.
**Notation**: P × Q = {(p, q) : p ∈ P, q ∈ Q}
**Key Points**:
**Example**: If A = {red, blue} and B = {bag, coat, shirt}, then A × B has 2 × 3 = 6 ordered pairs:
A × B = {(red, bag), (red, coat), (red, shirt), (blue, bag), (blue, coat), (blue, shirt)}
**Important Observation**: P × Q ≠ Q × P in general. The Cartesian product is NOT commutative.
**Practical Applications**:
**Worked Example**:
If (2x + 1, y – 3) = (7, 5), find x and y.
Since ordered pairs are equal:
**Definition**: A relation R from a non-empty set A to a non-empty set B is a subset of the Cartesian product A × B.
**Notation**: R ⊆ A × B, written as R: A → B
**Key Terminology**:
**Representations of Relations**:
1. **Roster Form**: List all ordered pairs explicitly
Example: R = {(1,2), (2,3), (3,4)}
2. **Set-Builder Form**: Describe the relationship between elements
Example: R = {(x, y) : y = x + 1, x ∈ A, y ∈ B}
3. **Arrow Diagram**: Visual representation with arrows from domain to range
**Important Fact**: The total number of possible relations from set A to set B = 2^(n(A) × n(B))
If n(A) = p and n(B) = q, total relations = 2^(pq)
**Worked Example**:
Let A = {1, 2, 3, 4, 5, 6}. Define R = {(x, y) : y = x + 1}
**Example with Arrow Diagram**:
If R shows relationship "x is square of y" where P = {4, 9, 25} and Q = {-3, -2, 2, 3, 5}
**Definition**: A relation f from set A to set B is called a **function** (or mapping) if:
1. Every element of A has an image in B
2. Each element of A has exactly ONE image in B
3. Domain of f = A
**Notation**: f: A → B, or f(a) = b means (a, b) ∈ f
**Key Conditions for Function**:
**Distinguishing Function from Relation**: A relation is a function only if it passes the **vertical line test** (graphically) and satisfies the uniqueness condition.
**Worked Example**:
Examine if R = {(1, 2), (2, 3), (3, 4)} is a function:
Examine if R = {(2, 2), (2, 4), (3, 3)} is a function:
**Real Valued Function**: A function whose range is either R or a subset of R.
**Real Function**: A function whose domain is either R or a subset of R, AND whose range is either R or a subset of R.
These are critical for calculus and higher mathematics.
where n is non-negative integer and a₀, a₁, a₂, ..., aₙ ∈ R
**Prerequisites**: Let f: X → R and g: X → R be two real functions, where X ⊆ R
**Important Note**: When combining functions, always ensure that the resulting function is well-defined. The domain of (f/g) must exclude points where g(x) = 0.
1. **Ordered Pairs**: Always respect order; (a, b) ≠ (b, a) unless a = b
2. **Function Definition**: EVERY element of domain must have exactly ONE image
3. **Domain vs Codomain**: Domain is what we use; Codomain includes unused elements
4. **Special Functions**: Know graphs and properties of f(x) = x, x², x³, 1/x, |x|, [x], sgn(x)
5. **Number of Relations**: From A to B = 2^(n(A) × n(B))
6. **Composite Properties**: Know intersection and union properties with Cartesian products
7. **Common Mistakes**:
Q1. If (2x + 1, y – 3) = (5, 2), find the value of x + y.
Answer: B — From equality of ordered pairs: 2x + 1 = 5 gives x = 2, and y – 3 = 2 gives y = 5; therefore x + y = 7.
Q2. If A = {1, 2} and B = {a, b, c}, how many elements are in A × B?
Answer: B — n(A × B) = n(A) × n(B) = 2 × 3 = 6 elements.
Q3. Which of the following statements is true?
Answer: B — If A and B are non-empty sets, then A × B contains at least one ordered pair (a, b), so it is non-empty; options A and D are false because order matters and empty set rule applies.
Q4. If A = {2, 3}, B = {3, 4} and C = {4, 5}, find A × (B ∩ C).
Answer: A — B ∩ C = {4}, so A × (B ∩ C) = {(2, 4), (3, 4)} with 2 elements.
Q5. The set P × P × P has 8 elements. How many elements does P have?
Answer: A — If n(P) = k, then n(P × P × P) = k³ = 8, so k = 2.
Q6. Let A = {p, q} and B = {1, 2, 3}. Which ordered pair is NOT in A × B?
Answer: B — In A × B, the first element must come from A = {p, q} and second from B = {1, 2, 3}; (1, p) has 1 as first element, which is not in A.
Q7. If A × B = {(a, x), (a, y), (b, x), (b, y)}, which of the following is correct?
Answer: B — A contains all first elements {a, b} and B contains all second elements {x, y}, so A = {a, b} and B = {x, y}.
Q8. State whether true or false: P × Q = Q × P if and only if P = Q. Explanation:
Answer: C — If P = φ and Q = φ, then P × Q = Q × P = φ even though P = Q is not the only case; the statement is too restrictive.
Q9. If M = {2, 4, 6} and N = {1, 3}, verify: n((M × N)) = n(M) × n(N). What is n(M × N)?
Answer: B — n(M) = 3 and n(N) = 2, so n(M × N) = 3 × 2 = 6.
Q10. For sets A, B, C: A × (B ∩ C) = (A × B) ∩ (A × C). If A = {1, 2}, B = {2, 3, 4}, C = {3, 4, 5}, find (A × B) ∩ (A × C).
Answer: A — B ∩ C = {3, 4}, so A × (B ∩ C) = {(1, 3), (1, 4), (2, 3), (2, 4)}, which equals (A × B) ∩ (A × C).
What is the Cartesian product P × Q?
The set of all ordered pairs (p, q) where p ∈ P and q ∈ Q, written as P × Q = {(p, q) : p ∈ P, q ∈ Q}.
When are two ordered pairs equal?
Two ordered pairs (a, b) and (c, d) are equal if and only if a = c AND b = d.
If n(A) = 3 and n(B) = 5, what is n(A × B)?
n(A × B) = n(A) × n(B) = 3 × 5 = 15 elements.
Is P × Q always equal to Q × P?
No; P × Q = Q × P only if P = Q, because ordered pairs have direction and (p, q) ≠ (q, p) in general.
What happens to the Cartesian product if one set is empty?
If P = φ or Q = φ, then P × Q = φ (the product is the empty set).
What does R × R represent geometrically?
R × R represents all points in the two-dimensional plane with coordinates (x, y) where x, y ∈ R.
What is an ordered triplet and how does A × A × A relate to it?
An ordered triplet is a set of three elements written as (a, b, c); A × A × A = {(a, b, c) : a, b, c ∈ A}.
State the distributive property: A × (B ∪ C) = ?
A × (B ∪ C) = (A × B) ∪ (A × C).
State the distributive property: A × (B ∩ C) = ?
A × (B ∩ C) = (A × B) ∩ (A × C).
If A × B = {(p, q), (p, r), (m, q), (m, r)}, what are A and B?
A is the set of all first elements {p, m} and B is the set of all second elements {q, r}.
If (x – 2, y + 1) = (1, 3), find x and y. Also state the condition for equality of two ordered pairs. [2 marks]
Use equality of ordered pairs: first elements equal AND second elements equal; solve x – 2 = 1 and y + 1 = 3 separately.
Let A = {1, 2, 3}, B = {4, 5} and C = {5, 6}. Show that A × (B ∪ C) = (A × B) ∪ (A × C) by computing both sides. [5 marks]
Find B ∪ C first; compute A × (B ∪ C) directly; separately compute (A × B) and (A × C), then find their union; verify both sides give the same set.
If A × B has 12 elements, n(A) = 4, find n(B). If A × B = {(a, 1), (a, 2), (b, 1), (b, 2), (c, 1), (c, 2), (d, 1), (d, 2), (e, 1), (e, 2), (f, 1), (f, 2)}, verify that the given product is NOT A × B and explain why. Also, extract the sets A and B from the given product. [6 marks]
Use cardinality formula n(A × B) = n(A) × n(B) to find n(B); count the actual elements in the given set — there are 12, but A has 6 elements {a, b, c, d, e, f} not 4; extract A as the set of first elements and B as the set of second elements.
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