**Work** is defined scientifically as the product of force applied on an object and the displacement of the object in the direction of the applied force.
**Formula:** W = F × s
where:
**SI Unit:** 1 Joule (J) = 1 Newton × 1 metre = 1 N·m = 1 kg·m²·s⁻²
**Key Characteristics of Work:**
**Important Point:** When describing work, always specify which force is doing work and on which object the work is being done.
**Graphical Representation:** On a force-displacement graph, work done equals the area under the curve. For constant force, this forms a rectangle with area = F × s.
Work done is zero in three situations:
**1. No Force Applied (F = 0):** If no force acts on an object, W = 0, even if displacement occurs.
**2. No Displacement (s = 0):** If an object does not move despite force application, W = 0. Example: Pushing against a rigid wall produces no work because the wall does not move. Though muscles consume energy (causing fatigue), scientifically no work is done on the wall.
**3. Force Perpendicular to Displacement:** When force and displacement are perpendicular to each other, the component of force in the direction of displacement is zero, so W = 0. Example: A girl carrying a box while walking applies upward force to support its weight, but displacement is horizontal. Since force and displacement are perpendicular, no work is done by this force on the box.
**Positive Work:** When displacement is in the same direction as the applied force, work is positive.
**Negative Work:** When displacement is opposite to the direction of applied force, work is negative.
**Important Concept:** When two objects interact, both do work on each other. One does positive work while the other does negative work. Example: In a goalkeeper-ball collision, the goalkeeper does negative work on the ball (reducing its kinetic energy), while the ball does positive work on the goalkeeper's hand (transferring energy to it).
**Example Problem:** A goalkeeper's hand moves back 15 cm while applying a force of 200 N opposite to a ball's motion. Work done = F × s = 200 N × (−0.15 m) = −30 J (negative because force opposes displacement).
---
**Definition:** The work-energy theorem states that the work done on an object equals the change in its energy.
**Mathematical Form:** Work done on an object = Change in its energy
**Significance:** This theorem establishes the fundamental connection between mechanical work and energy. It applies whether forces are constant or variable, and for single objects or systems.
**Physical Meaning:**
**Real-Life Examples:**
1. **Cricket Ball and Wickets:** A fielder does positive work by throwing a cricket ball. The ball gains kinetic energy. When the ball hits the wickets, it transfers this energy to the wickets, causing them to fall.
2. **Flower Pot Falling:** Work done in lifting a pot to height gives it potential energy. When it falls, gravity does positive work on it, converting potential energy to kinetic energy. The moving pot can then do work on objects below it.
3. **Carrom Game:** The moving striker (doing positive work on white coin, increasing its energy) collides with the white coin (which does negative work on striker, decreasing its energy). The white coin then does positive work on the black coin.
**Important Application:** This theorem allows solving complex problems without detailed analysis of every force, especially when forces are not constant. Instead, we calculate total work done and relate it to energy change.
---
Energy exists in multiple forms, with the ability to convert from one form to another:
**1. Mechanical Energy:** Energy due to motion or position of objects
**2. Thermal Energy:** Energy that makes objects warm or hot
**3. Electrical Energy:** Energy related to position or motion of charges
**4. Light Energy:** Energy that allows us to see
**5. Sound Energy:** Energy of vibrations of air or other molecules
**6. Chemical Energy:** Energy stored in chemical bonds between atoms
**7. Nuclear Energy:** Energy stored in nuclei of atoms
**Energy Conversion Examples:**
---
**Definition:** Mechanical energy is the energy possessed by an object due to its motion or position. It has two components: kinetic energy and potential energy.
**Definition:** Kinetic energy is the energy possessed by an object due to its motion. All moving objects possess kinetic energy.
**Derivation of Formula:**
Consider an object of mass m starting from rest and accelerating under constant force F over displacement s, reaching final velocity v.
Using kinematic equation: v² = u² + 2as
When u = 0: v² = 2as, so s = v²/(2a)
Work done by force: W = F × s = ma × s = ma × [v²/(2a)] = ½mv²
By work-energy theorem, this work equals the kinetic energy gained.
**Mathematical Formula:** K = ½mv²
where:
**SI Unit:** Joule (J)
**Characteristics:**
**Relationship with Work:**
**Example Problem 1:** A vehicle's velocity doubles. How does kinetic energy change?
**Example Problem 2:** A cricket ball of mass 0.2 kg bowled at 154.8 km/h (43 m/s).
**Example Problem 3:** Aircraft Landing on Carrier
---
**Definition:** Potential energy is the energy possessed by an object due to its position or state. It represents stored energy that can be converted to kinetic energy.
**Types:**
**1. Gravitational Potential Energy:**
**Mathematical Formula:** U = mgh
where:
**SI Unit:** Joule (J)
**Characteristics of Gravitational PE:**
**Derivation:** When an object of mass m is slowly lifted to height h, work done against gravity is W = mgh. By work-energy theorem, this work gets stored as potential energy.
**2. Elastic Potential Energy:**
**Example:** A stretched spring, compressed spring, or bent bow all possess elastic potential energy.
**Conservation During Vertical Motion:**
When an object falls from height h:
This shows that gravitational potential energy converts completely to kinetic energy.
**Key Concept:** Potential energy is "stored" energy. It has the capacity to do work. When released under appropriate conditions, it gets converted to kinetic energy and can do work on other objects.
**Example Problem:** A 2 kg pot at height of 5 m on a shelf.
---
**Statement:** In the absence of non-conservative forces (like friction), the total mechanical energy of an object remains constant.
**Mathematical Form:** E = K + U = constant
Or: K₁ + U₁ = K₂ + U₂
where:
**Conditions for Conservation:**
**Energy Transformations During Free Fall:**
When object falls from height h with initial velocity u:
**At Height h:** K₁ = ½mu², U₁ = mgh, Total E = ½mu² + mgh
**At Ground (h = 0):** K₂ = ½mv², U₂ = 0, Total E = ½mv²
By conservation: ½mu² + mgh = ½mv²
This gives: v² = u² + 2gh (matches kinematic equation)
**Graphical Understanding:** During fall:
**Example Problem:** Ball thrown upward with initial velocity 20 m/s from ground.
**When Mechanical Energy is NOT Conserved:**
If friction or air resistance acts:
---
**Definition:** Power is the rate at which work is done or energy is transferred. It measures how fast work is being accomplished.
**Mathematical Definition:** P = W/t
where:
**SI Unit:** Watt (W) = Joule/second (J/s) = kg·m²·s⁻³
**Other Units:**
**Physical Meaning:**
**Alternative Form Using Velocity:**
When force and velocity are in same direction:
P = W/t = (F × s)/t = F × (s/t) = F × v
**Formula:** P = F·v
where v is the velocity of object in direction of force.
**Characteristics:**
**Comparison of Power:**
Two machines doing same work:
**Example Problem 1:** A man lifts 50 kg load to height 4 m in 2 seconds.
**Example Problem 2:** Same 50 kg load lifted to 4 m in 4 seconds.
**Real-Life Context:**
---
**Definition:** A simple machine is a device that changes the direction or magnitude of a force applied to it, making it easier to perform work. Simple machines allow us to do the same work with less effort.
**Basic Types:**
**Definition:** A lever is a rigid bar that rotates about a fixed point called the fulcrum.
**Components:**
**Classes of Levers:**
**Class I Lever:** Fulcrum between effort and load
**Class II Lever:** Load between fulcrum and effort
**Class III Lever:** Effort between fulcrum and load
**Principle:** Lever works on principle of moments. At equilibrium: Effort × Effort arm = Load × Load arm
**Mechanical Advantage:** MA = Load/Effort = Effort arm/Load arm
**Definition:** A pulley is a wheel with a grooved rim through which a rope or string passes.
**Types:**
**Fixed Pulley:**
**Movable Pulley:**
**Pulley System (Block and Tackle):**
**Advantage:** Reduces effort needed and changes direction of applied force
**Definition:** An inclined plane is a flat surface set at an angle to the horizontal, used to raise or lower objects more easily.
**Principle:** Instead of lifting object vertically (requiring large force), it can be moved along incline with smaller effort force.
**Components:**
**Mechanical Advantage:** MA = Length of incline/Height = L/h
**Force Required:** Effort = (Load × h)/L = Load × sin(θ)
**Advantage:**
**Real Examples:**
**Definition:** A wedge is an inclined plane with two sloping surfaces, used to split objects or raise loads.
**Examples:**
**Mechanism:** Small force applied perpendicular to back converts to large force along sloping faces (by geometry).
**Definition:** A screw is an inclined plane wrapped around a cylinder, used to fasten objects together or lift loads.
**Principle:** Rotation converts to linear motion. Pitch (distance advanced in one complete rotation) determines mechanical advantage.
**Mechanical Advantage:** MA = Circumference/Pitch = 2πr/Pitch
**Examples:**
**Advantage:** Very high mechanical advantage due to multiple rotations
**Definition:** A wheel and axle is a system where a wheel (large radius) is fixed to an axle (small radius), rotating together about the same axis.
**Mechanical Advantage:** MA = Radius of wheel/Radius of axle
**Examples:**
**Advantage:**
**Ideal Mechanical Advantage:** MA = Effort arm/Load arm = Load/Effort
**Relationship Between Force and Distance:**
**Real vs. Ideal:**
**Limitations:**
---
When simple machines are used:
**Work Input:** Work done by applied effort force
W_input = Effort × Distance moved by effort
**Work Output:** Useful work done on load
W_output = Load × Distance moved by load
**In Ideal Machine:** W_input = W_output (no energy loss)
**In Real Machine:** W_output < W_input (some energy lost as heat due to friction)
**Efficiency:** η = (W_output/W_input) × 100%
The mechanical advantage allows us to do useful work more conveniently, though the total energy required remains the same in ideal cases.
Q1. A boy applies a force of 10 N to move a toy car through a distance of 2 m in the direction of the force. How much work is done?
Answer: B — Work = Force × Displacement = 10 N × 2 m = 20 J.
Q2. Which of the following is NOT correct about work done?
Answer: C — Work can be positive, negative, or zero depending on the relative direction of force and displacement; it is not always positive.
Q3. A student pushes a wall with all their strength but the wall does not move. Which statement correctly explains why no work is done?
Answer: B — Since displacement s = 0, work W = F × 0 = 0, regardless of how large the force is.
Q4. Ramesh observes that lifting 5 bags to a height of 1 m requires much more effort than lifting 1 bag to the same height. Which concept explains this observation?
Answer: B — Lifting 5 bags requires 5 times greater force; since W = F × s and force increases 5-fold while displacement stays same, work increases 5-fold.
Q5. A girl carries a heavy box while walking 10 m horizontally. She applies an upward force equal to the box's weight. How much work is done by this upward force?
Answer: C — The upward force is perpendicular to the horizontal displacement, so no component of force acts in the direction of motion; work = 0.
Q6. Which graph correctly represents the relationship between work done and displacement when a constant force of 5 N is applied?
Answer: B — Since W = 5 × s, work increases linearly with displacement, giving a straight line through origin with slope equal to the constant force (5).
Q7. A stone is lifted vertically upward by 4 m. The work done is 200 J. What is the force applied to lift the stone?
Answer: B — Using W = F × s, we get 200 J = F × 4 m, so F = 200/4 = 50 N.
Q8. A boy pulls a toy in a horizontal direction while walking. Does the force applied by his hand do positive work on the toy?
Answer: B — The pulling force is in the same direction as the toy's horizontal displacement, so work done is positive: W = +F × s.
Q9. Why do muscles feel tired even when you push a rigid wall that does not move, even though scientifically no work is done?
Answer: B — Muscle fatigue comes from repeated contraction and biochemical energy use within the muscle, not from work done on external objects.
Q10. The area under a force-displacement graph represents which quantity?
Answer: B — In a force-displacement graph, the area under the curve equals work done: W = F × s, which is the area of the rectangle or area under any force curve.
Define work done by a constant force in physics.
Work done = Force applied × Displacement in the direction of force.
What is 1 joule of work?
Work done when a force of 1 newton moves an object 1 metre in the direction of the force.
When is work done equal to zero?
Work is zero when there is no displacement, no force applied, or force is perpendicular to displacement.
How does lifting 3 bags differ from lifting 1 bag to the same height?
Lifting 3 bags requires 3 times the force and 3 times the work compared to lifting 1 bag.
Give an example where force is applied but work done is zero.
Pushing a wall: you apply force but the wall does not move, so no work is done.
What is the relationship between force, displacement, and work on a force-displacement graph?
Work done equals the area under the force-displacement graph between initial and final positions.
Is work positive or negative when lifting an object upward?
Work is positive because the applied force and displacement are both in the same direction (upward).
A girl carries a box while walking horizontally. Is work done by the upward force?
No, work is zero because the upward force is perpendicular to the horizontal displacement.
Why do muscles get tired even when pushing a rigid wall with no work done?
Muscles repeatedly contract and expand, using internal energy from the body, even though no external work is done.
Express 1 joule in terms of kilogram, metre, and second.
1 joule = 1 kg m² s⁻² (since 1 N = 1 kg m s⁻²).
Define work done by a constant force. Write the SI unit of work and express it in fundamental units. [2 marks]
State the formula W = F × s. 1 joule = 1 N × 1 m; express in kg, m, s: 1 J = 1 kg m² s⁻².
A student lifts a 10 kg bag from the ground to a shelf 2 m high. Explain why the work done by the student is not zero even though the bag returns to rest. Is the work positive or negative? [3 marks]
Work = force (mg) × displacement (2 m upward). Since force and displacement are in the same direction, work is positive. The bag's final motion state does not affect work done during the lifting process.
Compare the work done in the following scenarios: (a) Lifting 1 bag to a height of 1 m, (b) Lifting 2 bags to a height of 1 m, (c) Lifting 1 bag to a height of 2 m. Explain using the work formula why the work differs in each case and provide a real-life example showing how machines use this principle to reduce human effort. [5 marks]
Use W = F × s to show: (a) W = mg × 1, (b) W = 2mg × 1 = 2W, (c) W = mg × 2 = 2W. Recognize that increasing force or displacement increases work proportionally. Connect to simple machines like levers or pulleys that reduce the force needed by increasing displacement.
Practice with interactive flashcards, mind maps, upload your own chapters and get AI study kits instantly
Try StudyOS Free →