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Organic Chemistry: Some Basic Principles and Techniques

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Chapter Notes

COMPREHENSIVE CHAPTER NOTES: ORGANIC CHEMISTRY – SOME BASIC PRINCIPLES AND TECHNIQUES

GENERAL INTRODUCTION

**Organic chemistry** is the study of carbon-containing compounds (except carbonates, bicarbonates, and oxides of carbon). These compounds are vital for life and include DNA, proteins, carbohydrates, lipids, and synthetic polymers.

**Historical Context:**

  • Before 1828, scientists believed organic compounds could only be produced in living organisms due to a "vital force"
  • **Friedrich Wöhler's synthesis (1828)**: Synthesized urea (NH₂CONH₂) from inorganic ammonium cyanate (NH₄OCN), disproving the vital force theory
  • **Later syntheses**: Kolbe (1845) synthesized acetic acid; Berthelot (1856) synthesized methane
  • The development of electronic bonding theory modernized organic chemistry
  • **Importance**: Organic compounds are essential in medicines, dyes, plastics, fuels, textiles, and food products, making their study critical for understanding chemistry and material science.

    ---

    TETRAVALENCE OF CARBON: SHAPES OF ORGANIC COMPOUNDS

    The Shapes of Carbon Compounds

    **Carbon's tetrahedral nature** results from **sp³ hybridization**, where four hybrid orbitals arrange tetrahedrally (109.5° bond angles). Understanding molecular geometry is fundamental to predicting organic compound properties.

    **Hybridization Types and Bond Characteristics:**

    | Hybridization | Geometry | Bond Angle | Bond Strength | Example |

    |---|---|---|---|---|

    | **sp³** | Tetrahedral | 109.5° | Weakest single bonds | CH₄ (methane) |

    | **sp²** | Trigonal planar | 120° | Intermediate | CH₂=CH₂ (ethene) |

    | **sp** | Linear | 180° | Strongest | HC≡CH (ethyne) |

    **Key Concept**: sp orbitals contain more s-character (50%) than sp² (33%) or sp³ (25%), making them shorter, stronger, and closer to the nucleus. This affects:

  • **Bond length**: sp < sp² < sp³
  • **Bond strength**: sp > sp² > sp³
  • **Electronegativity**: Carbon with sp hybridization is most electronegative
  • **Examples:**

  • **Methane (CH₄)**: Carbon is sp³ hybridized; tetrahedral shape with H-C-H bonds of 109.5°
  • **Ethene (C₂H₄)**: Each carbon is sp² hybridized; trigonal planar, 120° bond angles
  • **Ethyne (C₂H₂)**: Each carbon is sp hybridized; linear molecule, 180° C-C-H angle
  • Characteristic Features of π Bonds

    **π bonds** form between adjacent atoms with **parallel p-orbital orientation**, creating a "side-on" overlap above and below the bonding axis.

    **Critical Properties:**

    1. **Restricted Rotation**: In C=C double bonds, rotation about the C-C bond is **restricted or prevented** because rotation disrupts p-orbital overlap. This creates **geometric isomerism** (cis/trans isomers in alkenes)

    2. **Electron Density Distribution**: The electron cloud of a π bond lies above and below the molecular plane, making these electrons:

  • Easily accessible to electrophilic reagents
  • More reactive than σ bonds
  • 3. **Reactivity**: Molecules with π bonds (alkenes, alkynes, aromatics) are **more reactive** than saturated alkanes because π electrons are more polarizable

    **Example**: In but-2-ene, the double bond prevents rotation:

  • **cis-but-2-ene**: CH₃ groups on same side (higher boiling point due to dipole)
  • **trans-but-2-ene**: CH₃ groups on opposite sides (lower boiling point)
  • **Exam Point**: σ bonds (from orbital head-on overlap) allow free rotation; π bonds (from parallel p-orbital overlap) restrict rotation and create double bond reactivity centers.

    ---

    STRUCTURAL REPRESENTATIONS OF ORGANIC COMPOUNDS

    Complete, Condensed, and Bond-line Structural Formulas

    Organic structures are represented in multiple ways for clarity and simplicity:

    **1. Complete Structural Formula (Lewis Structure)**

  • Shows every atom and every bond as a line (—) or pair of dots
  • Single bond: —; Double bond: ==; Triple bond: ≡
  • Lone pairs on heteroatoms may or may not be shown
  • Example: Ethane (C₂H₆)

    ```

    H—C—C—H or H—C—C—H

    | | H H

    H H

    ```

    **2. Condensed Structural Formula**

  • Atoms bonded to the same carbon are grouped together
  • Reduces lines but maintains structural information
  • Example: CH₃CH₂CH₃ (propane) instead of C₃H₈
  • **Examples:**

  • Ethane: CH₃CH₃
  • Ethene: CH₂=CH₂
  • 2-methylbutane: CH₃CH(CH₃)CH₂CH₃
  • **3. Bond-line (Skeletal) Structural Formula**

  • **Most simplified** representation used by organic chemists
  • **Rules**:
  • Carbon and hydrogen atoms are **not shown**
  • Vertices (corners) and line junctions represent **carbon atoms**
  • Each carbon is bonded to enough hydrogens to satisfy tetravalency (4 bonds total)
  • **Only heteroatoms** (O, N, S, halogen, etc.) and their hydrogens are explicitly written
  • Double/triple bonds shown as ==, ≡
  • **Example transformations:**

    CH₃CH₂CH(OH)CH₃ can be represented as:

    ```

    OH

    |

    _____|

    /

    (skeletal form shows a bent line with OH branch)

    ```

    **Cyclic compound examples:**

  • Cyclopropane: Triangle (3-membered ring)
  • Cyclopentane: Pentagon (5-membered ring)
  • Chlorocyclohexane: Hexagon with Cl labeled
  • **Exam Advantage**: Bond-line formulas appear frequently in questions; students must convert between all three formats.

    Three-Dimensional Representation of Organic Molecules

    Since organic molecules are **three-dimensional**, paper representations use specific conventions:

    **Wedge-and-Dash Notation:**

  • **Solid wedge (▲)**: Bond projecting **toward observer** (out of page)
  • **Dashed wedge (▼)**: Bond projecting **away from observer** (into page)
  • **Normal line**: Bond lies **in the plane of paper**
  • Broad end of wedge always faces observer
  • **Example - Methane (CH₄)**:

    ```

    H

    |

    H—C—H (with one H as wedge, one as dash)

    |

    H

    ```

    **Molecular Models:**

    Physical 3D models help visualize geometry:

  • **Framework model**: Shows only bonds (no atoms), emphasizes bonding pattern
  • **Ball-and-stick model**: Atoms as balls, bonds as sticks; good for showing angles
  • **Space-filling model**: Shows relative atomic sizes (van der Waals radii); emphasizes molecular volume
  • ---

    CLASSIFICATION OF ORGANIC COMPOUNDS

    Organic compounds are classified by **structure** and **functional groups**:

    Structural Classification

    **I. Acyclic (Open-chain) Compounds**

  • Carbon atoms form straight or branched chains
  • Also called **aliphatic compounds**
  • Examples: butane (CH₃CH₂CH₂CH₃), 2-methylpropane
  • **II. Cyclic (Closed-chain/Ring) Compounds**

    **A. Alicyclic Compounds**

  • Carbon atoms joined in a ring (no aromatic character)
  • Examples: cyclopropane (3-membered), cyclopentane (5-membered), cyclohexane (6-membered)
  • Exhibit mostly alkane-like properties
  • **B. Aromatic Compounds**

  • Contain benzene ring or related ring systems
  • Special stability and reactivity due to π-electron delocalization
  • **Benzenoid aromatics**: Benzene, naphthalene, aniline
  • **Non-benzenoid aromatics**: Tropone (7-membered ring with special properties)
  • **C. Heterocyclic Compounds**

  • Rings contain atoms other than carbon (N, O, S)
  • Examples: pyridine (C₅H₅N), furan (C₄H₄O), thiophene (C₄H₄S)
  • Can be alicyclic (tetrahydrofuran) or aromatic
  • Functional Group Classification

    **Functional Group**: An atom or group of atoms bonded to carbon chain responsible for characteristic chemical properties

    **Common Functional Groups:**

    | Group | Name | Example | Parent Class |

    |---|---|---|---|

    | —OH | Hydroxyl | CH₃OH (methanol) | Alcohol |

    | —CHO | Aldehyde | CH₃CHO (acetaldehyde) | Aldehyde |

    | —CO— | Ketone | CH₃COCH₃ (acetone) | Ketone |

    | —COOH | Carboxyl | CH₃COOH (acetic acid) | Carboxylic acid |

    | —NH₂ | Amino | CH₃NH₂ (methylamine) | Amine |

    | —X (Cl, Br, I) | Halogen | CH₃Cl (chloromethane) | Alkyl halide |

    | —OR | Ether linkage | CH₃OCH₃ (dimethyl ether) | Ether |

    **Polyvalent Compounds**: Contain two or more functional groups (e.g., amino acids contain —COOH and —NH₂)

    Homologous Series

    **Definition**: A series of organic compounds where:

    1. Each member contains the same functional group

    2. Successive members differ by exactly **one CH₂ unit** (molecular weight differs by 14)

    3. All members follow the **same general formula**

    4. They exhibit **gradual variation in physical properties** and **similar chemical properties**

    **Examples:**

    **Alkane series**: General formula CₙH₂ₙ₊₂

  • CH₄ (methane), C₂H₆ (ethane), C₃H₈ (propane), C₄H₁₀ (butane)...
  • **Alkene series**: General formula CₙH₂ₙ

  • C₂H₄ (ethene), C₃H₆ (propene), C₄H₈ (butene)...
  • **Alcohol series**: General formula CₙH₂ₙ₊₂O

  • CH₃OH (methanol), C₂H₅OH (ethanol), C₃H₇OH (propanol)...
  • **Properties within homologous series**:

  • **Physical properties** change gradually (boiling point increases with chain length)
  • **Chemical properties** remain similar (all alcohols undergo similar reactions)
  • Difference in boiling points for successive members ≈ 20-30°C
  • ---

    NOMENCLATURE OF ORGANIC COMPOUNDS

    IUPAC System of Nomenclature

    The **International Union of Pure and Applied Chemistry (IUPAC)** system provides systematic names correlating structure to name—the reader can deduce structure from the name.

    **Advantages over Trivial Names**:

  • Unambiguous identification
  • Predictable from structure
  • Allows naming of millions of unknown compounds
  • **Trivial/Common Names** (still used):

  • Acetic acid (CH₃COOH) instead of ethanoic acid
  • Formic acid instead of methanoic acid
  • Acetone instead of propanone
  • **General Strategy**:

    **Systematic name = Prefix + Parent + Suffix**

    Where:

  • **Prefix**: Indicates substituents/branches
  • **Parent**: Longest carbon chain (determines base name)
  • **Suffix**: Indicates functional group (-ane for alkane, -ene for alkene, -ol for alcohol, etc.)
  • IUPAC Nomenclature of Alkanes

    **Straight-Chain Alkanes:**

    Saturated hydrocarbons containing only C-C single bonds; names end in **-ane**

    | Carbons | Name | Molecular Formula |

    |---|---|---|

    | 1 | Methane | CH₄ |

    | 2 | Ethane | C₂H₆ |

    | 3 | Propane | C₃H₈ |

    | 4 | Butane | C₄H₁₀ |

    | 5 | Pentane | C₅H₁₂ |

    | 6 | Hexane | C₆H₁₄ |

    | 7 | Heptane | C₇H₁₆ |

    | 8 | Octane | C₈H₁₈ |

    | 9 | Nonane | C₉H₂₀ |

    | 10 | Decane | C₁₀H₂₂ |

    **Alkyl Groups** (substituents derived by removing H from alkanes):

  • Prefix: "meth-", "eth-", "prop-", "but-" + suffix "-yl"
  • CH₃— = methyl; C₂H₅— = ethyl; C₃H₇— = propyl
  • **Branched Alkyl Groups**:

  • **n-Propyl**: CH₃CH₂CH₂—
  • **Isopropyl**: (CH₃)₂CH— (two CH₃ groups on same C)
  • **n-Butyl**: CH₃CH₂CH₂CH₂—
  • **sec-Butyl**: CH₃CH₂CH(CH₃)— (secondary position)
  • **Isobutyl**: (CH₃)₂CHCH₂—
  • **tert-Butyl**: C(CH₃)₃— (tertiary position)
  • **Neopentyl**: (CH₃)₃CCH₂—
  • Rules for Naming Branched Alkanes

    **Step 1: Identify Longest Carbon Chain**

  • This becomes the **parent** alkane name
  • If multiple chains of same length, choose the one with most branches
  • Example: In a molecule with one 8-carbon chain and one 7-carbon chain, use octane as parent

    **Step 2: Number the Chain**

  • Number from the end giving **lowest numbers** to substituents
  • If multiple choices give same total, lowest number goes to first point of difference
  • Example:

    ```

    CH₃—CH—CH₂—CH—CH₃

    | |

    CH₃ CH₃

    ```

    Numbering: C1—C2—C3—C4—C5 (gives 2,4)

    Not: C5—C4—C3—C2—C1 (gives 2,4 also, but count from left)

    Use 2,4-dimethylpentane

    **Step 3: Name and Position Substituents**

  • Write position number, hyphen, then substituent name
  • If two identical substituents: use di-, tri-, tetra-, penta- (without considering these prefixes in alphabetical order)
  • **Step 4: Write Complete Name**

  • Alphabetical order of different substituents (but not counting di-, tri- etc.)
  • Separate numbers from letters by hyphens
  • Separate numbers from numbers by commas
  • No space between "methyl" and "pentane" in "2-methylpentane"
  • **Examples:**

    **Example 1:**

    ```

    CH₃

    |

    CH₃—CH—CH₂—CH₂—CH₃

    1 2 3 4 5

    ```

    Name: **2-methylpentane** (one methyl on carbon 2 of pentane chain)

    **Example 2:**

    ```

    CH₃ CH₃

    | |

    CH₃—CH—CH₂—CH—CH₃

    1 2 3 4 5

    ```

    Name: **2,4-dimethylpentane** (two methyl groups; numbering gives 2,4—not 2,4 from other end which would also be 2,4)

    **Example 3:**

    ```

    CH₂CH₃ CH₃

    | |

    CH₃—CH—CH₂—CH—CH₃

    1 2 3 4 5

    ```

    Name: **4-ethyl-2-methylpentane** (alphabetical: "ethyl" before "methyl"; no "di-" because different groups)

    **Example 4:**

    ```

    CH₃—CH—CH₂—CH₂—CH—CH₂—CH₃

    | |

    CH₃ CH₂CH₃

    1 2 6 7

    ```

    Longest chain = 7 carbons (heptane)

    Numbering from correct end: C1—C2—C3—C4—C5—C6—C7 (gives positions 2 and 6)

    Name: **6-ethyl-2-methylheptane**

    Nomenclature of Alkenes and Alkynes

    **Alkenes** (C=C double bond):

  • General formula: CₙH₂ₙ
  • Suffix: **-ene**
  • Position of double bond indicated by **lowest number** of carbons at either end
  • Examples:
  • CH₂=CH—CH₂—CH₃ → **but-1-ene** (double bond at C1)
  • CH₃—CH=CH—CH₃ → **but-2-ene** (double bond at C2)
  • **Alkynes** (C≡C triple bond):

  • General formula: CₙH₂ₙ₋₂
  • Suffix: **-yne**
  • Position indicated by lowest number
  • Examples:
  • HC≡C—CH₂—CH₃ → **but-1-yne**
  • CH₃—C≡C—CH₃ → **but-2-yne**
  • Nomenclature of Compounds with Functional Groups

    When functional groups are present, priority is given in this order:

    1. Carboxylic acid (—COOH) → suffix **-oic acid**

    2. Aldehyde (—CHO) → suffix **-al**

    3. Ketone (C=O) → suffix **-one**

    4. Alcohol (—OH) → suffix **-ol**

    5. Amine (—NH₂) → suffix **-amine**

    6. Alkene (C=C) → suffix **-ene** or **-enol** if OH also present

    7. Alkyne (C≡C) → suffix **-yne**

    **Examples:**

    **1. Alcohol (—OH):**

  • CH₃CH₂OH → **ethanol** (2 carbons in chain + -ol)
  • HOCH₂CH₂CH₃ → **propan-1-ol** (number position of OH)
  • **2. Aldehyde (—CHO):**

  • CH₃CHO → **ethanal** (C in CHO counts as C1)
  • CH₃CH₂CHO → **propanal**
  • **3. Carboxylic Acid (—COOH):**

  • CH₃COOH → **ethanoic acid** (C in COOH = C1)
  • HOOC—CH₂—COOH → **propanedioic acid**
  • **4. With Multiple Functional Groups:**

  • HOCH₂CHO → **2-hydroxyethanal** (aldehyde has priority)
  • HOCH₂CH₂OH → **ethane-1,2-diol** (two OH groups)
  • ---

    ORGANIC REACTION MECHANISMS

    Concept of Organic Reaction Mechanism

    **Mechanism**: The **step-by-step sequence of elementary reactions** by which a reactant is converted to product, showing **movement of electrons** and **formation/breaking of bonds**.

    **Why Important:**

  • Explains **reaction pathways** and **reaction rates**
  • Predicts **products and by-products**
  • Helps design synthetic routes
  • Explains effect of conditions on reactions
  • **Types of Bond Cleavage:**

    **1. Homolytic Cleavage**

  • Bond breaks such that **each fragment gets one electron**
  • Produces **free radicals** (atoms with unpaired electrons, denoted by •)
  • Occurs with heat, light, or peroxides
  • Example: Cl—Cl → Cl• + Cl• (photochemical cleavage)
  • Results in **non-polar products** even if bond was polar
  • **2. Heterolytic Cleavage**

  • Bond breaks such that **both electrons go to one fragment**
  • Produces **cation and anion**
  • Occurs in polar solvents, with polar reagents
  • Example: C—Br → C⁺ + Br⁻ (in solution)
  • Results in **ionic intermediates**
  • Electronic Displacement Effects

    **Definition**: Redistribution of electron density in a molecule due to substituents, affecting reactivity.

    **Types:**

    **1. Inductive Effect**

  • **Permanent shift** of electron density through σ bonds
  • Caused by **electronegativity difference** between atoms
  • Effect **decreases with distance** from source
  • **Electron-withdrawing groups** (EWG): F, Cl, Br, NO₂, CN (pull electrons toward themselves)
  • **Electron-donating groups** (EDG): alkyl, —OH, —OR (push electrons away)
  • Example: In chloromethane (CH₃Cl), chlorine's high electronegativity pulls electron density:

    ```

    δ-Cl—CH₃(δ+)

    ```

    The carbon becomes partially positive, affecting reactivity toward nucleophiles.

    **2. Resonance Effect**

  • **Delocalization** of π electrons (or lone pairs) through π-bonded systems
  • Results in **stabilization** of carbocations and carbanions
  • **Electron-donating resonance**: —OR, —NR₂ groups donate electrons through resonance to conjugated system
  • **Electron-withdrawing resonance**: —C=O, —CN groups withdraw through resonance
  • Example: In aniline (C₆H₅NH₂), nitrogen's lone pair resonates into benzene ring, stabilizing it:

    ```

    NH₂ ↔ [ring with N-C double bond] ↔ ...

    ```

    Makes aniline **more reactive** toward electrophiles than benzene.

    **3. Effect on Reactivity**

  • **π bonds** are major sites of electrophilic attack (high electron density above/below plane)
  • **EWG** (like —NO₂) **decreases electron density** at double bond, **deactivates** molecule
  • **EDG** (like —OH) **increases electron density**, **activates** molecule toward electrophiles
  • **Steric effects**: Bulky groups physically block access to reactive site
  • ---

    TYPES OF ORGANIC REACTIONS

    Organic reactions are classified by **mechanism and outcome**:

    Substitution Reactions

    An atom or group is replaced by another atom or group.

    **Types:**

    **1. Nucleophilic Substitution (SN)**

  • Nucleophile (electron-rich species: OH⁻, CN⁻, etc.) attacks carbon bearing leaving group
  • Occurs at **sp³ carbon** (saturated)
  • Examples:
  • CH₃Br + OH⁻ → CH₃OH + Br⁻ (nucleophilic displacement)
  • RCl + NH₃ → RNH₂ + HCl (amine formation)
  • **2. Electrophilic Substitution (SE)**

  • Electrophile (electron-poor species: H⁺, Br⁺, NO₂⁺) attacks electron-rich π systems
  • Common in **aromatic rings**
  • Example: C₆H₆ + Br₂ → C₆H₅Br + HBr (bromination of benzene)
  • **3. Free Radical Substitution**

  • Mechanism involves **free radical intermediates**
  • Requires **heat or light**
  • Example: CH₄ + Cl₂ → CH₃Cl + HCl (chlorination under UV light)
  • Addition Reactions

    Atoms are added across π bonds (C=C or C≡C), decreasing degree of unsaturation.

    **Electrophilic Addition** (most common):

  • π electrons (nucleophilic) attacked by electrophile
  • Example: C₂H₄ + HBr → C₂H₅Br (addition to alkene)
  • Mechanism: Formation of carbocation intermediate
  • **Example mechanism:**

    ```

    CH₂=CH₂ + HBr → [CH₃—CH₂⁺] → CH₃CH₂Br

    (carbocation)

    ```

    Elimination Reactions

    Removal of atoms/groups from adjacent carbons forming π bonds.

    **Example:**

    ```

    CH₃—CH₂—Br + KOH → CH₂=CH₂ + KBr + H₂O

    ```

    Removal of HBr from ethyl bromide yields ethene.

    Oxidation-Reduction Reactions

    Transfer of electrons between reactants.

    **Examples:**

  • **Oxidation of alcohols**: CH₃CH₂OH + [O] → CH₃CHO (to aldehyde) or → CH₃COOH (to carboxylic acid)
  • **Hydrogenation of alkenes**: CH₂=CH₂ + H₂ → CH₃CH₃ (reduction using catalyst)
  • ---

    TECHNIQUES OF PURIFICATION OF ORGANIC COMPOUNDS

    Physical Methods

    **1. Crystallization**

  • **Principle**: Differential solubility in hot vs. cold solvent
  • **Procedure**:
  • Dissolve compound in hot solvent
  • Cool slowly; pure compound crystallizes
  • Filter crystals; wash with cold solvent
  • Dry crystals
  • **Best for**: Solid compounds with distinct solubility changes with temperature
  • **Example**: Recrystallization of naphthalene from hot ethanol
  • **2. Distillation**

  • **Principle**: Separation based on **boiling points**
  • **Procedure**:
  • Heat liquid mixture to vaporization
  • Vapor condenses at collection point
  • Liquid with lower boiling point distills first
  • **Variants**:
  • **Simple distillation**: For liquids differing by ≥30°C in boiling points
  • **Fractional distillation**: For liquids with similar boiling points (uses fractionating column)
  • **Steam distillation**: For heat-sensitive compounds; uses steam to lower boiling point
  • **Vacuum distillation**: For compounds that decompose at high temperature
  • **Example**: Separation of ethanol (b.p. 78°C) from water (b.p. 100°C)

    **3. Sublimation**

  • **Principle**: Substance vaporizes directly from solid to gas without melting
  • **Requirements**: Compound must have **vapor pressure** at reasonable temperature
  • **Examples**: Dry ice (CO₂), iodine (I₂), camphor sublime under reduced pressure
  • **Advantage**: Very pure product (only sublime compound vaporizes)
  • **4. Chromatography**

  • **Principle**: **Differential distribution** of components between mobile and stationary phases
  • **Types**:
  • **Paper chromatography**: Mobile phase (solvent) travels up paper; compounds separate by affinity
  • **Thin-layer chromatography (TLC)**: Stationary phase = silica/alumina on plate; superior resolution
  • **Gas chromatography (GC)**: Gas is mobile phase; excellent for volatile compounds
  • **Column chromatography**: Stationary phase packed in column; solvent percolates; fractions collected
  • **Principle**: Different compounds have different **Rf values** (ratio of distance traveled by compound to distance traveled by solvent)

    ---

    QUALITATIVE ANALYSIS OF ORGANIC COMPOUNDS

    **Objective**: Identify the **presence of elements** (C, H, N, S, halogens) and **functional groups** in organic compounds.

    Detection of Elements

    **Carbon and Hydrogen:**

  • **Test**: Heat compound with copper oxide (CuO)
  • **Reaction**:
  • C + 2CuO → 2Cu + CO₂↑ (black copper oxide turns red; CO₂ turns limewater white)
  • 2H + CuO → Cu + H₂O (water condenses on glass rod)
  • **Conclusion**: Presence of CO₂ and H₂O confirms C and H
  • **Nitrogen:**

  • **Denitrification test**: Heat compound with soda lime (CaO + NaOH)
  • **Indicator**: Ammonia (NH₃) gas released; pungent smell; turns red litmus blue
  • **Equation**: Organic-N + NaOH/heat → NH₃↑ + Na-salt
  • **Sulfur:**

  • **Test**: Fuse compound with sodium metal; cool; add dilute HCl
  • **Reaction**: S + Na → Na₂S; Na₂S + HCl → NaHS + NaCl
  • **Detection**: Lead acetate paper turns black (Na₂S + Pb²⁺ → PbS↓, black)
  • **Halogens (Cl, Br, I):**

  • **Denitrification with sodium**: Heat with Na metal in alcohol
  • **Products**: NaCl, NaBr, NaI
  • **Test with AgNO₃**: Add dilute HNO₃ then AgNO₃
  • Cl⁻ → AgCl↓ (white precipitate)
  • Br⁻ → AgBr↓ (pale yellow)
  • I⁻ → AgI↓ (yellow)
  • Detection of Functional Groups

    **Alkenes (C=C):**

  • **Baeyer's test**: Add dilute KMnO₄ (purple) in water
  • **Observation**: Purple color decolorizes; brown MnO₂ precipitate forms
  • **Equation**: C=C + KMnO₄ → diol + MnO₂↓
  • **Alkynes (C≡C):**

  • **Tollens' reagent test**: Add Tollens' reagent (ammoniacal silver solution)
  • **Observation**: Silver mirror forms (Ag⁺ → Ag metal)
  • **Only alkyne**: Reacts with Tollens' due to acidic terminal hydrogen in alkyne
  • **Alcohols (—OH):**

  • **Ferric chloride test**: Add neutral FeCl₃
  • **Observation**: No color change (unlike phenols which give colored complex)
  • **Alternative**: Oxidation test—oxidize with K₂Cr₂O₇₂ in acidic medium
  • Primary alcohols → aldehyde → carboxylic acid
  • Secondary alcohols → ketones
  • Color change: Orange Cr₂O₇²⁻ → green Cr³⁺
  • **Phenols (—OH on benzene):**

  • **FeCl₃ test**: Add ferric chloride
  • **Observation**: Characteristic colored complex (violet, purple, green depending on phenol type)
  • **Example**: Phenol + FeCl₃ → violet complex
  • **Aldehydes (—CHO):**

  • **Tollens' test**: Add Tollens' reagent (ammoniacal silver solution)
  • **Observation**: Silver mirror forms (RCHO oxidized to RCOOH; Ag⁺ → Ag)
  • **Fehling's test**: Add Fehling's reagent (Cu²⁺ complex in basic solution)
  • **Observation**: Blue color → red precipitate of Cu₂O↓
  • **Ketones (C=O):**

  • **2,4-DNP test**: Add 2,4-dinitrophenylhydrazine
  • **Observation**: Yellow/orange precipitate forms (2,4-DNP hydrazone)
  • **Note**: Aldehydes also give this test; use Tollens' to distinguish (aldehydes give silver mirror; ketones don't)
  • **Carboxylic Acids (—COOH):**

  • **Sodium carbonate test**: Add Na₂CO₃ solution
  • **Observation**: Effervescence (CO₂ gas); foam
  • **Equation**: RCOOH + Na₂CO₃ → RCOONa + H₂O + CO₂↑
  • **Amines (—NH₂):**

  • **Carbylamine test**: Add chloroform (CHCl₃) and alkali
  • **Reaction**: Amine + CHCl₃ + KOH → isocyanide (R—N=C)
  • **Observation**: Pungent odor (like decaying fish)
  • ---

    QUANTITATIVE ANALYSIS OF ORGANIC COMPOUNDS

    **Objective**: Determine **percentage composition** of elements (C, H, N, S)

    MCQs — 10 Questions with Answers

    Q1. What is the hybridization of carbon in acetylene (HC≡CH)?

    • A. sp ✓
    • B. sp²
    • C. sp³
    • D. sp³d

    Answer: A — Acetylene has a triple bond (1 σ + 2 π), requiring sp hybridization to form 2 σ bonds and accommodate 2 π bonds in linear geometry.

    Q2. Which statement about π bonds is correct?

    • A. π bonds allow free rotation about the bond axis
    • B. π bonds are formed by head-on overlap of atomic orbitals
    • C. π bonds place electron density above and below the molecular plane ✓
    • D. π bonds are stronger than σ bonds of the same atoms

    Answer: C — π bonds form from sideways overlap of p-orbitals, creating electron density above and below the bonding plane; rotation is restricted and they are weaker than σ bonds.

    Q3. Identify the number of σ bonds and π bonds in the compound CH₂=CH-C≡CH.

    • A. 5 σ and 1 π
    • B. 6 σ and 3 π
    • C. 7 σ and 3 π ✓
    • D. 8 σ and 2 π

    Answer: C — Structure has: C-C (σ), C=C (σ + π), C-C (σ), C≡C (σ + 2π), plus 4 C-H bonds (σ each) = 7 σ and 3 π total.

    Q4. Which carbon atom is most electronegative in the molecule CH₃-C≡C-CH₂OH?

    • A. First C (sp³ in CH₃)
    • B. Middle C atoms (sp in C≡C) ✓
    • C. Last C (sp³ in CH₂OH)
    • D. All carbons have equal electronegativity

    Answer: B — sp-hybridized carbons have 50% s-character, making them most electronegative; sp² has 33% s-character and sp³ has 25% s-character.

    Q5. In the condensed formula (CH₃)₂CHCH₂CH₃, how many carbon atoms are bonded to three other carbon atoms?

    • A. 0
    • B. 1 ✓
    • C. 2
    • D. 3

    Answer: B — The structure is (CH₃)₂CH-CH₂-CH₃; only the middle CH carbon (after the first C) is bonded to three other carbons (one primary and two methyls).

    Q6. Which representation correctly shows 2-methylbutane using bond-line formula?

    • A. A vertical line with two branches at the second position
    • B. A zigzag with 5 vertices total
    • C. A zigzag with 4 vertices and a methyl branch at position 2 ✓
    • D. A straight chain of 4 carbons only

    Answer: C — 2-methylbutane (5 carbons total) has a 4-carbon main chain with a methyl branch at C-2; bond-line shows 4 vertices for main chain plus one branch.

    Q7. Which pair of statements about organic compounds is INCORRECT?

    • A. Catenation allows carbon to form long chains; ethane and ethene both contain σ bonds
    • B. Rotation is restricted in C=C bonds; sp³ carbons are tetrahedral
    • C. π bonds are easily attacked by reagents; sp-hybridized C forms triple bonds
    • D. All atoms in alkenes are coplanar; carbon in H-C≡C-H is sp² hybridized ✓

    Answer: D — In acetylene H-C≡C-H, carbon is sp hybridized (linear), not sp² (which is trigonal planar); all other statements are correct.

    Q8. Wöhler's synthesis of urea from ammonium cyanate in 1828 was significant because it:

    • A. Proved organic compounds always require a vital force to form
    • B. Demonstrated that organic compounds could be synthesized from inorganic precursors ✓
    • C. Showed that catenation is impossible in inorganic chemistry
    • D. Established that all organic molecules contain nitrogen

    Answer: B — This landmark synthesis disproved Berzelius's vital force theory by showing organic compounds like urea could be made synthetically from inorganic starting materials.

    Q9. Consider ethene (C₂H₄): If a reagent approaches the double bond, why does it attack the π bond preferentially over σ bonds? [HOTS: Multi-step reasoning required]

    • A. σ bonds are stronger and harder to break
    • B. π electrons are located above and below the molecular plane, making them more accessible and exposed ✓
    • C. π bonds have lower bond dissociation energy only
    • D. Reagents cannot attack σ bonds in any organic molecule

    Answer: B — The π-electron cloud (from p-orbital sideways overlap) extends above and below the C-C bond plane, making these electrons easily exposed and accessible to attacking reagents, while σ-electrons are localized between atoms.

    Q10. In the following molecule, count the total number of σ bonds and identify which carbon has sp² hybridization: CH₃-CH=CH-CH₂-C≡N [Assertion-style: Both statements must be evaluated]

    • A. 11 σ bonds total; C-2 (first C in double bond) is sp² ✓
    • B. 10 σ bonds total; C-3 (second C in double bond) is sp²
    • C. 12 σ bonds total; C-4 is sp² hybridized
    • D. 9 σ bonds total; the nitrogen is sp hybridized

    Answer: A — σ bonds: 3 C-H (methyl) + 1 C-C + 1 C=C (σ part) + 1 C-C + 1 C≡N (σ part) + 2 C-H on C-2 + 1 C-H on C-3 + 1 C-H on C-4 + 1 C-H on C-5 = 11 σ total; both carbons in the double bond are sp², but C-2 is specified.

    Flashcards

    What is the hybridization of carbon in methane (CH₄) and what is its shape?

    Carbon is sp³ hybridized in methane, giving it a tetrahedral shape with 109.5° bond angles.

    Why is rotation about a C=C double bond restricted?

    Rotation is restricted because the π bond requires parallel p-orbital alignment; rotation would destroy maximum overlap and weaken the bond.

    Which hybridized carbon (sp, sp², or sp³) is most electronegative and why?

    sp-hybridized carbon is most electronegative because it has 50% s-character, and s-electrons are held closer to the nucleus than p-electrons.

    How many σ and π bonds are in ethyne (HC≡CH)?

    Ethyne has 3 σ bonds (1 C-C and 2 C-H) and 2 π bonds (between the two carbon atoms).

    What is the key difference between Lewis structure and bond-line structural formula?

    Lewis structure shows all atoms and electrons; bond-line formula omits C and H atoms and shows only zigzag lines and heteroatoms.

    State Wöhler's synthesis and its significance.

    Wöhler synthesized urea (NH₂CONH₂) from ammonium cyanate in 1828, disproving the 'vital force' theory and proving organic compounds can be made synthetically.

    In a π bond, where is the electron charge cloud located relative to the bonding atoms?

    The electron charge cloud of a π bond is located above and below the plane of the bonding atoms, making electrons easily accessible to attacking reagents.

    How does hybridization affect bond length in carbon compounds?

    sp-hybridized C forms shortest and strongest bonds; sp² is intermediate; sp³ forms longest and weakest bonds due to increasing p-character.

    Why must all atoms in ethene (C₂H₄) lie in the same plane?

    All atoms must be coplanar in ethene because the π bond requires parallel orientation of p-orbitals perpendicular to the molecular plane.

    What is catenation and which element is most famous for this property?

    Catenation is the ability of an element to form covalent bonds with itself; carbon is most famous for this due to its small size and high bond strength.

    Important Board Questions

    Define hybridization and explain why carbon in methane (CH₄) is sp³ hybridized. What is the shape of methane and its bond angle? [2 marks]

    State that hybridization is mixing of atomic orbitals to form new hybrid orbitals; carbon's 1s²2s²2p² configuration requires sp³ mixing to form 4 equivalent bonds; tetrahedral shape with 109.5° angles result from this geometry.

    Explain why rotation about the C=C double bond in ethene (C₂H₄) is restricted. Draw the structure and show how the π bond restricts rotation. What would happen if rotation occurred? [5 marks]

    Show that π bond forms from sideways overlap of parallel p-orbitals; rotation would misalign p-orbitals and break π-bond overlap; draw the molecule showing p-orbitals perpendicular to the molecular plane; explain that the resulting loss of π bonding energy prevents free rotation.

    Compare sp, sp², and sp³ hybridization in terms of (i) geometry, (ii) bond length, (iii) bond strength, and (iv) electronegativity of carbon. Justify your answer with reference to s-character. Give one example compound for each hybridization type. How does hybridization influence the reactivity of organic compounds? [6 marks]

    Create a table showing linear/trigonal planar/tetrahedral for geometry; explain that higher s-character means electrons closer to nucleus → shorter, stronger bonds and higher electronegativity; justify using orbital penetration; provide HC≡CH (sp), C₂H₄ (sp²), CH₄ (sp³); explain that π bonds (from sp and sp²) are reactive sites attacked by electrophiles due to exposed electron density.

    Next chapterHydrocarbons →

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