**Oscillatory motion** refers to any motion in which an object moves repeatedly back and forth about a mean (equilibrium) position. Unlike rectilinear or projectile motion, oscillations are repetitive in nature. Common examples include a swing, a pendulum, a boat on waves, and pistons in engines.
**Key distinction**: Every oscillatory motion is periodic, but not every periodic motion is oscillatory. For example, uniform circular motion is periodic but not oscillatory because there is no fixed equilibrium position about which the object oscillates.
**Real-life applications**:
The study of oscillations is fundamental because the concepts form the basis for understanding waves and many physical phenomena.
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**Periodic motion** is any motion that repeats itself at regular intervals of time. The motion follows a recognizable pattern that returns to its initial state after a fixed duration.
Examples shown in typical periodic motions include:
**Important distinction**: In oscillatory motion, the body has an **equilibrium position** within its path. When displaced from this position, a restoring force acts to bring it back, creating oscillations. For instance, a ball in a bowl experiences equilibrium at the bottom; when displaced, gravity and normal force combine to create a restoring force.
**Oscillations vs. Vibrations**: There is no physical difference. The terms differ only in frequency convention:
**Period (T)**: The smallest interval of time after which a motion repeats itself exactly. SI unit: **second (s)**.
**Frequency (ν)**: The number of complete oscillations or repetitions occurring per unit time. SI unit: **hertz (Hz) = s⁻¹**.
**Mathematical relation**:
$$ν = \frac{1}{T}$$
Therefore: $$T = \frac{1}{ν}$$
**Important notes**:
**Example 13.1**: A human heart beats 75 times in 60 seconds.
In oscillatory motion, **displacement** refers to the deviation of any physical quantity from a reference value, measured as a function of time.
**General definition**: Displacement is not restricted to position alone. It can represent:
**Key properties**:
**Fundamental periodic functions**:
$$f(t) = A \cos ωt \quad \text{or} \quad f(t) = A \sin ωt$$
where A is amplitude and ω is angular frequency.
**Period relationship**: If f(t) = A cos ωt has period T, then:
$$ωT = 2π$$
$$T = \frac{2π}{ω}$$
**General periodic function**:
$$f(t) = A \sin ωt + B \cos ωt$$
This can be rewritten as:
$$f(t) = D \sin(ωt + φ)$$
where:
$$D = \sqrt{A^2 + B^2} \quad \text{and} \quad \tan φ = \frac{B}{A}$$
**Fourier's Principle**: Any periodic function can be expressed as a superposition of sine and cosine functions of different periods with suitable coefficients. This is fundamental to the analysis of complex periodic phenomena.
**Example 13.2 Analysis**:
(i) **sin ωt + cos ωt** = √2 sin(ωt + π/4)
(ii) **sin ωt + cos 2ωt + sin 4ωt**
(iii) **e^(-ωt)**
(iv) **log(ωt)**
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**Simple Harmonic Motion (SHM)** is a special type of oscillatory motion in which the displacement of the particle from equilibrium varies sinusoidally with time.
**Mathematical equation**:
$$x(t) = A \cos(ωt + φ)$$
where:
**Alternative form**: The same motion can be expressed as:
$$x(t) = A \sin(ωt + φ') \quad \text{where } φ' = φ - \frac{π}{2}$$
Both representations are equivalent; choice depends on initial conditions.
**Definition**: The magnitude of maximum displacement from equilibrium position.
**Key characteristics**:
**Physical meaning**: Amplitude determines the total extent of oscillation and relates to the energy of the system.
**Instantaneous phase (ωt + φ)**: The argument of the cosine function at time t, determines the state of motion (position and velocity) at that instant.
**Phase constant (φ)**: The value of phase at t = 0.
$$φ = \arccos\left(\frac{x(0)}{A}\right)$$
If displacement at t = 0 is known, φ can be determined.
**Phase difference**: SHMs with same A and ω but different φ are out of phase. Time lag between two oscillations is related to phase difference Δφ by:
$$Δt = \frac{Δφ}{ω}$$
**Definition**: The rate of change of phase with time, measured in radians per second.
**Relationship with period**:
$$ω = \frac{2π}{T}$$
Therefore:
$$T = \frac{2π}{ω}$$
**Relationship with frequency**:
$$ω = 2πν$$
**Physical interpretation**: Angular frequency measures how quickly the oscillation completes its cycles. It is 2π times the ordinary frequency.
**SI unit**: rad/s or simply s⁻¹
**Example 13.3**: Determine which functions represent SHM.
(1) **sin ωt – cos ωt** = √2 sin(ωt – π/4)
(2) **sin² ωt** = ½ – ½cos 2ωt
**Displacement-time graph characteristics**:
**Key positions in one period**:
**Velocity behavior**: Maximum speed occurs at equilibrium (x = 0); zero speed at extreme positions (x = ±A).
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There is a fundamental geometric relationship between uniform circular motion and SHM: **the projection of uniform circular motion onto any diameter yields simple harmonic motion**.
**Setup**: Consider a particle P moving with constant angular speed ω on a circle of radius A in the horizontal plane.
**At time t = 0**: The position vector OP makes angle φ with the positive x-axis.
**At time t**: The particle has rotated through additional angle ωt, so OP makes angle (ωt + φ) with the x-axis.
**Projection on x-axis**: The x-coordinate of point P is:
$$x(t) = A \cos(ωt + φ)$$
This is precisely the equation for SHM.
**Projection on y-axis**: Similarly, the y-coordinate is:
$$y(t) = A \sin(ωt + φ)$$
This is SHM with phase difference π/2 from the x-projection.
When observing a particle in uniform circular motion from the side (edge-on viewing), the particle appears to oscillate back and forth along a diameter. This visual observation corresponds to viewing only the projection of the circular motion.
**Reference circle and reference particle**:
Despite this geometric connection, the forces are completely different:
**Example 13.4**: Obtaining SHM equations from circular motion.
For a particle with initial angular position π/4, rotating with period T = 4 s:
Position vector makes angle: (π/4) + 2πt/T
x-projection: $$x(t) = A \cos\left(\frac{2πt}{4} + \frac{π}{4}\right) = A \cos\left(\frac{πt}{2} + \frac{π}{4}\right)$$
This is SHM with amplitude A, period 4 s, and initial phase π/4 rad.
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**Definition**: Velocity is the time derivative of displacement.
Starting with displacement:
$$x(t) = A \cos(ωt + φ)$$
**Velocity equation**:
$$v(t) = \frac{dx}{dt} = -Aω \sin(ωt + φ)$$
This can also be written as:
$$v(t) = Aω \cos\left(ωt + φ + \frac{π}{2}\right)$$
**Maximum velocity** (amplitude of velocity):
$$v_{max} = Aω$$
This occurs when sin(ωt + φ) = ±1, i.e., when x = 0 (at equilibrium position).
**Minimum velocity**: v = 0 when x = ±A (at extreme positions).
**Phase relationship**: Velocity leads displacement by phase π/2 radians.
**Definition**: Acceleration is the time derivative of velocity.
$$a(t) = \frac{dv}{dt} = \frac{d^2x}{dt^2}$$
$$a(t) = -Aω^2 \cos(ωt + φ) = -ω^2 x(t)$$
**Critical result**:
$$a = -ω^2 x$$
This shows that **acceleration is directly proportional to displacement and always directed opposite to it** (restoring in nature).
**Maximum acceleration**:
$$a_{max} = Aω^2$$
This occurs at extreme positions where x = ±A.
**Zero acceleration**: a = 0 when x = 0 (at equilibrium position).
**Phase relationship**: Acceleration is 180° (π radians) out of phase with displacement.
Eliminating time from velocity and displacement equations:
From $v = -Aω \sin(ωt + φ)$ and $x = A \cos(ωt + φ)$
$$v^2 = A^2ω^2 \sin^2(ωt + φ) = A^2ω^2[1 - \cos^2(ωt + φ)]$$
$$v^2 = A^2ω^2 - ω^2x^2$$
$$v = ±ω\sqrt{A^2 - x^2}$$
**Physical interpretation**:
This relationship is independent of time and useful for solving problems without knowing time explicitly.
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**Definition**: The force that acts to restore the particle toward its equilibrium position is called the restoring force.
From Newton's second law and the acceleration in SHM:
$$F = ma = m \cdot (-ω^2x)$$
$$F = -mω^2 x$$
**Key characteristic**: The force is proportional to displacement and directed opposite to it.
For a particle to execute SHM, the restoring force must satisfy:
$$F = -kx$$
where k is the force constant (stiffness).
Comparing with F = ma = –mω²x:
$$k = mω^2$$
Therefore:
$$ω = \sqrt{\frac{k}{m}}$$
**Setup**: A mass m attached to a spring with spring constant k oscillating on a frictionless surface.
**Hooke's Law**: The spring force is F = –kx, where x is displacement from equilibrium.
**Angular frequency**:
$$ω = \sqrt{\frac{k}{m}}$$
**Period and frequency**:
$$T = 2π\sqrt{\frac{m}{k}}$$
$$ν = \frac{1}{2π}\sqrt{\frac{k}{m}}$$
**Physical insight**:
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For a particle in SHM with velocity $v = -Aω \sin(ωt + φ)$:
**Kinetic energy**:
$$KE = \frac{1}{2}mv^2 = \frac{1}{2}m A^2 ω^2 \sin^2(ωt + φ)$$
**Maximum kinetic energy** (at x = 0):
$$KE_{max} = \frac{1}{2}mA^2ω^2$$
**Minimum kinetic energy** (at x = ±A):
$$KE_{min} = 0$$
The potential energy associated with restoring force F = –kx = –mω²x is:
$$PE = \frac{1}{2}kx^2 = \frac{1}{2}mω^2 x^2 = \frac{1}{2}mω^2 A^2 \cos^2(ωt + φ)$$
**Maximum potential energy** (at x = ±A):
$$PE_{max} = \frac{1}{2}kA^2 = \frac{1}{2}mω^2A^2$$
**Minimum potential energy** (at x = 0):
$$PE_{min} = 0$$
**Total energy**:
$$E = KE + PE$$
$$E = \frac{1}{2}mω^2A^2\sin^2(ωt + φ) + \frac{1}{2}mω^2A^2\cos^2(ωt + φ)$$
$$E = \frac{1}{2}mω^2A^2[\sin^2(ωt + φ) + \cos^2(ωt + φ)]$$
$$E = \frac{1}{2}mω^2A^2 = \frac{1}{2}kA^2$$
**Critical result**: Total mechanical energy in SHM is **constant** and proportional to the square of amplitude.
**Key principle**: In undamped SHM, total mechanical energy is conserved. Energy continuously converts between kinetic and potential forms:
**Energy diagram**: The total energy line is horizontal; KE and PE curves are mirror images about E/2.
Over one complete period:
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A **simple pendulum** consists of:
**Equilibrium position**: The bob hangs vertically downward.
**Restoring force**: Arises from the component of gravitational force tangent to the circular arc.
For small angular displacement θ from vertical (in radians):
**Restoring force component** (tangential):
$$F = -mg \sin θ ≈ -mgθ$$ (for small θ)
where the approximation uses sin θ ≈ θ.
**Arc length displacement**: x ≈ Lθ
**Force equation**:
$$F = -mg \cdot \frac{x}{L} = -\frac{mg}{L}x$$
Comparing with F = –kx:
$$k = \frac{mg}{L}$$
**Angular frequency**:
$$ω = \sqrt{\frac{k}{m}} = \sqrt{\frac{mg/L}{m}} = \sqrt{\frac{g}{L}}$$
**Period of simple pendulum**:
$$T = 2π\sqrt{\frac{L}{g}}$$
**Frequency**:
$$ν = \frac{1}{2π}\sqrt{\frac{g}{L}}$$
**Independence of mass**: The period is independent of the mass of the bob. This remarkable result was discovered experimentally by Galileo.
**Dependence on length and gravity**:
**Small angle approximation**: The formula is valid only for small amplitude oscillations (θ < 15° or about 0.26 rad).
For small oscillations, the bob undergoes SHM:
**Total energy**:
$$E = \frac{1}{2}kA^2 = \frac{1}{2}mω^2A^2 = \frac{1}{2}m\left(\frac{g}{L}\right)A^2$$
At the lowest point (maximum KE):
$$KE_{max} = mgh_{max}$$
where h is vertical height difference from lowest point.
| Property | Simple Pendulum | Mass-Spring |
|----------|-----------------|-------------|
| Restoring force | Gravity component | Spring force |
| Equation | T = 2π√(L/g) | T = 2π√(m/k) |
| Mass dependence | Independent | Dependent |
| Validity | Small angles only | All amplitudes (ideal) |
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In real systems, oscillations decay over time due to:
**Damping force**: Typically proportional to velocity: F_d = –bv, where b is damping coefficient.
**Equation of motion**:
$$m\frac{d^2x}{dt^2} + b\frac{dx}{dt} + kx = 0$$
**Solution** (for underdamped case):
$$x(t) = Ae^{-bt/2m}\cos(ω't + φ)$$
where ω' < ω is the damped angular frequency.
**Key features**:
When an external periodic force is applied:
$$F_{ext} = F_0 \cos(Ωt)$$
where Ω is the driving frequency.
**Steady-state response**: The oscillator eventually oscillates at the driving frequency Ω, not its natural frequency ω.
**Resonance**: When driving frequency equals natural frequency (Ω = ω), the amplitude reaches a maximum.
**Practical importance**:
**Conditions for practical oscillations**: External driving force must be maintained to overcome damping and sustain oscillations.
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| Quantity | Formula | SI Unit |
|----------|---------|---------|
| Period | T = 1/ν = 2π/ω | s |
| Frequency | ν = 1/T | Hz = s⁻¹ |
| Angular frequency | ω = 2πν = 2π/T | rad/s |
| Displacement (SHM) | x = A cos(ωt + φ) | m |
| Velocity (SHM) | v = –Aω sin(ωt + φ) | m/s |
| Acceleration (SHM) | a = –ω²x | m/s² |
| Velocity-displacement | v² = ω²(A² – x²) | — |
| Force (SHM) | F = –kx = –mω²x | N |
| Kinetic energy | KE = ½mω²(A² – x²) | J |
| Potential energy | PE = ½mω²x² | J |
| Total energy | E = ½kA² = ½mω²A² | J |
| Spring-mass period | T = 2π√(m/k) | s |
| Simple pendulum period | T = 2π√(L/g) | s |
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**Must-know definitions**: Periodic motion, oscillatory motion, equilibrium position, amplitude, period, frequency, phase, simple harmonic motion
**Must-know relationships**: ν = 1/T, ω = 2πν, x = A cos(ωt + φ), v = –Aω sin(ωt + φ), a = –ω²x
**Must-know equations**: T = 2π√(m/k) for spring-mass, T = 2π√(L/g) for simple pendulum, E_total = ½kA² for energy
**Common mistakes to avoid**:
**Numerical problem types**:
Q1. A body executing periodic motion has a period of 2 seconds. What is its frequency?
Answer: A — Using ν = 1/T, frequency = 1/2 = 0.5 Hz.
Q2. Which of the following is an example of oscillatory motion?
Answer: C — Only the pendulum moves to and fro about an equilibrium position; others are either circular or non-repetitive.
Q3. A human heartbeat has a frequency of 1.25 Hz. What is the period between consecutive beats?
Answer: B — Period T = 1/ν = 1/1.25 = 0.8 s.
Q4. Which statement correctly distinguishes periodic motion from oscillatory motion?
Answer: B — Circular motion is periodic but not oscillatory; oscillatory motion always involves to-and-fro motion about equilibrium.
Q5. A mass-spring system oscillates with amplitude 0.1 m. At the equilibrium position, which is true?
Answer: B — At equilibrium, the restoring force is zero so acceleration is zero, but velocity reaches its maximum value before the body returns.
Q6. The period of oscillation of a quartz crystal is 1 microsecond (10⁻⁶ s). Its frequency in Hz is:
Answer: A — ν = 1/T = 1/(10⁻⁶) = 10⁶ Hz (1 megahertz).
Q7. Why is circular motion of a planet periodic but not oscillatory?
Answer: A — Oscillatory motion requires to-and-fro motion about equilibrium; circular motion repeats but lacks this characteristic.
Q8. Which statement about damped oscillations is NOT correct?
Answer: C — In damped oscillations, frequency remains essentially constant while amplitude decreases; frequency does not increase.
Q9. A tuning fork vibrates 440 times per second. If you want to express this as a period, how many milliseconds would one complete vibration take?
Answer: B — T = 1/ν = 1/440 s ≈ 0.00227 s = 2.27 ms (convert seconds to milliseconds).
Q10. Assertion: In oscillatory motion, the restoring force is always directed toward the equilibrium position. Reason: The force is proportional to displacement but opposite in sign.
Answer: A — Both statements are correct and logically connected: F = −kx means force opposes displacement, always pulling toward equilibrium (F ∝ −x).
What is the key difference between periodic and oscillatory motion?
Periodic motion repeats after time T, but oscillatory motion repeats to and fro about an equilibrium position where a restoring force acts.
Define period (T) and write its SI unit.
Period is the smallest time interval after which motion repeats; SI unit is second (s).
Write the relationship between frequency ν and period T.
ν = 1/T, meaning frequency in hertz equals the reciprocal of period in seconds.
What is an equilibrium position in oscillatory motion?
The position where no net external force acts on the body; if disturbed, a restoring force brings it back.
Why is circular motion periodic but not oscillatory?
Circular motion repeats after time period but does not move to and fro about a mean position.
What physical property creates oscillations in a mass-spring system?
The restoring force provided by the spring, which is proportional to displacement and directed toward equilibrium.
Give two real-life examples where oscillatory motion is important.
Vibrating strings in musical instruments produce sound, and oscillating atoms in solids determine temperature through their average vibration energy.
What is meant by damping in oscillatory motion?
Damping is the gradual loss of oscillation amplitude due to friction and other dissipative forces.
In simple harmonic motion, what is the direction of the net force?
Always directed toward the mean (equilibrium) position, opposite to the direction of displacement.
How do oscillations and vibrations differ in terminology?
Oscillations are called when frequency is low (tree branches), vibrations when frequency is high (musical strings).
Define oscillatory motion. Give two real-life examples and explain why they are considered oscillatory. [2 marks]
State that oscillatory motion is periodic to-and-fro about equilibrium with restoring force. Pick examples like pendulum or mass-spring and mention the restoring force in each case.
A body executing periodic motion completes 50 oscillations in 10 seconds. Calculate its frequency and period. If the amplitude of oscillation is 5 cm, how would you distinguish this from circular motion? [5 marks]
Use ν = number of oscillations / time to find frequency; then T = 1/ν to find period. Explain that oscillatory motion is to-and-fro about equilibrium while circular motion repeats but does not oscillate about a mean position.
Explain why every oscillatory motion is periodic, but not every periodic motion is oscillatory. Use appropriate diagrams (height-time graphs) to illustrate your answer with at least two contrasting examples. [6 marks]
Define periodic (repeats after time T) and oscillatory (to-and-fro about equilibrium). Use graphs: smooth sinusoidal curve for true oscillation (pendulum), stepped parabolic curve for non-oscillatory periodic motion (bouncing ball), and circular path for periodic but non-oscillatory motion (planet orbit). Identify restoring force in oscillatory cases.
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