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Electromagnetic Waves

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Chapter Notes

ELECTROMAGNETIC WAVES

Introduction and Maxwell's Contribution

**Maxwell's Equations** unify electricity, magnetism, and light into a consistent mathematical framework. James Clerk Maxwell (1831–1879) demonstrated that:

  • A time-varying electric field produces a magnetic field (symmetric to Faraday's law)
  • The speed of electromagnetic waves equals the speed of light (3 × 10⁸ m/s)
  • **Light is an electromagnetic wave**
  • This revolutionary conclusion unified three domains of physics. Heinrich Hertz experimentally verified electromagnetic waves in 1887 (radio region, λ = 25 mm to 5 mm), confirming Maxwell's predictions and enabling modern communication technology.

    ---

    DISPLACEMENT CURRENT

    The Problem with Ampere's Circuital Law

    **Ampere's Circuital Law** (Chapter 4):

    ∮**B**·d**l** = μ₀i(t)

    When applying this law to a parallel plate capacitor being charged, a **contradiction** arises:

  • **Outside the capacitor** (Fig. 8.1a): A current i flows through the wire, so ∮**B**·d**l** = μ₀i
  • **Between capacitor plates** (Fig. 8.1b and c): No conduction current passes through surfaces with the same boundary loop, yet the magnetic field **B** at point P should be the same by symmetry
  • This inconsistency reveals that Ampere's law is **incomplete**.

    Maxwell's Solution: Displacement Current

    **Definition of Displacement Current:**

    The **displacement current** is a new term that arises from a time-varying electric field:

    $$i_d = \varepsilon_0 \frac{d\Phi_E}{dt}$$

    where:

  • ε₀ = permittivity of free space (8.85 × 10⁻¹² F/m)
  • Φ_E = electric flux through the surface
  • **Derivation of the Missing Term:**

    Inside the parallel plate capacitor with charge Q:

  • Electric field: E = Q/(A·ε₀)
  • Electric flux through surface S: Φ_E = E·A = Q/ε₀
  • Since charge changes with time (Q = ∫i dt):

    $$\frac{d\Phi_E}{dt} = \frac{1}{\varepsilon_0}\frac{dQ}{dt} = \frac{i}{\varepsilon_0}$$

    Therefore:

    $$\varepsilon_0 \frac{d\Phi_E}{dt} = i$$

    This **displacement current** equals the conduction current, resolving the contradiction.

    Physical Interpretation

    **Key Distinctions:**

  • **Conduction current (i_c)**: Flow of actual charges through a conductor (outside capacitor plates, i_c = i)
  • **Displacement current (i_d)**: Due to changing electric field (between capacitor plates, i_c = 0, i_d = i)
  • **Total current:**

    $$i_{total} = i_c + i_d = i_c + \varepsilon_0 \frac{d\Phi_E}{dt}$$

    The displacement current has **identical effects** to conduction current—it generates a magnetic field.

    ---

    AMPERE-MAXWELL LAW

    Generalized Ampere's Law

    **Statement:** The magnetic field around a closed loop equals μ₀ times the total current (conduction + displacement) passing through any surface bounded by the loop.

    **Mathematical Form:**

    $$\oint \mathbf{B} \cdot d\mathbf{l} = \mu_0 \left( i_c + \varepsilon_0 \frac{d\Phi_E}{dt} \right)$$

    Or equivalently:

    $$\oint \mathbf{B} \cdot d\mathbf{l} = \mu_0 i_c + \mu_0 \varepsilon_0 \frac{d\Phi_E}{dt}$$

    Significance and Symmetry

    **Restored Symmetry in Maxwell's Equations:**

  • **Faraday's Law**: Time-varying magnetic field → Electric field
  • $$\oint \mathbf{E} \cdot d\mathbf{l} = -\frac{d\Phi_B}{dt}$$

  • **Ampere-Maxwell Law**: Time-varying electric field → Magnetic field
  • $$\oint \mathbf{B} \cdot d\mathbf{l} = \mu_0 \varepsilon_0 \frac{d\Phi_E}{dt}$$ (in region with no conduction current)

    This **mutual regeneration** of time-varying E and B fields is the origin of **electromagnetic waves**.

    Example Application

    In a parallel plate capacitor with alternating voltage:

  • **Between plates**: E varies with time → displacement current i_d flows → magnetic field B is generated (perpendicular to E and circular around the axis)
  • **Outside plates**: Conduction current i_c flows → same magnetic field B
  • At the boundary: Both effects contribute, maintaining consistency
  • ---

    MAXWELL'S EQUATIONS IN VACUUM

    **Maxwell's four equations form the complete description of electromagnetism:**

    1. **Gauss's Law (Electricity):**

    $$\oint \mathbf{E} \cdot d\mathbf{A} = \frac{Q}{\varepsilon_0}$$

    (Electric charges create electric fields)

    2. **Gauss's Law (Magnetism):**

    $$\oint \mathbf{B} \cdot d\mathbf{A} = 0$$

    (No magnetic monopoles exist)

    3. **Faraday's Law:**

    $$\oint \mathbf{E} \cdot d\mathbf{l} = -\frac{d\Phi_B}{dt}$$

    (Changing magnetic flux creates electric field)

    4. **Ampere-Maxwell Law:**

    $$\oint \mathbf{B} \cdot d\mathbf{l} = \mu_0 i_c + \mu_0 \varepsilon_0 \frac{d\Phi_E}{dt}$$

    (Current and changing electric flux create magnetic field)

    ---

    ELECTROMAGNETIC WAVES: SOURCES AND NATURE

    Sources of Electromagnetic Waves

    **Key Principle:** **Only accelerated charges radiate electromagnetic waves.**

    **Non-sources:**

  • Stationary charges: Produce only static electric field (no variation)
  • Uniformly moving charges (steady current): Produce static magnetic field (no variation)
  • **Why accelerated charges?**

    An oscillating (accelerating) charge creates:

    1. Oscillating electric field in space

    2. This E-field variation → oscillating magnetic field (via Ampere-Maxwell law)

    3. This B-field variation → oscillating electric field (via Faraday's law)

    4. Mutual regeneration continues as wave propagates

    The wave frequency equals the **oscillation frequency** of the source charge.

    **Historical Verification:**

  • **Hertz (1887)**: Demonstrated EM waves using oscillating LC circuits (frequency ~10⁹ Hz, λ ≈ 30 cm)
  • **Jagdish Chandra Bose (1895)**: Produced shorter wavelengths (5–25 mm) at Calcutta
  • **Marconi (1895)**: First long-distance transmission (kilometers), founding wireless communication
  • **Why not visible light?** Yellow light oscillates at 6 × 10¹⁴ Hz—impossible to generate with circuits (max ~10¹¹ Hz). EM waves were demonstrated first in radio region, confirming that light is also EM waves.

    ---

    PROPERTIES OF ELECTROMAGNETIC WAVES

    Nature and Orientation

    **Fundamental Properties:**

    1. **Perpendicularity:** E, B, and direction of propagation (**k**) are **mutually perpendicular** (transverse wave)

    2. **In-phase oscillation:** E and B oscillate in phase (same time, same phase)

    3. **Sinusoidal variation:** For a wave propagating along +z direction:

    $$E_x = E_0 \sin(kz - \omega t)$$

    $$B_y = B_0 \sin(kz - \omega t)$$

    where:

  • **E₀** = electric field amplitude (V/m)
  • **B₀** = magnetic field amplitude (T)
  • **k** = wave number = 2π/λ (rad/m)
  • **ω** = angular frequency = 2πν (rad/s)
  • **λ** = wavelength (m)
  • **ν** = frequency (Hz)
  • Wave Relations

    **Dispersion Relation:**

    $$\omega = ck$$

    where **c** = speed of EM wave in vacuum

    **Relation to frequency and wavelength:**

    $$

    u \lambda = c$$

    or

    $$c =

    u \lambda = \frac{\omega}{k}$$

    **Field Magnitude Relation:**

    From Maxwell's equations:

    $$B_0 = \frac{E_0}{c}$$

    This shows **B₀ << E₀** (since c = 3 × 10⁸ m/s is large). For example, if E₀ = 6 V/m, then B₀ = 2 × 10⁻⁸ T.

    Speed in Different Media

    **In vacuum:**

    $$c = \frac{1}{\sqrt{\mu_0 \varepsilon_0}} = 3 \times 10^8 \text{ m/s}$$

    **In a material medium** (with permittivity ε and permeability μ):

    $$v = \frac{1}{\sqrt{\mu \varepsilon}}$$

    The speed is **slower** in a medium and depends on **refractive index** n = c/v (discussed in Ray Optics chapter).

    Self-Sustaining Nature

  • EM waves are **self-sustaining oscillations** of coupled E and B fields
  • **No material medium required** for propagation (unlike sound or water waves)
  • Vacuum is a perfect medium for EM wave propagation
  • Energy is transported by the wave from source to distant locations
  • ---

    WORKED NUMERICAL EXAMPLES

    **Example 8.1: Finding Magnetic Field from Electric Field**

    A plane EM wave of frequency ν = 25 MHz travels in free space along the x-direction. At a point, **E** = 6.3**ĵ** V/m. Find **B**.

    **Solution:**

    *Step 1: Find magnitude using B₀ = E₀/c*

    $$B_0 = \frac{E_0}{c} = \frac{6.3}{3 \times 10^8} = 2.1 \times 10^{-8} \text{ T}$$

    *Step 2: Find direction using **E** × **B** || direction of propagation*

  • Wave propagates along **x**-direction (given)
  • **E** is along **y**-direction (given as 6.3**ĵ**)
  • Need **E** × **B** = direction of propagation
  • For (**ĵ**) × (**B**) = (**î**):

  • **B** must be along **k̂** (z-direction)
  • Check: (**ĵ**) × (**k̂**) = (**î**) ✓
  • *Step 3: Final answer*

    $$\boxed{\mathbf{B} = 2.1 \times 10^{-8} \hat{\mathbf{k}} \text{ T}}$$

    ---

    **Example 8.2: Finding Wavelength and Frequency from Wave Equation**

    The magnetic field in a plane EM wave is:

    $$B_y = (2 \times 10^{-7}) \sin(0.5 \times 10^3 x + 1.5 \times 10^{11} t) \text{ T}$$

    (a) Find wavelength and frequency

    (b) Write the electric field equation

    **Solution:**

    *Step 1: Extract wave parameters from equation By = B₀ sin(kx + ωt)*

    Comparing with standard form B_y = B₀ sin(kz ± ωt):

  • **k** = 0.5 × 10³ rad/m = 500 rad/m
  • **ω** = 1.5 × 10¹¹ rad/s
  • *Step 2: Calculate wavelength*

    $$\lambda = \frac{2\pi}{k} = \frac{2\pi}{0.5 \times 10^3} = \frac{6.28}{500} = 1.26 \times 10^{-2} \text{ m} = 1.26 \text{ cm}$$

    *Step 3: Calculate frequency*

    $$

    u = \frac{\omega}{2\pi} = \frac{1.5 \times 10^{11}}{2\pi} = \frac{1.5 \times 10^{11}}{6.28} = 2.39 \times 10^{10} \text{ Hz} = 23.9 \text{ GHz}$$

    *Verification:* νλ = (2.39 × 10¹⁰)(1.26 × 10⁻²) = 3 × 10⁸ m/s = c ✓

    *Step 4: Find electric field amplitude*

    $$E_0 = cB_0 = (3 \times 10^8)(2 \times 10^{-7}) = 60 \text{ V/m}$$

    *Step 5: Determine electric field direction and write equation*

  • B is along y-direction, propagates along x-direction (from the equation form)
  • **E** must be perpendicular to both: along z-direction
  • Phase: Since B_y = B₀ sin(kx + ωt), the wave travels in **–x direction**
  • **E** and **B** oscillate in phase
  • $$\boxed{E_z = 60 \sin(0.5 \times 10^3 x + 1.5 \times 10^{11} t) \text{ V/m}}$$

    or equivalently:

    $$\boxed{E_z = 60 \sin(500x + 1.5 \times 10^{11} t) \text{ V/m}}$$

    ---

    KEY EXAM POINTS TO REMEMBER

  • **Displacement current:** id = ε₀(dΦ_E/dt); has same effects as conduction current
  • **Ampere-Maxwell law** resolves the contradiction in Ampere's law by including displacement current
  • **EM waves** are produced only by **accelerated charges**, not stationary or uniformly moving charges
  • **E, B, and k** are mutually perpendicular in an EM wave
  • **Relation:** B₀ = E₀/c (magnetic amplitude much smaller than electric)
  • **Speed in vacuum:** c = 1/√(μ₀ε₀) = 3 × 10⁸ m/s (fundamental constant)
  • **Wave equation:** νλ = c or ω = ck
  • **In media:** v = c/n = 1/√(με), where n is refractive index
  • **Maxwell's equations** (all four) are the foundation of classical electromagnetism
  • **Symmetry:** Faraday's law (B → E) and Ampere-Maxwell law (E → B) show mutual induction
  • ---

    ELECTROMAGNETIC SPECTRUM (PREVIEW)

    EM waves span an enormous range of wavelengths/frequencies:

  • **Radio waves:** λ ~ 10³–10⁶ m (ν ~ 10⁴–10¹¹ Hz)
  • **Microwaves:** λ ~ 10⁻³–10⁻¹ m (ν ~ 10⁹–10¹¹ Hz)
  • **Infrared:** λ ~ 10⁻⁷–10⁻⁴ m
  • **Visible light:** λ ~ 4–8 × 10⁻⁷ m (ν ~ 4–8 × 10¹⁴ Hz)
  • **Ultraviolet:** λ ~ 10⁻⁸–10⁻⁷ m
  • **X-rays:** λ ~ 10⁻¹⁰–10⁻⁸ m
  • **Gamma rays:** λ ~ 10⁻¹²–10⁻¹⁰ m
  • All travel at c in vacuum and obey the same Maxwell equations (detailed coverage in EM Spectrum section of full chapter).

    MCQs — 10 Questions with Answers

    Q1. A parallel plate capacitor is being charged by a current i. The electric flux through the capacitor plates is Φ_E. What is the displacement current between the plates?

    • A. i_d = ε₀(dΦ_E/dt) ✓
    • B. i_d = μ₀(dΦ_E/dt)
    • C. i_d = (1/ε₀)(dΦ_E/dt)
    • D. i_d = i (always equal to conduction current)

    Answer: A — By definition, displacement current is i_d = ε₀(dΦ_E/dt); it equals conduction current only when the changing flux rate matches.

    Q2. In a charging capacitor, when a circular loop is drawn around the connecting wire outside the capacitor and another identical loop is drawn between the plates with the same boundary, Ampere's law initially seems to give different values of B. Why?

    • A. Because conduction current is zero between the plates, but displacement current is not ✓
    • B. Because the magnetic field is not actually the same at both locations
    • C. Because Ampere's law is invalid for time-varying current
    • D. Because the capacitor plates create a magnetic field that cancels B outside

    Answer: A — Ampere's law fails without displacement current because the wire loop encloses conduction current i, but the loop between plates encloses no conduction current—only the changing electric flux (displacement current ε₀dΦ_E/dt) fixes this.

    Q3. A parallel plate capacitor with plate area A = 0.1 m² is charged such that the electric field between the plates increases at a rate dE/dt = 10⁵ V/(m·s). Find the displacement current. (ε₀ = 8.85 × 10⁻¹² F/m)

    • A. 0.0885 A
    • B. 0.00885 A ✓
    • C. 8.85 × 10⁻⁶ A
    • D. 8.85 × 10⁻³ A

    Answer: B — i_d = ε₀A(dE/dt) = 8.85 × 10⁻¹² × 0.1 × 10⁵ = 8.85 × 10⁻⁹ × 10⁵ = 8.85 × 10⁻⁴ × 10 = 0.00885 A.

    Q4. Which statement about electromagnetic waves is NOT correct?

    • A. EM waves require a medium to propagate ✓
    • B. The electric and magnetic fields are perpendicular to each other
    • C. All EM waves travel at speed c = 3 × 10⁸ m/s in vacuum
    • D. A changing magnetic field can create an electric field

    Answer: A — EM waves do NOT require a medium; they propagate through vacuum at constant speed c, unlike sound waves which need a medium.

    Q5. In an electromagnetic wave, the electric field amplitude is 100 V/m. What is the magnetic field amplitude? (c = 3 × 10⁸ m/s, μ₀ = 4π × 10⁻⁷ T·m/A)

    • A. 3.33 × 10⁻⁷ T ✓
    • B. 3.33 × 10⁻⁶ T
    • C. 3.33 × 10⁻⁸ T
    • D. 3.33 × 10⁻⁹ T

    Answer: A — For EM waves, E/B = c, so B = E/c = 100/(3 × 10⁸) = 3.33 × 10⁻⁷ T.

    Q6. Consider the following statements: (I) Displacement current is a real flow of charge. (II) Displacement current produces a magnetic field just like conduction current does. Which is/are correct?

    • A. Both (I) and (II) are correct
    • B. Only (I) is correct
    • C. Only (II) is correct ✓
    • D. Neither (I) nor (II) is correct

    Answer: C — Displacement current is NOT a real flow of charge but a changing electric field; however, it DOES produce a magnetic field, just as conduction current does.

    Q7. The electromagnetic spectrum includes (in order of increasing frequency): radio, microwave, infrared, visible, ultraviolet, X-ray, gamma ray. Which type of EM wave is used for sterilization in hospitals?

    • A. Microwave
    • B. Ultraviolet ✓
    • C. X-ray
    • D. Gamma ray

    Answer: B — Ultraviolet (UV) radiation has sufficient energy to damage DNA in microorganisms, making it ideal for sterilization; gamma rays are also used but UV is the primary choice in hospitals.

    Q8. A charged parallel plate capacitor is disconnected from a battery. The electric field between the plates remains constant. What is the displacement current at this instant?

    • A. Zero, because the field is constant ✓
    • B. Zero, because no current flows in the external circuit
    • C. Equal to the conduction current that was flowing before disconnection
    • D. Infinite, because the field is confined

    Answer: A — Displacement current i_d = ε₀(dΦ_E/dt) depends on the rate of change of electric field; if E is constant, dE/dt = 0, so i_d = 0.

    Q9. Derive the expression for displacement current and explain why Maxwell's modification to Ampere's law was necessary to ensure the consistency of electromagnetic theory. (This is a conceptual question requiring brief reasoning.)

    • A. Displacement current = ε₀(dΦ_E/dt); without it, different surfaces gave different B values for the same loop boundary ✓
    • B. Displacement current = μ₀(dΦ_E/dt); it was added to make Ampere's law dimensionally consistent
    • C. Displacement current = (dQ/dt); it replaces conduction current in capacitors
    • D. Displacement current = ε₀(d²Φ_E/dt²); it accounts for accelerating charges

    Answer: A — When a capacitor charges, conduction current flows in the wire but no charge crosses between the plates; to maintain B consistency, the changing E-field must contribute as i_d = ε₀(dΦ_E/dt).

    Q10. Two electromagnetic waves, one radio wave and one gamma ray, travel through vacuum. Which statement is correct?

    • A. The gamma ray travels faster than the radio wave
    • B. Both travel at the same speed c, but the gamma ray has much higher frequency and shorter wavelength ✓
    • C. The radio wave has higher energy because it has lower frequency
    • D. The gamma ray travels slower because it has higher frequency and loses energy faster

    Answer: B — All EM waves travel at c in vacuum regardless of frequency; gamma rays have much shorter wavelengths and higher frequencies (higher energy) than radio waves.

    Flashcards

    What is displacement current, and why did Maxwell introduce it?

    Displacement current = ε₀(dΦ_E/dt); Maxwell added it to Ampere's law because changing electric fields in a capacitor must produce magnetic fields for consistency.

    State the equation for displacement current.

    i_d = ε₀(dΦ_E/dt), where Φ_E is electric flux through a surface.

    Why does Ampere's circuital law alone fail for a charging capacitor?

    Different surfaces with the same boundary give different enclosed currents (wire surface vs. surface between plates), so magnetic field should be same but Ampere's law alone predicts zero between plates.

    What is the relationship between changing E-field and B-field according to Maxwell?

    A time-varying electric field generates a magnetic field, just as a current does; this is the essence of displacement current.

    What was Hertz's 1885 contribution to electromagnetic waves?

    Hertz experimentally demonstrated the existence of electromagnetic waves, proving Maxwell's prediction correct.

    Name three types of electromagnetic waves and their wavelength ranges.

    Radio waves (~10⁶ m), visible light (~500 nm), gamma rays (~10⁻¹² m); they span from longest to shortest wavelengths.

    What is the speed of electromagnetic waves in vacuum?

    c ≈ 3 × 10⁸ m/s, derived from Maxwell's equations using c = 1/√(ε₀μ₀).

    How are E and B fields oriented in an electromagnetic wave?

    E and B fields are perpendicular to each other and both perpendicular to the direction of wave propagation.

    Why is the speed of light so important in Maxwell's theory?

    The speed predicted by Maxwell's equations matched the measured speed of light, proving light is an electromagnetic wave and unifying optics with electromagnetism.

    What is the key difference between conduction current and displacement current?

    Conduction current flows due to movement of charges in conductors; displacement current arises from changing electric flux even without charge motion (e.g., in capacitor dielectric).

    Important Board Questions

    Define displacement current and state the equation that relates it to the rate of change of electric flux. [2 marks]

    Displacement current = ε₀(dΦ_E/dt). Mention that it arises from changing E-field even without charge motion and produces magnetic field like conduction current.

    A parallel plate capacitor with plate area 0.5 m² is connected to a time-varying voltage source. The electric field between the plates increases uniformly from 0 to 10⁴ V/m in 2 seconds. Calculate the displacement current. (ε₀ = 8.85 × 10⁻¹² F/m) [5 marks]

    Find dE/dt = (10⁴ V/m)/(2 s) = 5 × 10³ V/(m·s). Then use i_d = ε₀A(dE/dt) = ε₀A × dE/dt. Show all steps: calculate rate of change, substitute into formula, compute numerical answer with units.

    Explain why Maxwell's modification of Ampere's law (adding displacement current) was essential for the consistency of electromagnetic theory. Describe the problem that arose when applying the original Ampere's circuital law to a charging capacitor and how displacement current resolved it. [6 marks]

    Original Ampere's law: ∮B·dl = μ₀i_conduction. Problem: a loop around the wire sees conduction current i, but a loop between the plates sees zero conduction current, yet B must be the same. Solution: displacement current i_d = ε₀(dΦ_E/dt) between plates makes both surfaces consistent. Explain this using Figures 8.1(a), (b), (c) from the text and state the modified law: ∮B·dl = μ₀(i_conduction + i_displacement).

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