**Electromagnetic Induction** is the phenomenon in which electric currents are generated in conductors by varying magnetic fields. This chapter bridges the gap between electricity and magnetism, establishing that moving electric charges produce magnetic fields and changing magnetic fields produce electric currents.
**Historical Context:**
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**Setup:** A bar magnet moved toward/away from a stationary coil connected to a galvanometer.
**Key Observations:**
**Physical Principle:** The relative motion changes the magnetic flux through the coil, inducing an emf.
**Setup:** A coil C₂ (connected to battery) is moved toward/away from stationary coil C₁ (connected to galvanometer).
**Key Observations:**
**Significance:** No permanent magnet needed; time-varying magnetic field from a moving current-carrying coil can induce current in another coil.
**Setup:** Two coils C₁ and C₂ held **stationary**. C₂ connected to battery through tapping key K; C₁ connected to galvanometer.
**Key Observations:**
**Critical Insight:** **Relative motion is NOT required.** What matters is **change in magnetic flux through the circuit**, whether due to motion or change in current (and hence magnetic field).
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**Definition:** Magnetic flux (Φ_B) is the measure of the total magnetic field passing through a surface. It quantifies how much magnetic field "pierces" through an area.
For a plane surface of area **A** in uniform magnetic field **B**:
**Φ_B = B · A = BA cos θ** [Equation 6.1]
Where:
**Key Points:**
For surfaces where field is non-uniform or surface is curved:
**Φ_B = Σ B_i · dA_i = ∫ B · dA** [Equation 6.2]
Where:
**SI Unit:**
**Example:** A circular loop of radius 0.1 m perpendicular to a magnetic field of 0.5 T has flux:
Φ_B = BA = 0.5 × π(0.1)² = 0.005π Wb ≈ 0.0157 Wb
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**Faraday's Great Insight:** After analyzing all his experiments, Faraday discovered that an **emf (electromotive force) is induced in a circuit when the magnetic flux through it changes with time**. The magnitude of induced emf depends on **how fast** the flux changes.
**ε = -dΦ_B/dt** [Equation 6.3]
**For N-turn coil:**
**ε = -N(dΦ_B/dt)** [Equation 6.4]
Where:
1. **Magnitude of induced emf is proportional to:**
2. **The induced emf opposes the change** that produces it (negative sign)
3. **Flux can change due to:**
Consider rectangular loop PQRS with one side PQ of length l moving with velocity v perpendicular to uniform magnetic field B (perpendicular to loop plane):
**Φ_B = B · A = B · l · x**
where x = variable distance from reference
**dΦ_B/dt = Bl(dx/dt) = Blv**
**ε = -dΦ_B/dt = -Blv** (magnitude: **ε = Blv**)
This is the motional emf formula for a straight conductor moving in a magnetic field.
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**The polarity (direction) of the induced emf is such that the induced current opposes the change in magnetic flux that produced it.**
The **negative sign** in Faraday's law (Equation 6.3) mathematically represents Lenz's law.
**Example 1: Magnet Approaching Coil**
**Example 2: Magnet Receding from Coil**
**Why Lenz's law must be true:**
If induced current could **aid** rather than oppose flux change, then:
1. Magnet approaching coil would be attracted faster and faster
2. Its kinetic energy and velocity would increase continuously
3. No external work needed — perpetual motion machine possible
4. **Violates Law of Conservation of Energy**
**Energy balance in reality:**
**For moving loops in magnetic field:**
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**Motional emf** is the emf induced in a straight conductor moving through a uniform magnetic field due to the change in magnetic flux through the circuit containing the conductor.
**Setup:** Rectangular conductor PQRS with movable arm PQ of length l, moving with constant velocity v perpendicular to uniform magnetic field B (perpendicular to plane of loop).
**Step 1 — Express magnetic flux:**
If distance RQ = x (changing with time),
**Φ_B = B · A = B · l · x**
**Step 2 — Find rate of change of flux:**
**dΦ_B/dt = Bl(dx/dt) = Bl · v**
(since dx/dt = velocity v)
**Step 3 — Apply Faraday's Law:**
**ε = -dΦ_B/dt = -Blv**
**Magnitude of motional emf:**
**ε = Blv** [Equation 6.5]
Where:
1. **Lorentz force on charge carriers:** When conductor moves through magnetic field, free electrons in conductor experience Lorentz force **F = q(v × B)**
2. **Charge separation:** Electrons accumulate at one end (say Q), leaving positive charges at other end (P)
3. **Potential difference develops:** This charge separation creates an emf between ends P and Q
4. **Direction (Right-hand rule):** If **v** points left and **B** points out of page, then **v × B** points upward, so electrons accumulate at top → bottom end becomes positive
If conductor PQ moves in closed circuit of total resistance R:
**Current: I = ε/R = Blv/R**
**Direction:** Using Lenz's law — current direction opposes flux increase/decrease:
**Example 1: Rod Moving in Uniform Field**
**Example 2: Generator Principle**
| Aspect | Motional EMF | Induced EMF (General) |
|--------|-------------|----------------------|
| **Cause** | Moving conductor in static B field | Changing magnetic flux (any reason) |
| **Formula** | ε = Blv | ε = -dΦ_B/dt |
| **Mechanism** | Lorentz force on charge carriers | Faraday's law |
| **Examples** | Moving rod, rotating coil, vehicle speedometer | Transformer, changing current coil |
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**Problem:** Square loop of side 10 cm and resistance 0.5 Ω placed vertically in east-west plane. Uniform magnetic field 0.10 T set up in northeast direction (45° to plane). Field decreases to zero in 0.70 s at steady rate. Find induced emf and current.
**Solution:**
**Step 1 — Find initial magnetic flux:**
**Step 2 — Find final flux:**
**Step 3 — Calculate rate of change:**
**Step 4 — Apply Faraday's Law (N=1):**
**Step 5 — Calculate current:**
**Note:** Earth's magnetic field also present but doesn't contribute because it's constant (steady field produces no emf).
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**Problem:** Circular coil, radius 10 cm, 500 turns, resistance 2 Ω placed with plane perpendicular to horizontal component of earth's field. Rotated 180° about vertical diameter in 0.25 s. Earth's field: B_h = 3.0 × 10⁻⁵ T. Find induced emf and current.
**Solution:**
**Step 1 — Find initial flux (θ = 0°):**
**Step 2 — Find final flux after 180° rotation (θ = 180°):**
**Step 3 — Calculate total flux change:**
**Step 4 — Apply Faraday's Law for N turns:**
**Step 5 — Calculate current:**
**Important Note:** These are **estimated average values**. Instantaneous emf and current vary during rotation depending on rotational speed at each instant. Values are averages over 0.25 s time interval.
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**Problem:** Three planar loops (rectangular, triangular, irregular) moving out of/into uniform magnetic field region perpendicular to loop plane (field pointing away from reader). Determine induced current direction.
**Solutions Using Lenz's Law:**
**(i) Rectangular loop entering field region:**
**(ii) Triangular loop exiting field region:**
**(iii) Irregular loop exiting field region:**
**Key Principle:** Use Lenz's law in three steps:
1. Determine if flux is increasing or decreasing
2. Determine field direction needed to oppose this change
3. Use right-hand rule: curl fingers in current direction, thumb points in field direction
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**Problem (a):** Stationary closed loop in fixed magnetic field of strong permanent magnets. Can current be generated?
**Answer:** **No.** However strong the magnets:
**Problem (b):** Closed loop moving normal to constant electric field between capacitor plates. Electric field normal to loop plane.
**Cases:**
**Answer:** **No current in either case.**
**Problem (c):** Rectangular loop vs circular loop both moving out of uniform magnetic field region at constant velocity v. Which has constant induced emf?
**Analysis:**
**Rectangular Loop:**
**Circular Loop:**
**Conclusion:** Rectangular loop experiences constant emf during uniform exit; circular loop does not.
**Problem (d):** Rotating rod between capacitor plates (rod and plates both rotating at angular velocity ω). Predict capacitor polarity.
**Setup from Figure 6.9:**
**Solution:**
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| Concept | Formula | Key Points |
|---------|---------|-----------|
| **Magnetic Flux** | Φ_B = BA cos θ | Maximum when θ=0°; scalar quantity; unit = Wb = T·m² |
| **Faraday's Law (1 turn)** | ε = \|dΦ_B/dt\| | Magnitude only; direction from Lenz's law |
| **Faraday's Law (N turns)** | ε = N\|dΦ_B/dt\| | N-turn coil increases emf by factor N |
| **Motional EMF** | ε = Blv | For straight conductor length l, perpendicular to B and v |
| **Induced Current** | I = ε/R | Requires complete circuit; opposes flux change per Lenz |
| **Lenz's Law** | Direction opposes Δ flux | Conservative: prevents perpetual motion; conserves energy |
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**Magnetic Flux (uniform field):** Φ_B = BA cos θ
**Magnetic Flux (non-uniform):** Φ_B = ∫B·dA
**Faraday's Law:** ε = -N(dΦ_B/dt)
**Motional EMF:** ε = Blv
**Induced Current:** I = ε/R = N|dΦ_B/dt|/R
**Power dissipated:** P = I²R = ε²/R = (Blv)²/R
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✓ Understand all three Faraday-Henry experiments and what each demonstrates
✓ Define magnetic flux and distinguish from electric flux
✓ State Faraday's law mathematically and explain negative sign using Lenz's law
✓ Apply Lenz's law using right-hand rule for current direction (at least 5 different scenarios)
✓ Derive motional emf (ε = Blv) from Faraday's law starting with Φ_B = Blx
✓ Solve numerical problems: finding emf, current, flux change with different loop geometries
✓ Analyze rotating coils: flux changes as coil rotates through magnetic field
✓ Explain energy conservation in context of Lenz's law (work done vs heat dissipated)
✓ Distinguish between motional emf and transformer emf (both follow Faraday's law)
✓ Multiple choice: recognizing when flux changes vs when it doesn't
Q1. A coil of area 100 cm² is placed in a uniform magnetic field of 0.5 T perpendicular to the coil plane. What is the magnetic flux through the coil?
Answer: A — ΦB = BA cosθ = 0.5 × 0.01 × cos(0°) = 0.005 Wb = 5 mWb (area must be converted to m²).
Q2. In Faraday's Experiment 6.1, when the magnet is held stationary inside the coil, the galvanometer shows no deflection. This is because:
Answer: B — Faraday's law states that induced emf depends on dΦB/dt; when the magnet is stationary, flux is constant, so its rate of change is zero, producing no induced emf or current.
Q3. A magnetic flux through a coil increases from 0 to 10 Wb in 2 seconds. What is the magnitude of the induced emf?
Answer: B — |ε| = |dΦB/dt| = |ΔΦB/Δt| = |10 − 0|/2 = 5 V.
Q4. In Experiment 6.3, when the key K is pressed, the galvanometer shows a momentary deflection. When the key is held continuously pressed, there is no deflection. Which statement correctly explains this observation?
Answer: A — Initially, current in C2 rises from zero to maximum, changing the flux through C1 and inducing emf; once steady, flux becomes constant and dΦB/dt = 0, so no induced emf.
Q5. In Experiment 6.2, the deflection in the galvanometer is larger when coil C2 is moved towards C1 faster. Which of the following correctly explains this?
Answer: B — By Faraday's law, |ε| = |dΦB/dt|; faster motion causes flux to change more rapidly, increasing |dΦB/dt| and thus the induced emf and current.
Q6. Which of the following statements is NOT correct about magnetic flux?
Answer: D — Magnetic flux ΦB = BA cosθ is proportional to cosine, not sine, of the angle θ between B and the area vector.
Q7. A coil is placed in a magnetic field such that the magnetic flux through it is increasing with time. According to Lenz's law, the induced current in the coil will produce a magnetic field that:
Answer: B — Lenz's law states that the induced current creates a magnetic field opposing the change in flux, so if flux is increasing, the induced field opposes this increase.
Q8. In Faraday's experiments, an iron rod is inserted along the axis of two coils. The induced emf in the nearby coil increases dramatically. This is primarily because:
Answer: B — Iron has high permeability (μ >> μ₀), which significantly amplifies the magnetic field produced by the coil carrying current, leading to a much larger change in flux and induced emf.
Q9. Two identical coils are placed near each other. In coil 1, the current increases from 0 to 2 A in 0.1 s. In coil 2, which is stationary, the induced emf is observed. If in another scenario the same current change occurs in 0.2 s instead, how will the induced emf in coil 2 change? (Assertion: The induced emf will remain the same. Reason: The induced emf depends only on the change in current, not on the rate of change.)
Answer: D — Induced emf depends on dΦB/dt (rate of change of flux); if the same flux change occurs over a longer time (0.2 s instead of 0.1 s), the rate decreases to half, so induced emf is halved.
Q10. A rectangular coil of dimensions 20 cm × 10 cm is rotated in a uniform magnetic field of 2 T such that the angle θ between the magnetic field and the normal to the coil changes from 0° to 90° in 0.5 seconds. Calculate the average induced emf. (Initial flux: ΦB,i = BA cos(0°); Final flux: ΦB,f = BA cos(90°))
Answer: A — A = 0.2 × 0.1 = 0.02 m². ΦB,i = 2 × 0.02 × 1 = 0.04 Wb. ΦB,f = 2 × 0.02 × 0 = 0 Wb. |ε_avg| = |ΔΦB/Δt| = |0 − 0.04|/0.5 = 0.8 V.
What is magnetic flux and what is its SI unit?
Magnetic flux ΦB = B·A = BA cosθ is the scalar product of magnetic field and area vector, with SI unit weber (Wb) or T·m².
State Faraday's law of electromagnetic induction.
The induced emf in a coil is equal to the negative rate of change of magnetic flux through it: ε = −dΦB/dt.
What is the key observation from Experiment 6.1?
Moving a bar magnet towards or away from a coil induces current only while the magnet is in motion; the direction of current reverses when the magnet's direction of motion reverses.
Why does Experiment 6.3 show deflection even without motion?
When the key is pressed, the current in coil C2 changes from zero to maximum, causing the magnetic flux through C1 to change rapidly, inducing emf momentarily.
What is the role of an iron rod in Faraday's experiments?
Inserting an iron rod along the axis of the coils dramatically increases the induced emf because iron has high permeability and greatly enhances the magnetic field.
What does Lenz's law state about induced currents?
Lenz's law states that the direction of the induced current is always such that it opposes the change in magnetic flux that produces it (indicated by the negative sign in Faraday's law).
Is absolute motion of a magnet necessary to induce current, or is relative motion sufficient?
Only relative motion between the magnet and coil is necessary; if the magnet is held fixed and the coil moves, the same induced current is observed.
What is the difference between magnetic flux and induced emf?
Magnetic flux ΦB measures the total magnetic field passing through a surface, while induced emf is generated by the rate of change of this flux with time.
In Experiment 6.3, why does the galvanometer show no deflection when the key is held continuously pressed?
Once the current in coil C2 becomes steady (constant), the magnetic flux through C1 becomes constant, so dΦB/dt = 0, producing zero induced emf and no deflection.
How do the results differ when the North-pole versus South-pole of the magnet is moved towards the coil?
Both poles produce the same magnitude of induced emf, but the direction of the induced current reverses because the direction of the magnetic field (and hence the direction of flux change) is opposite.
Define magnetic flux. A coil of 50 turns has an area of 200 cm² and is placed perpendicular to a magnetic field of 0.4 T. Calculate the total magnetic flux through the coil. [2 marks]
Magnetic flux is ΦB = B·A = BA cosθ (scalar); total flux for N-turn coil is N × BA. Convert area to m² and use θ = 0° since perpendicular.
Explain Faraday's law of electromagnetic induction with reference to Experiment 6.3. Why is there a momentary deflection in the galvanometer when the key is pressed and released, but no deflection when the key is held continuously pressed? [5 marks]
State Faraday's law (ε = −dΦB/dt). Explain: key press → current in C2 changes → flux through C1 changes → dΦB/dt ≠ 0 → induced emf. Held pressed → current becomes steady → dΦB/dt = 0 → no emf. Key release → current drops → flux decreases → opposite deflection.
Derive the expression for magnetic flux through a non-uniform magnetic field over a curved surface. How does Faraday's law (in its differential form) relate this concept to the induced emf? Explain with the help of Experiment 6.1 why the induced current is larger when the magnet is moved faster towards the coil. [6 marks]
For non-uniform field: ΦB = ∫ B·dA (integral form). Faraday's law: ε = −dΦB/dt. Faster motion → magnetic field and flux change more rapidly → larger |dΦB/dt| → larger |ε| → larger induced current. Justify each step with Experiment 6.1 observations.
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