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Oscillations

NCERT Class 11 · Physics Based on NCERT Class 11 Physics textbook · Free CBSE study kit

Chapter Notes

INTRODUCTION TO OSCILLATIONS

**Oscillatory motion** refers to any motion in which an object moves repeatedly back and forth about a mean (equilibrium) position. Unlike rectilinear or projectile motion, oscillations are repetitive in nature. Common examples include a swing, a pendulum, a boat on waves, and pistons in engines.

**Key distinction**: Every oscillatory motion is periodic, but not every periodic motion is oscillatory. For example, uniform circular motion is periodic but not oscillatory because there is no fixed equilibrium position about which the object oscillates.

**Real-life applications**:

  • Vibrating strings in musical instruments (sitar, guitar, violin)
  • Vibrations of air molecules enabling sound propagation
  • Atomic vibrations in solids determining temperature
  • AC voltage oscillations in electrical circuits
  • Drumheads and speaker diaphragms
  • The study of oscillations is fundamental because the concepts form the basis for understanding waves and many physical phenomena.

    ---

    PERIODIC AND OSCILLATORY MOTIONS

    Definition and Characteristics

    **Periodic motion** is any motion that repeats itself at regular intervals of time. The motion follows a recognizable pattern that returns to its initial state after a fixed duration.

    Examples shown in typical periodic motions include:

  • An insect climbing a ramp and falling repeatedly
  • A child climbing and descending stairs repeatedly
  • A ball bouncing between palm and ground (parabolic paths given by Newton's equations)
  • **Important distinction**: In oscillatory motion, the body has an **equilibrium position** within its path. When displaced from this position, a restoring force acts to bring it back, creating oscillations. For instance, a ball in a bowl experiences equilibrium at the bottom; when displaced, gravity and normal force combine to create a restoring force.

    **Oscillations vs. Vibrations**: There is no physical difference. The terms differ only in frequency convention:

  • **Oscillation**: Used when frequency is low (e.g., tree branch oscillations)
  • **Vibration**: Used when frequency is high (e.g., musical string vibrations)
  • Period and Frequency

    **Period (T)**: The smallest interval of time after which a motion repeats itself exactly. SI unit: **second (s)**.

    **Frequency (ν)**: The number of complete oscillations or repetitions occurring per unit time. SI unit: **hertz (Hz) = s⁻¹**.

    **Mathematical relation**:

    $$ν = \frac{1}{T}$$

    Therefore: $$T = \frac{1}{ν}$$

    **Important notes**:

  • 1 Hz = 1 oscillation per second
  • Frequency need not be an integer
  • Period and frequency are reciprocals
  • **Example 13.1**: A human heart beats 75 times in 60 seconds.

  • Frequency: ν = 75/(60 s) = 1.25 Hz = 1.25 s⁻¹
  • Period: T = 1/1.25 = 0.8 s
  • Displacement

    In oscillatory motion, **displacement** refers to the deviation of any physical quantity from a reference value, measured as a function of time.

    **General definition**: Displacement is not restricted to position alone. It can represent:

  • Position x from equilibrium (block on spring)
  • Angular displacement θ from vertical (pendulum)
  • Voltage across capacitor (AC circuit)
  • Pressure variations (sound wave propagation)
  • Electric and magnetic field variations (light waves)
  • **Key properties**:

  • Displacement can be positive or negative
  • For periodic motion, displacement is a periodic function of time
  • Most commonly represented by sinusoidal or cosinusoidal functions
  • Mathematical Representation of Periodic Functions

    **Fundamental periodic functions**:

    $$f(t) = A \cos ωt \quad \text{or} \quad f(t) = A \sin ωt$$

    where A is amplitude and ω is angular frequency.

    **Period relationship**: If f(t) = A cos ωt has period T, then:

    $$ωT = 2π$$

    $$T = \frac{2π}{ω}$$

    **General periodic function**:

    $$f(t) = A \sin ωt + B \cos ωt$$

    This can be rewritten as:

    $$f(t) = D \sin(ωt + φ)$$

    where:

    $$D = \sqrt{A^2 + B^2} \quad \text{and} \quad \tan φ = \frac{B}{A}$$

    **Fourier's Principle**: Any periodic function can be expressed as a superposition of sine and cosine functions of different periods with suitable coefficients. This is fundamental to the analysis of complex periodic phenomena.

    **Example 13.2 Analysis**:

    (i) **sin ωt + cos ωt** = √2 sin(ωt + π/4)

  • Periodic with period T = 2π/ω
  • (ii) **sin ωt + cos 2ωt + sin 4ωt**

  • sin ωt has period 2π/ω
  • cos 2ωt has period π/ω
  • sin 4ωt has period π/(2ω)
  • Overall period is LCM = 2π/ω (the largest period)
  • (iii) **e^(-ωt)**

  • Non-periodic; decreases monotonically to zero
  • Does not represent physical oscillation
  • (iv) **log(ωt)**

  • Non-periodic; increases monotonically to infinity
  • Cannot represent physical displacement
  • ---

    SIMPLE HARMONIC MOTION

    Definition and Mathematical Form

    **Simple Harmonic Motion (SHM)** is a special type of oscillatory motion in which the displacement of the particle from equilibrium varies sinusoidally with time.

    **Mathematical equation**:

    $$x(t) = A \cos(ωt + φ)$$

    where:

  • **x(t)**: displacement as function of time
  • **A**: amplitude (maximum displacement magnitude)
  • **ω**: angular frequency (rad/s)
  • **φ**: phase constant or initial phase (rad)
  • **ωt + φ**: instantaneous phase (rad)
  • **Alternative form**: The same motion can be expressed as:

    $$x(t) = A \sin(ωt + φ') \quad \text{where } φ' = φ - \frac{π}{2}$$

    Both representations are equivalent; choice depends on initial conditions.

    Amplitude (A)

    **Definition**: The magnitude of maximum displacement from equilibrium position.

    **Key characteristics**:

  • Always taken as positive by convention
  • Fixed for a given SHM
  • Displacement varies between +A and –A
  • Different SHMs can have same ω and φ but different amplitudes
  • **Physical meaning**: Amplitude determines the total extent of oscillation and relates to the energy of the system.

    Phase and Phase Constant

    **Instantaneous phase (ωt + φ)**: The argument of the cosine function at time t, determines the state of motion (position and velocity) at that instant.

    **Phase constant (φ)**: The value of phase at t = 0.

    $$φ = \arccos\left(\frac{x(0)}{A}\right)$$

    If displacement at t = 0 is known, φ can be determined.

    **Phase difference**: SHMs with same A and ω but different φ are out of phase. Time lag between two oscillations is related to phase difference Δφ by:

    $$Δt = \frac{Δφ}{ω}$$

    Angular Frequency (ω)

    **Definition**: The rate of change of phase with time, measured in radians per second.

    **Relationship with period**:

    $$ω = \frac{2π}{T}$$

    Therefore:

    $$T = \frac{2π}{ω}$$

    **Relationship with frequency**:

    $$ω = 2πν$$

    **Physical interpretation**: Angular frequency measures how quickly the oscillation completes its cycles. It is 2π times the ordinary frequency.

    **SI unit**: rad/s or simply s⁻¹

    **Example 13.3**: Determine which functions represent SHM.

    (1) **sin ωt – cos ωt** = √2 sin(ωt – π/4)

  • This is SHM with amplitude A = √2, period T = 2π/ω, and phase constant φ = –π/4
  • (2) **sin² ωt** = ½ – ½cos 2ωt

  • Periodic but NOT SHM (oscillates about ½, not zero; contains cos 2ωt term)
  • Period T = π/ω
  • Graphical Representation

    **Displacement-time graph characteristics**:

  • Smooth sinusoidal curve
  • Oscillates between +A and –A
  • Completes one full cycle in period T
  • Returns to same position and velocity after time T
  • **Key positions in one period**:

  • t = 0: x = A cos φ
  • t = T/4: x = A cos(ωT/4 + φ) = A cos(π/2 + φ)
  • t = T/2: x = A cos(πt + φ) = –A cos φ
  • t = 3T/4: x = A cos(3π/2 + φ)
  • t = T: x = A cos(2π + φ) = A cos φ (returns to initial value)
  • **Velocity behavior**: Maximum speed occurs at equilibrium (x = 0); zero speed at extreme positions (x = ±A).

    ---

    SIMPLE HARMONIC MOTION AND UNIFORM CIRCULAR MOTION

    Connection Between Circular Motion and SHM

    There is a fundamental geometric relationship between uniform circular motion and SHM: **the projection of uniform circular motion onto any diameter yields simple harmonic motion**.

    Geometric Derivation

    **Setup**: Consider a particle P moving with constant angular speed ω on a circle of radius A in the horizontal plane.

    **At time t = 0**: The position vector OP makes angle φ with the positive x-axis.

    **At time t**: The particle has rotated through additional angle ωt, so OP makes angle (ωt + φ) with the x-axis.

    **Projection on x-axis**: The x-coordinate of point P is:

    $$x(t) = A \cos(ωt + φ)$$

    This is precisely the equation for SHM.

    **Projection on y-axis**: Similarly, the y-coordinate is:

    $$y(t) = A \sin(ωt + φ)$$

    This is SHM with phase difference π/2 from the x-projection.

    Physical Interpretation

    When observing a particle in uniform circular motion from the side (edge-on viewing), the particle appears to oscillate back and forth along a diameter. This visual observation corresponds to viewing only the projection of the circular motion.

    **Reference circle and reference particle**:

  • **Reference particle**: The particle moving uniformly on the circle
  • **Reference circle**: The circle on which it moves
  • These are mathematical constructs helping visualize SHM as projection of circular motion
  • Important Distinction

    Despite this geometric connection, the forces are completely different:

  • **Circular motion**: Requires centripetal force directed toward center (perpendicular to velocity)
  • **Linear SHM**: Requires restoring force directed toward equilibrium, proportional to displacement
  • **Example 13.4**: Obtaining SHM equations from circular motion.

    For a particle with initial angular position π/4, rotating with period T = 4 s:

    Position vector makes angle: (π/4) + 2πt/T

    x-projection: $$x(t) = A \cos\left(\frac{2πt}{4} + \frac{π}{4}\right) = A \cos\left(\frac{πt}{2} + \frac{π}{4}\right)$$

    This is SHM with amplitude A, period 4 s, and initial phase π/4 rad.

    ---

    VELOCITY AND ACCELERATION IN SIMPLE HARMONIC MOTION

    Velocity in SHM

    **Definition**: Velocity is the time derivative of displacement.

    Starting with displacement:

    $$x(t) = A \cos(ωt + φ)$$

    **Velocity equation**:

    $$v(t) = \frac{dx}{dt} = -Aω \sin(ωt + φ)$$

    This can also be written as:

    $$v(t) = Aω \cos\left(ωt + φ + \frac{π}{2}\right)$$

    **Maximum velocity** (amplitude of velocity):

    $$v_{max} = Aω$$

    This occurs when sin(ωt + φ) = ±1, i.e., when x = 0 (at equilibrium position).

    **Minimum velocity**: v = 0 when x = ±A (at extreme positions).

    **Phase relationship**: Velocity leads displacement by phase π/2 radians.

    Acceleration in SHM

    **Definition**: Acceleration is the time derivative of velocity.

    $$a(t) = \frac{dv}{dt} = \frac{d^2x}{dt^2}$$

    $$a(t) = -Aω^2 \cos(ωt + φ) = -ω^2 x(t)$$

    **Critical result**:

    $$a = -ω^2 x$$

    This shows that **acceleration is directly proportional to displacement and always directed opposite to it** (restoring in nature).

    **Maximum acceleration**:

    $$a_{max} = Aω^2$$

    This occurs at extreme positions where x = ±A.

    **Zero acceleration**: a = 0 when x = 0 (at equilibrium position).

    **Phase relationship**: Acceleration is 180° (π radians) out of phase with displacement.

    Important Velocity-Displacement Relationship

    Eliminating time from velocity and displacement equations:

    From $v = -Aω \sin(ωt + φ)$ and $x = A \cos(ωt + φ)$

    $$v^2 = A^2ω^2 \sin^2(ωt + φ) = A^2ω^2[1 - \cos^2(ωt + φ)]$$

    $$v^2 = A^2ω^2 - ω^2x^2$$

    $$v = ±ω\sqrt{A^2 - x^2}$$

    **Physical interpretation**:

  • At equilibrium (x = 0): v = ±Aω (maximum)
  • At extreme positions (x = ±A): v = 0 (minimum)
  • This relationship is independent of time and useful for solving problems without knowing time explicitly.

    ---

    FORCE LAW FOR SIMPLE HARMONIC MOTION

    Restoring Force

    **Definition**: The force that acts to restore the particle toward its equilibrium position is called the restoring force.

    From Newton's second law and the acceleration in SHM:

    $$F = ma = m \cdot (-ω^2x)$$

    $$F = -mω^2 x$$

    **Key characteristic**: The force is proportional to displacement and directed opposite to it.

    Condition for SHM

    For a particle to execute SHM, the restoring force must satisfy:

    $$F = -kx$$

    where k is the force constant (stiffness).

    Comparing with F = ma = –mω²x:

    $$k = mω^2$$

    Therefore:

    $$ω = \sqrt{\frac{k}{m}}$$

    Spring-Mass System

    **Setup**: A mass m attached to a spring with spring constant k oscillating on a frictionless surface.

    **Hooke's Law**: The spring force is F = –kx, where x is displacement from equilibrium.

    **Angular frequency**:

    $$ω = \sqrt{\frac{k}{m}}$$

    **Period and frequency**:

    $$T = 2π\sqrt{\frac{m}{k}}$$

    $$ν = \frac{1}{2π}\sqrt{\frac{k}{m}}$$

    **Physical insight**:

  • Stiffer springs (larger k) → higher frequency
  • Larger mass (larger m) → lower frequency
  • ---

    ENERGY IN SIMPLE HARMONIC MOTION

    Kinetic Energy

    For a particle in SHM with velocity $v = -Aω \sin(ωt + φ)$:

    **Kinetic energy**:

    $$KE = \frac{1}{2}mv^2 = \frac{1}{2}m A^2 ω^2 \sin^2(ωt + φ)$$

    **Maximum kinetic energy** (at x = 0):

    $$KE_{max} = \frac{1}{2}mA^2ω^2$$

    **Minimum kinetic energy** (at x = ±A):

    $$KE_{min} = 0$$

    Potential Energy

    The potential energy associated with restoring force F = –kx = –mω²x is:

    $$PE = \frac{1}{2}kx^2 = \frac{1}{2}mω^2 x^2 = \frac{1}{2}mω^2 A^2 \cos^2(ωt + φ)$$

    **Maximum potential energy** (at x = ±A):

    $$PE_{max} = \frac{1}{2}kA^2 = \frac{1}{2}mω^2A^2$$

    **Minimum potential energy** (at x = 0):

    $$PE_{min} = 0$$

    Total Mechanical Energy

    **Total energy**:

    $$E = KE + PE$$

    $$E = \frac{1}{2}mω^2A^2\sin^2(ωt + φ) + \frac{1}{2}mω^2A^2\cos^2(ωt + φ)$$

    $$E = \frac{1}{2}mω^2A^2[\sin^2(ωt + φ) + \cos^2(ωt + φ)]$$

    $$E = \frac{1}{2}mω^2A^2 = \frac{1}{2}kA^2$$

    **Critical result**: Total mechanical energy in SHM is **constant** and proportional to the square of amplitude.

    Energy Conservation

    **Key principle**: In undamped SHM, total mechanical energy is conserved. Energy continuously converts between kinetic and potential forms:

  • When particle passes through equilibrium: KE = maximum, PE = minimum
  • When particle is at extreme positions: KE = minimum, PE = maximum
  • At any other point: both KE and PE are non-zero
  • **Energy diagram**: The total energy line is horizontal; KE and PE curves are mirror images about E/2.

    Average Energy

    Over one complete period:

  • **Average KE**: $\langle KE \rangle = \frac{E}{2} = \frac{1}{4}mω^2A^2$
  • **Average PE**: $\langle PE \rangle = \frac{E}{2} = \frac{1}{4}mω^2A^2$
  • ---

    THE SIMPLE PENDULUM

    Definition and Setup

    A **simple pendulum** consists of:

  • A small mass (bob) of mass m
  • A light inextensible string of length L
  • Suspended from a fixed point
  • Oscillating under gravity
  • **Equilibrium position**: The bob hangs vertically downward.

    **Restoring force**: Arises from the component of gravitational force tangent to the circular arc.

    Equation of Motion for Small Angles

    For small angular displacement θ from vertical (in radians):

    **Restoring force component** (tangential):

    $$F = -mg \sin θ ≈ -mgθ$$ (for small θ)

    where the approximation uses sin θ ≈ θ.

    **Arc length displacement**: x ≈ Lθ

    **Force equation**:

    $$F = -mg \cdot \frac{x}{L} = -\frac{mg}{L}x$$

    Comparing with F = –kx:

    $$k = \frac{mg}{L}$$

    Angular Frequency and Period

    **Angular frequency**:

    $$ω = \sqrt{\frac{k}{m}} = \sqrt{\frac{mg/L}{m}} = \sqrt{\frac{g}{L}}$$

    **Period of simple pendulum**:

    $$T = 2π\sqrt{\frac{L}{g}}$$

    **Frequency**:

    $$ν = \frac{1}{2π}\sqrt{\frac{g}{L}}$$

    Important Properties

    **Independence of mass**: The period is independent of the mass of the bob. This remarkable result was discovered experimentally by Galileo.

    **Dependence on length and gravity**:

  • Longer pendulum → longer period (√L relationship)
  • Stronger gravity → shorter period (1/√g relationship)
  • **Small angle approximation**: The formula is valid only for small amplitude oscillations (θ < 15° or about 0.26 rad).

    Practical Applications

  • **Timekeeping**: Pendulums were used in clocks for centuries
  • **Gravity measurement**: Measuring g using a simple pendulum
  • **Seismic detection**: Pendulums detect ground vibrations
  • Energy in Simple Pendulum

    For small oscillations, the bob undergoes SHM:

    **Total energy**:

    $$E = \frac{1}{2}kA^2 = \frac{1}{2}mω^2A^2 = \frac{1}{2}m\left(\frac{g}{L}\right)A^2$$

    At the lowest point (maximum KE):

    $$KE_{max} = mgh_{max}$$

    where h is vertical height difference from lowest point.

    Simple Pendulum vs. Mass-Spring System

    | Property | Simple Pendulum | Mass-Spring |

    |----------|-----------------|-------------|

    | Restoring force | Gravity component | Spring force |

    | Equation | T = 2π√(L/g) | T = 2π√(m/k) |

    | Mass dependence | Independent | Dependent |

    | Validity | Small angles only | All amplitudes (ideal) |

    ---

    DAMPED AND FORCED OSCILLATIONS

    Damping in Real Oscillations

    In real systems, oscillations decay over time due to:

  • Friction with surrounding medium
  • Air resistance
  • Internal friction in materials
  • Energy dissipation through heat
  • **Damping force**: Typically proportional to velocity: F_d = –bv, where b is damping coefficient.

    Damped Harmonic Motion

    **Equation of motion**:

    $$m\frac{d^2x}{dt^2} + b\frac{dx}{dt} + kx = 0$$

    **Solution** (for underdamped case):

    $$x(t) = Ae^{-bt/2m}\cos(ω't + φ)$$

    where ω' < ω is the damped angular frequency.

    **Key features**:

  • Amplitude decreases exponentially: A(t) = A₀e^(–bt/2m)
  • Frequency decreases slightly
  • Eventually comes to rest at equilibrium
  • Energy is continuously dissipated
  • Forced Oscillations and Resonance

    When an external periodic force is applied:

    $$F_{ext} = F_0 \cos(Ωt)$$

    where Ω is the driving frequency.

    **Steady-state response**: The oscillator eventually oscillates at the driving frequency Ω, not its natural frequency ω.

    **Resonance**: When driving frequency equals natural frequency (Ω = ω), the amplitude reaches a maximum.

    **Practical importance**:

  • Bridges resonating with wind or marching troops
  • Microwave ovens using resonance of water molecules
  • Radio tuning using resonance of LC circuits
  • Musical instruments exploiting resonance
  • **Conditions for practical oscillations**: External driving force must be maintained to overcome damping and sustain oscillations.

    ---

    SUMMARY OF KEY FORMULAS AND RELATIONSHIPS

    | Quantity | Formula | SI Unit |

    |----------|---------|---------|

    | Period | T = 1/ν = 2π/ω | s |

    | Frequency | ν = 1/T | Hz = s⁻¹ |

    | Angular frequency | ω = 2πν = 2π/T | rad/s |

    | Displacement (SHM) | x = A cos(ωt + φ) | m |

    | Velocity (SHM) | v = –Aω sin(ωt + φ) | m/s |

    | Acceleration (SHM) | a = –ω²x | m/s² |

    | Velocity-displacement | v² = ω²(A² – x²) | — |

    | Force (SHM) | F = –kx = –mω²x | N |

    | Kinetic energy | KE = ½mω²(A² – x²) | J |

    | Potential energy | PE = ½mω²x² | J |

    | Total energy | E = ½kA² = ½mω²A² | J |

    | Spring-mass period | T = 2π√(m/k) | s |

    | Simple pendulum period | T = 2π√(L/g) | s |

    ---

    EXAMINATION IMPORTANT POINTS

    **Must-know definitions**: Periodic motion, oscillatory motion, equilibrium position, amplitude, period, frequency, phase, simple harmonic motion

    **Must-know relationships**: ν = 1/T, ω = 2πν, x = A cos(ωt + φ), v = –Aω sin(ωt + φ), a = –ω²x

    **Must-know equations**: T = 2π√(m/k) for spring-mass, T = 2π√(L/g) for simple pendulum, E_total = ½kA² for energy

    **Common mistakes to avoid**:

  • Confusing period with angular frequency
  • Using degrees instead of radians in trigonometric functions
  • Forgetting negative sign in restoring force
  • Applying simple pendulum formula for large angles
  • Not recognizing that frequency is independent of amplitude
  • **Numerical problem types**:

  • Finding period/frequency from given data
  • Determining amplitude and phase from initial conditions
  • Calculating maximum velocity and acceleration
  • Energy conversions in oscillating systems
  • Finding length of pendulum for given period
  • Determining motion parameters from graphs
  • MCQs — 10 Questions with Answers

    Q1. A body executing periodic motion has a period of 2 seconds. What is its frequency?

    • A. 0.5 Hz ✓
    • B. 2 Hz
    • C. 4 Hz
    • D. 0.25 Hz

    Answer: A — Using ν = 1/T, frequency = 1/2 = 0.5 Hz.

    Q2. Which of the following is an example of oscillatory motion?

    • A. Earth orbiting the Sun
    • B. A ball rolling down an incline
    • C. A pendulum swinging back and forth ✓
    • D. A car moving at constant velocity

    Answer: C — Only the pendulum moves to and fro about an equilibrium position; others are either circular or non-repetitive.

    Q3. A human heartbeat has a frequency of 1.25 Hz. What is the period between consecutive beats?

    • A. 0.5 s
    • B. 0.8 s ✓
    • C. 1.25 s
    • D. 2.0 s

    Answer: B — Period T = 1/ν = 1/1.25 = 0.8 s.

    Q4. Which statement correctly distinguishes periodic motion from oscillatory motion?

    • A. Periodic motion must be oscillatory and vice versa
    • B. Oscillatory motion is to-and-fro about equilibrium; periodic motion just repeats after time T ✓
    • C. Oscillatory motion has no equilibrium position
    • D. Periodic motion only occurs in springs and pendulums

    Answer: B — Circular motion is periodic but not oscillatory; oscillatory motion always involves to-and-fro motion about equilibrium.

    Q5. A mass-spring system oscillates with amplitude 0.1 m. At the equilibrium position, which is true?

    • A. Velocity is zero and acceleration is maximum
    • B. Velocity is maximum and acceleration is zero ✓
    • C. Both velocity and acceleration are maximum
    • D. Both velocity and acceleration are zero

    Answer: B — At equilibrium, the restoring force is zero so acceleration is zero, but velocity reaches its maximum value before the body returns.

    Q6. The period of oscillation of a quartz crystal is 1 microsecond (10⁻⁶ s). Its frequency in Hz is:

    • A. 10⁶ Hz ✓
    • B. 10⁻⁶ Hz
    • C. 1 Hz
    • D. 10³ Hz

    Answer: A — ν = 1/T = 1/(10⁻⁶) = 10⁶ Hz (1 megahertz).

    Q7. Why is circular motion of a planet periodic but not oscillatory?

    • A. It repeats after a fixed period but does not move to and fro about an equilibrium position ✓
    • B. It does not have a defined period
    • C. It involves a restoring force directed toward center
    • D. Oscillatory and periodic motions are the same thing

    Answer: A — Oscillatory motion requires to-and-fro motion about equilibrium; circular motion repeats but lacks this characteristic.

    Q8. Which statement about damped oscillations is NOT correct?

    • A. Amplitude decreases with time due to friction
    • B. The oscillation eventually stops at equilibrium
    • C. Frequency increases as amplitude decreases ✓
    • D. Energy is dissipated through dissipative forces

    Answer: C — In damped oscillations, frequency remains essentially constant while amplitude decreases; frequency does not increase.

    Q9. A tuning fork vibrates 440 times per second. If you want to express this as a period, how many milliseconds would one complete vibration take?

    • A. 0.44 ms
    • B. 2.27 ms ✓
    • C. 440 ms
    • D. 4.4 ms

    Answer: B — T = 1/ν = 1/440 s ≈ 0.00227 s = 2.27 ms (convert seconds to milliseconds).

    Q10. Assertion: In oscillatory motion, the restoring force is always directed toward the equilibrium position. Reason: The force is proportional to displacement but opposite in sign.

    • A. Both Assertion and Reason are true; Reason explains Assertion ✓
    • B. Both are true; Reason does not explain Assertion
    • C. Assertion is true; Reason is false
    • D. Assertion is false; Reason is true

    Answer: A — Both statements are correct and logically connected: F = −kx means force opposes displacement, always pulling toward equilibrium (F ∝ −x).

    Flashcards

    What is the key difference between periodic and oscillatory motion?

    Periodic motion repeats after time T, but oscillatory motion repeats to and fro about an equilibrium position where a restoring force acts.

    Define period (T) and write its SI unit.

    Period is the smallest time interval after which motion repeats; SI unit is second (s).

    Write the relationship between frequency ν and period T.

    ν = 1/T, meaning frequency in hertz equals the reciprocal of period in seconds.

    What is an equilibrium position in oscillatory motion?

    The position where no net external force acts on the body; if disturbed, a restoring force brings it back.

    Why is circular motion periodic but not oscillatory?

    Circular motion repeats after time period but does not move to and fro about a mean position.

    What physical property creates oscillations in a mass-spring system?

    The restoring force provided by the spring, which is proportional to displacement and directed toward equilibrium.

    Give two real-life examples where oscillatory motion is important.

    Vibrating strings in musical instruments produce sound, and oscillating atoms in solids determine temperature through their average vibration energy.

    What is meant by damping in oscillatory motion?

    Damping is the gradual loss of oscillation amplitude due to friction and other dissipative forces.

    In simple harmonic motion, what is the direction of the net force?

    Always directed toward the mean (equilibrium) position, opposite to the direction of displacement.

    How do oscillations and vibrations differ in terminology?

    Oscillations are called when frequency is low (tree branches), vibrations when frequency is high (musical strings).

    Important Board Questions

    Define oscillatory motion. Give two real-life examples and explain why they are considered oscillatory. [2 marks]

    State that oscillatory motion is periodic to-and-fro about equilibrium with restoring force. Pick examples like pendulum or mass-spring and mention the restoring force in each case.

    A body executing periodic motion completes 50 oscillations in 10 seconds. Calculate its frequency and period. If the amplitude of oscillation is 5 cm, how would you distinguish this from circular motion? [5 marks]

    Use ν = number of oscillations / time to find frequency; then T = 1/ν to find period. Explain that oscillatory motion is to-and-fro about equilibrium while circular motion repeats but does not oscillate about a mean position.

    Explain why every oscillatory motion is periodic, but not every periodic motion is oscillatory. Use appropriate diagrams (height-time graphs) to illustrate your answer with at least two contrasting examples. [6 marks]

    Define periodic (repeats after time T) and oscillatory (to-and-fro about equilibrium). Use graphs: smooth sinusoidal curve for true oscillation (pendulum), stepped parabolic curve for non-oscillatory periodic motion (bouncing ball), and circular path for periodic but non-oscillatory motion (planet orbit). Identify restoring force in oscillatory cases.

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