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Q1. What is 3^4?
Answer: B — 3^4 means 3 × 3 × 3 × 3 = 9 × 9 = 81; students often confuse it with 3 × 4 = 12.
Q2. Express 2 × 2 × 2 × 5 × 5 in exponential form.
Answer: B — Count: three 2's and two 5's, so 2^3 × 5^2; students may recount or confuse which base has which exponent.
Q3. What is the value of 5^0?
Answer: B — Any non-zero number to the power 0 equals 1; students often incorrectly think 5^0 = 0 or 5.
Q4.
Answer: A — When multiplying powers with the same base, add exponents: 2^4 × 2^3 = 2^(4+3) = 2^7 = 128.
Q5. A sheet of paper has thickness 0.001 cm. After folding 5 times (thickness doubles each fold), what is its thickness in exponential form?
Answer: B — The thickness after 5 folds is 0.001 × 2 × 2 × 2 × 2 × 2 = 0.001 × 2^5 cm; students may confuse the exponent with the fold number or multiply incorrectly.
Q6. Roxie has 7 dresses, 2 hats, and 3 pairs of shoes. In how many ways can she dress up?
Answer: B — For each dress (7 choices), she picks a hat (2 choices) and shoes (3 choices), so 7 × 2 × 3 = 42; students may add instead of multiply.
Q7. Simplify (3^2)^3 using the law of exponents.
Answer: B — Power of a power rule: multiply exponents (3^2)^3 = 3^(2×3) = 3^6 = 729; students may add exponents instead of multiplying.
Q8. A lotus pond doubles every day. If it is completely covered on day 30, on which day was it half covered?
Answer: B — Since the number doubles daily, day 29 must have half the lotuses of day 30; students may incorrectly divide 30 by 2 to get day 15.
Q9. What is 2^3 × 5^3 in simplest form?
Answer: A — Using m^a × n^a = (mn)^a: 2^3 × 5^3 = (2 × 5)^3 = 10^3 = 1000; students may add exponents or multiply bases without combining the exponents.
Q10. Express 32400 as a product of its prime factors in exponential form.
Answer: B — Prime factorisation: 32400 = 2 × 2 × 2 × 2 × 3 × 3 × 3 × 3 × 5 × 5 = 2^4 × 3^4 × 5^2; students may miscount the factors during division.
What does 5^4 mean in words?
5 multiplied by itself 4 times, or 5 × 5 × 5 × 5 = 625.
In the expression 7^3, what is the base and what is the exponent?
Base is 7, exponent (or power) is 3.
What is the rule for multiplying powers with the same base?
Add the exponents: n^a × n^b = n^(a+b).
What is the rule for a power raised to another power?
Multiply the exponents: (n^a)^b = n^(ab).
What is the value of any non-zero number to the power 0?
Any non-zero number to the power 0 equals 1 (e.g., 5^0 = 1).
How does a lotus pond with doubling growth relate to the answer from day 29 to day 30?
If the pond is full on day 30, it is exactly half full on day 29 because the quantity doubles each day.
What is 2^10 equal to?
2^10 = 1024, which represents the thickness increase factor every 10 paper folds.
Express 6 × 6 × 6 × a × a in exponential form.
6^3 × a^2 or 6^3a^2.
What does the sign '≈' mean in expressions like 131 cm ≈ thickness after 17 folds?
The sign '≈' means 'approximately equal to' when the exact value is rounded.
In a 5-digit password lock where each digit can be 0–9, how many total passwords are possible?
10^5 = 100,000 passwords (10 choices for each of 5 positions).
Define exponential notation and give one example with your own numbers. [1 mark]
Write n^a = n × n × ... (a times). Example: 4^3 = 4 × 4 × 4 = 64.
A paper sheet has thickness 0.001 cm. After 10 folds (doubling each fold), what is its thickness? Express the answer in exponential form and calculate the numerical value. [2 marks]
Thickness = 0.001 × 2^10 cm. Calculate 2^10 = 1024, so thickness = 0.001 × 1024 = 1.024 cm.
Simplify the following using laws of exponents and show each step: (i) 3^4 × 3^2 (ii) (5^2)^3 (iii) 2^4 × 3^4 [3 marks]
(i) Use n^a × n^b = n^(a+b): 3^4 × 3^2 = 3^6. (ii) Use (n^a)^b = n^(ab): (5^2)^3 = 5^6. (iii) Use m^a × n^a = (mn)^a: 2^4 × 3^4 = 6^4.
Estu has a safe with a 3-digit password lock. Each digit can be any number from 0 to 9. (a) Express the total number of possible passwords in exponential form. (b) Calculate the total number of passwords. (c) If a lotus pond triples its flowers every day and started with 1 lotus, express the number of lotuses after 5 days in exponential form. (d) How does exponential growth in the password combinations compare to the lotus pond growth? [5 marks]
(a) For 3 positions, each with 10 choices: 10^3. (b) 10^3 = 1000 passwords. (c) 1 × 3^5 = 3^5 = 243 lotuses. (d) Exponential growth means the quantity increases by a constant factor each step; lotus triples (factor 3) while passwords multiply by 10 per digit added.
Q1. Assertion (A):
The exponential form 2¹⁰ equals 1024.
Reason (R):
2¹⁰ means 2 is multiplied by itself 10 times, and this product equals 1024.
Answer: A — Both A and R are true, and R is the correct explanation of A — Both the assertion and reason are true. 2¹⁰ = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 = 1024, and the reason correctly explains why this is the case by referencing the definition of exponents.
Q2. Assertion (A):
When a sheet of paper is folded 26 times starting with thickness 0.001 cm, its thickness reaches approximately 670 metres, which is close to the height of Burj Khalifa in Dubai (830 m).
Reason (R):
With each fold, the thickness doubles, creating exponential growth, and after 26 folds the thickness increases dramatically due to this multiplicative pattern.
Answer: B — Both A and R are true, but R is NOT the correct explanation of A — The assertion is true—after 26 folds, the thickness is approximately 670 m. The reason is also true, but it does not directly explain why the thickness is 670 m specifically; it only explains the general pattern of exponential growth. A complete explanation would need to show the calculation 0.001 × 2²⁶ ≈ 670 m.
Q3. Assertion (A):
The expression 3² × 3⁵ can be simplified to 3¹⁰.
Reason (R):
When multiplying powers with the same base, we multiply the exponents together.
Answer: D — A is false but R is true — The assertion is false; 3² × 3⁵ = 3⁷, not 3¹⁰. However, the reason is also false because the correct rule is to ADD exponents when multiplying powers of the same base, not multiply them. Students who know the rule would still get the assertion wrong due to incorrect application.
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Case Study:
A biologist studying bacterial growth placed 2 bacteria in a petri dish. Every 2 hours, each bacterium divides into 2, effectively doubling the population. The biologist recorded the population at 2-hour intervals: at hour 0 (start) there were 2 bacteria, at hour 2 there were 4 bacteria, at hour 4 there were 8 bacteria, at hour 6 there were 16 bacteria. The biologist wants to predict the population after 12 hours without doing manual counting.
Q1. What is the pattern in bacterial population growth?
Answer: B
Q2. How many 2-hour periods are there in 12 hours?
Answer: A
Q3. Express the population after 12 hours using exponential notation, starting with 2 bacteria.
Answer: A
Q4. After how many hours will the population reach 256 bacteria?
Answer: C
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