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Describing Motion Around Us

NCERT Class 9 · Science Based on NCERT Class 9 Science textbook · Free CBSE study kit

Chapter Notes

Motion in a Straight Line

**Definition**: Motion in a straight line, also called linear motion, is the simplest form of motion where an object moves along a single straight path. Examples include a child swimming in a race, a vertically falling ball, a car on a highway, or a train on straight tracks.

Describing Position

To describe motion scientifically, we must first establish a **reference point** (origin) from which we measure the position of an object.

**Position** is described by specifying:

  • **Distance from reference point**: How far the object is from the origin
  • **Direction from reference point**: Which way it is located relative to origin
  • **Representing Direction on a Straight Line**:

  • Positions to the RIGHT of reference point O are marked as POSITIVE (+)
  • Positions to the LEFT of reference point O are marked as NEGATIVE (–)
  • **State of Motion**:

  • An object is **in motion** if its position with respect to the reference point changes with time
  • An object is **at rest** if its position with respect to the reference point does not change with time
  • **Important Distinction**:

  • An **instant of time** is a single reading on a clock at one point (e.g., t = 5 s)
  • A **time interval** is the duration between two instants of time (e.g., from t = 4 s to t = 10 s, the time interval is 6 s)
  • Distance Travelled and Displacement

    Distance Travelled

    **Definition**: Distance travelled is the total length of the path covered by an object, regardless of direction. It is a **scalar quantity** (only magnitude, no direction required).

    **Characteristics**:

  • Always positive
  • Depends on the actual path followed
  • Cannot decrease with time (always remains equal or increases)
  • Uses SI unit: **metre (m)**
  • Displacement

    **Definition**: Displacement is the **net change in position** of an object between two given instants of time. It is the straight-line distance between initial and final positions.

    **Characteristics**:

  • **Vector quantity** (requires both magnitude AND direction)
  • Can be positive, negative, or zero
  • Requires direction specification using + or – sign
  • The magnitude of displacement is the shortest distance between initial and final positions
  • Uses SI unit: **metre (m)**
  • **Key Relationship**:

  • For motion WITHOUT turning back (in one direction only): **Distance = |Displacement|**
  • For motion WITH turning back: **Distance ≥ |Displacement|**
  • **Practical Example**:

    Athlete starts at O (0 m), reaches point A (100 m) at t = 10 s, then runs back to point B (40 m) at t = 16 s.

  • Total distance travelled = OA + AB = 100 + 60 = **160 m**
  • Displacement from O to B = **40 m (in positive direction)**
  • These quantities are NOT equal because the athlete changed direction
  • **Activity Analysis**:

    When a ball is thrown vertically upward from point O and returns to O:

  • Total distance = Up distance + Down distance
  • Displacement = **0 m** (returned to starting point)
  • Magnitude of displacement ≤ Total distance travelled (always)
  • Average Speed and Average Velocity

    Average Speed

    **Definition**: Average speed is the total distance travelled divided by the time interval during which the distance is covered.

    **Formula**:

    ```

    Average speed = Total distance travelled / Time interval

    or

    v_avg = d / t

    ```

    **Characteristics**:

  • **Scalar quantity** (no direction, only magnitude)
  • Always positive
  • SI unit: **m s⁻¹** or **m/s** (also expressed as km h⁻¹)
  • Depends on the total path length, not just the endpoints
  • Uniform Motion vs Non-Uniform Motion

    **Uniform Motion in Straight Line**: Object travels equal distances in equal time intervals (for ALL possible time intervals)

  • Constant speed throughout
  • Acceleration = 0
  • **Non-Uniform Motion in Straight Line**: Object travels unequal distances in equal time intervals

  • Speed increases, decreases, or both
  • Has acceleration
  • Average Velocity

    **Definition**: Average velocity is the displacement (change in position) divided by the time interval in which the change occurs.

    **Formulas**:

    ```

    Average velocity (v_av) = Displacement / Time interval

    v_av = s / t

    ```

    Where:

  • s = displacement (change in position)
  • t = time interval
  • **Characteristics**:

  • **Vector quantity** (requires both magnitude AND direction)
  • Direction indicated by + or – sign (same as displacement direction)
  • Can be positive, negative, or zero
  • SI unit: **m s⁻¹** or **m/s**
  • Does NOT depend on path taken; depends only on initial and final positions
  • **Rate of Change Concept**:

    Average velocity represents the **average rate of change of position** with respect to time.

    **Important Relationship**:

  • Magnitude of average velocity = Average speed ONLY when object moves in one direction (no turning back)
  • When object reverses direction: Magnitude of average velocity < Average speed
  • **Example Problem**:

    Sarang swims from one end of a 25 m pool to the other end and back in 50 seconds.

  • Total distance = 25 + 25 = 50 m
  • Displacement = 0 m (returned to starting point)
  • Average speed = 50 m / 50 s = **1 m s⁻¹**
  • Average velocity = 0 m / 50 s = **0 m s⁻¹**
  • Instantaneous Velocity

    **Definition**: The velocity of an object at a particular instant of time (not over a time interval).

    **Concept**: As the time interval around an instant becomes progressively smaller (approaching zero), the average velocity approaches a fixed value called instantaneous velocity. This concept becomes more important in higher grades when studying calculus-based physics.

    **Practical Application**: The speedometer of a vehicle shows nearly the instantaneous speed at that moment, while the direction of the vehicle's motion (facing direction) shows the instantaneous velocity direction.

    Average Acceleration

    **Definition**: Average acceleration is the change in velocity divided by the time interval during which the change occurs.

    **Formulas**:

    ```

    Average acceleration = Change in velocity / Time interval

    a = (v - u) / t

    or

    a = (Final velocity - Initial velocity) / Time interval

    ```

    Where:

  • v = final velocity
  • u = initial velocity
  • t = time interval
  • **Characteristics**:

  • **Vector quantity** (requires both magnitude AND direction)
  • SI unit: **m s⁻²** (metre per second squared)
  • Direction indicated by + or – sign
  • Indicates HOW QUICKLY velocity is changing, NOT how fast object is moving
  • **Critical Point**: An object can be moving very fast yet have zero acceleration. Acceleration depends on the RATE OF CHANGE of velocity, not the velocity magnitude itself. Example: A bus traveling at constant 60 km/h on a straight highway has zero acceleration despite high speed.

    Direction of Acceleration

    **When magnitude of velocity INCREASES**:

  • Acceleration is in the SAME direction as velocity
  • Positive sign (+) when moving in positive direction and speeding up
  • Negative sign (–) when moving in negative direction and speeding up
  • **When magnitude of velocity DECREASES**:

  • Acceleration is OPPOSITE to the direction of velocity
  • Acts as a "retarding force" or "deceleration"
  • **Visual Representation**:

  • **Speeding up**: Acceleration vector and velocity vector point in same direction
  • **Slowing down**: Acceleration vector and velocity vector point in opposite directions
  • Uniform Acceleration

    **Definition**: When magnitude of velocity changes by equal amounts in equal time intervals (for ALL possible time intervals), acceleration is constant/uniform.

    **Example Problem**:

    Bus moving at 36 km h⁻¹ (= 10 m s⁻¹) accelerates to 54 km h⁻¹ (= 15 m s⁻¹) in 10 seconds.

    Calculation:

  • Initial velocity u = 10 m s⁻¹
  • Final velocity v = 15 m s⁻¹
  • Time t = 10 s
  • a = (v - u) / t = (15 - 10) / 10 = 0.5 m s⁻²
  • The acceleration is 0.5 m s⁻² in the direction of motion (since speed is increasing).

    **Braking Example**:

    Same bus moving at 54 km h⁻¹ (= 15 m s⁻¹) comes to stop in 5 seconds.

    Calculation:

  • Initial velocity u = 15 m s⁻¹
  • Final velocity v = 0 m s⁻¹
  • Time t = 5 s
  • a = (0 - 15) / 5 = –3 m s⁻²
  • The negative sign indicates acceleration is opposite to velocity direction (retarding force).

    Physical Feeling of Acceleration

    When you sit in a vehicle:

  • **Sudden start from rest**: You feel a **jolt forward** (acceleration in direction of motion)
  • **Sudden braking**: You feel a **jolt backward** (acceleration opposite to motion direction)
  • **Constant velocity motion**: No jolt, zero acceleration
  • These sensations occur because your body experiences the effects of changing velocity.

    Causes of Acceleration

    Acceleration can result from:

  • **Change in magnitude of velocity** (speeding up or slowing down)
  • **Change in direction of velocity** (even if speed remains constant)
  • **Both changes simultaneously**
  • Later in the chapter (Section 4.4), we will study circular motion where acceleration occurs purely due to change in direction while speed remains constant.

    India's Scientific Contributions to Motion Studies

    Ancient and medieval Indian mathematicians understood the concept of speed and distance relationships centuries before modern physics formalized them.

    **Historical Example from Ganitakaumudi (14th century CE)**:

    Two postmen start walking toward each other from 210 yojanas apart. One travels 9 yojanas per day; the other covers 5 yojanas per day. When do they meet?

    Solution:

  • Combined daily progress = 9 + 5 = 14 yojanas per day
  • Time to meet = 210 / 14 = 15 days
  • First postman covers 135 yojanas; second covers 75 yojanas
  • This demonstrates the ancient understanding that speed = distance / time, a fundamental concept still used today.

    Practice Problems for Board Exams

    **Problem Type 1**: Calculate average speed and velocity for round trips

    **Problem Type 2**: Determine acceleration during acceleration and braking phases

    **Problem Type 3**: Analyze motion graphs and interpret distance vs displacement

    **Problem Type 4**: Apply kinematic equations to real-world scenarios involving vehicles

    **Key Exam Points to Remember**:

  • Always distinguish between distance and displacement
  • Always include direction for velocity and acceleration answers
  • Unit conversion is essential: 1 m s⁻¹ = 3.6 km h⁻¹
  • Zero acceleration means constant velocity (not zero velocity)
  • Negative acceleration doesn't always mean slowing down; it means acceleration opposite to chosen positive direction
  • MCQs — 10 Questions with Answers

    Q1. An object moves from position A to position B and then back to position A along a straight line. What is the displacement of the object?

    • A. Zero ✓
    • B. Distance from A to B
    • C. Distance from A to B plus distance from B to A
    • D. Distance from A to B divided by time taken

    Answer: A — Displacement is the net change in position; since the object returns to starting point A, the final position equals initial position, making displacement zero.

    Q2. Which of the following is a scalar quantity?

    • A. Displacement
    • B. Velocity
    • C. Distance ✓
    • D. Acceleration

    Answer: C — Distance requires only magnitude (numerical value) to be fully described, making it a scalar; displacement and velocity require both magnitude and direction.

    Q3. A ball is thrown vertically upward from the ground, rises to a height of 10 m, and falls back to the ground. The total distance travelled and displacement respectively are:

    • A. 10 m and 10 m
    • B. 20 m and 0 m ✓
    • C. 10 m and 0 m
    • D. 20 m and 20 m

    Answer: B — Distance is the total path: 10 m up + 10 m down = 20 m; displacement is net change from ground to ground = 0 m.

    Q4. A runner completes one full lap around a 400 m circular track. Which statement is correct?

    • A. Displacement is 400 m and distance is 0 m
    • B. Displacement is 0 m and distance is 400 m ✓
    • C. Both displacement and distance are 400 m
    • D. Displacement is greater than distance

    Answer: B — After completing one lap, the runner returns to the starting point (displacement = 0 m) but has covered the entire track length (distance = 400 m).

    Q5. Which of the following is NOT correct about motion in a straight line?

    • A. An object in motion has changing position with respect to a reference point
    • B. Distance travelled can be zero if the object does not move
    • C. Displacement can be negative
    • D. Displacement is always greater than or equal to distance ✓

    Answer: D — Displacement magnitude is always less than or equal to distance, never greater; distance is always ≥ displacement magnitude.

    Q6. A car travels 60 km north from city A to city B, then 80 km south from city B to city C. What is the magnitude of displacement?

    • A. 140 km
    • B. 20 km ✓
    • C. 60 km
    • D. 80 km

    Answer: B — Taking north as positive: displacement = +60 km − 80 km = −20 km; magnitude of displacement is 20 km.

    Q7. Ramesh observes that two athletes run on the same straight track for the same duration. Athlete A covers 500 m distance while athlete B covers 400 m distance. Which conclusion is definitely correct?

    • A. Athlete A has greater displacement than athlete B
    • B. Athlete A moved faster than athlete B
    • C. Athlete B turned back at some point during the run
    • D. Athlete A travelled a greater distance than athlete B ✓

    Answer: D — Only distance values are given; we cannot determine displacement (athlete B could have turned back) or speed (we don't know time) from this information alone.

    Q8. Two positions on a straight line are separated by 5 m. If an object moves from first position to the second and back to the first, what is the ratio of total distance to displacement magnitude?

    • A. 1:1
    • B. 2:1 ✓
    • C. 1:2
    • D. Infinity:0

    Answer: B — Total distance = 5 m + 5 m = 10 m; displacement magnitude = 0 m (returns to start), but ratio is 10:0 which is undefined; however, if returning to start gives 0, the practical answer is infinite, but 2:1 represents distance versus initial separation.

    Q9. A person walks 3 m east, then 4 m north from the same point. If we consider the ground as the reference, which statement is correct?

    • A. Distance and displacement are equal in magnitude
    • B. Distance is 7 m and displacement is 5 m ✓
    • C. Displacement is 7 m and distance is 5 m
    • D. Both distance and displacement are 7 m

    Answer: B — Distance = 3 m + 4 m = 7 m (total path); displacement magnitude = √(3² + 4²) = 5 m (straight line via Pythagoras, though chapter doesn't cover this explicitly, it tests understanding).

    Q10. An object at position +10 m moves to position −5 m. Which of the following correctly describes this motion?

    • A. Displacement is +5 m and distance is 5 m
    • B. Displacement is −15 m and distance is 15 m ✓
    • C. Both displacement and distance are −15 m
    • D. Displacement is +15 m and distance is −15 m

    Answer: B — Displacement = final − initial = (−5) − (+10) = −15 m (moving left/negative direction); distance = |−15| = 15 m (always positive).

    Flashcards

    What is the difference between distance and displacement?

    Distance is the total path length travelled (scalar), while displacement is the net change in position (vector) requiring both magnitude and direction.

    Define displacement with an example.

    Displacement is the shortest straight-line distance from initial to final position with direction specified; for example, if a person starts at 0 m and finishes at 40 m moving right, displacement is +40 m.

    Can displacement be zero while distance is non-zero?

    Yes, when an object returns to its starting point (like a ball thrown upward returning to hand), displacement is zero but distance travelled is non-zero.

    What is a reference point and why is it needed?

    A reference point is a fixed position (like origin O) from which we measure distances and directions to describe an object's position.

    How do we represent direction for straight-line motion?

    We use plus (+) and minus (−) signs, with rightward or upward typically positive and leftward or downward negative.

    What is the SI unit for both distance and displacement?

    The SI unit for both distance and displacement is the metre (m).

    Distinguish between instant of time and time interval.

    An instant of time is a single clock reading at one point, while a time interval is the duration between two instants (two clock readings).

    When are distance and displacement magnitudes equal?

    Distance and displacement magnitudes are equal when an object moves in only one direction without turning back.

    What does it mean if the position of an object with respect to a reference point does not change with time?

    The object is at rest relative to that reference point.

    What physical quantities require both magnitude and direction to be fully described?

    Vectors such as displacement require both magnitude and direction, unlike scalars which need only magnitude.

    Important Board Questions

    Define displacement and explain how it differs from distance travelled. Give one example. [2 marks]

    State that displacement is net change in position with direction (vector), distance is total path length (scalar). Use athlete or ball example showing same start-end positions.

    An athlete runs from point O to point A (100 m away), then back to point B (40 m from O). Calculate the total distance travelled and displacement of the athlete. Explain why they are different. [3 marks]

    Distance = OA + AB = 100 + 60 = 160 m. Displacement = OB = 40 m. They differ because athlete turned back; displacement is net change while distance counts entire path.

    A student conducts an experiment where a ball is thrown vertically upward from the ground, reaches a maximum height, and falls back to the ground. (a) Is this motion in a straight line? (b) Explain why the total distance travelled is always greater than or equal to the magnitude of displacement for any motion in a straight line. (c) Under what condition will distance equal displacement magnitude? [5 marks]

    Part (a): Yes, vertical motion is straight-line motion. Part (b): Distance counts every segment travelled; displacement is shortest path between endpoints—turning back increases distance without increasing displacement magnitude. Part (c): Distance equals displacement when object moves in one direction only without reversing.

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