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Vector Algebra

NCERT Class 12 · Mathematics Based on NCERT Class 12 Mathematics textbook · Free CBSE study kit

Chapter Notes

Introduction to Vectors

**Definition**: A quantity that has both **magnitude** (length) and **direction** is called a **vector**. A **directed line segment** AB (written as AB or **a**) represents a vector with:

  • **Initial point**: A (starting point)
  • **Terminal point**: B (ending point)
  • **Magnitude**: |AB| = distance from A to B (always non-negative)
  • **Direction**: indicated by the arrow from A to B
  • **Key Distinction**: Scalar quantities (length, mass, time, speed, temperature) have only magnitude. Vector quantities (displacement, velocity, acceleration, force) have both magnitude and direction.

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    Position Vector and Coordinate Representation

    **Position Vector**: For a point P(x, y, z) in 3D space with respect to origin O(0, 0, 0), the vector **OP** is called the **position vector** of P, denoted as **r** or **p**.

    **Magnitude Formula**:

    |**r**| = √(x² + y² + z²)

    **Direction Cosines**: For position vector **r** = **OP** of point P(x, y, z):

  • **Direction angles** α, β, γ are angles made with positive x, y, z axes respectively
  • **Direction cosines** l, m, n are defined as:
  • l = cos α = x/r
  • m = cos β = y/r
  • n = cos γ = z/r
  • **Fundamental property**: **l² + m² + n² = 1** (always)
  • **Direction Ratios**: Numbers proportional to direction cosines, denoted a, b, c (usually the components themselves):

  • For vector **r** = xi + yj + zk, direction ratios are a:b:c = x:y:z
  • **Important note**: a² + b² + c² ≠ 1 in general (unlike direction cosines)
  • Relationship: l = a/√(a²+b²+c²), m = b/√(a²+b²+c²), n = c/√(a²+b²+c²)
  • ---

    Types of Vectors

    **Zero Vector (Null Vector)**: Vector **0** where initial and terminal points coincide. Magnitude = 0, direction is undefined/arbitrary.

    **Unit Vector**: Vector with magnitude exactly 1 unit. For any vector **a** ≠ **0**, unit vector is: **â** = **a**/|**a**|

    **Coinitial Vectors**: Two or more vectors sharing the same initial point.

    **Collinear Vectors**: Vectors parallel to the same line, regardless of magnitude or direction. Vectors **a** and **b** are collinear if and only if **b** = λ**a** for some non-zero scalar λ.

    **Equal Vectors**: Vectors **AB** and **CD** are equal (written **AB** = **CD**) if:

  • Same magnitude: |**AB**| = |**CD**|
  • Same direction
  • Position of initial/terminal points is irrelevant
  • **Negative of a Vector**: Vector **−a** has same magnitude as **a** but opposite direction. Properties:

  • **a** + (−**a**) = **0**
  • |−**a**| = |**a**|
  • ---

    Addition of Vectors

    Triangle Law of Vector Addition

    When displacement goes from A → B → C, the net displacement from A → C is represented by:

    **AC** = **AB** + **BC**

    **Algebraic interpretation**: For vectors **a** and **b**, to find **a** + **b**:

    1. Position **a** from point A to B

    2. Position **b** from B to C (keeping magnitude and direction unchanged)

    3. Resultant **a** + **b** = **AC** (from initial point of **a** to terminal point of **b**)

    Parallelogram Law of Vector Addition

    If **a** and **b** are represented as adjacent sides of a parallelogram ABCD:

  • **a** = **AB**, **b** = **AD**
  • Resultant **a** + **b** = **AC** (diagonal through common point)
  • **AC** = **AB** + **BC** = **AB** + **AD** (since **BC** = **AD**)
  • Both laws are equivalent and give same result.

    Properties of Vector Addition

    **Property 1 - Commutative Law**: **a** + **b** = **b** + **a**

  • Proof: Using parallelogram ABCD where **AB** = **a**, **AD** = **b**, diagonal **AC** = **a** + **b**
  • From triangle ABC: **AC** = **AB** + **BC** = **a** + **b**
  • From triangle ADC: **AC** = **AD** + **DC** = **b** + **a** (since **DC** = **AB**)
  • Therefore **a** + **b** = **b** + **a**
  • **Property 2 - Associative Law**: (**a** + **b**) + **c** = **a** + (**b** + **c**)

  • Proof: Represent vectors as successive displacements
  • Whether you group them left or right, final position is same
  • Allows writing **a** + **b** + **c** without parentheses
  • **Additive Identity**: **a** + **0** = **0** + **a** = **a**

  • Zero vector is additive identity
  • **Vector Difference**: **a** − **b** = **a** + (−**b**)

  • Geometric: If we place **−b** (opposite direction of **b**) at terminal point of **a**, then **a** − **b** is resultant
  • ---

    Multiplication of Vector by Scalar

    **Definition**: For vector **a** and scalar λ, the product λ**a** is a vector such that:

  • **Magnitude**: |λ**a**| = |λ| · |**a**|
  • **Direction**:
  • Same as **a** if λ > 0
  • Opposite to **a** if λ < 0
  • Undefined if λ = 0 (gives zero vector)
  • **Important Cases**:

  • λ = 0: 0**a** = **0**
  • λ = 1: 1**a** = **a**
  • λ = −1: −**a** is negative of **a** (opposite direction, same magnitude)
  • λ = 1/|**a**|: λ**a** = unit vector **â**
  • **Collinearity via Scalar Multiplication**: Vectors **a** and **b** are collinear ⟺ **b** = λ**a** for some non-zero λ ∈ ℝ

    ---

    Components of a Vector - Standard Unit Vectors

    **Unit Vectors Along Axes**:

  • **î** = unit vector along x-axis = (1,0,0)
  • **ĵ** = unit vector along y-axis = (0,1,0)
  • **k̂** = unit vector along z-axis = (0,0,1)
  • Each has magnitude 1: |**î**| = |**ĵ**| = |**k̂**| = 1
  • **Component Form of Position Vector**: For point P(x, y, z), position vector is:

    **r** = x**î** + y**ĵ** + z**k̂**

    **Scalar Components**: x, y, z (the coefficients)

    **Vector Components**: x**î**, y**ĵ**, z**k̂** (components along each axis)

    **Magnitude from Components**:

    |**r**| = √(x² + y² + z²)

    Operations in Component Form

    For vectors **a** = a₁**î** + a₂**ĵ** + a₃**k̂** and **b** = b₁**î** + b₂**ĵ** + b₃**k̂**:

    **Addition**:

    **a** + **b** = (a₁ + b₁)**î** + (a₂ + b₂)**ĵ** + (a₃ + b₃)**k̂**

    **Subtraction**:

    **a** − **b** = (a₁ − b₁)**î** + (a₂ − b₂)**ĵ** + (a₃ − b₃)**k̂**

    **Scalar Multiplication**:

    λ**a** = λa₁**î** + λa₂**ĵ** + λa₃**k̂**

    **Equality**: **a** = **b** ⟺ a₁ = b₁, a₂ = b₂, a₃ = b₃

    **Collinearity**: **a** and **b** are collinear ⟺ a₁/b₁ = a₂/b₂ = a₃/b₃ (provided denominators ≠ 0)

    Unit Vector in a Given Direction

    **Formula**: **â** = **a**/|**a**| = **a**/√(a₁² + a₂² + a₃²)

    **Example**: For **a** = 2**î** + 3**ĵ** + **k̂**

  • |**a**| = √(4 + 9 + 1) = √14
  • **â** = (2**î** + 3**ĵ** + **k̂**)/√14 = (2/√14)**î** + (3/√14)**ĵ** + (1/√14)**k̂**
  • Direction Ratios and Direction Cosines from Components

    For **a** = a₁**î** + a₂**ĵ** + a₃**k̂**:

  • **Direction ratios**: a₁ : a₂ : a₃
  • **Direction cosines**:
  • l = a₁/√(a₁² + a₂² + a₃²)
  • m = a₂/√(a₁² + a₂² + a₃²)
  • n = a₃/√(a₁² + a₂² + a₃²)
  • **Example**: For **a** = **î** + **ĵ** − 2**k̂**

  • Direction ratios: 1:1:(−2)
  • |**a**| = √(1 + 1 + 4) = √6
  • Direction cosines: l = 1/√6, m = 1/√6, n = −2/√6
  • ---

    Vector Joining Two Points

    **Formula**: For points P₁(x₁, y₁, z₁) and P₂(x₂, y₂, z₂), the vector from P₁ to P₂ is:

    **P₁P₂** = (x₂ − x₁)**î** + (y₂ − y₁)**ĵ** + (z₂ − z₁)**k̂**

    **Derivation**: Using position vectors:

    **P₁P₂** = **OP₂** − **OP₁** = **r₂** − **r₁**

    **Magnitude**: |**P₁P₂**| = √[(x₂−x₁)² + (y₂−y₁)² + (z₂−z₁)²] (distance formula)

    **Example**: Vector from P(2, 3, 0) to Q(−1, −2, −4):

    **PQ** = (−1−2)**î** + (−2−3)**ĵ** + (−4−0)**k̂** = −3**î** − 5**ĵ** − 4**k̂**

    ---

    Section Formula

    Internal Division

    **Theorem**: Point R divides line segment PQ **internally** in ratio m:n ⟺ **PR** : **RQ** = m : n

    **Position Vector Formula**:

    **r** = (m**r₂** + n**r₁**)/(m + n)

    where **r₁** and **r₂** are position vectors of P and Q respectively.

    **Key insight**: Larger weight (m) is on terminal point (Q), smaller weight (n) on initial point (P).

    **Midpoint Formula** (when m = n):

    **r** = (**r₁** + **r₂**)/2

    External Division

    **Theorem**: Point R divides line segment PQ **externally** in ratio m:n ⟺ **PR** : **RQ** = m : n (with R outside segment)

    **Position Vector Formula**:

    **r** = (m**r₂** − n**r₁**)/(m − n)

    **Note**: m > n for external division; if m = n, denominators become zero (points at infinity).

    **Example - Internal Division**: P with **r₁** = 2**î** − **ĵ** + **k̂** and Q with **r₂** = **î** + 3**ĵ** − 5**k̂**, find R dividing PQ in ratio 2:1 internally:

    **r** = [2(**î** + 3**ĵ** − 5**k̂**) + 1(2**î** − **ĵ** + **k̂**)]/(2+1)

    = (4**î** + 5**ĵ** − 9**k̂**)/3

    **Example - External Division**: Same P and Q, ratio 2:1 externally:

    **r** = [2(**î** + 3**ĵ** − 5**k̂**) − 1(2**î** − **ĵ** + **k̂**)]/(2−1)

    = **0î** + 7**ĵ** − 11**k̂**

    ---

    Distributive Laws for Scalar Multiplication

    For vectors **a**, **b**, **c** and scalars k, m:

    **Law 1**: k(**a** + **b**) = k**a** + k**b**

    **Law 2**: (k + m)**a** = k**a** + m**a**

    **Law 3**: k(m**a**) = (km)**a**

    **Proof concept**: These follow from component-wise operations and distributivity of real number multiplication.

    ---

    Important Exam Points and Common Mistakes

    **Do Not Confuse**:

  • |−**a**| = |**a**| (magnitudes are always equal)
  • But −**a** ≠ **a** (different directions)
  • **Direction Cosines vs Ratios**:

  • Direction cosines always satisfy l² + m² + n² = 1
  • Direction ratios do NOT necessarily satisfy this
  • To convert ratios a, b, c to cosines: divide by √(a² + b² + c²)
  • **Equality of Vectors**:

  • Requires all three components to match
  • Position is irrelevant for free vectors
  • **a** + **b** = **c** + **d** does NOT imply **a** = **c** or **b** = **d**
  • **Collinearity Condition**:

  • **a** || **b** ⟺ **a** = λ**b** for non-zero λ
  • In component form: a₁/b₁ = a₂/b₂ = a₃/b₃
  • Works only if denominators are non-zero
  • **Section Formula Signs**:

  • Internal: both coefficients positive, sum in denominator
  • External: coefficients have opposite signs, difference in denominator
  • Remember: m is weight at terminal point, n at initial
  • MCQs — 10 Questions with Answers

    Q1. Which of the following is a vector quantity?

    • A. Speed of 20 m/s
    • B. Velocity of 20 m/s towards north ✓
    • C. Temperature of 30°C
    • D. Mass of 5 kg

    Answer: B — Velocity requires both magnitude (20 m/s) and direction (towards north); others are scalars lacking direction.

    Q2. If a point P has coordinates (3, 4, 0), what is the magnitude of its position vector?

    • A. 5 ✓
    • B. 7
    • C. √7
    • D. 12

    Answer: A — |OP| = √(3² + 4² + 0²) = √(9 + 16) = √25 = 5.

    Q3. For direction cosines l, m, n of a vector, which statement is NOT correct?

    • A. l² + m² + n² = 1
    • B. Each lies between −1 and 1
    • C. They are unique for any non-zero vector
    • D. They are proportional to direction ratios ✓

    Answer: D — Direction cosines are NOT proportional to direction ratios; rather, they are calculated from ratios via normalization: l = a/√(a²+b²+c²).

    Q4. Two vectors **a** and **b** are collinear. Which is necessarily true?

    • A. |**a**| = |**b**|
    • B. **a** and **b** are parallel to the same line ✓
    • C. **a** = **b**
    • D. Both have the same initial point

    Answer: B — Collinear vectors are parallel to the same line; they may differ in magnitude or direction, so A and C are not necessary.

    Q5. A displacement vector goes from point A(1,2,3) to point B(4,6,3). What is its magnitude?

    • A. 5 ✓
    • B. √41
    • C. 7
    • D. √34

    Answer: A — AB = (4−1, 6−2, 3−3) = (3, 4, 0); |AB| = √(3² + 4²) = √25 = 5.

    Q6. Which pair represents equal vectors in a square ABCD?

    • A. AB and CD
    • B. AB and BC
    • C. AB and DC ✓
    • D. AD and BC

    Answer: C — In square ABCD, AB and DC have the same magnitude and direction (both rightward, equal side length), making them equal vectors.

    Q7. The direction cosines of a vector are l = 1/2, m = 1/2, and n = ?. Find n.

    • A. 1/2
    • B. 1/√2 ✓
    • C. √2/2
    • D. 0

    Answer: B — Using l² + m² + n² = 1: (1/2)² + (1/2)² + n² = 1 → 1/4 + 1/4 + n² = 1 → n² = 1/2 → n = ±1/√2; taking positive value gives 1/√2.

    Q8. A girl travels from A to B (displacement **AB**), then from B to C (displacement **BC**). The net displacement is represented by: (i) **AB** + **BC** = **AC** (triangle law); (ii) This follows from free vector property. Which statement is correct?

    • A. Both (i) and (ii) are correct ✓
    • B. Only (i) is correct
    • C. Only (ii) is correct
    • D. Neither is correct

    Answer: A — The triangle law (i) is fundamental to vector addition, and (ii) enables parallel shifting so terminal point of AB meets initial point of BC.

    Q9. If direction ratios of a vector are 1, 2, 2, then its direction cosines are:

    • A. 1/3, 2/3, 2/3 ✓
    • B. 1, 2, 2
    • C. 1/5, 2/5, 2/5
    • D. Cannot be determined

    Answer: A — Magnitude of ratio vector = √(1² + 2² + 2²) = √9 = 3; direction cosines = (1/3, 2/3, 2/3) after normalization.

    Q10. How does the unit vector differ from the direction of the original vector **a**?

    • A. Unit vector points in opposite direction
    • B. Unit vector has magnitude 1 but same direction as **a** ✓
    • C. Unit vector cannot be defined for negative vectors
    • D. Direction is completely different from **a**

    Answer: B — The unit vector **â** = **a**/|**a**| preserves direction of **a** but scales magnitude to exactly 1.

    Flashcards

    What is a vector? Define with one example from physics.

    A vector is a quantity with both magnitude and direction (e.g., displacement 40 km north); a directed line segment from A to B represents it.

    What is the position vector of point P(x, y, z)?

    The vector OP from origin O(0,0,0) to point P(x,y,z), with magnitude |OP| = √(x² + y² + z²).

    Define direction cosines and state the fundamental identity.

    Direction cosines l, m, n are cosα, cosβ, cosγ (cosines of angles with x, y, z axes); key identity: l² + m² + n² = 1.

    What is the relationship between direction cosines and coordinates?

    If |OP| = r, then coordinates of P are (lr, mr, nr) where l = x/r, m = y/r, n = z/r.

    Distinguish between direction cosines and direction ratios.

    Direction cosines are l, m, n with l² + m² + n² = 1; direction ratios a, b, c are proportional to them with a² + b² + c² ≠ 1 in general.

    What is a unit vector and how is it denoted?

    A unit vector has magnitude 1; the unit vector in direction of vector a is denoted â = a/|a|.

    State the triangle law of vector addition with a diagram example.

    If a girl moves A→B then B→C, net displacement is AC = AB + BC; vectors add by placing terminal point of first at initial point of second.

    What are collinear vectors and how do they differ from equal vectors?

    Collinear vectors are parallel to the same line (may differ in magnitude/direction); equal vectors have identical magnitude AND direction regardless of position.

    Define the negative of a vector with notation.

    The negative of vector AB is the vector BA (same magnitude, opposite direction), denoted −AB = BA.

    What are coinitial vectors and give an example from a diagram.

    Two or more vectors sharing the same initial (starting) point are coinitial; example: vectors AB and AD from same point A in a square.

    Important Board Questions

    Classify the following as scalar or vector quantities: (i) 10 kg, (ii) 5 m/s north, (iii) 100° angle, (iv) Force of 50 Newton. Give reason for each classification. [2 marks]

    Scalars have magnitude only (e.g., mass, temperature); vectors require both magnitude and direction (e.g., velocity, force). Check if each quantity specifies a direction.

    A point P has coordinates (1, 2, 2) in 3D space. Find: (i) its position vector OP, (ii) magnitude |OP|, (iii) direction cosines l, m, n. Show all working steps. [5 marks]

    Position vector **OP** = (1, 2, 2); find magnitude using √(x² + y² + z²); then direction cosines l = x/|OP|, m = y/|OP|, n = z/|OP|. Verify: l² + m² + n² = 1.

    Given direction ratios of a vector are 2, −2, 1. Find its direction cosines. Also, if the vector has magnitude 18, find the vector's components. Derive the relation between direction cosines and direction ratios fully. [6 marks]

    First normalize direction ratios: √(2² + (−2)² + 1²) = 3. Then direction cosines = (2/3, −2/3, 1/3). Components = direction cosines × magnitude = 18 × (2/3, −2/3, 1/3) = (12, −12, 6). Show that direction cosines satisfy l² + m² + n² = 1 as proof.

    Next chapterThree Dimensional Geometry →

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