**INTRODUCTION TO TRIGONOMETRY – COMPLETE CHEAT SHEET**
**1. WHAT IS TRIGONOMETRY?**
• Trigonometry = study of relationships between sides and angles of triangles
• Word origin: 'tri' (three) + 'gon' (sides) + 'metron' (measure)
• Focus: Right-angled triangles and acute angles
• Real-world applications: Finding heights/distances without direct measurement (buildings, rivers, balloons, celestial objects)
**2. DEFINING SIDES IN RIGHT TRIANGLES**
For acute angle A in right triangle ABC (with right angle at B):
• **Hypotenuse** = side opposite the right angle (longest side)
• **Opposite side** = side facing angle A (does not touch angle A)
• **Adjacent side** = side next to angle A (one arm of the angle, not hypotenuse)
**3. THE SIX TRIGONOMETRIC RATIOS**
For acute angle A in right triangle:
• **sin A = (Opposite)/(Hypotenuse)** → sine
• **cos A = (Adjacent)/(Hypotenuse)** → cosine
• **tan A = (Opposite)/(Adjacent)** → tangent
• **cosec A = (Hypotenuse)/(Opposite) = 1/sin A** → cosecant (reciprocal of sine)
• **sec A = (Hypotenuse)/(Adjacent) = 1/cos A** → secant (reciprocal of cosine)
• **cot A = (Adjacent)/(Opposite) = 1/tan A** → cotangent (reciprocal of tangent)
Memory aid: **SOH-CAH-TOA** (Sin=Opp/Hyp, Cos=Adj/Hyp, Tan=Opp/Adj)
**4. IMPORTANT RELATIONSHIPS BETWEEN RATIOS**
• **tan A = sin A / cos A** → tangent equals sine divided by cosine
• **cot A = cos A / sin A** → cotangent equals cosine divided by sine
• **sin A × cosec A = 1** → sine and cosecant are reciprocals
• **cos A × sec A = 1** → cosine and secant are reciprocals
• **tan A × cot A = 1** → tangent and cotangent are reciprocals
**5. FUNDAMENTAL PROPERTY: RATIOS ARE INDEPENDENT OF TRIANGLE SIZE**
• If angle A is fixed, trigonometric ratios remain **constant** regardless of triangle size
• Proof basis: Similar triangles have proportional sides (AA similarity)
• Example: Two right triangles with same angle A will have identical sin A, cos A, etc., even if their sides differ
**6. CALCULATING UNKNOWN RATIOS FROM ONE RATIO**
If one ratio is known, all others can be found:
• **Method**: If sin A = p/q, construct a right triangle where opposite = p, hypotenuse = q
• Use **Pythagoras theorem** (a² + b² = c²) to find the third side (adjacent)
• Then calculate all remaining ratios
Example: If sin A = 1/3
**7. NOTATION AND CONVENTIONS**
• **sin²A means (sin A)²**, not sin × A twice
• **sin A is NOT sin × A** → it's a single function value
• **cosec A ≠ sin⁻¹A** → sin⁻¹A is 'sine inverse' (different concept, studied later)
• Similar conventions apply to cos, tan, sec, cot
• Letter **θ (theta)** often used to denote angles
**8. TRIGONOMETRIC RATIOS FOR ANGLES 0° AND 90°**
• **At 0°**: sin 0° = 0, cos 0° = 1, tan 0° = 0
• **At 90°**: sin 90° = 1, cos 90° = 0, cot 90° = 0
• **Undefined ratios**: tan 90° and sec 90° (division by zero)
**9. COMMON MISTAKES TO AVOID**
• ❌ Confusing opposite and adjacent → Always draw/identify angle first
• ❌ Using wrong sides → Remember: hypotenuse is always the longest side in denominator for sin/cos
• ❌ Forgetting Pythagoras theorem → Essential for finding third side when calculating other ratios
• ❌ Mixing up reciprocal pairs → cosec is reciprocal of sin, sec of cos, cot of tan
• ❌ Wrong triangle identification → Ensure right angle is correctly positioned
**10. PROBLEM-SOLVING APPROACH**
**For finding unknown ratios:**
**For height/distance problems:**
**11. KEY TRIGONOMETRIC IDENTITIES (To be proven)**
• **sin²A + cos²A = 1** → Fundamental identity (proved using Pythagoras)
• **1 + tan²A = sec²A** → Derived from fundamental identity
• **1 + cot²A = cosec²A** → Derived from fundamental identity
These identities allow simplification and proof of trigonometric equations.
Q1. A student measures angle A in a right triangle ABC (right angle at B) using two different right triangles: one where AB = 3, BC = 4, and another where AB = 6, BC = 8. She calculates sin A in both triangles and gets different values. Why does this happen?
Answer: A — By the AA similarity criterion and proportionality of similar triangles, sin A = BC/AC is constant for a given angle regardless of triangle size; the student made a calculation error, not a conceptual one. Option B wrongly suggests trigonometric ratios depend on absolute side lengths rather than their proportion.
Q2. In right triangle ABC with right angle at C, a student observes that sin A × cosec A = 1. Her teacher asks her to verify this is true for ALL acute angles. Which reasoning correctly explains why this must always be true?
Answer: A — Cosec A is defined as 1/sin A, making them reciprocals by definition, so their product is always 1. Option B confuses the hypotenuse with another side in the definition of cosec A.
Q3. A surveyor uses the relationship tan A = sin A / cos A to calculate the height of a building. A student claims this relationship is merely a rearrangement and doesn't reveal anything new about angle A. Is this claim correct?
Answer: B — The relationship tan A = sin A / cos A is algebraically derived from definitions but reveals a fundamental interconnection between the three primary ratios, not merely a rearrangement. Option A misses the conceptual significance of how ratios relate.
Q4. Two students draw right triangles with angle A = 60°. One student uses a 3-4-5 triangle to find sin 60°, while another uses a different right triangle. They get different numerical values. What is the most likely explanation?
Answer: B — A 3-4-5 right triangle has angles approximately 37°, 53°, and 90°, so it cannot contain a 60° angle; this eliminates one calculation as impossible. Option A assumes both calculations are valid, which they cannot be.
Q5. Assertion (A): For any acute angle A in a right triangle, cot A = cos A / sin A. Reason (R): Cotangent is defined as the reciprocal of tangent, and tangent equals sin A / cos A. Choose the correct option:
Answer: A — Both statements are true: cot A = 1/tan A = 1/(sin A/cos A) = cos A/sin A, and R correctly explains why A is true. The logical chain directly connects the definition of cot to the formula.
Q6. Assertion (A): If sin A = 3/5 for some acute angle A, then cos A must equal 4/5. Reason (R): In any right triangle, sin²A + cos²A = 1 (the Pythagorean identity). Choose the correct option:
Answer: A — If sin A = 3/5, then sin²A = 9/25, so cos²A = 1 − 9/25 = 16/25, giving cos A = 4/5 (positive for acute A). The Pythagorean identity (R) directly justifies this conclusion (A).
Q7. A student claims: 'Since sin A and cos A are both ratios of sides in a right triangle, they must always be less than 1.' Is this claim always true, sometimes true, or never true?
Answer: A — For acute angles, sin A = opposite/hypotenuse < 1 and cos A = adjacent/hypotenuse < 1 always hold because the hypotenuse is the longest side in a right triangle. Option C confuses absolute side lengths with ratios.
Q8. When you extend point P on the hypotenuse AC (or beyond) and draw perpendiculars to form new right triangles, the trigonometric ratios of angle A remain unchanged. This is true because:
Answer: B — The AA similarity criterion guarantees that all triangles formed with the same angle A are similar to ABC, and similarity preserves proportional side ratios. Option A states a true fact but does not explain why ratios remain unchanged.
Q9. A right triangle has sides in the ratio 1 : √3 : 2 (opposite to angles 30°, 60°, and 90° respectively). A student uses this to claim that sin 30° = 1/2. Is this reasoning correct?
Answer: A — Sin 30° = opposite/hypotenuse = 1/2 follows directly from the side ratio, and this value holds for ANY 30-60-90 triangle (by similarity). Option C wrongly suggests trigonometric ratios depend on absolute side lengths.
Q10. A student observes that in her right triangle, sin A < cos A. She concludes that angle A must be less than 45°. Is her conclusion logically justified?
Answer: B — If sin A < cos A, then opposite/hypotenuse < adjacent/hypotenuse, so opposite < adjacent; in a right triangle this occurs precisely when A < 45°. Option A incorrectly assumes sine increases monotonically with angle size.
In right triangle ABC with acute angle A, define sine of angle A.
sin A = (side opposite to angle A) / (hypotenuse) = BC/AC.
What is the relationship between tan A, sin A, and cos A?
tan A = sin A / cos A, which equals (opposite/hypotenuse) ÷ (adjacent/hypotenuse) = opposite/adjacent.
Name the reciprocal relationship for sine, cosine, and tangent.
cosec A = 1/sin A, sec A = 1/cos A, and cot A = 1/tan A.
Why do trigonometric ratios remain constant even if triangle size changes?
Triangles with the same angle are similar; their corresponding sides are proportional, keeping ratios equal.
In right triangle ABC with right angle at B, which side is the hypotenuse?
AC is the hypotenuse because it is the side opposite the right angle.
For acute angle A in right triangle ABC, define cosine of angle A.
cos A = (side adjacent to angle A) / (hypotenuse) = AB/AC.
What does 'opposite side' mean for angle A in a right triangle?
The side opposite to angle A is the side that does not form angle A and faces it.
If sin A = 1/3, what can you say about the sides BC and AC?
The sides BC and AC are in ratio 1:3, meaning if BC = k, then AC = 3k for some positive k.
Which trigonometric ratios are independent, and which are dependent?
sin A, cos A, and tan A are independent; cosec A, sec A, and cot A are their reciprocals and dependent.
When you change from angle A to angle C in the same right triangle, what happens to 'opposite' and 'adjacent'?
The sides that were opposite to A become adjacent to C, and vice versa, because the angle position changes.
In right triangle ABC with right angle at B, side AB = 5 cm and side BC = 12 cm. Find sin A and cos A. [2 marks]
Use Pythagoras theorem to find AC (hypotenuse = 13 cm). Then apply definitions: sin A = opposite/hypotenuse = BC/AC = 12/13 and cos A = adjacent/hypotenuse = AB/AC = 5/13.
If sin A = 3/5 in a right triangle, find the values of cos A and tan A without using a calculator. Explain your reasoning. [3 marks]
Set opposite = 3k and hypotenuse = 5k for some positive k. Use Pythagoras to find adjacent = 4k. Then cos A = adjacent/hypotenuse = 4/5 and tan A = opposite/adjacent = 3/4. Explain that k cancels out in ratios.
A student stands 15 metres away from the base of a tower. The angle of elevation to the top of the tower is A. If tan A = 4/3, find the height of the tower. Also explain why the trigonometric ratio remains the same if we move to a different distance and measure a different angle. [5 marks]
Use tan A = height/distance; 4/3 = height/15, so height = 20 metres. For the second part, explain using similar triangles: when angle A is fixed, any right triangle with angle A has proportional sides, so the ratio opposite/adjacent is always 4/3 regardless of triangle size. Similar triangles have equal trigonometric ratios for the same angle.
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