**Organic chemistry** is the study of carbon-containing compounds (except carbonates, bicarbonates, and oxides of carbon). These compounds are vital for life and include DNA, proteins, carbohydrates, lipids, and synthetic polymers.
**Historical Context:**
**Importance**: Organic compounds are essential in medicines, dyes, plastics, fuels, textiles, and food products, making their study critical for understanding chemistry and material science.
---
**Carbon's tetrahedral nature** results from **sp³ hybridization**, where four hybrid orbitals arrange tetrahedrally (109.5° bond angles). Understanding molecular geometry is fundamental to predicting organic compound properties.
**Hybridization Types and Bond Characteristics:**
| Hybridization | Geometry | Bond Angle | Bond Strength | Example |
|---|---|---|---|---|
| **sp³** | Tetrahedral | 109.5° | Weakest single bonds | CH₄ (methane) |
| **sp²** | Trigonal planar | 120° | Intermediate | CH₂=CH₂ (ethene) |
| **sp** | Linear | 180° | Strongest | HC≡CH (ethyne) |
**Key Concept**: sp orbitals contain more s-character (50%) than sp² (33%) or sp³ (25%), making them shorter, stronger, and closer to the nucleus. This affects:
**Examples:**
**π bonds** form between adjacent atoms with **parallel p-orbital orientation**, creating a "side-on" overlap above and below the bonding axis.
**Critical Properties:**
1. **Restricted Rotation**: In C=C double bonds, rotation about the C-C bond is **restricted or prevented** because rotation disrupts p-orbital overlap. This creates **geometric isomerism** (cis/trans isomers in alkenes)
2. **Electron Density Distribution**: The electron cloud of a π bond lies above and below the molecular plane, making these electrons:
3. **Reactivity**: Molecules with π bonds (alkenes, alkynes, aromatics) are **more reactive** than saturated alkanes because π electrons are more polarizable
**Example**: In but-2-ene, the double bond prevents rotation:
**Exam Point**: σ bonds (from orbital head-on overlap) allow free rotation; π bonds (from parallel p-orbital overlap) restrict rotation and create double bond reactivity centers.
---
Organic structures are represented in multiple ways for clarity and simplicity:
**1. Complete Structural Formula (Lewis Structure)**
Example: Ethane (C₂H₆)
```
H—C—C—H or H—C—C—H
| | H H
H H
```
**2. Condensed Structural Formula**
**Examples:**
**3. Bond-line (Skeletal) Structural Formula**
**Example transformations:**
CH₃CH₂CH(OH)CH₃ can be represented as:
```
OH
|
_____|
/
(skeletal form shows a bent line with OH branch)
```
**Cyclic compound examples:**
**Exam Advantage**: Bond-line formulas appear frequently in questions; students must convert between all three formats.
Since organic molecules are **three-dimensional**, paper representations use specific conventions:
**Wedge-and-Dash Notation:**
**Example - Methane (CH₄)**:
```
H
|
H—C—H (with one H as wedge, one as dash)
|
H
```
**Molecular Models:**
Physical 3D models help visualize geometry:
---
Organic compounds are classified by **structure** and **functional groups**:
**I. Acyclic (Open-chain) Compounds**
**II. Cyclic (Closed-chain/Ring) Compounds**
**A. Alicyclic Compounds**
**B. Aromatic Compounds**
**C. Heterocyclic Compounds**
**Functional Group**: An atom or group of atoms bonded to carbon chain responsible for characteristic chemical properties
**Common Functional Groups:**
| Group | Name | Example | Parent Class |
|---|---|---|---|
| —OH | Hydroxyl | CH₃OH (methanol) | Alcohol |
| —CHO | Aldehyde | CH₃CHO (acetaldehyde) | Aldehyde |
| —CO— | Ketone | CH₃COCH₃ (acetone) | Ketone |
| —COOH | Carboxyl | CH₃COOH (acetic acid) | Carboxylic acid |
| —NH₂ | Amino | CH₃NH₂ (methylamine) | Amine |
| —X (Cl, Br, I) | Halogen | CH₃Cl (chloromethane) | Alkyl halide |
| —OR | Ether linkage | CH₃OCH₃ (dimethyl ether) | Ether |
**Polyvalent Compounds**: Contain two or more functional groups (e.g., amino acids contain —COOH and —NH₂)
**Definition**: A series of organic compounds where:
1. Each member contains the same functional group
2. Successive members differ by exactly **one CH₂ unit** (molecular weight differs by 14)
3. All members follow the **same general formula**
4. They exhibit **gradual variation in physical properties** and **similar chemical properties**
**Examples:**
**Alkane series**: General formula CₙH₂ₙ₊₂
**Alkene series**: General formula CₙH₂ₙ
**Alcohol series**: General formula CₙH₂ₙ₊₂O
**Properties within homologous series**:
---
The **International Union of Pure and Applied Chemistry (IUPAC)** system provides systematic names correlating structure to name—the reader can deduce structure from the name.
**Advantages over Trivial Names**:
**Trivial/Common Names** (still used):
**General Strategy**:
**Systematic name = Prefix + Parent + Suffix**
Where:
**Straight-Chain Alkanes:**
Saturated hydrocarbons containing only C-C single bonds; names end in **-ane**
| Carbons | Name | Molecular Formula |
|---|---|---|
| 1 | Methane | CH₄ |
| 2 | Ethane | C₂H₆ |
| 3 | Propane | C₃H₈ |
| 4 | Butane | C₄H₁₀ |
| 5 | Pentane | C₅H₁₂ |
| 6 | Hexane | C₆H₁₄ |
| 7 | Heptane | C₇H₁₆ |
| 8 | Octane | C₈H₁₈ |
| 9 | Nonane | C₉H₂₀ |
| 10 | Decane | C₁₀H₂₂ |
**Alkyl Groups** (substituents derived by removing H from alkanes):
**Branched Alkyl Groups**:
**Step 1: Identify Longest Carbon Chain**
Example: In a molecule with one 8-carbon chain and one 7-carbon chain, use octane as parent
**Step 2: Number the Chain**
Example:
```
CH₃—CH—CH₂—CH—CH₃
| |
CH₃ CH₃
```
Numbering: C1—C2—C3—C4—C5 (gives 2,4)
Not: C5—C4—C3—C2—C1 (gives 2,4 also, but count from left)
Use 2,4-dimethylpentane
**Step 3: Name and Position Substituents**
**Step 4: Write Complete Name**
**Examples:**
**Example 1:**
```
CH₃
|
CH₃—CH—CH₂—CH₂—CH₃
1 2 3 4 5
```
Name: **2-methylpentane** (one methyl on carbon 2 of pentane chain)
**Example 2:**
```
CH₃ CH₃
| |
CH₃—CH—CH₂—CH—CH₃
1 2 3 4 5
```
Name: **2,4-dimethylpentane** (two methyl groups; numbering gives 2,4—not 2,4 from other end which would also be 2,4)
**Example 3:**
```
CH₂CH₃ CH₃
| |
CH₃—CH—CH₂—CH—CH₃
1 2 3 4 5
```
Name: **4-ethyl-2-methylpentane** (alphabetical: "ethyl" before "methyl"; no "di-" because different groups)
**Example 4:**
```
CH₃—CH—CH₂—CH₂—CH—CH₂—CH₃
| |
CH₃ CH₂CH₃
1 2 6 7
```
Longest chain = 7 carbons (heptane)
Numbering from correct end: C1—C2—C3—C4—C5—C6—C7 (gives positions 2 and 6)
Name: **6-ethyl-2-methylheptane**
**Alkenes** (C=C double bond):
**Alkynes** (C≡C triple bond):
When functional groups are present, priority is given in this order:
1. Carboxylic acid (—COOH) → suffix **-oic acid**
2. Aldehyde (—CHO) → suffix **-al**
3. Ketone (C=O) → suffix **-one**
4. Alcohol (—OH) → suffix **-ol**
5. Amine (—NH₂) → suffix **-amine**
6. Alkene (C=C) → suffix **-ene** or **-enol** if OH also present
7. Alkyne (C≡C) → suffix **-yne**
**Examples:**
**1. Alcohol (—OH):**
**2. Aldehyde (—CHO):**
**3. Carboxylic Acid (—COOH):**
**4. With Multiple Functional Groups:**
---
**Mechanism**: The **step-by-step sequence of elementary reactions** by which a reactant is converted to product, showing **movement of electrons** and **formation/breaking of bonds**.
**Why Important:**
**Types of Bond Cleavage:**
**1. Homolytic Cleavage**
**2. Heterolytic Cleavage**
**Definition**: Redistribution of electron density in a molecule due to substituents, affecting reactivity.
**Types:**
**1. Inductive Effect**
Example: In chloromethane (CH₃Cl), chlorine's high electronegativity pulls electron density:
```
δ-Cl—CH₃(δ+)
```
The carbon becomes partially positive, affecting reactivity toward nucleophiles.
**2. Resonance Effect**
Example: In aniline (C₆H₅NH₂), nitrogen's lone pair resonates into benzene ring, stabilizing it:
```
NH₂ ↔ [ring with N-C double bond] ↔ ...
```
Makes aniline **more reactive** toward electrophiles than benzene.
**3. Effect on Reactivity**
---
Organic reactions are classified by **mechanism and outcome**:
An atom or group is replaced by another atom or group.
**Types:**
**1. Nucleophilic Substitution (SN)**
**2. Electrophilic Substitution (SE)**
**3. Free Radical Substitution**
Atoms are added across π bonds (C=C or C≡C), decreasing degree of unsaturation.
**Electrophilic Addition** (most common):
**Example mechanism:**
```
CH₂=CH₂ + HBr → [CH₃—CH₂⁺] → CH₃CH₂Br
(carbocation)
```
Removal of atoms/groups from adjacent carbons forming π bonds.
**Example:**
```
CH₃—CH₂—Br + KOH → CH₂=CH₂ + KBr + H₂O
```
Removal of HBr from ethyl bromide yields ethene.
Transfer of electrons between reactants.
**Examples:**
---
**1. Crystallization**
**2. Distillation**
**Example**: Separation of ethanol (b.p. 78°C) from water (b.p. 100°C)
**3. Sublimation**
**4. Chromatography**
**Principle**: Different compounds have different **Rf values** (ratio of distance traveled by compound to distance traveled by solvent)
---
**Objective**: Identify the **presence of elements** (C, H, N, S, halogens) and **functional groups** in organic compounds.
**Carbon and Hydrogen:**
**Nitrogen:**
**Sulfur:**
**Halogens (Cl, Br, I):**
**Alkenes (C=C):**
**Alkynes (C≡C):**
**Alcohols (—OH):**
**Phenols (—OH on benzene):**
**Aldehydes (—CHO):**
**Ketones (C=O):**
**Carboxylic Acids (—COOH):**
**Amines (—NH₂):**
---
**Objective**: Determine **percentage composition** of elements (C, H, N, S)
Q1. What is the hybridization of carbon in acetylene (HC≡CH)?
Answer: A — Acetylene has a triple bond (1 σ + 2 π), requiring sp hybridization to form 2 σ bonds and accommodate 2 π bonds in linear geometry.
Q2. Which statement about π bonds is correct?
Answer: C — π bonds form from sideways overlap of p-orbitals, creating electron density above and below the bonding plane; rotation is restricted and they are weaker than σ bonds.
Q3. Identify the number of σ bonds and π bonds in the compound CH₂=CH-C≡CH.
Answer: C — Structure has: C-C (σ), C=C (σ + π), C-C (σ), C≡C (σ + 2π), plus 4 C-H bonds (σ each) = 7 σ and 3 π total.
Q4. Which carbon atom is most electronegative in the molecule CH₃-C≡C-CH₂OH?
Answer: B — sp-hybridized carbons have 50% s-character, making them most electronegative; sp² has 33% s-character and sp³ has 25% s-character.
Q5. In the condensed formula (CH₃)₂CHCH₂CH₃, how many carbon atoms are bonded to three other carbon atoms?
Answer: B — The structure is (CH₃)₂CH-CH₂-CH₃; only the middle CH carbon (after the first C) is bonded to three other carbons (one primary and two methyls).
Q6. Which representation correctly shows 2-methylbutane using bond-line formula?
Answer: C — 2-methylbutane (5 carbons total) has a 4-carbon main chain with a methyl branch at C-2; bond-line shows 4 vertices for main chain plus one branch.
Q7. Which pair of statements about organic compounds is INCORRECT?
Answer: D — In acetylene H-C≡C-H, carbon is sp hybridized (linear), not sp² (which is trigonal planar); all other statements are correct.
Q8. Wöhler's synthesis of urea from ammonium cyanate in 1828 was significant because it:
Answer: B — This landmark synthesis disproved Berzelius's vital force theory by showing organic compounds like urea could be made synthetically from inorganic starting materials.
Q9. Consider ethene (C₂H₄): If a reagent approaches the double bond, why does it attack the π bond preferentially over σ bonds? [HOTS: Multi-step reasoning required]
Answer: B — The π-electron cloud (from p-orbital sideways overlap) extends above and below the C-C bond plane, making these electrons easily exposed and accessible to attacking reagents, while σ-electrons are localized between atoms.
Q10. In the following molecule, count the total number of σ bonds and identify which carbon has sp² hybridization: CH₃-CH=CH-CH₂-C≡N [Assertion-style: Both statements must be evaluated]
Answer: A — σ bonds: 3 C-H (methyl) + 1 C-C + 1 C=C (σ part) + 1 C-C + 1 C≡N (σ part) + 2 C-H on C-2 + 1 C-H on C-3 + 1 C-H on C-4 + 1 C-H on C-5 = 11 σ total; both carbons in the double bond are sp², but C-2 is specified.
What is the hybridization of carbon in methane (CH₄) and what is its shape?
Carbon is sp³ hybridized in methane, giving it a tetrahedral shape with 109.5° bond angles.
Why is rotation about a C=C double bond restricted?
Rotation is restricted because the π bond requires parallel p-orbital alignment; rotation would destroy maximum overlap and weaken the bond.
Which hybridized carbon (sp, sp², or sp³) is most electronegative and why?
sp-hybridized carbon is most electronegative because it has 50% s-character, and s-electrons are held closer to the nucleus than p-electrons.
How many σ and π bonds are in ethyne (HC≡CH)?
Ethyne has 3 σ bonds (1 C-C and 2 C-H) and 2 π bonds (between the two carbon atoms).
What is the key difference between Lewis structure and bond-line structural formula?
Lewis structure shows all atoms and electrons; bond-line formula omits C and H atoms and shows only zigzag lines and heteroatoms.
State Wöhler's synthesis and its significance.
Wöhler synthesized urea (NH₂CONH₂) from ammonium cyanate in 1828, disproving the 'vital force' theory and proving organic compounds can be made synthetically.
In a π bond, where is the electron charge cloud located relative to the bonding atoms?
The electron charge cloud of a π bond is located above and below the plane of the bonding atoms, making electrons easily accessible to attacking reagents.
How does hybridization affect bond length in carbon compounds?
sp-hybridized C forms shortest and strongest bonds; sp² is intermediate; sp³ forms longest and weakest bonds due to increasing p-character.
Why must all atoms in ethene (C₂H₄) lie in the same plane?
All atoms must be coplanar in ethene because the π bond requires parallel orientation of p-orbitals perpendicular to the molecular plane.
What is catenation and which element is most famous for this property?
Catenation is the ability of an element to form covalent bonds with itself; carbon is most famous for this due to its small size and high bond strength.
Define hybridization and explain why carbon in methane (CH₄) is sp³ hybridized. What is the shape of methane and its bond angle? [2 marks]
State that hybridization is mixing of atomic orbitals to form new hybrid orbitals; carbon's 1s²2s²2p² configuration requires sp³ mixing to form 4 equivalent bonds; tetrahedral shape with 109.5° angles result from this geometry.
Explain why rotation about the C=C double bond in ethene (C₂H₄) is restricted. Draw the structure and show how the π bond restricts rotation. What would happen if rotation occurred? [5 marks]
Show that π bond forms from sideways overlap of parallel p-orbitals; rotation would misalign p-orbitals and break π-bond overlap; draw the molecule showing p-orbitals perpendicular to the molecular plane; explain that the resulting loss of π bonding energy prevents free rotation.
Compare sp, sp², and sp³ hybridization in terms of (i) geometry, (ii) bond length, (iii) bond strength, and (iv) electronegativity of carbon. Justify your answer with reference to s-character. Give one example compound for each hybridization type. How does hybridization influence the reactivity of organic compounds? [6 marks]
Create a table showing linear/trigonal planar/tetrahedral for geometry; explain that higher s-character means electrons closer to nucleus → shorter, stronger bonds and higher electronegativity; justify using orbital penetration; provide HC≡CH (sp), C₂H₄ (sp²), CH₄ (sp³); explain that π bonds (from sp and sp²) are reactive sites attacked by electrophiles due to exposed electron density.
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